![Need to solve a sum
i/(1-i) + i/(1+i)
Solution
We need to find the result of i/(1-i) + i/(1+i)
Now we have : i/(1-i) + i/(1+i)
let's make the denominator equal.
=> i(1+i)/ (1+i)(1-i) + i (1-i)/ (1+i)(1-i)
= [ i + i^2 + i - i^2 ] / (1+i)(1-i)
=>2i / (1+i)(1-i)
=> 2i / 1^2 - i^2
=> 2i / 1 +1
=> 2i / 2
=> i
Therefore i/(1-i) + i/(1+i) simplified is i.](https://image.slidesharecdn.com/needtosolveasumi1-ii1isolutionweneedtofind-230325053520-2586e104/85/Need-to-solve-a-sumi-1-i-i-1-i-SolutionWe-need-to-find-pdf-1-320.jpg)
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Need to solve a sumi(1-i) + i(1+i)SolutionWe need to find .pdf
- 1. Need to solve a sum i/(1-i) + i/(1+i) Solution We need to find the result of i/(1-i) + i/(1+i) Now we have : i/(1-i) + i/(1+i) let's make the denominator equal. => i(1+i)/ (1+i)(1-i) + i (1-i)/ (1+i)(1-i) = [ i + i^2 + i - i^2 ] / (1+i)(1-i) =>2i / (1+i)(1-i) => 2i / 1^2 - i^2 => 2i / 1 +1 => 2i / 2 => i Therefore i/(1-i) + i/(1+i) simplified is i.