An object is thrown with an initial velocity of 14 ft per second. Its height is given by h= -14t^2 + 56 at time t seconds. After how many seconds does it hit the ground? Solution we have... speed = 14 ft/second distance or h = -14t^2 + 56 also we know that ...Distance = speed * time putting the above values in the formula..we get -14t^2 + 56 = 14 * t taking common 14 from LHS ,,we get 14 ( -t^2 + 4) = 14 * t divide both sides by 14 and we get ... -t^2 + 4 = t or 0 = t^2 + t - 4 solve the value of t by discriminent and you get the value of t and put the value of t in formula ..distance = speed * time and you get distance also.,..