I have taken coaching from NARESH INSTITUTE for CRT (Campus Recruitment Training). In these videos, I have explained all the questions with answer and how to approach for the question etc, in the same manner how they have taught to me at the time of training. Hope u like it. Aptitude training playlist link : https://www.youtube.com/playlist?list=PL3v9ipJOEEPfumKHa02HWjCfPvGQiPZiG For full playlist of Interview puzzles videos : https://www.youtube.com/playlist?list=PL3v9ipJOEEPfI4zt4ExamGJwndkvg0SFc 24 standard interview puzzles: https://www.youtube.com/playlist?list=PL3v9ipJOEEPefIF4nscYOobim1iRBJTjw for C and C++ questions, that are asked in the interviews, go through the posts in the link : http://comsciguide.blogspot.com/ for more videos, my youtube channel : https://www.youtube.com/channel/UCvMy2V7gYW7VR2WgyvLj3-A

1. Calenders
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2. 1. What is the maximum number of years, a person has to wait to celebrate
his birthday?
2. In which year, can the calendar of the year 2010, can be used once
again immediately?
3. 12th june 1980, falls on which day?
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3. • If 1st January of a non-leap year is Monday, then 31st December of the same
year falls Monday and 1st Jan of next year falls on Tuesday.
• If 1st Jan of a leap year is Monday, then 31st December of the same year falls
Tuesday and 1st Jan of next year falls on Wednesday.
• A leap year calendar (4n) can be used after 28 years. The calendar of the year
in the form of (4n+1) can be used after every 6 years.
• The calendar of year 4n+2 and 4n+3 can be used after every 11years.
2010 – Friday
2011 – Saturday 2017 – Sunday
2012 – Sunday 2018 – Monday
2013 – Tuesday 2019 – Tuesday
2014 – Wednesday 2020 – Wednesday
2015 – Thursday 2021 – Friday
2016 – Friday
Year in the Form Repetition after
years
4n 28
4n+1 6
4n+2 11
4n+3 11
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4. • Odd days : The days those cannot be converted into weeks
• A non-leap year has one odd day and a leap year has 2 odd
days.
• 31st dec – 0100 is the last day of century.
• Last day of the century can be Friday, Wednesday, Monday or
Sunday.
• A century begins with Saturday, Thursday, Tuesday or Monday
For Years Odd days
100 5
200 3
300 1
400 0
For Years Odd days
500 5
600 3
700 1
800 0
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5. What is the maximum number of years, a person has to wait to celebrate
his birthday?
1.
Ans :
A leap year should be divisible by 4. but if a leap year that is ending with 00
then that should be divisible by 400. then only it is called as Leap year.
1896 , 1900, 1904 …in this series 1900 is not a leap year
Therefore a person born on 28th February in leap year have to wait again
for 1904.
Maximum number of years is 8
Maximum number of years is 8
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6. In which year, can the calendar of the year 2010, can be used once
again immediately?
2.
2010 calendar can be used again after 11 years i.e. in 2021
Ans:
2010 is in the form of 4n+2
 2010 calendar can be used again
after 11 years i.e. in 2021
Year in the Form Repetition after
years
4n 28
4n+1 6
4n+2 11
4n+3 11
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7. 12th June 1980, falls on which day?3.
Ans :
For this kind of question, first find out the number of odd days
Till 1979 we have to find out the number of odd days.
1979 – 1600 + 300 + 79
Now find out the number of odd days till the date
Up to may there are 3 + 1 + 3 + 2 + 3 + 5 = 3 odd days
=> 1 + 3 = 4 odd days
Therefore the day is Thursday
0 1 19 2 + 60 1 = 99 odd days = 1 odd days 1 Mon
2 Tues
3 wed
4 Thu
5 Fri
6 Sat
0 Sun
For June till 12th
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Problems for practice are given in the description of the video.
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9. Practice problems
on Calendars
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10. 1. 16/4/1994 falls on which day?
2. 18/2/1995 falls on which day?
3. Find out the day on which u born?
Practice:
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11. 16/4/1994, falls on which day?1.
Ans :
For this kind of question, first find out the number of odd days
Till 1993 we have to find out the number of odd days.
1993 – 1600 + 300 + 93
Now find out the number of odd days till the date
Up to may there are 3 + 0 + 3 + 2 = 1 odd days
=> 1 + 5 = 6 odd days
Therefore the day is Saturday
0 1 23 2 + 60 1 = 117 odd days = 5 odd days 1 Mon
2 Tues
3 wed
4 Thu
5 Fri
6 Sat
0 Sun
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12. 18/2/1995, falls on which day?2.
Ans :
For this kind of question, first find out the number of odd days
Till 1995 we have to find out the number of odd days.
1995 – 1600 + 300 + 95
Now find out the number of odd days till the date
Up to may there are 3 + 4= 0 odd days
=> 0 + 6 = 6 odd days
Therefore the day is Saturday
0 1 23 2 + 74 1 = 118 odd days = 6 odd days 1 Mon
2 Tues
3 wed
4 Thu
5 Fri
6 Sat
0 Sun
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13. Subscribe to :
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