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1.
𝐴 = 𝜋𝑟2
𝐴 = 𝜋202
𝐴 = 3.141592654
𝐴 = 𝜋400
𝐴 = 1256.637061/4
𝐴 = 3.141592654𝑥2
𝐴 = 628.3185307
ESTA CANTIDAD POR DOS
171.6814693 ∗ 2 = 343.3629386
ESTE RESULTADO SERIA EL AREA DE
LA PARTE SOMBREADA
81 = 9
DESPUES SE SACARA LA RAIZ DE LA DIAGONAL DEL CUADRADO
MENOR
𝑑 = 𝑙2 + 𝑙2
𝑑 = 92 + 92
𝑑 = 81 + 81
𝑑 = 162
𝑑 = 12.72792206
9 in
9in
12.72732206
2
= 6.36396103
Cuando obtuvimos el resultado, USAREMOS LA FORMULA
PARA SACAR EL AREA DEL CIRCULO
𝐴 = 𝜋𝑟2
𝐴 = 𝜋 ∗ 6.363961032
𝐴 = 𝜋 ∗ 40.49999999
𝐴 = 127.2345024
ESTE RESULTADO SERIA EL AREA DEL
CIRCULO
Problema de-razonamiento-abigail

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Problema de-razonamiento-abigail

  • 1.
  • 2. 1.
  • 3.
  • 4. 𝐴 = 𝜋𝑟2 𝐴 = 𝜋202 𝐴 = 3.141592654 𝐴 = 𝜋400 𝐴 = 1256.637061/4 𝐴 = 3.141592654𝑥2 𝐴 = 628.3185307
  • 5.
  • 6. ESTA CANTIDAD POR DOS 171.6814693 ∗ 2 = 343.3629386 ESTE RESULTADO SERIA EL AREA DE LA PARTE SOMBREADA
  • 7.
  • 8. 81 = 9 DESPUES SE SACARA LA RAIZ DE LA DIAGONAL DEL CUADRADO MENOR 𝑑 = 𝑙2 + 𝑙2 𝑑 = 92 + 92 𝑑 = 81 + 81 𝑑 = 162 𝑑 = 12.72792206 9 in 9in
  • 9. 12.72732206 2 = 6.36396103 Cuando obtuvimos el resultado, USAREMOS LA FORMULA PARA SACAR EL AREA DEL CIRCULO 𝐴 = 𝜋𝑟2 𝐴 = 𝜋 ∗ 6.363961032 𝐴 = 𝜋 ∗ 40.49999999 𝐴 = 127.2345024 ESTE RESULTADO SERIA EL AREA DEL CIRCULO