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Chemical Reactions
Lecture-10
Stereo-chemical aspects of
nucleophilic substitution reaction
Lecture-10
2. Which of the following reaction will go faster if the concentration of the
nucleophile is raised?
(a) I and III (b) I, II and III
(c) l and II (d) none
Can you crack it
Lecture-10
Plane Polarised light
Light which is produced by passing ordinary light through a Nicol prism
and which has vibrations in single plane only is called plane polarised
light
Stereo-chemical aspects of nucleophilic substitution reaction
Stereo-chemical aspects of nucleophilic substitution reaction
Light passing through crossed polarizers
Light passing through polarizers
If the spatial arrangement of four groups around a central carbon is
tetrahedral and all the substituents attached to that carbon are
different, such a carbon is called asymmetric carbon or stereocenter.
The asymmetry of the molecule is responsible for the optical activity
in such organic compounds.
Asymmetric molecule
Chirality
The objects which are non-superimposable on their mirror image are
said to be chiral and this property is known as chirality.
Chirality
A compound having at least one carbon atom having all the four
different groups attached to it is called chiral compound or optically
active compound.
How to identify whether a molecule is chiral?
Let us have few examples
★
1. CH3 - CH2 - CH - CH3
|
Br
★
2. CH3 - CH2 - CH - CH = CH2
|
Br
Lecture-10
Identify chiral and achiral molecules in each of the following pair of
compounds.
(Wedge and dash representations according to Class XI. Fig 12.1).
Lecture-10
Practice is must
Lecture-10
5. In which of the following molecules carbon atom marked with an asterisk ()
is asymmetric?
(A) (a), (b), (c), (d)
(C) (b), (c), (d)
(B) (a), (b), (c)
(D) (a), (c). (d)
Can you crack it
Lecture-10
Lecture-10
Lecture-10
50:50 mixture of the above two is obtained then the process is called
racemisation and the product is optically inactive, as one isomer will
rotate light in the direction opposite to another
Lecture-10
Nuc
H3CH2C
H3C
H Nuc
LG
H3CH2C
H3C
H
H
CH3
CH2CH3
Nuc
50% : 50%
Fresh look at SN1 and SN2 mechanisms
Lecture-10
H3CH2C
H3C
H
LG
50% : 50%
Fresh look at SN1 and SN2 mechanisms
Lecture-10
SN2 Mechanism
Lecture-10
..from NCERT
Lecture-10
..from NCERT
Lecture-10
..from NCERT
From NCERT
For Nucleophilic substitution
I
Short Tricks
Bulky alkyl groups ⇒SN1
Light alkyl groups ⇒SN2
Lecture-11
𝛽
- Elimination Reactions
When haloalkanes are heated with alcoholic KOH, they undergo
dehydrohalogenation to form alkenes. These reactions are called 𝛽-
eliminations because the hydrogen atom present at 𝛽- position of the
haloalkane is removed
𝛽
- Elimination Reactions
Lecture-11
𝛽
- Elimination Reactions
Lecture-11
Lecture-11
Lecture-11
(1) E2 is a concerted mechanism where all the bonds are broken and
formed in a single step. The E1, on the other hand, is a stepwise
mechanism.
(2) E2 reactions are favored by strong bases such as the methoxide
(MeC–), ethoxide (EtO–), potassium tert-butoxide (tBuOK), DBN, DBU,
LDA and etc.
The E1 reactions are favored by weak bases. The most common weak
bases are water and alcohols:
Differences between E1 and E2 mechanisms
on the
(3) E2 is a second-order reaction and the rate depends
concentration of both, the substrate and the base.
E2 : Rate = k [Substrate] [Base]
E1 : Rate = k [Substrate]
Differences between E1 and E2 mechanisms
Choosing between El and E2 is easier since the reactivity pattern is the
same for both: the rate of El and E2 increase with the degree of
substitution.
El or E2 ? The key factor here is the strength of the base.
E2 reactions are favored by strong bases.
E1 reactions are favored by weak bases.
Weak base – E1 Strong base - E2
Choosing between the El and E2 mechanisms
𝛽
- Elimination Reactions
The reactivity of haloalkanes towards elimination reaction follows the
order
Tertiary > Secondary > Primary
𝛽
- Elimination Reactions
Among various halides with same alkyl group the order of reactivity is
RI > RBr > RCl
𝛽
- Elimination Reactions
In case of two different products, the preferred alkene is the one
which is maximum alkylated i.e., which carries more number of alkyl
groups attached to the doubly bonded carbon atoms. This
generalisation is known as Saytzeff Rule. For example, 2-bromobutane
on reaction with alcoholic KOH gives but-2-enes as the major product
𝛽
- Elimination Reactions
Bulky alkyl groups ⇒SN1
Light alkyl groups ⇒SN2
For Nucleophilic substitution
I
Short Tricks
When Nucleophile is heavy, it becomes base
II
Aq KOH
CH3 - CH2 - OH
CH3 - CH2 - X
Alc KOH
CH2 = CH2
Short Tricks
CH3 - CH2 - CH2 - Cl + aqueous KOH
CH3
CH3 - C - CH3 + aqueous KOH
Cl
CH3 - CH2 - X + Alcoholic KOH
CH3 - CH2 - CH - CH3 + Alcoholic KOH
X
Elimination Versus Substitution (PRACTICE)
Match the items of Column I and Column II.
Column I Column II
(i) SN1 reaction (a) vic- dibromides
(ii) Chemicals in fire extinguisher (b) gem- dihalides
(iii) Bromination of alkenes (c) Racemisation
(iv) Alkylidene halides (d) Saytzeff rule
(v) Elimination of HX from alkyl halide (e) Chlorobromocarbons
(A) (i)–c, (ii)–e, (iii)–a, (iv)–b, (v)–d
(B) (i)–a, (ii)–c, (iii)–e, (iv)–b, (v)–d
(C) (i)–d, (ii)–a, (iii)–c, (iv)–b, (v)–e
(D) (i)–e, (ii)–c, (iii)–b, (iv)–a, (v)–d
Can you crack it
(A) CH3 - CH = CH2
(B) CH3 - CH - CH3
|
OH
(B) CH3CH2 - CH2 - OH
(D) None
The product of the following reaction is
Alc KOH
CH3 - CH2 - CH2 - Cl ?
Can you crack it
Haloarenes 3 (5).pdf

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Haloarenes 3 (5).pdf

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  • 48. Lecture-10 2. Which of the following reaction will go faster if the concentration of the nucleophile is raised? (a) I and III (b) I, II and III (c) l and II (d) none Can you crack it
  • 49. Lecture-10 Plane Polarised light Light which is produced by passing ordinary light through a Nicol prism and which has vibrations in single plane only is called plane polarised light Stereo-chemical aspects of nucleophilic substitution reaction
  • 50. Stereo-chemical aspects of nucleophilic substitution reaction
  • 51. Light passing through crossed polarizers
  • 52. Light passing through polarizers
  • 53. If the spatial arrangement of four groups around a central carbon is tetrahedral and all the substituents attached to that carbon are different, such a carbon is called asymmetric carbon or stereocenter. The asymmetry of the molecule is responsible for the optical activity in such organic compounds. Asymmetric molecule
  • 55. The objects which are non-superimposable on their mirror image are said to be chiral and this property is known as chirality. Chirality
  • 56. A compound having at least one carbon atom having all the four different groups attached to it is called chiral compound or optically active compound. How to identify whether a molecule is chiral?
  • 57. Let us have few examples ★ 1. CH3 - CH2 - CH - CH3 | Br ★ 2. CH3 - CH2 - CH - CH = CH2 | Br
  • 58. Lecture-10 Identify chiral and achiral molecules in each of the following pair of compounds. (Wedge and dash representations according to Class XI. Fig 12.1).
  • 60. Lecture-10 5. In which of the following molecules carbon atom marked with an asterisk () is asymmetric? (A) (a), (b), (c), (d) (C) (b), (c), (d) (B) (a), (b), (c) (D) (a), (c). (d) Can you crack it
  • 63. Lecture-10 50:50 mixture of the above two is obtained then the process is called racemisation and the product is optically inactive, as one isomer will rotate light in the direction opposite to another
  • 65. Lecture-10 H3CH2C H3C H LG 50% : 50% Fresh look at SN1 and SN2 mechanisms
  • 71. For Nucleophilic substitution I Short Tricks Bulky alkyl groups ⇒SN1 Light alkyl groups ⇒SN2
  • 72.
  • 74. When haloalkanes are heated with alcoholic KOH, they undergo dehydrohalogenation to form alkenes. These reactions are called 𝛽- eliminations because the hydrogen atom present at 𝛽- position of the haloalkane is removed 𝛽 - Elimination Reactions
  • 76.
  • 79. (1) E2 is a concerted mechanism where all the bonds are broken and formed in a single step. The E1, on the other hand, is a stepwise mechanism. (2) E2 reactions are favored by strong bases such as the methoxide (MeC–), ethoxide (EtO–), potassium tert-butoxide (tBuOK), DBN, DBU, LDA and etc. The E1 reactions are favored by weak bases. The most common weak bases are water and alcohols: Differences between E1 and E2 mechanisms
  • 80. on the (3) E2 is a second-order reaction and the rate depends concentration of both, the substrate and the base. E2 : Rate = k [Substrate] [Base] E1 : Rate = k [Substrate] Differences between E1 and E2 mechanisms
  • 81.
  • 82. Choosing between El and E2 is easier since the reactivity pattern is the same for both: the rate of El and E2 increase with the degree of substitution. El or E2 ? The key factor here is the strength of the base. E2 reactions are favored by strong bases. E1 reactions are favored by weak bases. Weak base – E1 Strong base - E2 Choosing between the El and E2 mechanisms
  • 83.
  • 85. The reactivity of haloalkanes towards elimination reaction follows the order Tertiary > Secondary > Primary 𝛽 - Elimination Reactions
  • 86. Among various halides with same alkyl group the order of reactivity is RI > RBr > RCl 𝛽 - Elimination Reactions
  • 87. In case of two different products, the preferred alkene is the one which is maximum alkylated i.e., which carries more number of alkyl groups attached to the doubly bonded carbon atoms. This generalisation is known as Saytzeff Rule. For example, 2-bromobutane on reaction with alcoholic KOH gives but-2-enes as the major product 𝛽 - Elimination Reactions
  • 88. Bulky alkyl groups ⇒SN1 Light alkyl groups ⇒SN2 For Nucleophilic substitution I Short Tricks
  • 89. When Nucleophile is heavy, it becomes base II Aq KOH CH3 - CH2 - OH CH3 - CH2 - X Alc KOH CH2 = CH2 Short Tricks
  • 90. CH3 - CH2 - CH2 - Cl + aqueous KOH CH3 CH3 - C - CH3 + aqueous KOH Cl CH3 - CH2 - X + Alcoholic KOH CH3 - CH2 - CH - CH3 + Alcoholic KOH X Elimination Versus Substitution (PRACTICE)
  • 91. Match the items of Column I and Column II. Column I Column II (i) SN1 reaction (a) vic- dibromides (ii) Chemicals in fire extinguisher (b) gem- dihalides (iii) Bromination of alkenes (c) Racemisation (iv) Alkylidene halides (d) Saytzeff rule (v) Elimination of HX from alkyl halide (e) Chlorobromocarbons (A) (i)–c, (ii)–e, (iii)–a, (iv)–b, (v)–d (B) (i)–a, (ii)–c, (iii)–e, (iv)–b, (v)–d (C) (i)–d, (ii)–a, (iii)–c, (iv)–b, (v)–e (D) (i)–e, (ii)–c, (iii)–b, (iv)–a, (v)–d Can you crack it
  • 92. (A) CH3 - CH = CH2 (B) CH3 - CH - CH3 | OH (B) CH3CH2 - CH2 - OH (D) None The product of the following reaction is Alc KOH CH3 - CH2 - CH2 - Cl ? Can you crack it