1) The intensity of an electric current goes down when the resistance in a circuit increases. This is because higher resistance restricts electron movement, reducing current according to Ohm's law. 2) Adding a resistor in series with an existing 1k resistor will increase the total circuit resistance. The current will decrease accordingly due to Ohm's law. 3) Circuit 3 will illuminate a light bulb most intensely because it has the lowest total resistance. Lower resistance allows more current to flow for a given voltage, resulting in brighter illumination according to Ohm's law.

1. For the day 8/14/2023
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1- Observe the following circuits, carry out the requested processes and present the
results obtained in a PDF document.
a- What happens to the intensity of the electric current, in a circuit, whose
resistance undergoes an increase? why?
1) goes up, 2) goes down, 3) stays the same.
Answer:
The intensity of the electric current goes down.
Because when the resistance (R) in an electric circuit increases, the electric
current flowing through it decreases. This is due to Ohm's law, ( I = V/R) which
shows that current is inversely propor�onal to resistance. Namely, higher
resistance restricts the movement of electrons, reducing their flow and resul�ng
in lower current.
b- For the circuit shown in the figure, what would happen to the total value of the
resistance? If you put a resistor in series with the 1k resistor. It shows the procedures to
answer the ques�ons presented.
Answer:
Adding a resistor in series with a 1k ohm resistor will increase the total resistance.
Because the total resistance in a series circuit is the sum of all individual resistances.
Once again, as resistance increases, the current flowing through the circuit decreases,
following Ohm's law.
Before adding any resistor, the current in circuit (I=V/R= 9/1k= 9mA), and when adding
the new resistor in series the current in circuit becomes (I=V/RTotal= 9/(1k+Rnew) <
9mA), this means the current in circuit will definitely be less than 9mA.

2. c- Which of the circuits, shown below, will illuminate the light bulb more intensely? why
? .
1), 2), 3).
Answer:
Circuit #3 will illuminate the light bulb more intensely.
In a series circuit, the current passing through all components is the same. According to
Ohm's law (V = I * R), as resistance decreases, the current increases for a constant
voltage. Therefore, in circuit 3, the total resistance is lower than in circuits 1 and 2,
resul�ng in a higher total current flowing through the circuit. This increased current leads
to a brighter illumina�on of the light bulb, making it more intense compared to the other
circuits.