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Animal: Man Trait: degree of skin pigmentation Background: Assume that there are two gene pairs that both help determine skin color (there are actually many gene pairs), and that they are incompletely dominant. If a person has the AABB Genotype they have a very dark brown skin; if AABb or AaBB , dark brown; if AaBb or AAbb or aaBB, medium brown ; if Aabb or aaBb, light brown; and if aabb , very pale. Problem: A person with the AABb genotype mates with an Aabb person. What are the possibilities of the children for this couple? Trait: degree of skin pigmentation Background: Assume that there are two gene pairs that both help determine skin color (there are actually many gene pairs), and that they are incompletely dominant. If a person has the AABB Genotype they have a very dark brown skin; if AABb or AaBB , dark brown; if AaBb or AAbb or aaBB, medium brown ; if Aabb or aaBb, light brown; and if aabb , very pale. Problem: A person with the AABb genotype mates with an Aabb person. What are the possibilities of the children for this couple? a. a complete key, including all genotypes and their phenotypes (even those that might not be needed in that particular cross) b. the cross itself (both parents genotypes) c. your calculations of the offspring possibilities (Punnett square, probability, etc.) d. genotype and phenotype ratios of those offspring e. answers to any special questions within each problem Genetics Ty.pe: Dihybrid, cumulative factors (blending), incomplete dominance Animal: man Trait: degree of skin pigmentation Background: Assume that there are two gene pairs that both help determine skin color (there are actually many gene pairs), and that they are incompletely dominant. If a person has the AA BB genotype they have very dark brown skin; if AA B b or A a BB , dark brown; if A a B b or AAbb or aa BB , medium brown; if A abb or aa B b , light brown; and if aabb , very pale. Problem: A person with the AA B b genotype mates with an A abb person. What are the possibilities for the children of this couple? .

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please! 1. Match and pair the following basic genetic concepts with their respective descriptions/definitions: 1. Gene a. Two different alleles 2. Allele b. Observable heritable feature that may vary among organisms. 3. Phenotype c. Two identical alleles 4. Genotype d. Describes the specific alleles present in the offspring. 5. Homozygous e. Segments of DNA responsible for producing a particular trait. 6. Heterozygous f. Variants of a gene present for a particular character. 2. From the figure presented here, determine the following: a. Which letter(s) show a phenotype? b. Which letter(s) show a genotype? c. In letter (c), are we looking at a homozygous recessive, a homozygous dominant, or a heterozygous individual? d. In letter (e), are we looking at a homozygous recessive, a homozygous dominant, or a heterozygous individual? 3. A and a are dominant and recessive alleles, respectively, of the same gene. Which genotype(s) would result in an individual with the dominant trait? A) AA and aa B) AA and aa C) only AA D) AA and Aa E) only Aa 4. For Labrador retrievers, black fur color (B) is dominant to yellow fur color (b). If a heterozygous black male mated with a homozygous yellow female, what would the puppies look like? Determine the phenotypic ratios. - Step 1: Determine the genotype of the female and male Labradors. Heterozygous black male: Homozygous yellow female: - Step 2: Write/Type the cross between the two Labradors. X -Step 3: Do a Punnett Square to determine the probable genotypes for the offspring and to determine the phenotypic ratio. -Step 4: Determine the Phenotype ratios of the progeny: s. There are many humans traits that are fairly simple and that follow the Mendelian pattern of inheritance. However, most of our traits are much more complex, involving many genes or interactions between genes. For example, hair color is determined by at least four genes, each one coding for the productions of melanin, a brown pigment. Because the effect of these genes is cumulative, hair color can range from blonde (little melanin) to very dark brown (much melanin). 2 Human traits are of great interest to us and there are few traits that seem to exhibit Mendelian inheritance, such as the ones shown below (this can be found in your lab manual). Figure 134 some madiy absenutle human Menoulae tak. Mid-digital hair b. Tongue rolling c. Widow's peak d. Earlobe attachment e. Hitchhiker's thumb f. Relative finger length With the information provided in your lab manual, Section 13-3 (pages 172-174), choose one out the six traits presented here and complete the following table..

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1. John has tyoe o blood. His child has type A blood. What type of blood Could his mother have? Draw Punnett squares. 2. artan\'s syndrome is caused by an autosomal dominant altele. What are chances of having a child that will develop syndrome if one of the parents has Marfan\'s syndrome. \"President Lincoln may have had 3. The allele for green skin color frogs) is .2 and the allele for yellow color What would the probabilites phenotypes, d genotypes of all offspring from two Brown skin is dominant over yellow in snake skin. Smooth scales are all dominant Show a Punnett square that would show genotypes and probabilities of a cross between a yellow skinned 4. 5. In the and a brown rough skinned snake. were question above how would you know whether the offspring heterozygotes or true breeding for dominant traits? Solution Answer: 1) John has O blood group, so genotype is \"IOIO\" Mother blood group---? child blood group --- A, so genotype is IAIA or IAIO Child genotype can be either IAIA or IAIO Based in chidren blood group, if we cross father blood group with A, then.. 1) IOIO X IAIA 2) IOIO X IAIO From the above , we can say that mother blood is A, and genotype can be IAIA orIAIOIAIAIOIAIOIAIOIOIAIOIAIO.

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