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B.SATEESH KUMAR
ASSISTANT PROFESSOR IN CHEMISTRY
GDC(M)-SKLM
B.SATEESH KUMAR , CHEMISTRY , GDC(M)-SKLM
1. The major product formed in the following reaction
is….
It is very easy to solve here the reagent H2,
10% Pd/C, EtOH,used to deprotect the ‘Bn’
and Cbz in amino acid by hydrogenolysis.
Boc not effected
B.SATEESH KUMAR , CHEMISTRY , GDC(M)-SKLM
2. The major product formed in the following reaction
is….
You want
solution just
turn over
the slide
B.SATEESH KUMAR , CHEMISTRY , GDC(M)-SKLM
Solution: Answer :1
We know that LiAlH4 (LAH) is a very strong H- reducing agent.
One mole of LAH is reduce only Epoxide into corresponding alcohol
,acetal is not effected
Here epoxide Ring opening takes place from axial attack of H– at
position (2),which is sterically free.
B.SATEESH KUMAR , CHEMISTRY , GDC(M)-SKLM
3. The major products A and B in the following
reaction sequence are
Solution: Answer- 1
In first step Schmidt reaction here carboxylic acid reacts with azide gives
isocyanate product (A) with same stereochemistry .
In the second step t-BuOH reacts with isocyanate gives Boc Protected amino
compound (B).
Csir net chemistry bits 2

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Csir net chemistry bits 2

  • 1. B.SATEESH KUMAR ASSISTANT PROFESSOR IN CHEMISTRY GDC(M)-SKLM
  • 2.
  • 3. B.SATEESH KUMAR , CHEMISTRY , GDC(M)-SKLM 1. The major product formed in the following reaction is….
  • 4. It is very easy to solve here the reagent H2, 10% Pd/C, EtOH,used to deprotect the ‘Bn’ and Cbz in amino acid by hydrogenolysis. Boc not effected
  • 5. B.SATEESH KUMAR , CHEMISTRY , GDC(M)-SKLM 2. The major product formed in the following reaction is…. You want solution just turn over the slide
  • 6. B.SATEESH KUMAR , CHEMISTRY , GDC(M)-SKLM Solution: Answer :1 We know that LiAlH4 (LAH) is a very strong H- reducing agent. One mole of LAH is reduce only Epoxide into corresponding alcohol ,acetal is not effected Here epoxide Ring opening takes place from axial attack of H– at position (2),which is sterically free.
  • 7. B.SATEESH KUMAR , CHEMISTRY , GDC(M)-SKLM 3. The major products A and B in the following reaction sequence are
  • 8. Solution: Answer- 1 In first step Schmidt reaction here carboxylic acid reacts with azide gives isocyanate product (A) with same stereochemistry . In the second step t-BuOH reacts with isocyanate gives Boc Protected amino compound (B).