SlideShare a Scribd company logo
1 of 69
UNIT - 3
AVERAGES
INTRODUCTION:
Average:
Average = (Sum of observations/Number of observations)
Average Speed:
Suppose a man covers a certain distance at X kmph and an equal
distance at Y kmph.
Then, the average speed during the whole journey is {2xy/(x+y)} kmph.
1. The average of first 10 even numbers is?
A. 18 B. 22 C. 11 D. 9
EXPLANATION:
Sum of 10 even numbers = 10 * 11 = 110
Average = 110/10 = 11
2. The average of 11 numbers is 10.9. If the average of first six is 10.5
and that of the last six is 11.4 the sixth number is?
A. 11.2 B. 11.3 C. 11.4 D. 11.5
EXPLANATION:
1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 119.9 = 11.5
6th number = 11.5
3. The average of first 10 natural numbers is?
A. 5 B. 5.5 C. 5.2 D. 5.6
EXPLANATION:
Sum of 10 natural no. = 110/2 = 55
Average = 55/10 = 5.5
FORMULA: N+1 / 2
4. The average of first 10 odd numbers is?
A. 15 B. 12 C. 13 D. 10
EXPLANATION:
Sum of 10 odd no. = 100
Average = 100/10 = 10
FORMULA: N
5. The average age of three boys is 15 years and their ages are in
proportion 3:5:7. What is the age in years of the youngest boy?
A. 15 B. 12 C. 13 D. 9
6. The average of 9 observations was 9, that of the 1st of 5 being 10 and
that of the last 5 being 8. What was the 5th observation?
A. 12 B. 11 C. 10 D. 9
EXPLANATION:
3x + 5x + 7x = 45
x =3
3x = 9
EXPLANATION:
1 to 9 = 9 * 9 = 81
1 to 5 = 5 * 10 = 50
5 to 9 = 5 * 8 = 40
5th = 50 + 40 = 90 – 81 = 9
7. The average of 10 numbers is calculated as 15. It is discovered later
on that while calculating the average, one number namely 36 was
wrongly read as 26. The correct average is?
A. 12 B. 11 C. 10 D. 16
EXPLANATION:
10 * 15 + 36 – 26 = 160/10 = 16
8. The average age of 8 men increases by 2 years when two women are
included in place of two men of ages 20 and 24 years. Find the average
age of the women?
A. 24 B. 32 C. 30 D. 36
EXPLANATION:
20 + 24 + 8 * 2 = 60/2 = 30
9. A team of eight entered for a shooting competition. The best marks
man scored 85 points. If he had scored 92 points, the average scores for.
The team would have been 84. How many points altogether did the team
score?
A. 625 B. 665 C. 660 D. 675
EXPLANATION:
8 * 84 = 672 – 7 = 665
10. The average age of a husband and a wife is 23 years when they were
married five years ago but now the average age of the husband, wife and
child is 20 years(the child was born during the interval). What is the
present age of the child?
A. 4 B. 2 C. 3 D. 6
EXPLANATION:
28 * 2 = 56
20 * 3 = 60
-----------
4 years
11. A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150
each and two blankets at a certain rate which is now slipped off from his
memory. But he remembers that the average price of the blankets was
Rs.150. Find the unknown rate of two blankets?
A. 225 B. 265 C. 450 D. 475
EXPLANATION:
10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050 = 450
12. The average temperature for Monday, Tuesday, Wednesday and
Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and
Friday was 46 degrees. If the temperature on Monday was 42 degrees.
Find the temperature on Friday?
A. 34 B. 32 C. 30 D. 36
EXPLANATION:
M + Tu + W + Th = 4 * 48 = 192
Tu + W + Th + F = 4 * 46 = 184
M = 42
Tu + W + Th = 192 -42 = 150
F = 184 – 150 = 34
13. Three years ago the average age of a family of six members was 19
years. A boy have been born, the average age of the family is the same
today. What is the age of the boy?
A. 4 B. 2 C. 3 D. 1
EXPLANATION:
6 * 22 = 132
7 * 19 = 133
--------------
1
14. The average of five results is 46 and that of the first four is 45. The
fifth result is?
A. 54 B. 52 C. 50 D. 56
EXPLANATION:
5 * 46 – 4 * 45 = 50
15. The average of 11 results is 50, if the average of first six results is
49 and that of the last six is 52. Find the sixth result?
A. 54 B. 52 C. 50 D. 56
EXPLANATION:
1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 – 550 = 56
16. Find the average of the first 20 natural numbers?
A. 12.5 B. 11.5 C. 10.5 D. 16.5
EXPLANATION:
Average of the first 'n' natural numbers = (n + 1)/2
We get (20 + 1)/2 = 10.5
17. The average of 13 numbers is 60. Average of the first 7 of them is
57 and that of the last 7 is 61. Find the 8th number?
A. 54 B. 61 C. 50 D. 46
EXPLANATION:
Sum of all the 13 numbers = 13 * 60 = 780
Sum of the first 7 of them = 7 * 57 = 399
Sum of the last 7 of them = 7 * 61 = 427
So, the 8th number = 427 + 399 - 780 = 46
18. A batsman makes a score of 64 runs in the 16th innings and thus
increased his average by 3. Find his average after the 16th inning?
A. 19 B. 11 C. 15 D. 16
EXPLANATION:
Let the average after the 16th inning be P.
So, the average after the 15th inning will be (P-3) Hence, 15(P-30) + 64
= 16P => P = 19
19. The average marks of a class of 30 students is 40 and that of another
class of 50 students is 60. Find the average marks of all the students?
A. 52.5 B. 51.5 C. 50.5 D. 56.5
EXPLANATION:
Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 60 = 3000
Sum of the marks for the class of 80 students =
1200 + 3000 = 4200
Average marks of all the students = 4200/80 = 52.5
20. The average salary of a person for the months of January, February,
March and April is Rs.8000 and that for the months February, March,
April and May is Rs.8500. If his salary for the month of May is
Rs.6500, find his salary for the month of January?
A. 6250 B. 6500 C. 4500 D. 5000
EXPLANATION:
Sum of the salaries of the person for the months of January, February,
March and April = 4 * 8000 = 32000 ----(1)
Sum of the salaries of the person for the months of February, March,
April and May = 4 * 8500 = 34000 ----(2)
(2)-(1) i.e. May - Jan = 2000
Salary of May is Rs.6500
Salary of January = Rs.4500
21. The average age of a group of 10 persons was decreased by 3 years
when one person, whose age was 42 years, was replaced by a new
person. Find the age of the new person?
A. 12 B. 11 C. 15 D. 16
EXPLANATION:
Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average = (P-3) 10(P-3) = 10P - 42 + Q => Q = 12
22. The average of four positive integers is 69. The highest integer is 93
and the least integer is 39. The difference between the remaining two
integers is 28. Which of the following integers is the higher of the
remaining two integers?
A. 82 B. 81 C. 85 D. 86
EXPLANATION:
Let the four integers be A, B, C and D where A > B > C > D.
(A + B + C + D)/4 = 69 => A + B + C + D = 276 ---> (1)
A = 93, D = 39 and B - C = 28
(1) => B + C = 276 - (A + D) = 276 - 132 = 144.
B + B -28 = 144
B = (144 + 28)/2 = 86
23. The average mark of the students of a class in a particular exam is
80. If 5 students whose average mark in that exam is 40 are excluded,
the average mark of the remaining will be 90. Find the number of
students who wrote the exam.
A. 22 B. 21 C. 25 D. 26
EXPLANATION:
Let the number of students who wrote the exam be x.
Total marks of students = 80 x.
Total marks of (x - 5) students = 90(x - 5)
80x - (5 * 40) = 90(x - 5)
250 = 10x => x = 25
24. The average height of 50 pupils in a class is 150 cm. Five of them
whose height is 146 cm, leave the class and five others whose average
height is 156 cm, join. The new average height of the pupils of the class
(in cm) is
A. 151 B. 165 C. 150 D. 155
EXPLANATION:
Total height = 150 * 50 = 7500 cm.
New average = [7500 - 5 * 146 + 5 * 156 ] / 50 = 151 cm
25. The average age of students of a class is 15.8 years. The average age
of boys in the class is 16.4 years and that of the girls is 15.4 years. The
ration of the number of boys to the number of girls in the class is:
A. 2:3 B. 3:2 C. 1:2 D. 2:1
EXPLANATION:
Let the ratio be k : 1. Then,
k * 16.4 + 1 * 15.4 = (k + 1) * 15.8
= (16.4 - 15.8)k = (15.8 - 15.4)
= k = 0.4/0.6 = 2/3
Required ratio = 2/3 : 1 = 2:3
26. The average age of husband, wife and their child 3 years ago was 27
years and that of wife and the child 5 years ago was 20 years. The
present age of the husband is:
A. 42 B. 40 C. 45 D. 46
EXPLANATION:
Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) =
90 years.
Sum of the present age of wife and child = (20 * 2 + 5 * 2) = 50 years.
Husband's present age = (90 - 50) = 40 years.
27. The mean weight of a class of 35 students is 45 kg. If the weight of
the teacher be included, the mean weight increases by 500 g. Find the
weight of the teacher.
A. 62 B. 60 C. 65 D. 63
EXPLANATION:
Mean weight of 35 students = 45 kg.
Total weight of 35 students = (45 × 35) kg = 1575 kg.
Mean weight of 35 students and the teacher (45 + 0.5) kg = 45.5 kg.
Total weight of 35 students and the teacher = (45.5 × 36) kg = 1638 kg.
Weight of the teacher = (1638 - 1575) kg = 63 kg.
Hence, the weight of the teacher is 63 kg.
28. The mean of five numbers is 28. If one of the numbers is excluded,
the mean gets reduced by 2. Find the excluded number.
A. 32 B. 30 C. 35 D. 36
EXPLANATION:
Mean of 5 numbers = 28.
Sum of these 5 numbers = (28 x 5) = 140.
Mean of the remaining 4 numbers = (28 - 2) =26.
Sum of these remaining 4 numbers = (26 × 4) = 104.
Excluded number
= (sum of the given 5 numbers) - (sum of the remaining 4 numbers)
= (140 - 104)
= 36.
Hence, the excluded number is 36.
29. A pupil's marks were wrongly entered as 83 instead of 63. Due to
the average marks for the class got increased by half. The number of
pupils in the class is:
A. 42 B. 40 C. 45 D. 46
EXPLANATION:
Let there be x pupils in the class.
Total increase in marks = (x * 1/2) = x/2
x/2 = (83 - 63) => x/2 = 20 => x = 40
30. The average weight of A, B and C is 45 kg. If the average weight of
A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:
A. 32 B. 30 C. 31 D. 36
EXPLANATION:
Let A, B, C represent their respective weights.
Then, we have:
A + B + C = (45 * 3) = 135 --- (i)
A + B = (40 * 2) = 80 --- (ii)
B + C = (43 * 2) = 86 --- (iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 --- (iv)
Subtracting (i) from (iv), we get: B = 31
B's weight = 31 kg.
THANK YOU..,
In the first 10 overs of a cricket
game, the run rate was only
3.2. What should be the run
rate in the remaining 40 overs
to reach the target of 282 runs?
A family consists of two grandparents,
two parents and three grandchildren.
The average age of the grandparents is
67 years, that of the parents is 35 years
and that of the grandchildren is 6 years.
What is the average age of the family?
A grocer has a sale of Rs. 6435,
Rs. 6927, Rs. 6855, Rs. 7230 and
Rs. 6562 for 5 consecutive
months. How much sale must he
have in the sixth month so that he
gets an average sale of Rs. 6500?
The average weight of 8 person's
increases by 2.5 kg when a new
person comes in place of one of
them weighing 65 kg. What might
be the weight of the new person?
The average monthly income of P
and Q is Rs. 5050. The average
monthly income of Q and R is Rs.
6250 and the average monthly
income of P and R is Rs. 5200. The
monthly income of P is:

More Related Content

Similar to Unit 3 - Averages.pptx

Mental maths ix q & a
Mental maths ix q & aMental maths ix q & a
Mental maths ix q & amaanas2001
 
Apt series 1
Apt series 1Apt series 1
Apt series 1christy
 
Aptitude average
Aptitude averageAptitude average
Aptitude averageAratiSavant
 
Alhikmah preparation for checkpoint math paper 2
Alhikmah preparation for checkpoint math paper 2Alhikmah preparation for checkpoint math paper 2
Alhikmah preparation for checkpoint math paper 2Wina Winarni
 
Alhikmah preparation for checkpoint math paper 2
Alhikmah preparation for checkpoint math paper 2Alhikmah preparation for checkpoint math paper 2
Alhikmah preparation for checkpoint math paper 2Wina Winarni
 
Preparation for checkpoint math paper 2
Preparation for checkpoint math paper 2Preparation for checkpoint math paper 2
Preparation for checkpoint math paper 2Wina Winarni
 
GRADE 5 SESSION 5.pptx
GRADE 5 SESSION 5.pptxGRADE 5 SESSION 5.pptx
GRADE 5 SESSION 5.pptxLuisSalenga1
 
Gmat Math Tough Problems
Gmat Math Tough ProblemsGmat Math Tough Problems
Gmat Math Tough ProblemsVijay Thakkar
 
Actuarial Science (ACET) Mock Test Paper II By Sourav Sir's Classes
Actuarial Science (ACET) Mock Test Paper II By Sourav Sir's ClassesActuarial Science (ACET) Mock Test Paper II By Sourav Sir's Classes
Actuarial Science (ACET) Mock Test Paper II By Sourav Sir's ClassesSOURAV DAS
 
1st term quiz competition.pptx
1st term quiz competition.pptx1st term quiz competition.pptx
1st term quiz competition.pptxJustusEkeneNwaka
 
Rationalization-CE-2-Mathematics-Pre-test-1.pptx
Rationalization-CE-2-Mathematics-Pre-test-1.pptxRationalization-CE-2-Mathematics-Pre-test-1.pptx
Rationalization-CE-2-Mathematics-Pre-test-1.pptxdudaynorombaba
 
RS Agarwal Quantitative Aptitude - 6 chap
RS Agarwal Quantitative Aptitude - 6 chapRS Agarwal Quantitative Aptitude - 6 chap
RS Agarwal Quantitative Aptitude - 6 chapVinoth Kumar.K
 

Similar to Unit 3 - Averages.pptx (20)

Average.pdf
Average.pdfAverage.pdf
Average.pdf
 
Mental maths ix q & a
Mental maths ix q & aMental maths ix q & a
Mental maths ix q & a
 
Apt series 1
Apt series 1Apt series 1
Apt series 1
 
Aptitude average
Aptitude averageAptitude average
Aptitude average
 
6 chap
6 chap6 chap
6 chap
 
Alhikmah preparation for checkpoint math paper 2
Alhikmah preparation for checkpoint math paper 2Alhikmah preparation for checkpoint math paper 2
Alhikmah preparation for checkpoint math paper 2
 
Alhikmah preparation for checkpoint math paper 2
Alhikmah preparation for checkpoint math paper 2Alhikmah preparation for checkpoint math paper 2
Alhikmah preparation for checkpoint math paper 2
 
Preparation for checkpoint math paper 2
Preparation for checkpoint math paper 2Preparation for checkpoint math paper 2
Preparation for checkpoint math paper 2
 
GRADE 5 SESSION 5.pptx
GRADE 5 SESSION 5.pptxGRADE 5 SESSION 5.pptx
GRADE 5 SESSION 5.pptx
 
Gmat Math Tough Problems
Gmat Math Tough ProblemsGmat Math Tough Problems
Gmat Math Tough Problems
 
Tough Quant
Tough QuantTough Quant
Tough Quant
 
Actuarial Science (ACET) Mock Test Paper II By Sourav Sir's Classes
Actuarial Science (ACET) Mock Test Paper II By Sourav Sir's ClassesActuarial Science (ACET) Mock Test Paper II By Sourav Sir's Classes
Actuarial Science (ACET) Mock Test Paper II By Sourav Sir's Classes
 
GRADE-6-SESSION-3.pptx
GRADE-6-SESSION-3.pptxGRADE-6-SESSION-3.pptx
GRADE-6-SESSION-3.pptx
 
1st term quiz competition.pptx
1st term quiz competition.pptx1st term quiz competition.pptx
1st term quiz competition.pptx
 
Rationalization-CE-2-Mathematics-Pre-test-1.pptx
Rationalization-CE-2-Mathematics-Pre-test-1.pptxRationalization-CE-2-Mathematics-Pre-test-1.pptx
Rationalization-CE-2-Mathematics-Pre-test-1.pptx
 
Aptitude test papers
Aptitude test papers Aptitude test papers
Aptitude test papers
 
Mat cat que
Mat cat queMat cat que
Mat cat que
 
RS Agarwal Quantitative Aptitude - 6 chap
RS Agarwal Quantitative Aptitude - 6 chapRS Agarwal Quantitative Aptitude - 6 chap
RS Agarwal Quantitative Aptitude - 6 chap
 
Questions on ratio and proportion
Questions on ratio and proportion Questions on ratio and proportion
Questions on ratio and proportion
 
Questions on ratio and proportion
Questions on ratio and proportion Questions on ratio and proportion
Questions on ratio and proportion
 

Recently uploaded

ECONOMIC CONTEXT - PAPER 1 Q3: NEWSPAPERS.pptx
ECONOMIC CONTEXT - PAPER 1 Q3: NEWSPAPERS.pptxECONOMIC CONTEXT - PAPER 1 Q3: NEWSPAPERS.pptx
ECONOMIC CONTEXT - PAPER 1 Q3: NEWSPAPERS.pptxiammrhaywood
 
Interactive Powerpoint_How to Master effective communication
Interactive Powerpoint_How to Master effective communicationInteractive Powerpoint_How to Master effective communication
Interactive Powerpoint_How to Master effective communicationnomboosow
 
ECONOMIC CONTEXT - LONG FORM TV DRAMA - PPT
ECONOMIC CONTEXT - LONG FORM TV DRAMA - PPTECONOMIC CONTEXT - LONG FORM TV DRAMA - PPT
ECONOMIC CONTEXT - LONG FORM TV DRAMA - PPTiammrhaywood
 
Proudly South Africa powerpoint Thorisha.pptx
Proudly South Africa powerpoint Thorisha.pptxProudly South Africa powerpoint Thorisha.pptx
Proudly South Africa powerpoint Thorisha.pptxthorishapillay1
 
“Oh GOSH! Reflecting on Hackteria's Collaborative Practices in a Global Do-It...
“Oh GOSH! Reflecting on Hackteria's Collaborative Practices in a Global Do-It...“Oh GOSH! Reflecting on Hackteria's Collaborative Practices in a Global Do-It...
“Oh GOSH! Reflecting on Hackteria's Collaborative Practices in a Global Do-It...Marc Dusseiller Dusjagr
 
Alper Gobel In Media Res Media Component
Alper Gobel In Media Res Media ComponentAlper Gobel In Media Res Media Component
Alper Gobel In Media Res Media ComponentInMediaRes1
 
DATA STRUCTURE AND ALGORITHM for beginners
DATA STRUCTURE AND ALGORITHM for beginnersDATA STRUCTURE AND ALGORITHM for beginners
DATA STRUCTURE AND ALGORITHM for beginnersSabitha Banu
 
Hierarchy of management that covers different levels of management
Hierarchy of management that covers different levels of managementHierarchy of management that covers different levels of management
Hierarchy of management that covers different levels of managementmkooblal
 
Meghan Sutherland In Media Res Media Component
Meghan Sutherland In Media Res Media ComponentMeghan Sutherland In Media Res Media Component
Meghan Sutherland In Media Res Media ComponentInMediaRes1
 
History Class XII Ch. 3 Kinship, Caste and Class (1).pptx
History Class XII Ch. 3 Kinship, Caste and Class (1).pptxHistory Class XII Ch. 3 Kinship, Caste and Class (1).pptx
History Class XII Ch. 3 Kinship, Caste and Class (1).pptxsocialsciencegdgrohi
 
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptxPOINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptxSayali Powar
 
KSHARA STURA .pptx---KSHARA KARMA THERAPY (CAUSTIC THERAPY)————IMP.OF KSHARA ...
KSHARA STURA .pptx---KSHARA KARMA THERAPY (CAUSTIC THERAPY)————IMP.OF KSHARA ...KSHARA STURA .pptx---KSHARA KARMA THERAPY (CAUSTIC THERAPY)————IMP.OF KSHARA ...
KSHARA STURA .pptx---KSHARA KARMA THERAPY (CAUSTIC THERAPY)————IMP.OF KSHARA ...M56BOOKSTORE PRODUCT/SERVICE
 
Historical philosophical, theoretical, and legal foundations of special and i...
Historical philosophical, theoretical, and legal foundations of special and i...Historical philosophical, theoretical, and legal foundations of special and i...
Historical philosophical, theoretical, and legal foundations of special and i...jaredbarbolino94
 
Enzyme, Pharmaceutical Aids, Miscellaneous Last Part of Chapter no 5th.pdf
Enzyme, Pharmaceutical Aids, Miscellaneous Last Part of Chapter no 5th.pdfEnzyme, Pharmaceutical Aids, Miscellaneous Last Part of Chapter no 5th.pdf
Enzyme, Pharmaceutical Aids, Miscellaneous Last Part of Chapter no 5th.pdfSumit Tiwari
 
Framing an Appropriate Research Question 6b9b26d93da94caf993c038d9efcdedb.pdf
Framing an Appropriate Research Question 6b9b26d93da94caf993c038d9efcdedb.pdfFraming an Appropriate Research Question 6b9b26d93da94caf993c038d9efcdedb.pdf
Framing an Appropriate Research Question 6b9b26d93da94caf993c038d9efcdedb.pdfUjwalaBharambe
 
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdfssuser54595a
 
CELL CYCLE Division Science 8 quarter IV.pptx
CELL CYCLE Division Science 8 quarter IV.pptxCELL CYCLE Division Science 8 quarter IV.pptx
CELL CYCLE Division Science 8 quarter IV.pptxJiesonDelaCerna
 

Recently uploaded (20)

ECONOMIC CONTEXT - PAPER 1 Q3: NEWSPAPERS.pptx
ECONOMIC CONTEXT - PAPER 1 Q3: NEWSPAPERS.pptxECONOMIC CONTEXT - PAPER 1 Q3: NEWSPAPERS.pptx
ECONOMIC CONTEXT - PAPER 1 Q3: NEWSPAPERS.pptx
 
Interactive Powerpoint_How to Master effective communication
Interactive Powerpoint_How to Master effective communicationInteractive Powerpoint_How to Master effective communication
Interactive Powerpoint_How to Master effective communication
 
ECONOMIC CONTEXT - LONG FORM TV DRAMA - PPT
ECONOMIC CONTEXT - LONG FORM TV DRAMA - PPTECONOMIC CONTEXT - LONG FORM TV DRAMA - PPT
ECONOMIC CONTEXT - LONG FORM TV DRAMA - PPT
 
Proudly South Africa powerpoint Thorisha.pptx
Proudly South Africa powerpoint Thorisha.pptxProudly South Africa powerpoint Thorisha.pptx
Proudly South Africa powerpoint Thorisha.pptx
 
“Oh GOSH! Reflecting on Hackteria's Collaborative Practices in a Global Do-It...
“Oh GOSH! Reflecting on Hackteria's Collaborative Practices in a Global Do-It...“Oh GOSH! Reflecting on Hackteria's Collaborative Practices in a Global Do-It...
“Oh GOSH! Reflecting on Hackteria's Collaborative Practices in a Global Do-It...
 
Alper Gobel In Media Res Media Component
Alper Gobel In Media Res Media ComponentAlper Gobel In Media Res Media Component
Alper Gobel In Media Res Media Component
 
DATA STRUCTURE AND ALGORITHM for beginners
DATA STRUCTURE AND ALGORITHM for beginnersDATA STRUCTURE AND ALGORITHM for beginners
DATA STRUCTURE AND ALGORITHM for beginners
 
TataKelola dan KamSiber Kecerdasan Buatan v022.pdf
TataKelola dan KamSiber Kecerdasan Buatan v022.pdfTataKelola dan KamSiber Kecerdasan Buatan v022.pdf
TataKelola dan KamSiber Kecerdasan Buatan v022.pdf
 
Hierarchy of management that covers different levels of management
Hierarchy of management that covers different levels of managementHierarchy of management that covers different levels of management
Hierarchy of management that covers different levels of management
 
Meghan Sutherland In Media Res Media Component
Meghan Sutherland In Media Res Media ComponentMeghan Sutherland In Media Res Media Component
Meghan Sutherland In Media Res Media Component
 
History Class XII Ch. 3 Kinship, Caste and Class (1).pptx
History Class XII Ch. 3 Kinship, Caste and Class (1).pptxHistory Class XII Ch. 3 Kinship, Caste and Class (1).pptx
History Class XII Ch. 3 Kinship, Caste and Class (1).pptx
 
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptxPOINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
 
KSHARA STURA .pptx---KSHARA KARMA THERAPY (CAUSTIC THERAPY)————IMP.OF KSHARA ...
KSHARA STURA .pptx---KSHARA KARMA THERAPY (CAUSTIC THERAPY)————IMP.OF KSHARA ...KSHARA STURA .pptx---KSHARA KARMA THERAPY (CAUSTIC THERAPY)————IMP.OF KSHARA ...
KSHARA STURA .pptx---KSHARA KARMA THERAPY (CAUSTIC THERAPY)————IMP.OF KSHARA ...
 
Model Call Girl in Bikash Puri Delhi reach out to us at 🔝9953056974🔝
Model Call Girl in Bikash Puri  Delhi reach out to us at 🔝9953056974🔝Model Call Girl in Bikash Puri  Delhi reach out to us at 🔝9953056974🔝
Model Call Girl in Bikash Puri Delhi reach out to us at 🔝9953056974🔝
 
Historical philosophical, theoretical, and legal foundations of special and i...
Historical philosophical, theoretical, and legal foundations of special and i...Historical philosophical, theoretical, and legal foundations of special and i...
Historical philosophical, theoretical, and legal foundations of special and i...
 
Enzyme, Pharmaceutical Aids, Miscellaneous Last Part of Chapter no 5th.pdf
Enzyme, Pharmaceutical Aids, Miscellaneous Last Part of Chapter no 5th.pdfEnzyme, Pharmaceutical Aids, Miscellaneous Last Part of Chapter no 5th.pdf
Enzyme, Pharmaceutical Aids, Miscellaneous Last Part of Chapter no 5th.pdf
 
Framing an Appropriate Research Question 6b9b26d93da94caf993c038d9efcdedb.pdf
Framing an Appropriate Research Question 6b9b26d93da94caf993c038d9efcdedb.pdfFraming an Appropriate Research Question 6b9b26d93da94caf993c038d9efcdedb.pdf
Framing an Appropriate Research Question 6b9b26d93da94caf993c038d9efcdedb.pdf
 
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
18-04-UA_REPORT_MEDIALITERAСY_INDEX-DM_23-1-final-eng.pdf
 
CELL CYCLE Division Science 8 quarter IV.pptx
CELL CYCLE Division Science 8 quarter IV.pptxCELL CYCLE Division Science 8 quarter IV.pptx
CELL CYCLE Division Science 8 quarter IV.pptx
 
Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝
Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝
Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝
 

Unit 3 - Averages.pptx

  • 2. INTRODUCTION: Average: Average = (Sum of observations/Number of observations) Average Speed: Suppose a man covers a certain distance at X kmph and an equal distance at Y kmph. Then, the average speed during the whole journey is {2xy/(x+y)} kmph.
  • 3. 1. The average of first 10 even numbers is? A. 18 B. 22 C. 11 D. 9
  • 4. EXPLANATION: Sum of 10 even numbers = 10 * 11 = 110 Average = 110/10 = 11
  • 5. 2. The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.4 the sixth number is? A. 11.2 B. 11.3 C. 11.4 D. 11.5
  • 6. EXPLANATION: 1 to 11 = 11 * 10.9 = 119.9 1 to 6 = 6 * 10.5 = 63 6 to 11 = 6 * 11.4 = 68.4 63 + 68.4 = 131.4 – 119.9 = 11.5 6th number = 11.5
  • 7. 3. The average of first 10 natural numbers is? A. 5 B. 5.5 C. 5.2 D. 5.6
  • 8. EXPLANATION: Sum of 10 natural no. = 110/2 = 55 Average = 55/10 = 5.5 FORMULA: N+1 / 2
  • 9. 4. The average of first 10 odd numbers is? A. 15 B. 12 C. 13 D. 10
  • 10. EXPLANATION: Sum of 10 odd no. = 100 Average = 100/10 = 10 FORMULA: N
  • 11. 5. The average age of three boys is 15 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy? A. 15 B. 12 C. 13 D. 9
  • 12. 6. The average of 9 observations was 9, that of the 1st of 5 being 10 and that of the last 5 being 8. What was the 5th observation? A. 12 B. 11 C. 10 D. 9
  • 13. EXPLANATION: 3x + 5x + 7x = 45 x =3 3x = 9
  • 14. EXPLANATION: 1 to 9 = 9 * 9 = 81 1 to 5 = 5 * 10 = 50 5 to 9 = 5 * 8 = 40 5th = 50 + 40 = 90 – 81 = 9
  • 15. 7. The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is? A. 12 B. 11 C. 10 D. 16
  • 16. EXPLANATION: 10 * 15 + 36 – 26 = 160/10 = 16
  • 17. 8. The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women? A. 24 B. 32 C. 30 D. 36
  • 18. EXPLANATION: 20 + 24 + 8 * 2 = 60/2 = 30
  • 19. 9. A team of eight entered for a shooting competition. The best marks man scored 85 points. If he had scored 92 points, the average scores for. The team would have been 84. How many points altogether did the team score? A. 625 B. 665 C. 660 D. 675
  • 20. EXPLANATION: 8 * 84 = 672 – 7 = 665
  • 21. 10. The average age of a husband and a wife is 23 years when they were married five years ago but now the average age of the husband, wife and child is 20 years(the child was born during the interval). What is the present age of the child? A. 4 B. 2 C. 3 D. 6
  • 22.
  • 23. EXPLANATION: 28 * 2 = 56 20 * 3 = 60 ----------- 4 years
  • 24. 11. A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? A. 225 B. 265 C. 450 D. 475
  • 25. EXPLANATION: 10 * 150 = 1500 3 * 100 + 5 * 150 = 1050 1500 – 1050 = 450
  • 26. 12. The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 42 degrees. Find the temperature on Friday? A. 34 B. 32 C. 30 D. 36
  • 27. EXPLANATION: M + Tu + W + Th = 4 * 48 = 192 Tu + W + Th + F = 4 * 46 = 184 M = 42 Tu + W + Th = 192 -42 = 150 F = 184 – 150 = 34
  • 28. 13. Three years ago the average age of a family of six members was 19 years. A boy have been born, the average age of the family is the same today. What is the age of the boy? A. 4 B. 2 C. 3 D. 1
  • 29. EXPLANATION: 6 * 22 = 132 7 * 19 = 133 -------------- 1
  • 30. 14. The average of five results is 46 and that of the first four is 45. The fifth result is? A. 54 B. 52 C. 50 D. 56
  • 31. EXPLANATION: 5 * 46 – 4 * 45 = 50
  • 32. 15. The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result? A. 54 B. 52 C. 50 D. 56
  • 33. EXPLANATION: 1 to 11 = 11 * 50 = 550 1 to 6 = 6 * 49 = 294 6 to 11 = 6 * 52 = 312 6th = 294 + 312 – 550 = 56
  • 34. 16. Find the average of the first 20 natural numbers? A. 12.5 B. 11.5 C. 10.5 D. 16.5
  • 35. EXPLANATION: Average of the first 'n' natural numbers = (n + 1)/2 We get (20 + 1)/2 = 10.5
  • 36. 17. The average of 13 numbers is 60. Average of the first 7 of them is 57 and that of the last 7 is 61. Find the 8th number? A. 54 B. 61 C. 50 D. 46
  • 37. EXPLANATION: Sum of all the 13 numbers = 13 * 60 = 780 Sum of the first 7 of them = 7 * 57 = 399 Sum of the last 7 of them = 7 * 61 = 427 So, the 8th number = 427 + 399 - 780 = 46
  • 38. 18. A batsman makes a score of 64 runs in the 16th innings and thus increased his average by 3. Find his average after the 16th inning? A. 19 B. 11 C. 15 D. 16
  • 39. EXPLANATION: Let the average after the 16th inning be P. So, the average after the 15th inning will be (P-3) Hence, 15(P-30) + 64 = 16P => P = 19
  • 40. 19. The average marks of a class of 30 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students? A. 52.5 B. 51.5 C. 50.5 D. 56.5
  • 41. EXPLANATION: Sum of the marks for the class of 30 students = 30 * 40 = 1200 Sum of the marks for the class of 50 students = 50 * 60 = 3000 Sum of the marks for the class of 80 students = 1200 + 3000 = 4200 Average marks of all the students = 4200/80 = 52.5
  • 42. 20. The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8500. If his salary for the month of May is Rs.6500, find his salary for the month of January? A. 6250 B. 6500 C. 4500 D. 5000
  • 43. EXPLANATION: Sum of the salaries of the person for the months of January, February, March and April = 4 * 8000 = 32000 ----(1) Sum of the salaries of the person for the months of February, March, April and May = 4 * 8500 = 34000 ----(2) (2)-(1) i.e. May - Jan = 2000 Salary of May is Rs.6500 Salary of January = Rs.4500
  • 44. 21. The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person? A. 12 B. 11 C. 15 D. 16
  • 45. EXPLANATION: Initial average age of the 10 persons be P. Age of the new person Q. Sum of the ages of the initial 10 persons = 10P New average = (P-3) 10(P-3) = 10P - 42 + Q => Q = 12
  • 46. 22. The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 28. Which of the following integers is the higher of the remaining two integers? A. 82 B. 81 C. 85 D. 86
  • 47. EXPLANATION: Let the four integers be A, B, C and D where A > B > C > D. (A + B + C + D)/4 = 69 => A + B + C + D = 276 ---> (1) A = 93, D = 39 and B - C = 28 (1) => B + C = 276 - (A + D) = 276 - 132 = 144. B + B -28 = 144 B = (144 + 28)/2 = 86
  • 48. 23. The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 40 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam. A. 22 B. 21 C. 25 D. 26
  • 49. EXPLANATION: Let the number of students who wrote the exam be x. Total marks of students = 80 x. Total marks of (x - 5) students = 90(x - 5) 80x - (5 * 40) = 90(x - 5) 250 = 10x => x = 25
  • 50. 24. The average height of 50 pupils in a class is 150 cm. Five of them whose height is 146 cm, leave the class and five others whose average height is 156 cm, join. The new average height of the pupils of the class (in cm) is A. 151 B. 165 C. 150 D. 155
  • 51. EXPLANATION: Total height = 150 * 50 = 7500 cm. New average = [7500 - 5 * 146 + 5 * 156 ] / 50 = 151 cm
  • 52. 25. The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ration of the number of boys to the number of girls in the class is: A. 2:3 B. 3:2 C. 1:2 D. 2:1
  • 53. EXPLANATION: Let the ratio be k : 1. Then, k * 16.4 + 1 * 15.4 = (k + 1) * 15.8 = (16.4 - 15.8)k = (15.8 - 15.4) = k = 0.4/0.6 = 2/3 Required ratio = 2/3 : 1 = 2:3
  • 54. 26. The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is: A. 42 B. 40 C. 45 D. 46
  • 55. EXPLANATION: Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) = 90 years. Sum of the present age of wife and child = (20 * 2 + 5 * 2) = 50 years. Husband's present age = (90 - 50) = 40 years.
  • 56. 27. The mean weight of a class of 35 students is 45 kg. If the weight of the teacher be included, the mean weight increases by 500 g. Find the weight of the teacher. A. 62 B. 60 C. 65 D. 63
  • 57. EXPLANATION: Mean weight of 35 students = 45 kg. Total weight of 35 students = (45 × 35) kg = 1575 kg. Mean weight of 35 students and the teacher (45 + 0.5) kg = 45.5 kg. Total weight of 35 students and the teacher = (45.5 × 36) kg = 1638 kg. Weight of the teacher = (1638 - 1575) kg = 63 kg. Hence, the weight of the teacher is 63 kg.
  • 58. 28. The mean of five numbers is 28. If one of the numbers is excluded, the mean gets reduced by 2. Find the excluded number. A. 32 B. 30 C. 35 D. 36
  • 59. EXPLANATION: Mean of 5 numbers = 28. Sum of these 5 numbers = (28 x 5) = 140. Mean of the remaining 4 numbers = (28 - 2) =26. Sum of these remaining 4 numbers = (26 × 4) = 104. Excluded number = (sum of the given 5 numbers) - (sum of the remaining 4 numbers) = (140 - 104) = 36. Hence, the excluded number is 36.
  • 60. 29. A pupil's marks were wrongly entered as 83 instead of 63. Due to the average marks for the class got increased by half. The number of pupils in the class is: A. 42 B. 40 C. 45 D. 46
  • 61. EXPLANATION: Let there be x pupils in the class. Total increase in marks = (x * 1/2) = x/2 x/2 = (83 - 63) => x/2 = 20 => x = 40
  • 62. 30. The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is: A. 32 B. 30 C. 31 D. 36
  • 63. EXPLANATION: Let A, B, C represent their respective weights. Then, we have: A + B + C = (45 * 3) = 135 --- (i) A + B = (40 * 2) = 80 --- (ii) B + C = (43 * 2) = 86 --- (iii) Adding (ii) and (iii), we get: A + 2B + C = 166 --- (iv) Subtracting (i) from (iv), we get: B = 31 B's weight = 31 kg.
  • 65. In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
  • 66. A family consists of two grandparents, two parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family?
  • 67. A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
  • 68. The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
  • 69. The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is: