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Chapter 6:
TQM Tools and Techniques.
Mohd Zaizu llyas
Objectives
At the end of this topic,
DEFINE and EXPLAIN
1.QFD,
2.Benchmarking,
3.Kanban,
4.JIT.
you should be able to
DESCRIBE, EXPLAIN
S.Quality Tools
and DEMONSTRATE
Why need Quality tools?
• Most decision point and root causes remain
unclear until valid data are studied and
analyzed.
• Collecting and analyzing data using total
quality tools make the task easy for everyone.
Why need Quality tools?
• No matter where you fit into organization in
future, you may use all or some of these tool
and employers will serve you well for better
prospects.
This chapter will explain the most widely
used of quality tools.
•
What is the Quality tools?
The Seven Basic Tools of Quality is a
designat ion given to a fixed set of graphical
techniques ident if ied as being most helpf ul
troubleshoot ing issues relat ed to qualit y.
•
in
What is the Quality tools?
•
•
•
The tools are:-
1) the Pareto charts
2) the Cause-and-Effect I Ishikawa diagram
/Fishbone diagram
the Check Sheet
the Flow Chart
the Histogram
the Scatter Diagram
the Control Chart
•
•
•
•
•
3)
4)
5)
6}
7)
1) Pareto Chart
• Pareto charts are useful for separating
important from the trivial.
the
• Named after Italian economist and sociologist
Vilfredo Pareto {1848-1923). Was promoted
by Dr.Josep Juran.
• Pareto charts are important
help an organization decide
because they can
where to focus
limited resources.
• On a Pareto chart, data are arrayed along an
X-axis and a Y-axis.
Example
• In a factory, Only20% of problems will produce
80%
80%
20%
of
of
of
defects.
defect's cost will be assigned to only
the total number of defect types
•
occurri•
ng.
So, 80% of defect costs will spring 20% of total
cost element .
•
Purpose of Pareto
• Pareto can show you where to apply your
resources by "revealing few from the trivial
many"..
• ➔(Highlight few most important issues out of
many)
Pareto Chart
-
45
40
35
30
25
20
15
10
5
0
·-
(I)
0
c
'
-
co
«
c0
9
-
·
=
I
J
o a
.0°
I
"'
•
II,..,
E
a
I
l
t j
t
I
c
A B AII Others
D
Customers
Figure 15-1
Pareto Chart
Figure 15-1 represents
and All others.
75% sales are from 2 customers; A,B
All ot hers include many more customers
brings insignificant sales (>5%)
Which customers should be kept happy?
D, E
• customers A,B, C,
•
• but
•
Pareto Chart
100"%
90%
0"%
70%
60"%
50",
40"%
0"%
20"%
900
I
800 +
1
700
a
3 60
0 •
U )
--
(I)
a
Go
I
500
400
300
200
100
[]
•
b h l h
d a d
55•
Up
36-
45
26--
35
46•
55
18•
Figure 15-2
Swift V-12 Sales
by Age Group
25
Customer Age Group
Pareto Chart
Figure 15-2 shows sales of particular model
automobile by age group of the buyers.
• of
• The manufacturer has limited
advertising.
budget in
• The chart reveals the most logical choice to
target to advertise.
Concent rat ing on advertising on 26-45 age
will result in the best return of investment.
(75%)
•
The significant few ➔26-45 age
•
• The insignificant many are those under 26 &
above 45
Pareto Chart
• Figure 15-3
80
70
90
80
-
~ 60
6
-
- 50
40
30
20
10
0
U)
o
o
- ¢
1i-
o0
3
q
cr
Part
Failed
Miswire Incorrect
Part
PC Bd
Short
PC Bd
Open
AII Others
Pareto Chart
• Figure
defect
All the
15-3 shows 80% of the cost was related to 5
causes.
other (about 30 more) were insignificant.
•
• The longest bar ($70k) accounted for 40%, if solved,
immediate reduction in rework cost will happen.
After eliminate the longest bar, the team sorted data
again to develop level 2 Pareto Chart Read page
484-489 for further understanding
•
Pareto Chart
• Figure 15-4
•
_ -------
45
40
' !
90
80
70
60
50
40
30
? (
IO
(
- I
l
t
«4
t
m
I I
t )
«
· )
' 0
f
0
t
E
D
(
I
+
' -
)
I '
I
tt
( t
IO
't) I l
I
f
[ l o (p
/ w p
Mt
II
tolny A
I
L
( )1
/of
Helo
yt YI
J II
Steps in Constructing Pareto Chart
1.
2.
3.
4.
Select the subject of the chart
Determine what data to be gathered
Gather the data related to the quality problem
Make a check sheet of the gat hered data, record
total numbers in each category.
Determine total numbers of nonconformities,
calculate percentage each.
Select scales of the chart
Draw PARETO Chart from largest category to
smallest.
Analyze the chart
the
5.
6.
7.
8.
) Cause and Effect Diagrams/ Ishikawa
Diagrams
Cause and Effect Diagrams
• Use to identify and isolate causes of a
problem. Developed by Dr. Kaoru Ishikawa.
(1915-1989)
• Also called
Diagram.
Ishikawa Diagram/ Fishbone
Cause and Effect Diagrams
• Benefits;
-Creating the diagram - enlightened,
instructive process.
- Focus a group, reducing irrelevant
discussion.
-Separate causes from symptoms
-Can be used with any problems
Cause and Effect Diagrams
¢
C
A
U
S
E


C
A
U
S
E

C
A
U
S
E

i
w 

E
F
F
E
C
T
I
Figure15-8
BasicCause-and-Effect
orFishboneDiagram
I
C
A
U
S
E
I
C
A
U
S
E C
A
U
S
E
6 Common major factors
Diagrams
in Ishikawa
1.
2.
3.
4.
5.
6.
Man (Operator)
Method
Measurement
Material
Machine
Environment
Ishikawa Diagram
ENVIRONMENT MACHINE
Problem A
MEASUREMENT MATERIAL
Cause and Effect Diagrams
15-8, the spine points to the
• From figure
effect.
The effect is
•
•
the problem we are interested in.
The lower level factors affecting major factor
branch.
Check Figure 15-7 to see whether the major
•
causes can be identified.
Cause and Effect Diagrams
• E,g: Machine soldering defects
- Six major groupings of causes are;
•
•
•
•
•
•
Solder machine itself
Operators Materials
Methods/procedures
Measurement of accuracy
Environment
Cause and Effect Diagrams
MACHINE OPERA
TOR
attitude
attention
training
skill
- MA
TERIALS
handling
solderability
maintenance
vendors - ◄
ollor
-
storage
age
s
.,,
;.
) , e o o t a i a « o n
',parts flux
u
wt /it I
[ l I t t I
l"
humidity waveheight
temperature
waittime
partprep
preheat
conveyorangle
con
" .s
S
p
peed
lighting
roomtemp
cleanliness instruments
h f l
,
calibration skill

)
fluxtype lighting
'
ing
pollution
ENVIRONMENT
train
MEA'UHL M
ENI
specific gravity
Figure15--10
ComplotodCauso-and-EttoctDia@rm
Cause and Effect Diagrams
• Normally created by teams to brainstorm the
cause/effect.
Completed diagram reveals factors & relat ionship
which not been obvious.
Some problems previously were isolated now can
identified.
Therefore, further action shall be taken.
Cause and Effect Diagrams serve as a reminder.
•
• be
•
•
FIVE WHYs
The '5 Whys' is a question-asking method
used to explore the cause/effect relationships
underlying a particular problem.
Objective: To determine a root cause of a
defect or problem.
The technique was originally developed by
Sakichi Toyoda (1867-1930)and was later used
•
•
•
within Toyota Motor Corporation during the
evolution of their manufacturing
methodologies.
• Part of Toyota Production System activities.
of 5 whys
Example
•
•
•
My car cannot start. (the problem statement)
Why?
Why?
why)
Why?
Why?
-
-
The
The
battery is dead. (first why)
alternator is not functioning. (second
•
•
-
-
The
The
alternator
alternator
belt has broken. (third why)
belt was well beyond its useful
service
why)
Why? -
life and has never been replaced. (fourth
• I have not been maintaining my car according
to the recommended service schedule. (fifth why,
root cause)
This example could be taken further to a sixth, sevent h,
or even greater level.
How To Complete The 5 Whys
1. Write down the specific problem. Describe it
completely. It also helps a team focus on the same
problem.
2. Ask Why the
answer down
problem happens and write the
below the problem.
3. If the answer
problem that
doesn't identify the root cause of the
you wrote down in step 1, ask Why
again and write that answer down.
4. Loop back to step 3 until the team is in agreement
that the problem's root cause is identified. Again,
this may take fewer or more times than five Whys.
5 Whys Examples
Problem Statement: Customers are unhappy because they are
being shipped products that don't meet their specificat ions.
1. Why are customers BEING SHIPPED BAD PRODUCTS?
Because manufacturing built the products to a specification that is
different from what the customer and the sales person agreed to.
2. Why did manufacturing build the products to a different specification
than that of sales?
- Because the sales person expedites work on the shop floor by calling the
head of manufacturing directly to begin work. An error happened when
the specifications were being communicated or written down.
3. Why does the sales person call the head of manufacturing directly to
company?
- Because the "start work" form requires the sales director's approval
before work can begin and slows the manuf acturing process (or stops it
when the director is out of the office).
start work instead of following the procedure established in the
4. Why does the form contain an approval for the sales director?
Because the sales director needs to be continually updated on salesfor
discussions with the CEO.
3) Check sheets
Check sheets
• Many organizations:
They are :"DATA RICH, INFORMATION POOR"
• Check sheet can
applications.
be a valuable tool in wide
Purpose: To make it easy to collect data for
specific purposes or to convert into valuable
inf ormation.
•
E.g; Weekly Summary of Shaft Dimensional
Tolerance Results
Shaft length: Week of 7/11
Length
(Spec: 1.120-1.130")
Date Date Date
Length Length Rem
11
11
11
11
12
12
12
12
13
13
13
13
14
14
14
14
15
15
15
15
1.124
1.126
1.119
1.120
1.124
1.125
1.121
1.126
1.123
1.120
1.124
1.126
1.125
1.126
1.126
1.122
1.124
1.124
1.124
1.123
1.128
1.128
1.123
1.122
1.126
1.127
1.124
1.124
1.125
1.122
1.123
1.123
1.127
1.129
1.123
1.124
1.121
1.127
1.122
1.122
11
11
11
11
12
12
12
12
13
13
13
13
14
14
14
14
15
15
15
15
11
11
11
11
12
12
12
12
13
13
13
13
14
14
14
14
15
15
15
15
1.123
1.125
1.122
1.123
1.125
1.125
1.125
1.127
1.121
1.118
1.125
1.124
1.124
1.125
1.124
1.122
1.123
1.123
1.122
1.121
•
Figure 15--11
Weekly Summary of Shaft
Dimensional Tolerance Results
Note: This is not a check sheet.
Check sheets
Figure 15-11 reports how the works
produced relates to the shaft length
specificat ions.
• being
limits 1.120
waste!
is the check
- 1.130
• Machine setup
Outside range
So Figure 15-12
inches.
• sheet set up to
display useful information.
It produces histogram.
•
Chec k S heet
S h a ft le n g t h : W eek o f 7 / 11 (Spec: 1.120--1.130)
1.118°·
1. 119°
1.120
13
11
11 13
.... Out of Limits
1.121
1.122
1.123
1.124
12 1315 15
11 11 13 14 14 15 15 15
11 11 11 13 1313 14 15 15 15
11
11
12 12 12 1313 14 14 141515 15
1212 12121313 14 14
1.125
11 12 12 13 14 14
1.126
1.127
1.128
1.129
1.130
1.131°°
1.132°°
12 12 14 15
11 11 •
14 Enter day of month for
data point.
Figure 15--12
Check Sheet of Shaft Dimensional
Tolerance Results
4) Flow Chart
Flow Chart
• A flowchart is a type of diagram that
represents an algorit hm or process, showing
the steps as boxes of various kinds, and their
order by connecting these wit h arrows
Flow Chart
Pluginlamp
El
A simple flowchsrt representing s
c r a s s far d=sling with s nan-functioning
lamp.
Example of the flow chart symbol
Flcwchart
•
Name
(Alterrates)
P r e s s
Description
5ymbol
An nnratirn nr artinn step.
A start or sop pIn: In a process.
Iermmator
)
0
D
t
_
t _
LI
Aques:ion or banch in the proces,
Decision
A waiting pcriod.
I
Aterrte Process
A formally defired sub-process.
An alternate to the normal process step,
Indicates data Inputs ard outputs to anc from a process.
Dacumert Adocument or report.
5) Histograms
Histograms
• Used to chart frequency of
does something happen?)
occurrence. (How often
processes: attributes
• Commonly associated
variables
with and
DATATYPES EXAMPLES
Has/ has not
Attributes
Good/ bad
Pass/ fail
Accept/ Reject
Conform / non-conform
Measured values (Dimension, weight,
voltage, surface, etc.)
Variables
Histograms
•
•
•
Attribute data: Go/no go information.
Variable data: measurement informat ion.
Looking at Figure 15-14, we are using attributes data;
either
But, it
to the
they passed or they failed the screening.
does not reveal about the process cont ribut ing
adjustment .
•
• Also, does not tell the robust process. This is why
variables data is needed.
Histograms
• Figure
(Spec:
15-14 : Shaft Acceptence:
1.120-1.130)
week of 7/11
Date
11
12
13
14
15
Total
Accepted
11
12
11
12
12
58
Rejected
1
0
1
0
0
2
Histograms and Statistics
• Example: textbook - page 500
BEAD EXPERIMENT
There are 900 white beads, 100 red beads =1000beads
1.
2.
The beads mixed thoroughly.
50 beads are drawn at random. - Count how many
Check mark is entered in histogram.
red beads. -
3.
4.
All the beads are put back into container and mixed again.
Repeat Step 1 ➔Step 3
The process does not change, but the output changed!
If these steps are taken over and over, Histogram as in Figure 15-15
occur
will
Histograms
.
£
and Statistics
'10
25
20
15
I'll
0
a
E
cU
0
6
....
Ill
10
. 0 I
E
•
I
[
z 5
0
I
i
I I
r
'
:
1 I
I
Figure 15--15
roquency Distribution of Red
Hoads in Samples
1 5 6 7
2 3 4 9 10
8
Number of Red Beads in Sample
Sampleswith O red beads
Samples with 1 red bead
Samples wit h 2 red beads
Sampleswit h 3 red beads
Samples with 4 red beads
Sampleswit h 5 red beads
Sampleswith 6 red beads
Samples with 7 red beads
Samples with 8 red beads
Samples with 9 red beads
Samples with 10 rod boads
Total samplos takot
0
1
3
9
19
31
21
11
3
2
0
100
1
5 1
Figure
Data on /tot Itontdn In {amplo
Histograms and Statistics
• The flatter and wider the frequency
distribution curve, the greater
variability.
Taller and narrower the curve,
variability.
- 2 things in process variability;
• Standard deviation, a
•Mean,µ
the process
• the less process
Histograms and Statistics
• Mean is the sum of the observations divided by the number
of observations
Also describes the central location of the data in the chart,
•
- Standard Deviation describes the spread or dispersion of data.
Calculating the Mean, µ
= X : n
X=product of the number of beads in a sample
of samples containing the number of beads.
times the number
*See Figure 15-17b, page 503 for further understanding.
1 4
2 3 5 6
Measured data from
Figure 15--16
# of Red
Beads
0
1
2
3
4
5
6
7
8
9
10
# of
Samples
•
0
1
3
9
19
31
21
11
3
2
0
n = 100
Figure 15-17a
Raw Data from the Colored Bead Experiment (see Figure 15--16)
Histograms and Statistics
1 2 3
Mu ltiply Co l
by Col 2
4 5 6
Measured data fror
Figure 15--16
1
# of Hed
Beads
0
1
2
3
4
5
G
7
8
9
1 0
# of
S a m p le s X Value
0
1
3
9
19
31
21
11
3
2
0
100
0
1
6
2 7
76
155
126
7 7
24
18
0
X = 5 1 0
•
n --
= X : n
=510 :
=5.1
100
Figure 15--17b
Calculating Values of X and 2X
Histograms and Statistics
2 6
Sum of
Distance?
1 4
Deviation
from
5
Deviation
squared
(Col 4?
3
Multiply Col
by Col 2.
Measured data from
Figure 15--16
1
- )
(Col 1 (Col2 Col5 )
# of Red
Beads
# of
Samples d?
X Value d
-5.1
- 4 . 1
-3.1
-2.1
1 . 1
-0.1
0.9
1.9
2.9
3.9
4.9
0
1
6
27
76
155
126
77
24
18
0
2 X = 5 1 0
0
16.81
28.83
39.69
22.99
0.31
17.01
39.71
25.23
30.42
0
1
2
3
4
5
6
7
8
9
10
0
1
3
9
19
31
21
11
3
2
0
100
26.01
16.81
9.61
4.41
1.21
0.01
0.81
3.61
8.41
15.21
24.01
•
0
221
p =
= 2d?
Figure 15--17c
Completed Deviation Data Table
Histograms and Statistics
Deviation, a
• Calculating Standard
o=[d/(n-1)
d = The deviation of any unit from
n = the number of units sampled.
the mean
■ From Figure 15-17c,
■ n(100)
a=/2MIR1
o=V221799
= 1 . 4 o = 1.49, 20 = 2.99, 30 = 4.47
I
I
30
25 I
I
I
0 11
a
m
I
E 20 I
I
I
cU
0
- 15
I
1;
I
o I •
I,,.
m I
I
n 1
0
E
I
z
2 I
5 I
I
I
I
II I
I
3
I .I'
i
I y
d4
•
I
I
8
l
I
0
II
I
2
I
1
1
5
I
6
•
I
I
7
I
I
9
I
0 I
r
1
I
10
t I
I
~
. -
+
a
.
-26
.-
-30
-
+20
,_
-
.~
-
+30
-
-~
-·
Jl
Red Beads in Sample
15-18
Figure
Application of Standard Deviation Calculations to
Red
BeadHistogram
Shape of Histograms
A F K
..,,,.
'1
L
B G
_ /
c
I ~
~
llll
ucL
L c u
--
LCL
ucu
UCL
E J L c u
Figure 15-19
Histograms of Varying
'hapes H
Figure 15-19
Process A is much tighter, normal
favorable.
Process B greater variances.
C and Dare not cent ered, skewed
product will be lost .
• distribution,
•
• to left and right,
• F - someone has discarded. Take out the reject, and
only collect data within acceptable range.
G -the vendor has screened out the parts, took out
the best to other customers.
H - a proper normal distribut ion between upper and
lower limit s.
I and Jskewing! Signif icant loss of product ...
K until P shifting ... why???
•
•
•
•
6) Scatter Diagram
Scatter Diagram
• A scatter diagram is a tool for analyzing
relationships between two variables. One
variable is plotted on the horizontal axis and
the other is plotted on the vertical axis
While the diagram shows relationships,
It does not by itself prove that one variable
causes the other.
•
•
Scatter Diagram
• Scatter diagrams will generally show one of
six possible correlat ions between the
variables:
Scatter Diagram
• 1) Strong Positive Correlation - The value of V
increases as the value of X increases.
clearly
i d
, N e t t
i t . t h
M t
,
o - - - - - - - - - - - - - -
oO. 2 4 6
X
Scatter Diagram
2) Strong Negative Correlation - The value of V
•
decreases as the value of X increases
clearly
6
.5
- - - - - - - - - - - - - - - -
- - _ ; . _
• d
A l t l
•a
d
4 l l l l ]
te
- l l
l t d . l h
0 - - - - - - - - - - - - -
2 4
0 6
Xx
Scatter Diagram
3) Weak Positive Correlation -The value of Y
increases slightly as the value of X increases.
t l
.. td
. •
1
,
" } l b s 4 A l p
~ « i
- + - - - - - - - - - - - - -
0
4
0 . 2 6
x
Scatter Diagram
4) Weak Negative Correlation - The value
X
of
Y decreases
■
Increases. slightly as the value of
6 . · ~ ~ ~ - - - - -
$
' m l b l E l l
] }
• 9
f { l s . A l . l b
l b . A . a l . A A
e 0
t t l
flt•
2 4
0 6
X
Scatter Diagram
5) Complex Correlation -The value of Y
but
seems to be related to the value of X, the
relationship is
4
3 .5
3
2 . 5
not easily determined
., •
•
-
Y
•
2
1.5
1
0 . 5
0
•
0 2 4 6
X
Scatter Diagram
6) No Correlation -There is no
between
demonstrated connection
the two variables
7
6
5
4
•
•
• •
Y
3
2
1
0
• $
4
0 2 6
X
7) Control Chart
Control Chart
---------~-~----------------UCL
2
O
0
•ProcessAve(age

---------------------------LCL
o
Figure15-27
BasicControlChart Samples
■
■
Figure 15-27 shows a basic of control chart.
Data stay between Upper Control Limit (UCL) and Lower Control Limit
(LCL)
Control Chart
• As long as the plots stay between the limits, and don't congregate on 1
side or the ot her of the average line, the process is in STA
TISTICAL
CONTROL.
Common causes/chance: Small random changes in the process
that cannot be avoided - but still in statistical control
Varying out of the centerline of the process
Result of the sum of numerous small resources of natural variation
that are always part of the process.
Eg; Setting on machines, environment, methods etc.
Special causes/Assignable causes: Variations in the process that can be
identified as having a specific cause.
A plot point breaks through UCL or LCL
OR there a several points in a row above/below the lines.
Result of the factors that are not part of the process and only occur
special case.
Eg: New operator involve, electricity blackout, shipment faulty of
material etc.
•
•
is
Control Chart
• Only after the special has been identified, it
should be corrected, and restart the process.
How to correct? (By eliminating root cause)
Control chart is usually operated under
•
•
Statistical Process Control (SPC) - Chapter 18.
Control Chart
Control Chart - Statistical Process Control (SPC)
• What is SPC?
SPC is a statistical method of separating variation
resulting from special causes resulting from natural
causes, to eliminate the special causes, and to
establish and maintain consistency in the process,
enabling process improvement.
Control Chart
• Common factors that can affect output are;
5M's
Machines and environment employed
Material used Methods
(work instructions)
Measurements taken
Manpower (People who operate the process)
If these factors are perfect; th is means;
1. Environment facilitates quality work and there are no
misadjustments in the machines
No flaws in materials
Follow work instruction accurate and precisely
Accurate and repeatable measurements
People work with extreme care - follow instructions
extremely well
2.
3.
4.
5.
Control Chart
n g .
R
Sum
Ex
Subgroup
#
- Mean Value
X
Measured Values
1
1
5 s
Date 4 2 7
3 4 8 9 0
7/6
7/6
7/6
7/6
7/7
7/7
7/7
7/7
7/8
7/8
7/8
7/8
101
103
103
96
99
101
100
97
102
100
101
100
101
98
102
99
99
100
98
100
101
100
101
98
102
98
100
97
100
100
98
98
101
101
98
102
1002
1006
1007
993
1004
999
1000
995
1003
998
1001
1000
100.2
100.6
100.7
99.3
100.4
99.9
100.0
99.5
100.3
99.8
100.1
100.0
1
2
3
4
5
6
7
8
9
10
11
12
98
100
101
99
102
103
103
101
97
105
99
103
102
101
99
102
100
99
101
102
100
99
98
101
99
100
100
101
103
99
99
99
103
98
104
99
100
104
99
102
101
98
100
96
98
102
100
100
98
102
102
98
102
101
99
99
100
97
98
100
101
99
98
100
98
100
102
100
102
97
100
99
100
101
103
99
100
99
100
103
99
99
102
98
4
6
5
6
5
5
5
7
6
8
6
5
I
I
■
I
68
Total 1,200.8
X = 100.067, =5.667
k= 12, R
,
Figure 18-5
Initial Data for Precision Spacer Process
From Figure 18-5,
•
[
G
; Average Range, [R]is
Average of subgroup range, R is
R - 2 « +
R ==(Max value of x - Min value of
[so.=68=12=5.667]
The average,
r-2r=
k
-
x
== number of sub groups
== subgroup average x)
= 1 2 0 0 . 8
s o . = = 1 2
= = 1 0 0 . 0 6 7
A2is the confidence level
data, the larger the value
for the
of A,
the farther the control limits.
UCL=x+A,R
LCL=x-A,R
Control Chart
Factors for
x charts
Factors for
R charts
Number of
data points
in subgroup
LCL
0,
UCL
0,
•
(n)
2
3
4
5
1.88
1.02
0.73
0.58
0
0
0
0
3.27
2.57
2.28
2.11
0.48
0.42
0.37
0.34
0.31
0
0.08
0.14
0.18
0.22
6
7
8
9
10
2.00
1.92
1.86
1.82
1.78 I
II
11
12
13
14
15
0.29
0.27
0.25
0.24
0.22
0.26
0.28
0.31
0.33
0.35
1.74
1.72
1.69
1.67
1.65
I
16
17
18
19
20
0.21
0.20
0.19
6.19
0.18
0.36
0.38
0.39
0.40
0.41
1.64
1.62
1.61
1.60
1.59
Figure 18--6
Factors Table for x•
and R-Charts
• From Figure 18-6;
n=10, so UCL and LCL in x-bar chart is;
UCL =100.067 +(0.31x5.667) ==101.82377
X
LCL- ==100.067-(0.31x5.667) ==98.31023
X
And UCL and LCL for the values in R chart;
UCL,= D,R =1.785.667 = 10.08726
LCL,=D,R=0.22x5.667 =1.2467
(a)
Figure 18-7
Chart
11
03
---
'
II
r e
- -
-
....
---
102
- - - -,
I
-
--
-
I
- - - - -
... - - - -
- -
. '
-
- -
- _, - -
- - -i- - - - - - ·
- - - - - - - - UCL,
«
a)
0
cU
h
->--
' y
•
101
-~
1 t 
I"'
'
/
I
 V
k
x
•
100
0
2
/
_.,...
..
I
_,...
9
.
•0
0»
99
-~
E
-
-
-
7
--
0
-.,. --
- ~
- - - - - .- -
I
-- - ---- --
·- - - - - - - . -
: - - -
- - - ~ -
,... - ~ - LCL,
- - - - -
= = %
98 I
--
1
97 a
I
5
I
10
2 3 4 6 7 8 9 1
1 12 1
3 14 15 16 17 18 19 20 21
Subgroup Number
18-7 (b)
Figure
mCh a r t
12
11
10
9
8
7
6
5
4
3
2
1
0
±
£
; ~
I
- -
- - - - -
• - -
- - - • - . 4 UC L
w «
I
- F
±
~
'
I F
#
~
- ; 8
q
c
I 
I
s
c
•
I
-
er
V
""''

/
- r
."-
R
X I
I """
._
0
.......
" '
I '-.
I
=E
c
#/
#
i±
±
#
c
2
G
,,_
- - -,- - - - - - - - --
- - « . . -
-
-
- - - - - - - - ·- - - - - - - - - - - - - - - L C L ,
'
- - - -
'
5 '
d
10 11
2 3 4 6 7 8 9 12 13 14 15 16 17 18 19 2 0 2 1
1
Subgroup Num ber
Figure 18--7
x- and FR-Charts
Control Chart
• Suppose that we have been setting up a new process (not stable).
in Figure 18-8
• It would look like
5
-g
00
LCl - - - - - - -
Jc
- • - - - - - - - - - - - - - - - - - - - - - - - - -
I I
1 2 3 4 5 6 7 8 9 10 1 1 12 13 14 15
rtuure 18--8
hart tor an Unstable Process Subgroup Number
In Figure 18-8;
•
•
•
Subgroup 7 was out of limits.
Can we ignore? NO!
Because-control limit has been calculated with the data inclusive of
special cause event. (E.g: result of untrained operator etc)
We MUST determine and eliminate the cause.
After eliminate it, flush out SUBGROUP 7 and recalculate the process
average (x-bar} and the control limits.
We will find narrower limit, Figure 18-9
•
•
•
Figure 18-9
c
0»
~
UCL-
x
q
o
• x
<
>
9
c
0
LCL,
::j
0 )
+
lSubgroup Number
10 11 1 2 13 14 15
1 2 3 4 5 6 8 9
ruuro 18--9
II Mo
w , Narrower Limits
o I'onotrated Note: Subgroup 7 deleted
• If still penetrates the new out of limits, repeat the same action .. Until the points
are all well between the limits.
Control Chart
• X-bar chart is used to show the center of
process measurements (accuracy).
R chart is to show the spread of the data
(precision).
the
•
• Without Range, it would not be able to
understand the PROCESS CAPABILITY of the
chart.
Control Chart-Advantages of a Stable Process
• Stable process?? It is a process that
common variation.
Advantages;
exhibits only
•
Management knows the process capability, so they can predict
cost well.
Productivity MAX,cost MIN
Management can measure effect faster and more reliable.
Got data if management wants to alter spec limits.
Stable process is basic requirement for process improvement
efforts.
1.
2.
3.
4.
s.
7 NEW QC TOOLS
• A committee for developing QC
affiliated with JUSE was set up
1972.
tools
in April
• Their aim was to develop QC techniques
for use by managerial level and staff.
• In January 1977 the committee announced
the results of its research in
7 NEW QC TOOLS
the form of a new set of methods
New QC Tools'.
The tools are:-
called 'The Seven
•
•
•
•
•
•
•
1) Affinity Diagram
2)Interrelationship
3)Tree diagram
diagram
4)
5)
6)
7)
Prioritization Matrix
Matrix Diagram
Process Decision Process Chart (PDPC)
Activity Network Diagram
Howto
determinethe
processis
s1A
T1$TICA
cNTRO"
yo1?
Quiz
• Define and
Rule 1 and
Show examples (Diagrams picture)
Rule 2 to show the process is not
in statistical control.
Rule 1: A process is not in statistical co ntrol if any subgroup statis tic falls
outs
i de of the control limits. This point is marked with an "
X"
directly on the control chart.
- # 4 - - l / p p e f f o p ' f f ( l Lifnyt
Zone A
Zone8
i i . i i i ' i i . « i i
T
Zone C
ZoneC
ZoneB
ZoneA
- J } s t f&ft@f[ft
. i i . . i i .
- - - - .25 ) L t @ - f [ -[ --f } f - f ? t Lfflf - 0
5 15
1 10 20
F
igur
e 15-8 Rule 1 - - Lack of Statistical Control
Rule 2: A process
successive
is not in statistical control
subgroup statistics fall in one
if any two out of three
of the A zones or beyond
second of the two points
on the same side of the centerline. The
in or beyond zone A is marked with an "X."
- lL/pp@ff'ft!fpllffflt
ZoneA
Zone B
Zone C
Zone C
ZoneB
Zone A
. . . . . . . . . . e l l .
L 0 4 Rf f'(flfol[fit
15
1 10
5 20 25
Rule 2 L a ck of Statistical Control
Fgiure15-9
control if four out of five successive
Rule 3: A process is not in statistical
subgroup statistics fall in one of the B zones or beyond on thesame
sidteeof1 the center·rlli;ne
.
+
th
.e
..£f,our
~t1
hp o i:.nt marke
ed
el w i;t
h
an
y
• "
0On.l1.y :i.s
Zone B
Zone C
ZoneC
Zone B
Zone A
h i . f l # f l . h f [ t f l e f i f e
- I L _ Q t 4 t f f o f t [ r t ] [ f i t
10
1 5 15 20 25
'
Figure 15-10 Rule 3 -- Lackof Statistical Control
Rule 4: A process is not in statistical
in zone C on either side of
is marked with an "X."
control if eight successive points fall
the centerline. Only the eight point
-lJD9per font!fol[Ifft!f
Zone A
Zone B
ZoneC
Z
o ne C
Zone B
Zone A
= l s # t e l # # h f ; f f ' f ] ] f f
= = ' Lower fontfolLirjt
1 10 25
20
15
Statistical error: Type I and Type II
• Statisticians speak of two significant sorts of
statistical error.
Type I e
rror: An incorrect decision to REJECT
something when it is true.
- False alarm
Type 1
1e
rror: An incorrect decision to ACCEPT
something when it is true.
- Oversight
•
•
OUTSIDE CONTROL LIMITS [INSIDE CONTROL LIMIT
ype error
ecause presen
Chance cause present
]
Actual condition
Innocent Not innocent
FalsePositive(i.e. guilty but not caught)
Type l error
-
Judged "innocent" True Positive
Test result
False Negative (i.e. innocent but condemned)
Type ll error
Judged "not innocent" True Negative
Common Use Control Chart for attribute data
(Counted values)
P chart - No. of defects in samples of varying size
percentage of fraction.
(e.g anywhere defects can be counted)
• as a
•
• np chart- no. of defective pieces in samples
size.
C chart - No. of defects in a single product .
blemish, deform, scrat ches in one part)
of fixed
.
• (e.g:
• U chart - No. of defects per-unit area. (Carpet area,
lenght)
Exercise
1. Control charts for X and RR are to be established on a certain dimension part,
measured
in mm. Data were collected in subgroup sizes of6 and are give below. Determine the trial
forX-barandRchart
centerline and control limits
SUBGROUP
NUMBERS
1
2
3
4
5
6
7
8
9
10
1
1
12
20.40
20.41
20.45
20.34
20.36
20.42
20.50
20.31
20.39
20.39
20.40
20.41
20.40
0.39
0.36
0.34
0.36
0.37
0.33
0.38
0.35
0.38
0.33
0.32
0.34
0.30
13
14
15
16
1
18
19
20
21
22
23
24
25
-
X
20.35
20.40
20.36
20.65
20.20
20.40
20.43
20.37
20.48
20.42
20.39
20.38
R
0.34
0.36
0.32
0.36
0.36
0.35
0.31
0.34
0.30
0.33
0.30
0.37
Exercise 2
samples:
the
Consider
Sample
following 20
15-1
Observations
38
22
31
33
20
24
34.
.
30
34
33
51
12
19
17
26
17
21
35
16
31
1
2
3
4
5
6
7
8
9
10
11
12
1
3
'··
14
15
16
17
18
19
20
24
41
40
37
43
24
37
40
39
41
36
22
50
21
7
2, .
3
20
45
16
13
42
32
38
22
46
27
31
32
35
55
22
14
36
29
33
40
23
28
32·
'
23
59
22
40
52
32
29
4
46
20
25
4.4.
24
52
21
31
28
25
52
27
50
15
60
32
46
54
42
33
47
9
18
27
29
21
30
42
34
41
22
27
29
'
limits for the X and R charts.
the control
a. Determine
ia
fi n
- d' i
I} C
..:I
L
a.d
..,,r.,l
;,i'!. W
'W
"h
-a!
d
'lik
t .G
.,-.,d
..·
n v
yO
au
l c
<o n
I c lI
1
K
·--t
1e d
...
bro
u11 l
- it 1
1
1
:h
l t.~
'l
I''.)I~
0
O [I'Lt ""' X
b.
1
N ~ U
process?
Quality Function Deployment
• Defined as:
- A systematic method for transferring customer
wants/needs/expectations into product and
process characteristics
QUALITY FUNCTION
DEPLOYMENT
Quality Function Deployment
•
➔
➔
Voice of the customer
House of Quality
QFD: An approach that integrates the "voice of the
customer" into the product and service
development process.
House of quality
A
technical
correlations
engineering
metrics
A
relative
importance
I _ I ' -! _I _ I 1
relationships
between
customer needs
and
engineering
I I I I I I I
I I I I I I I
- T - - r 7 - - ; •
benchmarking
on needs
I I I I I I
I
customer
needs - T - - r 7 - - ; •
- I-
'-
' ' ' ' '
- - - -
' ' '
-- - -
' '
-
metrics
_ I
I
I I I _ I I I
I
e g s e g g g
I I I I I
' ' ' } A - ' } A ' -'• I I I I I I I
-
- T
- - r 7 - ; •
I I I I I I I I I I I
target and final specs
QFD & House of Quality
Identify customer wants
Ident ify how the good/ service will sat isfy customer
wants
Relate the customer's wants to the product's hows
Identify relationships between the firm's hows
Develop importance ratings
Evaluate competing products
•
•
•
•
•
•
Example
Facial Foam 100ml :
QFD
•
•
•
A :
B :
C:
Nivea Visage (Biersdorf
L'Oreal (Paris)
Hamburg)
Biore (Kao)
Facial Foam C
Facial Foam A Facial Foam B
QFD Details
I I I I
Relationship
? s o n g Posisve
Product Characteristics
_
:..::::.-:::
0
£
- "
=
©
c
CJ
-
-c
•
u
""'O
c
±-' V Positive
<?
c
0
:..::::.-:::
c
CD
..0
©
h
•
o
0..
£
( / )
b l
4
0 )
·
C
-
, X
x Negative
E -0
h
c
c
-
?) stong Negatve
o
· - ·b
-l
o
E
G
© -
>
.= I
CD
;
-c,
©
cr
c
Customer
Requirement
Membersihkan dam
menghaluskan kulit
Menghilangkan sel
ulit mati
Mengecilkan pori-pori
Mer utihkan/mencerat
kan kulit
Tidal menyebabkan
alergi
TOTAL
c
©
er Competitive Evaluation
C
0--
-0-
V -0- B
2
C
2
C
2
B
2
C
2
A
3
B
3
A
3
A
3
A
3
V
X
x
20 V '
-
1 4
A
4
B
4
C
4
B
4
5
✓ --
20 V 1 5
2
V
0
V
25
1 5
V i V
25
1 5
0
X Xx
V
10
100
- -
1
Facial
5
RM
16.750
Foam 100ml
A: Niwea Visage
(Beiersdotf Hamburg)
B: L'Oreal (Paris) 32.000
14.600
C: Biore (Kao)
r .
I I • - I : . 1 .
• •
a d a a
<
@
2
>
- £
X < d >
.
(<
✓
>
3
<
.8.
X
1 $ .% ......
>
X X L
I •
Product Ch aracte ri sti cs
Relationship
( s t a n o P o s e
, -
?
=-.
c
,1%
L -
-
/ c c
z
, T
a
4 ;
a
.15
--'
-
£ c
5E
c
. 2
-£
a
5z
V
c
c
-c
Fasitivu
c n
e
.c
- c
x Negative
=
=
,T3
±
•- ()y sans Negate
- c
E
, 1
£
=- c
d
7 ._
CL
c
CL
€ cr- c
C u s t o m e r
R e q u i r e m e n t
hfemnbersihkan dar
mnenghaluskan kulit
tMenghilangkan sel
ulit m ati
Mengecilkan pori-pori
t f e r u t i h k a mime n c e r a
h k a n k u l i t
T id a k m e r r ye b a bk an
alergi
I
-c 1
Cr Competitiwe Ewaluati0nr
c
0 - -
0 - -
-
-0-- A
3
E
3
A
3
A
3
A
E
2
C
2
c
2
B
2
c
-
"
V
x
20 V - ·
1 4
A
4
El
4
c
4
El
4
0 0 m l
5
✓- -
'
- 20
1 5
- 0
-
"
25
1 5
2 ✓- ·
X
I
V
2
- -
25
1 5
- ✓- -
I
X
"
- 1 0
1 2 3 5
RM
I Facial Foam 1
I I
1 00
T O T A L
liwea wWisage (
B e ie r s d o r f
H a m b u r g
white
pure
m icro act ive
anti
gentl du llr
white
ning
sc r ub
anti
cdulln
ess
nourl
s h in g
scrub
apprc
wed
teste
d
asian
A:
A 4'#,
Competitiwe Ewaluatiu 16.750
e e s s 4'#,
El L'Oreal (Paris) 32.000
:
crush
able
c M i C & E M i C : E ir e ( K a 0 } 14.600
I I
l ll
Tabel Score
Hasil
B
Hasil
B
0,40
0,60
1,00
0,50
0,40
2,90
A A
0,60
0,80
0,75
0,75
0,30
3,20
C C
20
20
25
25
10
3
4
3
3
3
16
2
3
4
2
4
15
4
2
2
4
2
14
0,80
0,40
0,50
1,00
0,20
2,90
I I I I I I
I
To conclude :
• ProductA (Nivea Visage) Facial Foam has the highest
score among others. Means this product is the best
chosen by customers.
Benefit s Of QFD
•
•
•
•
Customer Driven
Reduces Implementat ion
Promotes T
eamwork
Provides Documentat ion
Time
Quality Function Deployment (QFD)
• QFD seeks to bring the voice of customers into
process of designing and developing a product
the
or
.
service.
QFD can point out areas of strength as well as
weaknesses in both existing or new products.
When a company uses QFD, they stop developing
products/ services on their own int erpretat ion.
•
•
Main benefits of QFD
1. - QFD gives information which is then
customer requirements.
Customer focused
translated into a set of specific
2. Time efficient -- Time is not wasted on
have no value to customers.
Teamwork oriented - All decisions are
developing features that
3. based on consensus and
involve in-depth
Documentation
documentation.
discussion and brainstorming
oriented - QFD forces the issue of
This document changes as new information
4.
gained. Having up-to-date information about customer
requirements, will be very helpful.

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TQM Tools and Techniques. ( PDFDrive ).pptx

  • 1. Chapter 6: TQM Tools and Techniques. Mohd Zaizu llyas
  • 2. Objectives At the end of this topic, DEFINE and EXPLAIN 1.QFD, 2.Benchmarking, 3.Kanban, 4.JIT. you should be able to DESCRIBE, EXPLAIN S.Quality Tools and DEMONSTRATE
  • 3. Why need Quality tools? • Most decision point and root causes remain unclear until valid data are studied and analyzed. • Collecting and analyzing data using total quality tools make the task easy for everyone.
  • 4. Why need Quality tools? • No matter where you fit into organization in future, you may use all or some of these tool and employers will serve you well for better prospects. This chapter will explain the most widely used of quality tools. •
  • 5. What is the Quality tools? The Seven Basic Tools of Quality is a designat ion given to a fixed set of graphical techniques ident if ied as being most helpf ul troubleshoot ing issues relat ed to qualit y. • in
  • 6. What is the Quality tools? • • • The tools are:- 1) the Pareto charts 2) the Cause-and-Effect I Ishikawa diagram /Fishbone diagram the Check Sheet the Flow Chart the Histogram the Scatter Diagram the Control Chart • • • • • 3) 4) 5) 6} 7)
  • 7. 1) Pareto Chart • Pareto charts are useful for separating important from the trivial. the • Named after Italian economist and sociologist Vilfredo Pareto {1848-1923). Was promoted by Dr.Josep Juran. • Pareto charts are important help an organization decide because they can where to focus limited resources. • On a Pareto chart, data are arrayed along an X-axis and a Y-axis.
  • 8. Example • In a factory, Only20% of problems will produce 80% 80% 20% of of of defects. defect's cost will be assigned to only the total number of defect types • occurri• ng. So, 80% of defect costs will spring 20% of total cost element . •
  • 9. Purpose of Pareto • Pareto can show you where to apply your resources by "revealing few from the trivial many".. • ➔(Highlight few most important issues out of many)
  • 11. Pareto Chart Figure 15-1 represents and All others. 75% sales are from 2 customers; A,B All ot hers include many more customers brings insignificant sales (>5%) Which customers should be kept happy? D, E • customers A,B, C, • • but •
  • 12. Pareto Chart 100"% 90% 0"% 70% 60"% 50", 40"% 0"% 20"% 900 I 800 + 1 700 a 3 60 0 • U ) -- (I) a Go I 500 400 300 200 100 [] • b h l h d a d 55• Up 36- 45 26-- 35 46• 55 18• Figure 15-2 Swift V-12 Sales by Age Group 25 Customer Age Group
  • 13. Pareto Chart Figure 15-2 shows sales of particular model automobile by age group of the buyers. • of • The manufacturer has limited advertising. budget in • The chart reveals the most logical choice to target to advertise. Concent rat ing on advertising on 26-45 age will result in the best return of investment. (75%) • The significant few ➔26-45 age • • The insignificant many are those under 26 & above 45
  • 14. Pareto Chart • Figure 15-3 80 70 90 80 - ~ 60 6 - - 50 40 30 20 10 0 U) o o - ¢ 1i- o0 3 q cr Part Failed Miswire Incorrect Part PC Bd Short PC Bd Open AII Others
  • 15. Pareto Chart • Figure defect All the 15-3 shows 80% of the cost was related to 5 causes. other (about 30 more) were insignificant. • • The longest bar ($70k) accounted for 40%, if solved, immediate reduction in rework cost will happen. After eliminate the longest bar, the team sorted data again to develop level 2 Pareto Chart Read page 484-489 for further understanding •
  • 16. Pareto Chart • Figure 15-4 • _ ------- 45 40 ' ! 90 80 70 60 50 40 30 ? ( IO ( - I l t «4 t m I I t ) « · ) ' 0 f 0 t E D ( I + ' - ) I ' I tt ( t IO 't) I l I f [ l o (p / w p Mt II tolny A I L ( )1 /of Helo yt YI J II
  • 17. Steps in Constructing Pareto Chart 1. 2. 3. 4. Select the subject of the chart Determine what data to be gathered Gather the data related to the quality problem Make a check sheet of the gat hered data, record total numbers in each category. Determine total numbers of nonconformities, calculate percentage each. Select scales of the chart Draw PARETO Chart from largest category to smallest. Analyze the chart the 5. 6. 7. 8.
  • 18. ) Cause and Effect Diagrams/ Ishikawa Diagrams
  • 19. Cause and Effect Diagrams • Use to identify and isolate causes of a problem. Developed by Dr. Kaoru Ishikawa. (1915-1989) • Also called Diagram. Ishikawa Diagram/ Fishbone
  • 20. Cause and Effect Diagrams • Benefits; -Creating the diagram - enlightened, instructive process. - Focus a group, reducing irrelevant discussion. -Separate causes from symptoms -Can be used with any problems
  • 21. Cause and Effect Diagrams ¢ C A U S E C A U S E C A U S E i w E F F E C T I Figure15-8 BasicCause-and-Effect orFishboneDiagram I C A U S E I C A U S E C A U S E
  • 22. 6 Common major factors Diagrams in Ishikawa 1. 2. 3. 4. 5. 6. Man (Operator) Method Measurement Material Machine Environment
  • 24. Cause and Effect Diagrams 15-8, the spine points to the • From figure effect. The effect is • • the problem we are interested in. The lower level factors affecting major factor branch. Check Figure 15-7 to see whether the major • causes can be identified.
  • 25. Cause and Effect Diagrams • E,g: Machine soldering defects - Six major groupings of causes are; • • • • • • Solder machine itself Operators Materials Methods/procedures Measurement of accuracy Environment
  • 26. Cause and Effect Diagrams MACHINE OPERA TOR attitude attention training skill - MA TERIALS handling solderability maintenance vendors - ◄ ollor - storage age s .,, ;. ) , e o o t a i a « o n ',parts flux u wt /it I [ l I t t I l" humidity waveheight temperature waittime partprep preheat conveyorangle con " .s S p peed lighting roomtemp cleanliness instruments h f l , calibration skill ) fluxtype lighting ' ing pollution ENVIRONMENT train MEA'UHL M ENI specific gravity Figure15--10 ComplotodCauso-and-EttoctDia@rm
  • 27. Cause and Effect Diagrams • Normally created by teams to brainstorm the cause/effect. Completed diagram reveals factors & relat ionship which not been obvious. Some problems previously were isolated now can identified. Therefore, further action shall be taken. Cause and Effect Diagrams serve as a reminder. • • be • •
  • 28. FIVE WHYs The '5 Whys' is a question-asking method used to explore the cause/effect relationships underlying a particular problem. Objective: To determine a root cause of a defect or problem. The technique was originally developed by Sakichi Toyoda (1867-1930)and was later used • • • within Toyota Motor Corporation during the evolution of their manufacturing methodologies. • Part of Toyota Production System activities.
  • 29. of 5 whys Example • • • My car cannot start. (the problem statement) Why? Why? why) Why? Why? - - The The battery is dead. (first why) alternator is not functioning. (second • • - - The The alternator alternator belt has broken. (third why) belt was well beyond its useful service why) Why? - life and has never been replaced. (fourth • I have not been maintaining my car according to the recommended service schedule. (fifth why, root cause) This example could be taken further to a sixth, sevent h, or even greater level.
  • 30. How To Complete The 5 Whys 1. Write down the specific problem. Describe it completely. It also helps a team focus on the same problem. 2. Ask Why the answer down problem happens and write the below the problem. 3. If the answer problem that doesn't identify the root cause of the you wrote down in step 1, ask Why again and write that answer down. 4. Loop back to step 3 until the team is in agreement that the problem's root cause is identified. Again, this may take fewer or more times than five Whys.
  • 31. 5 Whys Examples Problem Statement: Customers are unhappy because they are being shipped products that don't meet their specificat ions. 1. Why are customers BEING SHIPPED BAD PRODUCTS? Because manufacturing built the products to a specification that is different from what the customer and the sales person agreed to. 2. Why did manufacturing build the products to a different specification than that of sales? - Because the sales person expedites work on the shop floor by calling the head of manufacturing directly to begin work. An error happened when the specifications were being communicated or written down. 3. Why does the sales person call the head of manufacturing directly to company? - Because the "start work" form requires the sales director's approval before work can begin and slows the manuf acturing process (or stops it when the director is out of the office). start work instead of following the procedure established in the 4. Why does the form contain an approval for the sales director? Because the sales director needs to be continually updated on salesfor discussions with the CEO.
  • 33. Check sheets • Many organizations: They are :"DATA RICH, INFORMATION POOR" • Check sheet can applications. be a valuable tool in wide Purpose: To make it easy to collect data for specific purposes or to convert into valuable inf ormation. •
  • 34. E.g; Weekly Summary of Shaft Dimensional Tolerance Results Shaft length: Week of 7/11 Length (Spec: 1.120-1.130") Date Date Date Length Length Rem 11 11 11 11 12 12 12 12 13 13 13 13 14 14 14 14 15 15 15 15 1.124 1.126 1.119 1.120 1.124 1.125 1.121 1.126 1.123 1.120 1.124 1.126 1.125 1.126 1.126 1.122 1.124 1.124 1.124 1.123 1.128 1.128 1.123 1.122 1.126 1.127 1.124 1.124 1.125 1.122 1.123 1.123 1.127 1.129 1.123 1.124 1.121 1.127 1.122 1.122 11 11 11 11 12 12 12 12 13 13 13 13 14 14 14 14 15 15 15 15 11 11 11 11 12 12 12 12 13 13 13 13 14 14 14 14 15 15 15 15 1.123 1.125 1.122 1.123 1.125 1.125 1.125 1.127 1.121 1.118 1.125 1.124 1.124 1.125 1.124 1.122 1.123 1.123 1.122 1.121 • Figure 15--11 Weekly Summary of Shaft Dimensional Tolerance Results Note: This is not a check sheet.
  • 35. Check sheets Figure 15-11 reports how the works produced relates to the shaft length specificat ions. • being limits 1.120 waste! is the check - 1.130 • Machine setup Outside range So Figure 15-12 inches. • sheet set up to display useful information. It produces histogram. •
  • 36. Chec k S heet S h a ft le n g t h : W eek o f 7 / 11 (Spec: 1.120--1.130) 1.118°· 1. 119° 1.120 13 11 11 13 .... Out of Limits 1.121 1.122 1.123 1.124 12 1315 15 11 11 13 14 14 15 15 15 11 11 11 13 1313 14 15 15 15 11 11 12 12 12 1313 14 14 141515 15 1212 12121313 14 14 1.125 11 12 12 13 14 14 1.126 1.127 1.128 1.129 1.130 1.131°° 1.132°° 12 12 14 15 11 11 • 14 Enter day of month for data point. Figure 15--12 Check Sheet of Shaft Dimensional Tolerance Results
  • 38. Flow Chart • A flowchart is a type of diagram that represents an algorit hm or process, showing the steps as boxes of various kinds, and their order by connecting these wit h arrows
  • 39. Flow Chart Pluginlamp El A simple flowchsrt representing s c r a s s far d=sling with s nan-functioning lamp.
  • 40. Example of the flow chart symbol Flcwchart • Name (Alterrates) P r e s s Description 5ymbol An nnratirn nr artinn step. A start or sop pIn: In a process. Iermmator ) 0 D t _ t _ LI Aques:ion or banch in the proces, Decision A waiting pcriod. I Aterrte Process A formally defired sub-process. An alternate to the normal process step, Indicates data Inputs ard outputs to anc from a process. Dacumert Adocument or report.
  • 42. Histograms • Used to chart frequency of does something happen?) occurrence. (How often processes: attributes • Commonly associated variables with and DATATYPES EXAMPLES Has/ has not Attributes Good/ bad Pass/ fail Accept/ Reject Conform / non-conform Measured values (Dimension, weight, voltage, surface, etc.) Variables
  • 43. Histograms • • • Attribute data: Go/no go information. Variable data: measurement informat ion. Looking at Figure 15-14, we are using attributes data; either But, it to the they passed or they failed the screening. does not reveal about the process cont ribut ing adjustment . • • Also, does not tell the robust process. This is why variables data is needed.
  • 44. Histograms • Figure (Spec: 15-14 : Shaft Acceptence: 1.120-1.130) week of 7/11 Date 11 12 13 14 15 Total Accepted 11 12 11 12 12 58 Rejected 1 0 1 0 0 2
  • 45. Histograms and Statistics • Example: textbook - page 500 BEAD EXPERIMENT There are 900 white beads, 100 red beads =1000beads 1. 2. The beads mixed thoroughly. 50 beads are drawn at random. - Count how many Check mark is entered in histogram. red beads. - 3. 4. All the beads are put back into container and mixed again. Repeat Step 1 ➔Step 3 The process does not change, but the output changed! If these steps are taken over and over, Histogram as in Figure 15-15 occur will
  • 46. Histograms . £ and Statistics '10 25 20 15 I'll 0 a E cU 0 6 .... Ill 10 . 0 I E • I [ z 5 0 I i I I r ' : 1 I I Figure 15--15 roquency Distribution of Red Hoads in Samples 1 5 6 7 2 3 4 9 10 8 Number of Red Beads in Sample Sampleswith O red beads Samples with 1 red bead Samples wit h 2 red beads Sampleswit h 3 red beads Samples with 4 red beads Sampleswit h 5 red beads Sampleswith 6 red beads Samples with 7 red beads Samples with 8 red beads Samples with 9 red beads Samples with 10 rod boads Total samplos takot 0 1 3 9 19 31 21 11 3 2 0 100 1 5 1 Figure Data on /tot Itontdn In {amplo
  • 47. Histograms and Statistics • The flatter and wider the frequency distribution curve, the greater variability. Taller and narrower the curve, variability. - 2 things in process variability; • Standard deviation, a •Mean,µ the process • the less process
  • 48. Histograms and Statistics • Mean is the sum of the observations divided by the number of observations Also describes the central location of the data in the chart, • - Standard Deviation describes the spread or dispersion of data. Calculating the Mean, µ = X : n X=product of the number of beads in a sample of samples containing the number of beads. times the number *See Figure 15-17b, page 503 for further understanding.
  • 49. 1 4 2 3 5 6 Measured data from Figure 15--16 # of Red Beads 0 1 2 3 4 5 6 7 8 9 10 # of Samples • 0 1 3 9 19 31 21 11 3 2 0 n = 100 Figure 15-17a Raw Data from the Colored Bead Experiment (see Figure 15--16)
  • 50. Histograms and Statistics 1 2 3 Mu ltiply Co l by Col 2 4 5 6 Measured data fror Figure 15--16 1 # of Hed Beads 0 1 2 3 4 5 G 7 8 9 1 0 # of S a m p le s X Value 0 1 3 9 19 31 21 11 3 2 0 100 0 1 6 2 7 76 155 126 7 7 24 18 0 X = 5 1 0 • n -- = X : n =510 : =5.1 100 Figure 15--17b Calculating Values of X and 2X
  • 51. Histograms and Statistics 2 6 Sum of Distance? 1 4 Deviation from 5 Deviation squared (Col 4? 3 Multiply Col by Col 2. Measured data from Figure 15--16 1 - ) (Col 1 (Col2 Col5 ) # of Red Beads # of Samples d? X Value d -5.1 - 4 . 1 -3.1 -2.1 1 . 1 -0.1 0.9 1.9 2.9 3.9 4.9 0 1 6 27 76 155 126 77 24 18 0 2 X = 5 1 0 0 16.81 28.83 39.69 22.99 0.31 17.01 39.71 25.23 30.42 0 1 2 3 4 5 6 7 8 9 10 0 1 3 9 19 31 21 11 3 2 0 100 26.01 16.81 9.61 4.41 1.21 0.01 0.81 3.61 8.41 15.21 24.01 • 0 221 p = = 2d? Figure 15--17c Completed Deviation Data Table
  • 52. Histograms and Statistics Deviation, a • Calculating Standard o=[d/(n-1) d = The deviation of any unit from n = the number of units sampled. the mean ■ From Figure 15-17c, ■ n(100) a=/2MIR1 o=V221799 = 1 . 4 o = 1.49, 20 = 2.99, 30 = 4.47
  • 53. I I 30 25 I I I 0 11 a m I E 20 I I I cU 0 - 15 I 1; I o I • I,,. m I I n 1 0 E I z 2 I 5 I I I I II I I 3 I .I' i I y d4 • I I 8 l I 0 II I 2 I 1 1 5 I 6 • I I 7 I I 9 I 0 I r 1 I 10 t I I ~ . - + a . -26 .- -30 - +20 ,_ - .~ - +30 - -~ -· Jl Red Beads in Sample 15-18 Figure Application of Standard Deviation Calculations to Red BeadHistogram
  • 54. Shape of Histograms A F K ..,,,. '1 L B G _ / c I ~ ~ llll ucL L c u -- LCL ucu UCL E J L c u Figure 15-19 Histograms of Varying 'hapes H
  • 55. Figure 15-19 Process A is much tighter, normal favorable. Process B greater variances. C and Dare not cent ered, skewed product will be lost . • distribution, • • to left and right, • F - someone has discarded. Take out the reject, and only collect data within acceptable range. G -the vendor has screened out the parts, took out the best to other customers. H - a proper normal distribut ion between upper and lower limit s. I and Jskewing! Signif icant loss of product ... K until P shifting ... why??? • • • •
  • 57. Scatter Diagram • A scatter diagram is a tool for analyzing relationships between two variables. One variable is plotted on the horizontal axis and the other is plotted on the vertical axis While the diagram shows relationships, It does not by itself prove that one variable causes the other. • •
  • 58. Scatter Diagram • Scatter diagrams will generally show one of six possible correlat ions between the variables:
  • 59. Scatter Diagram • 1) Strong Positive Correlation - The value of V increases as the value of X increases. clearly i d , N e t t i t . t h M t , o - - - - - - - - - - - - - - oO. 2 4 6 X
  • 60. Scatter Diagram 2) Strong Negative Correlation - The value of V • decreases as the value of X increases clearly 6 .5 - - - - - - - - - - - - - - - - - - _ ; . _ • d A l t l •a d 4 l l l l ] te - l l l t d . l h 0 - - - - - - - - - - - - - 2 4 0 6 Xx
  • 61. Scatter Diagram 3) Weak Positive Correlation -The value of Y increases slightly as the value of X increases. t l .. td . • 1 , " } l b s 4 A l p ~ « i - + - - - - - - - - - - - - - 0 4 0 . 2 6 x
  • 62. Scatter Diagram 4) Weak Negative Correlation - The value X of Y decreases ■ Increases. slightly as the value of 6 . · ~ ~ ~ - - - - - $ ' m l b l E l l ] } • 9 f { l s . A l . l b l b . A . a l . A A e 0 t t l flt• 2 4 0 6 X
  • 63. Scatter Diagram 5) Complex Correlation -The value of Y but seems to be related to the value of X, the relationship is 4 3 .5 3 2 . 5 not easily determined ., • • - Y • 2 1.5 1 0 . 5 0 • 0 2 4 6 X
  • 64. Scatter Diagram 6) No Correlation -There is no between demonstrated connection the two variables 7 6 5 4 • • • • Y 3 2 1 0 • $ 4 0 2 6 X
  • 66. Control Chart ---------~-~----------------UCL 2 O 0 •ProcessAve(age ---------------------------LCL o Figure15-27 BasicControlChart Samples ■ ■ Figure 15-27 shows a basic of control chart. Data stay between Upper Control Limit (UCL) and Lower Control Limit (LCL)
  • 67. Control Chart • As long as the plots stay between the limits, and don't congregate on 1 side or the ot her of the average line, the process is in STA TISTICAL CONTROL. Common causes/chance: Small random changes in the process that cannot be avoided - but still in statistical control Varying out of the centerline of the process Result of the sum of numerous small resources of natural variation that are always part of the process. Eg; Setting on machines, environment, methods etc. Special causes/Assignable causes: Variations in the process that can be identified as having a specific cause. A plot point breaks through UCL or LCL OR there a several points in a row above/below the lines. Result of the factors that are not part of the process and only occur special case. Eg: New operator involve, electricity blackout, shipment faulty of material etc. • • is
  • 68. Control Chart • Only after the special has been identified, it should be corrected, and restart the process. How to correct? (By eliminating root cause) Control chart is usually operated under • • Statistical Process Control (SPC) - Chapter 18.
  • 69. Control Chart Control Chart - Statistical Process Control (SPC) • What is SPC? SPC is a statistical method of separating variation resulting from special causes resulting from natural causes, to eliminate the special causes, and to establish and maintain consistency in the process, enabling process improvement.
  • 70. Control Chart • Common factors that can affect output are; 5M's Machines and environment employed Material used Methods (work instructions) Measurements taken Manpower (People who operate the process) If these factors are perfect; th is means; 1. Environment facilitates quality work and there are no misadjustments in the machines No flaws in materials Follow work instruction accurate and precisely Accurate and repeatable measurements People work with extreme care - follow instructions extremely well 2. 3. 4. 5.
  • 71. Control Chart n g . R Sum Ex Subgroup # - Mean Value X Measured Values 1 1 5 s Date 4 2 7 3 4 8 9 0 7/6 7/6 7/6 7/6 7/7 7/7 7/7 7/7 7/8 7/8 7/8 7/8 101 103 103 96 99 101 100 97 102 100 101 100 101 98 102 99 99 100 98 100 101 100 101 98 102 98 100 97 100 100 98 98 101 101 98 102 1002 1006 1007 993 1004 999 1000 995 1003 998 1001 1000 100.2 100.6 100.7 99.3 100.4 99.9 100.0 99.5 100.3 99.8 100.1 100.0 1 2 3 4 5 6 7 8 9 10 11 12 98 100 101 99 102 103 103 101 97 105 99 103 102 101 99 102 100 99 101 102 100 99 98 101 99 100 100 101 103 99 99 99 103 98 104 99 100 104 99 102 101 98 100 96 98 102 100 100 98 102 102 98 102 101 99 99 100 97 98 100 101 99 98 100 98 100 102 100 102 97 100 99 100 101 103 99 100 99 100 103 99 99 102 98 4 6 5 6 5 5 5 7 6 8 6 5 I I ■ I 68 Total 1,200.8 X = 100.067, =5.667 k= 12, R , Figure 18-5 Initial Data for Precision Spacer Process
  • 72. From Figure 18-5, • [ G ; Average Range, [R]is Average of subgroup range, R is R - 2 « + R ==(Max value of x - Min value of [so.=68=12=5.667] The average, r-2r= k - x == number of sub groups == subgroup average x) = 1 2 0 0 . 8 s o . = = 1 2 = = 1 0 0 . 0 6 7 A2is the confidence level data, the larger the value for the of A, the farther the control limits. UCL=x+A,R LCL=x-A,R
  • 73. Control Chart Factors for x charts Factors for R charts Number of data points in subgroup LCL 0, UCL 0, • (n) 2 3 4 5 1.88 1.02 0.73 0.58 0 0 0 0 3.27 2.57 2.28 2.11 0.48 0.42 0.37 0.34 0.31 0 0.08 0.14 0.18 0.22 6 7 8 9 10 2.00 1.92 1.86 1.82 1.78 I II 11 12 13 14 15 0.29 0.27 0.25 0.24 0.22 0.26 0.28 0.31 0.33 0.35 1.74 1.72 1.69 1.67 1.65 I 16 17 18 19 20 0.21 0.20 0.19 6.19 0.18 0.36 0.38 0.39 0.40 0.41 1.64 1.62 1.61 1.60 1.59 Figure 18--6 Factors Table for x• and R-Charts
  • 74. • From Figure 18-6; n=10, so UCL and LCL in x-bar chart is; UCL =100.067 +(0.31x5.667) ==101.82377 X LCL- ==100.067-(0.31x5.667) ==98.31023 X And UCL and LCL for the values in R chart; UCL,= D,R =1.785.667 = 10.08726 LCL,=D,R=0.22x5.667 =1.2467
  • 75. (a) Figure 18-7 Chart 11 03 --- ' II r e - - - .... --- 102 - - - -, I - -- - I - - - - - ... - - - - - - . ' - - - - _, - - - - -i- - - - - - · - - - - - - - - UCL, « a) 0 cU h ->-- ' y • 101 -~ 1 t I"' ' / I V k x • 100 0 2 / _.,... .. I _,... 9 . •0 0» 99 -~ E - - - 7 -- 0 -.,. -- - ~ - - - - - .- - I -- - ---- -- ·- - - - - - - . - : - - - - - - ~ - ,... - ~ - LCL, - - - - - = = % 98 I -- 1 97 a I 5 I 10 2 3 4 6 7 8 9 1 1 12 1 3 14 15 16 17 18 19 20 21 Subgroup Number
  • 76. 18-7 (b) Figure mCh a r t 12 11 10 9 8 7 6 5 4 3 2 1 0 ± £ ; ~ I - - - - - - - • - - - - - • - . 4 UC L w « I - F ± ~ ' I F # ~ - ; 8 q c I I s c • I - er V ""'' / - r ."- R X I I """ ._ 0 ....... " ' I '-. I =E c #/ # i± ± # c 2 G ,,_ - - -,- - - - - - - - -- - - « . . - - - - - - - - - - - ·- - - - - - - - - - - - - - - L C L , ' - - - - ' 5 ' d 10 11 2 3 4 6 7 8 9 12 13 14 15 16 17 18 19 2 0 2 1 1 Subgroup Num ber Figure 18--7 x- and FR-Charts
  • 77. Control Chart • Suppose that we have been setting up a new process (not stable). in Figure 18-8 • It would look like 5 -g 00 LCl - - - - - - - Jc - • - - - - - - - - - - - - - - - - - - - - - - - - - I I 1 2 3 4 5 6 7 8 9 10 1 1 12 13 14 15 rtuure 18--8 hart tor an Unstable Process Subgroup Number
  • 78. In Figure 18-8; • • • Subgroup 7 was out of limits. Can we ignore? NO! Because-control limit has been calculated with the data inclusive of special cause event. (E.g: result of untrained operator etc) We MUST determine and eliminate the cause. After eliminate it, flush out SUBGROUP 7 and recalculate the process average (x-bar} and the control limits. We will find narrower limit, Figure 18-9 • • •
  • 79. Figure 18-9 c 0» ~ UCL- x q o • x < > 9 c 0 LCL, ::j 0 ) + lSubgroup Number 10 11 1 2 13 14 15 1 2 3 4 5 6 8 9 ruuro 18--9 II Mo w , Narrower Limits o I'onotrated Note: Subgroup 7 deleted • If still penetrates the new out of limits, repeat the same action .. Until the points are all well between the limits.
  • 80. Control Chart • X-bar chart is used to show the center of process measurements (accuracy). R chart is to show the spread of the data (precision). the • • Without Range, it would not be able to understand the PROCESS CAPABILITY of the chart.
  • 81. Control Chart-Advantages of a Stable Process • Stable process?? It is a process that common variation. Advantages; exhibits only • Management knows the process capability, so they can predict cost well. Productivity MAX,cost MIN Management can measure effect faster and more reliable. Got data if management wants to alter spec limits. Stable process is basic requirement for process improvement efforts. 1. 2. 3. 4. s.
  • 82. 7 NEW QC TOOLS • A committee for developing QC affiliated with JUSE was set up 1972. tools in April • Their aim was to develop QC techniques for use by managerial level and staff. • In January 1977 the committee announced the results of its research in
  • 83. 7 NEW QC TOOLS the form of a new set of methods New QC Tools'. The tools are:- called 'The Seven • • • • • • • 1) Affinity Diagram 2)Interrelationship 3)Tree diagram diagram 4) 5) 6) 7) Prioritization Matrix Matrix Diagram Process Decision Process Chart (PDPC) Activity Network Diagram
  • 85. Quiz • Define and Rule 1 and Show examples (Diagrams picture) Rule 2 to show the process is not in statistical control.
  • 86. Rule 1: A process is not in statistical co ntrol if any subgroup statis tic falls outs i de of the control limits. This point is marked with an " X" directly on the control chart. - # 4 - - l / p p e f f o p ' f f ( l Lifnyt Zone A Zone8 i i . i i i ' i i . « i i T Zone C ZoneC ZoneB ZoneA - J } s t f&ft@f[ft . i i . . i i . - - - - .25 ) L t @ - f [ -[ --f } f - f ? t Lfflf - 0 5 15 1 10 20 F igur e 15-8 Rule 1 - - Lack of Statistical Control
  • 87. Rule 2: A process successive is not in statistical control subgroup statistics fall in one if any two out of three of the A zones or beyond second of the two points on the same side of the centerline. The in or beyond zone A is marked with an "X." - lL/pp@ff'ft!fpllffflt ZoneA Zone B Zone C Zone C ZoneB Zone A . . . . . . . . . . e l l . L 0 4 Rf f'(flfol[fit 15 1 10 5 20 25 Rule 2 L a ck of Statistical Control Fgiure15-9
  • 88. control if four out of five successive Rule 3: A process is not in statistical subgroup statistics fall in one of the B zones or beyond on thesame sidteeof1 the center·rlli;ne . + th .e ..£f,our ~t1 hp o i:.nt marke ed el w i;t h an y • " 0On.l1.y :i.s Zone B Zone C ZoneC Zone B Zone A h i . f l # f l . h f [ t f l e f i f e - I L _ Q t 4 t f f o f t [ r t ] [ f i t 10 1 5 15 20 25 ' Figure 15-10 Rule 3 -- Lackof Statistical Control
  • 89. Rule 4: A process is not in statistical in zone C on either side of is marked with an "X." control if eight successive points fall the centerline. Only the eight point -lJD9per font!fol[Ifft!f Zone A Zone B ZoneC Z o ne C Zone B Zone A = l s # t e l # # h f ; f f ' f ] ] f f = = ' Lower fontfolLirjt 1 10 25 20 15
  • 90. Statistical error: Type I and Type II • Statisticians speak of two significant sorts of statistical error. Type I e rror: An incorrect decision to REJECT something when it is true. - False alarm Type 1 1e rror: An incorrect decision to ACCEPT something when it is true. - Oversight • •
  • 91. OUTSIDE CONTROL LIMITS [INSIDE CONTROL LIMIT ype error ecause presen Chance cause present ] Actual condition Innocent Not innocent FalsePositive(i.e. guilty but not caught) Type l error - Judged "innocent" True Positive Test result False Negative (i.e. innocent but condemned) Type ll error Judged "not innocent" True Negative
  • 92. Common Use Control Chart for attribute data (Counted values) P chart - No. of defects in samples of varying size percentage of fraction. (e.g anywhere defects can be counted) • as a • • np chart- no. of defective pieces in samples size. C chart - No. of defects in a single product . blemish, deform, scrat ches in one part) of fixed . • (e.g: • U chart - No. of defects per-unit area. (Carpet area, lenght)
  • 93. Exercise 1. Control charts for X and RR are to be established on a certain dimension part, measured in mm. Data were collected in subgroup sizes of6 and are give below. Determine the trial forX-barandRchart centerline and control limits SUBGROUP NUMBERS 1 2 3 4 5 6 7 8 9 10 1 1 12 20.40 20.41 20.45 20.34 20.36 20.42 20.50 20.31 20.39 20.39 20.40 20.41 20.40 0.39 0.36 0.34 0.36 0.37 0.33 0.38 0.35 0.38 0.33 0.32 0.34 0.30 13 14 15 16 1 18 19 20 21 22 23 24 25 - X 20.35 20.40 20.36 20.65 20.20 20.40 20.43 20.37 20.48 20.42 20.39 20.38 R 0.34 0.36 0.32 0.36 0.36 0.35 0.31 0.34 0.30 0.33 0.30 0.37
  • 94. Exercise 2 samples: the Consider Sample following 20 15-1 Observations 38 22 31 33 20 24 34. . 30 34 33 51 12 19 17 26 17 21 35 16 31 1 2 3 4 5 6 7 8 9 10 11 12 1 3 '·· 14 15 16 17 18 19 20 24 41 40 37 43 24 37 40 39 41 36 22 50 21 7 2, . 3 20 45 16 13 42 32 38 22 46 27 31 32 35 55 22 14 36 29 33 40 23 28 32· ' 23 59 22 40 52 32 29 4 46 20 25 4.4. 24 52 21 31 28 25 52 27 50 15 60 32 46 54 42 33 47 9 18 27 29 21 30 42 34 41 22 27 29 ' limits for the X and R charts. the control a. Determine ia fi n - d' i I} C ..:I L a.d ..,,r.,l ;,i'!. W 'W "h -a! d 'lik t .G .,-.,d ..· n v yO au l c <o n I c lI 1 K ·--t 1e d ... bro u11 l - it 1 1 1 :h l t.~ 'l I''.)I~ 0 O [I'Lt ""' X b. 1 N ~ U process?
  • 95.
  • 96. Quality Function Deployment • Defined as: - A systematic method for transferring customer wants/needs/expectations into product and process characteristics
  • 97. QUALITY FUNCTION DEPLOYMENT Quality Function Deployment • ➔ ➔ Voice of the customer House of Quality QFD: An approach that integrates the "voice of the customer" into the product and service development process.
  • 98. House of quality A technical correlations engineering metrics A relative importance I _ I ' -! _I _ I 1 relationships between customer needs and engineering I I I I I I I I I I I I I I - T - - r 7 - - ; • benchmarking on needs I I I I I I I customer needs - T - - r 7 - - ; • - I- '- ' ' ' ' ' - - - - ' ' ' -- - - ' ' - metrics _ I I I I I _ I I I I e g s e g g g I I I I I ' ' ' } A - ' } A ' -'• I I I I I I I - - T - - r 7 - ; • I I I I I I I I I I I target and final specs
  • 99. QFD & House of Quality Identify customer wants Ident ify how the good/ service will sat isfy customer wants Relate the customer's wants to the product's hows Identify relationships between the firm's hows Develop importance ratings Evaluate competing products • • • • • •
  • 100. Example Facial Foam 100ml : QFD • • • A : B : C: Nivea Visage (Biersdorf L'Oreal (Paris) Hamburg) Biore (Kao) Facial Foam C Facial Foam A Facial Foam B
  • 101. QFD Details I I I I Relationship ? s o n g Posisve Product Characteristics _ :..::::.-::: 0 £ - " = © c CJ - -c • u ""'O c ±-' V Positive <? c 0 :..::::.-::: c CD ..0 © h • o 0.. £ ( / ) b l 4 0 ) · C - , X x Negative E -0 h c c - ?) stong Negatve o · - ·b -l o E G © - > .= I CD ; -c, © cr c Customer Requirement Membersihkan dam menghaluskan kulit Menghilangkan sel ulit mati Mengecilkan pori-pori Mer utihkan/mencerat kan kulit Tidal menyebabkan alergi TOTAL c © er Competitive Evaluation C 0-- -0- V -0- B 2 C 2 C 2 B 2 C 2 A 3 B 3 A 3 A 3 A 3 V X x 20 V ' - 1 4 A 4 B 4 C 4 B 4 5 ✓ -- 20 V 1 5 2 V 0 V 25 1 5 V i V 25 1 5 0 X Xx V 10 100 - - 1 Facial 5 RM 16.750 Foam 100ml A: Niwea Visage (Beiersdotf Hamburg) B: L'Oreal (Paris) 32.000 14.600 C: Biore (Kao)
  • 102. r . I I • - I : . 1 . • • a d a a < @ 2 > - £ X < d > . (< ✓ > 3 < .8. X 1 $ .% ...... > X X L I • Product Ch aracte ri sti cs Relationship ( s t a n o P o s e , - ? =-. c ,1% L - - / c c z , T a 4 ; a .15 --' - £ c 5E c . 2 -£ a 5z V c c -c Fasitivu c n e .c - c x Negative = = ,T3 ± •- ()y sans Negate - c E , 1 £ =- c d 7 ._ CL c CL € cr- c C u s t o m e r R e q u i r e m e n t hfemnbersihkan dar mnenghaluskan kulit tMenghilangkan sel ulit m ati Mengecilkan pori-pori t f e r u t i h k a mime n c e r a h k a n k u l i t T id a k m e r r ye b a bk an alergi I -c 1 Cr Competitiwe Ewaluati0nr c 0 - - 0 - - - -0-- A 3 E 3 A 3 A 3 A E 2 C 2 c 2 B 2 c - " V x 20 V - · 1 4 A 4 El 4 c 4 El 4 0 0 m l 5 ✓- - ' - 20 1 5 - 0 - " 25 1 5 2 ✓- · X I V 2 - - 25 1 5 - ✓- - I X " - 1 0 1 2 3 5 RM I Facial Foam 1 I I 1 00 T O T A L liwea wWisage ( B e ie r s d o r f H a m b u r g white pure m icro act ive anti gentl du llr white ning sc r ub anti cdulln ess nourl s h in g scrub apprc wed teste d asian A: A 4'#, Competitiwe Ewaluatiu 16.750 e e s s 4'#, El L'Oreal (Paris) 32.000 : crush able c M i C & E M i C : E ir e ( K a 0 } 14.600 I I l ll
  • 103. Tabel Score Hasil B Hasil B 0,40 0,60 1,00 0,50 0,40 2,90 A A 0,60 0,80 0,75 0,75 0,30 3,20 C C 20 20 25 25 10 3 4 3 3 3 16 2 3 4 2 4 15 4 2 2 4 2 14 0,80 0,40 0,50 1,00 0,20 2,90 I I I I I I I To conclude : • ProductA (Nivea Visage) Facial Foam has the highest score among others. Means this product is the best chosen by customers.
  • 104. Benefit s Of QFD • • • • Customer Driven Reduces Implementat ion Promotes T eamwork Provides Documentat ion Time
  • 105. Quality Function Deployment (QFD) • QFD seeks to bring the voice of customers into process of designing and developing a product the or . service. QFD can point out areas of strength as well as weaknesses in both existing or new products. When a company uses QFD, they stop developing products/ services on their own int erpretat ion. • •
  • 106. Main benefits of QFD 1. - QFD gives information which is then customer requirements. Customer focused translated into a set of specific 2. Time efficient -- Time is not wasted on have no value to customers. Teamwork oriented - All decisions are developing features that 3. based on consensus and involve in-depth Documentation documentation. discussion and brainstorming oriented - QFD forces the issue of This document changes as new information 4. gained. Having up-to-date information about customer requirements, will be very helpful.