The solution of the problems 2.1 and 2.2 of 9th class physics. https://youtu.be/mZLOfpdtDxs for video description.

1. Class 9th Physics
Chapter#2, Kinematics
Problem #2.1-2.2
By: Muhammad Zeeshan
Easy learning

2. Given data: Velocity (V) = 36Km/h
=
𝟑𝟔𝟎𝟎𝟎
𝟑𝟔𝟎𝟎
= 𝟏𝟎 𝒎/𝒔
Time (T) = 10sec
Find. Distance S=?
Formula: S=VT
S=(10)(10)
𝒎
𝒔
× 𝒔
S= 100m
P#2.1. A train moves with a uniform
velocity of 36Km/h for 10s. Find the
distance traveled by it

3. Data: initial velocity Vi =0
Distance (S) = 1Km = 1000m
Time t =100sec
Find: Final velocity Vf=?
Formula: Vf=Vi+at -------- (i)
We need the value of “a” so we first find it then put in this
equation.
For a, S=Vit +1/2 at2 ⇒1000=0+1/2(a)(10000)
a=𝟐 ×
𝟏𝟎𝟎𝟎
𝟏𝟎𝟎𝟎𝟎
= 𝟎. 𝟐m/s2
Now put values in eq. (i)
Vf = 0+(0.2)(100)
Vf = 20 m/s
P#2.2. A train starts from rest. It moves through
1Km in 100s with uniform acceleration. What will
be its speed at the end of 100s.