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• "Performance Task - Mind Map"
Submitted by:
Imac Andrew O. Antivola
Grade 9 - Understanding
Submitted to:
Jamaica May C. Cruz
Teacher
How to solve
quadratic
equation?
Extracting the
square root
ax²+c = 0
Factoring
Completing
the square
Quadratic
Formula
Differences
They have
different
processes or
techniques for
solving quadratic
equations.
Similarities
They can be
used to solved
quadratic
Equations.
Disadvantage Disadvantage
Advantage
Equations that
are factorable
can be easily
solved by
Factoring.
Disadvantage
Equations that
are not
factorable cannot
be solved by
factoring.
Advantage
Equations that
cannot be solved
by factoring and
extracting the
square roots can
be solved by
completing the
square.
The process is
quite confusing
and cannot be
used if bx is
missing.
Advantage
It can be used
to solve any
quadratic
equation.
It takes a long
time to
compute.
Advantage
Simpliest way
to solve the
equation of
the form
(ax+b) ² = c.
Disadvantage
Equation can't
be solved with
bx if the
equation is
not perfect
square.

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Mind map-in-quadratic-equation

  • 1. • "Performance Task - Mind Map" Submitted by: Imac Andrew O. Antivola Grade 9 - Understanding Submitted to: Jamaica May C. Cruz Teacher
  • 2. How to solve quadratic equation? Extracting the square root ax²+c = 0 Factoring Completing the square Quadratic Formula Differences They have different processes or techniques for solving quadratic equations. Similarities They can be used to solved quadratic Equations. Disadvantage Disadvantage Advantage Equations that are factorable can be easily solved by Factoring. Disadvantage Equations that are not factorable cannot be solved by factoring. Advantage Equations that cannot be solved by factoring and extracting the square roots can be solved by completing the square. The process is quite confusing and cannot be used if bx is missing. Advantage It can be used to solve any quadratic equation. It takes a long time to compute. Advantage Simpliest way to solve the equation of the form (ax+b) ² = c. Disadvantage Equation can't be solved with bx if the equation is not perfect square.