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Derivacion logoritmica
1.
Derivacion logoritmica 3) 𝑦
= 𝑥ln 𝑥 , 𝑥 > 0 ln 𝑦 = ln 𝑥ln 𝑥 ln 𝑦 = ln 𝑥. ln 𝑥 ln 𝑦 = (ln 𝑥)2 𝑦´. 1 𝑦 = 2 𝑙𝑛 𝑥. 1 𝑥 𝑦´ 𝑦 =. 2 ln 𝑥 𝑥 5) 𝑦 = 23𝑥 ln 𝑦 = ln 23𝑥 ln 𝑦 = 3𝑥 𝑙𝑛 (2) 𝑦´ 𝑦 = 3. 1 2 𝑦´ = 3 2 𝑦 11) 𝑦 = 𝑥(𝑥2−1) √𝑥2+1 𝑦 = 𝑥3−𝑥 (𝑥2+1) 1 2 ⁄ 𝑦 = (𝑥3 − 𝑥). (𝑥2 + 1) −1 2 ⁄ ln 𝑦 = ln((𝑥3 − 𝑥)(𝑥2 + 1) −1 2 ⁄ ) ln 𝑦 = (𝑥3 − 𝑥) + ln(𝑥2 + 1) −1 2 ⁄ 𝑦´. 1 𝑦 = (3𝑥2−1) (𝑥3−𝑥) − 2 (𝑥2+1) . (2𝑥) 𝑦´ 𝑦 = 3𝑥2−1 (𝑥3−𝑥) − 4𝑥 (𝑥2+1) Felinny montero dl1200
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