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Large Energy Storage System Eduard Heindl Hochschule Furtwangen University, Germany
Renewable Energy needs storage wind 60% solar 40% supply change source: Lueder von Bremen, EWEC 2009 storage for up to seven days required!
Electicity: Daily Production Base load: coal, nuclear daily production: 1600GWh Problem: how to use this energy 70GW 280GW Hydro Storage capacity in Germany: 40GWh 0h midnight 24h  time „ priceless energie“ solar power, wind power Consumption in Germany 12h high noon
Energy demand:  Joe Public ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
1km
Think Big! 1km 500m 1700GWh
Basic Principle capacity power converter h ,[object Object],[object Object],[object Object],connec t power grid
Construction 1km mine shaft base tunnel, water intake 1. tunnel 1km blast   hole construction road deep well drilling plant
Construction work 1km 1. tunnel lower saw mill wire saw upper saw mill blast hole construction road
Diamond wire sawing Surface 1. Tunnel traction cut surface Diamondwire saw rock drilling holes r
Diamond wire sawing surface 1. tunnel traction Diamond wire saw rock drilling holes r cut surface
Baseplate seperation base-tunnel 2. tunnel traktion sawing string rock drilling holes r cutted rock remaining rock top view!
Rock Bottom Area Separation ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],m a F m a r a 0 =a r +a s h ρ F s p s B s ;T s p s =304bar h=1000m:
Cutting completed 1km 1. tunnel 2. tunnel construction road the wall and the floor of the cylinder are  separated from the surrounding rock
 
Energy Storage Capacity h=r D=2r l=2r Generated surface: M = 2 * π * r * l = 4 * π * r²  (1) Real density ρ 2  = ρ 1  – ρ 3   (2) Potential energy in gravitation field E =  g * m * h  (3) Real mass of cylinder  m = π * r² * 2 h * ρ 2   (4) Eq. 4 and eq. 3 using h = r results in: E = g * π * r² * 2 * r * ρ 2  * r  (5) Eq. 5 condensed: E =  2 π g ρ 2  *   r 4 the power V=4πr³
500 1.700 Beispiel Daily electrical power  production in Germany Energy storage capacity depends on the Radius r Example Source: www.eia.doe.gov/cneaf/electricity/epm/table1_1.html Daily electrical power  production in USA 800
Sealing ,[object Object],[object Object],[object Object],[object Object]
Sealing the Walls rock mass piston 1. tunnel platform sealed wall support column sealing water under pressure Saw line
Closing the Cracks rock mass piston piston 1. tunnel water under pressure wall with sealant ad sealant seal crack
Complete the Sealing rock mass piston piston  1. tunnel water under pressure wall with sealant ad sealing seal crack
Sealing rock mass piston pin joint with sensor seal steel podest water pressure
Water Volume ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Speed of movement ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Piston position fine tuning ,[object Object],piston low pressure sealing about 1 bar Seal low pressure seal low pressure seal high pressure exchange pump x x
Thermal effects ,[object Object],[object Object],[object Object],[object Object],* Quelle: Regierungspräsidiums Freiburg www.lgrb.uni-freiburg.de
Price of the system ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
pump storage power station 0,39 500 100 1.000 example system Price per kWh storage volume (excluding the energy converter) price system radius [m]
0,39 500 100 1.000 day week month year 200€/kW pump storage power station example system system radius [m] price Price per kWh storage volume (using different converters, 200€/kW)
Calculation 157 € /m 1 000 Drilling 821 Total 3 € /m 1 000 Sealing 157 € /m² 100 Seal shield 39 € /m² 10 Sawing 464 € /m 50 000 Tunnel Mio € unit cost per Building
Calculation 2 861 Total 2 040 € /kWh (T=7d) 200 Pumps and Generators 821 Storage system Mio € Cost
Return on Investment DRAFT! Assumption:  there are 100 days (2,400h) where the power could be bought  with a mean price of 20€/MWh and there are 2400h where it could be sold  for 70€/MWh, the other times of the year, there is no activity. The conversion  efficiency is 70% (worst case ) 710 Total  (Q=70%) 1 200 € /MWh (T=100d) 70 Power sell Per year 490 € /MWh (T=100d) 20 Power buy per year Mio € Turnover
Return on Investment ,[object Object],[object Object]
Requirements: Storage Systems ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],source Dirk Uwe Sauer
Maintenance Steps ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Worst case scenario ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Research Topics ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Thank you for your interest! Questions? eduard-heindl.de/energy-storage

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Ultra Large Energy Storage System

  • 1. Large Energy Storage System Eduard Heindl Hochschule Furtwangen University, Germany
  • 2. Renewable Energy needs storage wind 60% solar 40% supply change source: Lueder von Bremen, EWEC 2009 storage for up to seven days required!
  • 3. Electicity: Daily Production Base load: coal, nuclear daily production: 1600GWh Problem: how to use this energy 70GW 280GW Hydro Storage capacity in Germany: 40GWh 0h midnight 24h time „ priceless energie“ solar power, wind power Consumption in Germany 12h high noon
  • 4.
  • 5. 1km
  • 6. Think Big! 1km 500m 1700GWh
  • 7.
  • 8. Construction 1km mine shaft base tunnel, water intake 1. tunnel 1km blast hole construction road deep well drilling plant
  • 9. Construction work 1km 1. tunnel lower saw mill wire saw upper saw mill blast hole construction road
  • 10. Diamond wire sawing Surface 1. Tunnel traction cut surface Diamondwire saw rock drilling holes r
  • 11. Diamond wire sawing surface 1. tunnel traction Diamond wire saw rock drilling holes r cut surface
  • 12. Baseplate seperation base-tunnel 2. tunnel traktion sawing string rock drilling holes r cutted rock remaining rock top view!
  • 13.
  • 14. Cutting completed 1km 1. tunnel 2. tunnel construction road the wall and the floor of the cylinder are separated from the surrounding rock
  • 15.  
  • 16. Energy Storage Capacity h=r D=2r l=2r Generated surface: M = 2 * π * r * l = 4 * π * r² (1) Real density ρ 2 = ρ 1 – ρ 3 (2) Potential energy in gravitation field E = g * m * h (3) Real mass of cylinder m = π * r² * 2 h * ρ 2 (4) Eq. 4 and eq. 3 using h = r results in: E = g * π * r² * 2 * r * ρ 2 * r (5) Eq. 5 condensed: E = 2 π g ρ 2 * r 4 the power V=4πr³
  • 17. 500 1.700 Beispiel Daily electrical power production in Germany Energy storage capacity depends on the Radius r Example Source: www.eia.doe.gov/cneaf/electricity/epm/table1_1.html Daily electrical power production in USA 800
  • 18.
  • 19. Sealing the Walls rock mass piston 1. tunnel platform sealed wall support column sealing water under pressure Saw line
  • 20. Closing the Cracks rock mass piston piston 1. tunnel water under pressure wall with sealant ad sealant seal crack
  • 21. Complete the Sealing rock mass piston piston 1. tunnel water under pressure wall with sealant ad sealing seal crack
  • 22. Sealing rock mass piston pin joint with sensor seal steel podest water pressure
  • 23.
  • 24.
  • 25.
  • 26.
  • 27.
  • 28. pump storage power station 0,39 500 100 1.000 example system Price per kWh storage volume (excluding the energy converter) price system radius [m]
  • 29. 0,39 500 100 1.000 day week month year 200€/kW pump storage power station example system system radius [m] price Price per kWh storage volume (using different converters, 200€/kW)
  • 30. Calculation 157 € /m 1 000 Drilling 821 Total 3 € /m 1 000 Sealing 157 € /m² 100 Seal shield 39 € /m² 10 Sawing 464 € /m 50 000 Tunnel Mio € unit cost per Building
  • 31. Calculation 2 861 Total 2 040 € /kWh (T=7d) 200 Pumps and Generators 821 Storage system Mio € Cost
  • 32. Return on Investment DRAFT! Assumption: there are 100 days (2,400h) where the power could be bought with a mean price of 20€/MWh and there are 2400h where it could be sold for 70€/MWh, the other times of the year, there is no activity. The conversion efficiency is 70% (worst case ) 710 Total (Q=70%) 1 200 € /MWh (T=100d) 70 Power sell Per year 490 € /MWh (T=100d) 20 Power buy per year Mio € Turnover
  • 33.
  • 34.
  • 35.
  • 36.
  • 37.
  • 38. Thank you for your interest! Questions? eduard-heindl.de/energy-storage