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Resource Element = Covered by 1 sub carrier and one symbol period i.e 1 Symbol
Resource Block = Covered by 12 Subcarriers and 6 or 7 symbols(Based on Cyclic prefix)
We can calculate the capacity if we know the Bandwidth allocated, Modulation scheme used and Cyclic
Prefix type.
Consider
Bandwidth Allocated = 5MHz
Modulation Scheme = QPSK(2 its per symbol)
Cyclic prefix used = Normal Cyclic Prefix (7 symbols in a slot)
Capacity = No of bits transferred in a sub frame / Duration of the Subframe(i.e 1milli sec)
Calculation No of Bits transferred in a Subframe
Total number of Resource block in a slot = Bandwidth / (Each subcarrier bandwidth * no of subcarriers in
a Resource Block)
Bandwidth = 5Mhz
Each sub carrier width = 15Khz
No of sub carriers in a Resource Block = 12 (As 12 Subcarrier is 1 Resource block )
Calculation of total no of resource blocks in 5MHz Bandwidth
so Resource block in one slot = 5 Mhz / (15 KHz *12 ) = 27.77 (But used RBs will be 25 for 5MHz
bandwidth)
so Total Resource block in one subframe = 2 * Resource blocks in a slot = 50 RBs
Calculation of total no of symbols/Resource Elements in 5MHz Bandwidth
Total no of symbols / Resource Elements = 50 * no of symbols(REs) in a Resource block
No of symbols(REs) in a resource block = 12 subcarrier * 7 symbols = 84 symbols(REs)
Total symbols(REs ) in 50 Resource blocks = 50 * 84 = 4200 Resource Elements.
****Calculation of total no of bits sent in 5MHz Bandwidth in one subframe ****
In one symbol we can send no of bits at a time which depends on the modulation scheme (like
BPSK,QPSK ,64QAM
BPSK - 1 bit,QPSK - 2 bit ,64 QAM - 6bits in a Symbol/ Resource elements
We will consider QPSK Scheme so in one symbol 2bits we can send.
So 1 Symbol = 2 bits.
So total no of Bits sent in a subframe = 2 * 4200 = 8400 bits.
So capacity = 8400 / 1ms = 8.4 MBPS
So capacity in 5MHz Bandwidth with QPSK Modulation with normal cyclic Prefix is 8.4MBPS.
if Modulation scheme is BPSK, 1 bits in a symbol = 1 * 4200 / 1ms = 4.2 MBPS
if Modulation scheme is 64QAM , 6 bits in a symbol = 6 * 4200 / 1ms = 25.2 MBPS.

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Resource element lte explanations!

  • 1. Resource Element = Covered by 1 sub carrier and one symbol period i.e 1 Symbol Resource Block = Covered by 12 Subcarriers and 6 or 7 symbols(Based on Cyclic prefix) We can calculate the capacity if we know the Bandwidth allocated, Modulation scheme used and Cyclic Prefix type. Consider Bandwidth Allocated = 5MHz Modulation Scheme = QPSK(2 its per symbol) Cyclic prefix used = Normal Cyclic Prefix (7 symbols in a slot) Capacity = No of bits transferred in a sub frame / Duration of the Subframe(i.e 1milli sec) Calculation No of Bits transferred in a Subframe Total number of Resource block in a slot = Bandwidth / (Each subcarrier bandwidth * no of subcarriers in a Resource Block) Bandwidth = 5Mhz Each sub carrier width = 15Khz No of sub carriers in a Resource Block = 12 (As 12 Subcarrier is 1 Resource block ) Calculation of total no of resource blocks in 5MHz Bandwidth so Resource block in one slot = 5 Mhz / (15 KHz *12 ) = 27.77 (But used RBs will be 25 for 5MHz bandwidth) so Total Resource block in one subframe = 2 * Resource blocks in a slot = 50 RBs Calculation of total no of symbols/Resource Elements in 5MHz Bandwidth Total no of symbols / Resource Elements = 50 * no of symbols(REs) in a Resource block No of symbols(REs) in a resource block = 12 subcarrier * 7 symbols = 84 symbols(REs) Total symbols(REs ) in 50 Resource blocks = 50 * 84 = 4200 Resource Elements. ****Calculation of total no of bits sent in 5MHz Bandwidth in one subframe **** In one symbol we can send no of bits at a time which depends on the modulation scheme (like BPSK,QPSK ,64QAM BPSK - 1 bit,QPSK - 2 bit ,64 QAM - 6bits in a Symbol/ Resource elements We will consider QPSK Scheme so in one symbol 2bits we can send. So 1 Symbol = 2 bits. So total no of Bits sent in a subframe = 2 * 4200 = 8400 bits. So capacity = 8400 / 1ms = 8.4 MBPS So capacity in 5MHz Bandwidth with QPSK Modulation with normal cyclic Prefix is 8.4MBPS. if Modulation scheme is BPSK, 1 bits in a symbol = 1 * 4200 / 1ms = 4.2 MBPS if Modulation scheme is 64QAM , 6 bits in a symbol = 6 * 4200 / 1ms = 25.2 MBPS.