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EGR2302-Engineering Economics
Al Akhawayn University
1
Chapter 4:
Nominal and Effective Interest
Rates
Session 9-10-11
Dr Abdelaziz Berrado
EGR2302-Engineering Economics
Al Akhawayn University
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Topics to Be Covered in Today’s Lecture
 Section 4.1: Nominal and Effective Interest Rates
statements
 Section 4.2: Effective Annual Interest Rates
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Section 4.1
NOMINAL  EFFECTIVE RATES
• Review Simple Interest and Compound Interest (from Chapter 1)
• Compound Interest –
– Interest computed on Interest
– For a given interest period
• The time standard for interest computations – One Year
• One Year: Can be segmented into:
– 365 days
– 52 Weeks
– 12 Months
– One quarter: 3 months – 4 quarters/year
• Interest can be computed more frequently than one time a year
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4.1 Common Compounding
Frequencies
• Interest May be computed (compounded):
– Annually – One time a year (at the end)
– Every 6 months – 2 times a year (semi-annual)
– Every quarter – 4 times a year (quarterly)
– Every Month – 12 times a year (monthly)
– Every Day – 365 times a year (daily)
– …
– Continuous – infinite number of compounding periods
in a year.
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4.1 Quotation of Interest Rates
• Interest rates can be quoted in more than one way.
• Example:
– Interest equals “5% per 6-months”
– Interest is “12%” (12% per what?)
– Interest is 1% per month
– “Interest is “12.5% per year, compounded monthly”
• Thus, one must “decipher” the various ways to state
interest and to calculate.
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4.1 Two Common Forms of
Quotation
• Two types of interest quotation
– 1. Quotation using a Nominal Interest Rate
– 2. Quoting an Effective Periodic Interest Rate
• Nominal and Effective Interest rates are common in
business, finance, and engineering economy
• Each type must be understood in order to solve various
problems where interest is stated in various ways.
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4.1 Notion of a Nominal Interest Rate
• A Nominal Interest Rate, r.
• Definition:
A Nominal Interest Rate, r,
is an interest Rate that does
not include
any consideration
of compounding
Nominal means, “in name only”,
not the real rate in
this case.
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4.1 Quoting a Nominal Interest Rate
• Interest rates may be quoted (stated – communicated) in
terms of a nominal rate.
• You will see there are two ways to quote an interest rate:
– 1. Quote the Nominal rate
– 2. Quote the true, effective rate.
• For now – we study the nominal quotation.
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4.1 Definition of a Nominal Interest
Rate
• Mathematically we have the following definition:
r = (interest rate per period)(No. of Periods)
Examples Follow…..
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4.1 Examples – Nominal
Interest Rates
• 1.5% per month for 24 months
– Same as: (1.5%)(24) = 36% per 24 months
• 1.5% per month for 12 months
– Same as (1.5%)(12 months) = 18%/year
• 1.5% per month for 6 months
– Same as: (1.5%)(6 months) = 9%/6 months or semiannual
period
• 1% per week for 1 year
– Same as: (1%)(52 weeks) = 52% per year
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4.1 Nominal Rates…..
• A nominal rate (so quoted) do not reference the frequency
of compounding. They all have the format “r% per time
period”
• Nominal rates can be misleading
• We need an alternative way to quote interest rates….
• The true Effective Interest Rate is then applied….
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4.1 The Effective Interest Rate (EIR)
• When so quoted, an Effective interest rate is a
true, periodic interest rate.
• It is a rate that applies for a stated period of time
• It is conventional to use the year as the time
standard
• So, the EIR is often referred to as the Effective
Annual Interest Rate (EAIR)
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4.1 The EAIR
• Example:
– “12 per cent compounded monthly”
• Pick this statement apart:
– 12% is the nominal rate
– “compounded monthly” conveys the frequency of
the compounding throughout the year
– This example: 12 compounding periods within a
year.
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4.1 The EAIR and the Nominal Rate
• The EAIR adds to a nominal rate by informing
the user of the frequency of compounding within a
year.
• Notation:
• It is conventional to use the following notation for
the EAIR
– “ia” or,
– “i”
• The EAIR is an extension of the nominal rate –
“r”
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4.1 Focus on the Differences
• Nominal Rates:
– Format: “r% per time period, t”
– Ex: 5% per 6-months”
• Effective Interest Rates:
– Format: “r% per time period, compounded ‘m’
times a year.
– ‘m’ denotes or infers the number of times per
year that interest is compounded.
– Ex: 18% per year, compounded monthly
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4.1 Which One to Use: “r” or “i”?
• Some problems may state only the nominal
interest rate.
• Remember: Always apply the Effective Interest
Rate in solving problems.
• Published interest tables, closed-form time value
of money formula, and spreadsheet function
assume that only Effective interest is applied in
the computations.
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4.1 Time Based Units Associated with
Interest Rate Statements
• Time Period, t - Interest rates are stated as %
per time period. (t usually in years)
• Compounding Period, (CP) - Length of time
between compounding operations.
• Compounding Frequency-Let “m” represent the
number of times that interest is computed
(compounded) within time period “t”.
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4.1 Effective Rate per CP
• The Effective interest Rate per compounding
period, CP is:
i effective per CP
=
r%/time period t
m compounding periods/t
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4.1 Example:
• Given:
r = 9% per year, compounded monthly
Effective Monthly Rate:
0.09/12 = 0.0075 = 0.75%/month
Here, “m” counts months so, m = 12 compounding
periods within a year.
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4.1 Example 4.1
• Given, “9% per year, compounded quarterly”
Qtr. 1 Qtr. 2 Qtr. 3 Qtr. 4
One Year: Equals 4 Quarters
CP equals a quarter (3 – months)
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4.1 Example 4.1 (9%/yr: Compounded
quarterly)
• Given, “9% per year, compounded quarterly”
Qtr. 1 Qtr. 2 Qtr. 3 Qtr. 4
What is the Effective Rate per Quarter?
 iQtr. = 0.09/4 = 0.0225 = 2.25%/quarter
 9% rate is a nominal rate;
 The 2.25% rate is a true effective
monthly rate
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4.1 Example 4.1 (9%/yr: Compounded quarterly)
• Given, “9% per year, compounded quarterly”
Qtr. 1: 2.25% Qtr. 2:2.25% Qtr. 3:2.25% Qtr. 4:2.25%
The effective rate (true rate) per quarter
is 2.25% per quarter
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4.1 Statement: 9% compounded monthly
• r = 9% (the nominal rate).
• “compounded monthly means “m” =12.
• The true (effective) monthly rate is:
– 0.09/12 = 0.0075 = 0.75% per month
0.75%
1
0.75%
2
0.75%
3
0.75%
4
0.75%
5
0.75%
6
0.75%
7
0.75%
8
0.75%
9
0.75%
10
0.75%
11
0.75%
12
One Year Duration (12 months)
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4.1 Statement: 4.5% per 6 months –
compounded weekly
• Nominal Rate: 4.5%.
• Time Period: 6 months.
• Compounded weekly:
– Assume 52 weeks per year
– 6-months then equal 52/2 = 26 weeks per 6 months
• The true, effective weekly rate is:
– (0.045/26) = 0.00173 = 0.173% per week
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4.1 Table 4.1
• It can be unclear as to whether a stated rate is a
nominal rate or an effective rate.
• Three different statements of interest
follow………
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4.1 Varying Statements of
Interest Rates
• “8% per year, compounded quarterly”
– Nominal rate is stated: 8%
– Compounding Frequency is given
• Compounded quarterly
• True quarterly rate is 0.8/4 = 0.02 = 2% per
quarter
Here, one must calculate the effective
quarterly rate!
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4.1 Effective Rate Stated
• “Effective rate = 8.243% per year,
compounded quarterly:
– No nominal rate given (must be calculated)
– Compounding periods – m = 4
• No need to calculate the true effective rate!
– It is already given: 8.243% per year!
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4.1 Only the interest rate is stated
• “8% per year”.
• Note:
– No information on the frequency of
compounding.
– Must assume it is for one year!
– “m” is assumed to equal “1”.
• Assume that “8% per year” is a true,
effective annual rate!
– No other choice!
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Section 4.2
Effective Annual Interest Rates
• Here, we show how to calculate true, effective,
annual interest rates.
• We assume the year is the standard of measure for
time.
• The year can be comprised of various numbers of
compounding periods (within the year).
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4.2 Typical Compounding
Frequencies
• Given that one year is the standard:
– m = 1: compounded annually (end of the year);
– m = 2: semi-annual compounding (every 6 months);
– m = 4: quarterly compounding;
– m = 12: monthly compounding;
– m = 52: weekly compounding;
– m = 365: daily compounding;
• Could keep sub-dividing the year into smaller and smaller
time periods.
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4.2 Calculation of the EAIR
• EAIR – “the Effective Annual Interest Rate”.
• The EAIR is the true, annual rate given a
frequency of compounding within the year.
• We need the following notation…….
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4.2 EAIR Notation
• r = the nominal interest rate per year.
• m = the number of compounding periods within
the year.
• i = the effective interest rate per compounding
period (r/m)
• ia or ie = the true, effective annual rate given the
value of m.
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4.2 Derivation of the EAIR
relationship
• Assume $1 of principal at time t = 0.
• Conduct a period-by-period Future Worth
calculation.
• Notation “problem”.
– At times, “i” is used in place of “ie” or “ia”.
– So, “i” can also represent the true effective annual
interest rate!
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4.2 Deriving the EAIR…
• Consider a one-year time period.
0 1
Invest $1 of principal at time t = 0 at interest
rate i per year.
$P = $1.00
$F=$P(1+ia)1
One year later, F = P(1+ia)1
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m
1
4.2 Deriving the EAIR…
• Interest could be compounded more than one time within
the year!
0 1
$P = $1.00
$F=$P(1+ia)1
Assume the one year is now divided into
“m” compounding periods.
2 3 4 5
Replace “i” with “ia” since m now  1.
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4.2 Rewriting….
• F = P + P(ia)
• Now, the rate i per CP must be compounded through all
“m” periods to obtain F1
• Rewrite as:
– F = P + P(ia) = P(1 + ia)
– F = P( 1 + i )m
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4.2 Two similar expressions for F
• We have two expressions for F;
• F = P(1 + ia);
• F = P( 1 + i )m;
• Equate the two expressions;
• P(1 + ia) = P( 1 + i )m;
• P(1 + ia) = P( 1 + i )m;
Solve ia in terms of “i”.
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4.2 Expression for ia
• Solving for ia yields;
1 + ia = (1+i)m ( 1 )
ia = (1 + i )m – 1 ( 2 )
If we start with a nominal rate, “r” then….
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4.2 The EAIR is……
• Given a nominal rate, “r”
• iCompounding period = r/m ;
• The EAIR is calculated as;
EAIR = (1 + r/m)m - 1. ( 3 )
Or, iCompounding period = ( 1+ ia)1/m – 1
Then: Nominal rate – “r” = (i)(m) ( 4 )
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4.2 Example: EAIR given a
nominal rate.
• Given: interest is 8% per year compounded quarterly”.
• What is the true annual interest rate?
• Calculate:
EAIR = (1 + 0.08/4)4 – 1
EAIR = (1.02)4 – 1 = 0.0824 = 8.24%/year
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4.2 Example: “18%/year, comp.
monthly”
• What is the true, effective annual interest
rate?
r = 0.18/12 = 0.015 = 1.5% per month.
1.5% per month is an effective monthly
rate.
The effective annual rate is:
(1 + 0.18/12)12 – 1 = 0.1956 = 19.56%/year
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4.2 Previous Example
• “18%, c.m. (compounded monthly)
• Note:
– Nominal Rate is 18%;
– The true effective monthly rate is 1.5%/month;
– The true effective annual rate is 19.56%/year.
• One nominal rate creates 2 effective rates!
– Periodic rate and an effective annual rate.
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4.2 EAIR’s for 18%
• m = 1
– EAIR = (1 + 0.18/1)1 – 1 = 0.18 (18%)
• m = 2 (semiannual compounding)
– EAIR = (1 + 0.18/2)2 – 1 = 18.810%
• m = 4 (quarterly compounding)
– EAIR = (1 + 0.18/4)4 – 1 = 19.252%
• m = 12 ( monthly compounding)
– EAIR = ( 1 + 0.18/12)12 – 1 = 19.562%
• m = 52 ( weekly compounding)
– EAIR = (1 + 0.18/52)52 – 1 = 19.684%
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4.2 Continuing for 18%.....
• m = 365 (daily compounding).
– EAIR = ( 1 + 0.18/365)365 – 1 = 19.714%
• m = 365(24) (hourly compounding).
– EAIR = (1 + 0.18/8760)8760 – 1 = 19.72%
• Could keep subdividing the year into smaller time
periods.
• Note: There is an apparent limit as “m” gets larger
and larger…called continuous compounding.
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4.2 Example: 12% Nominal
No. of EAIR EAIR
Comp. Per. (Decimal) (per cent)
Annual 1 0.1200000 12.00000%
semi-annual 2 0.1236000 12.36000%
Quartertly 4 0.1255088 12.55088%
Bi-monthly 6 0.1261624 12.61624%
Monthly 12 0.1268250 12.68250%
Weekly 52 0.1273410 12.73410%
Daily 365 0.1274746 12.74746%
Hourly 8760 0.1274959 12.74959%
Minutes 525600 0.1274968 12.74968%
seconds 31536000 0.1274969 12.74969%
12% nominal for various compounding periods
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Assignments and Announcements
 Assignments due at the beginning of next
class:
 Read Sections 4.2, 4.3, 4.4, 4.5,
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Topics to Be Covered in Today’s Lecture
 Section 4.3: Payment Period (PP)
 Section 4.4: Equivalence: Comparing PP to CP
 Section 4.5: Single Amounts: CP = PP
 Section 4.6: Series Analysis – PP = CP
 Section 4.7: Single Amounts/Series with PP  CP
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Section 4.3: Payment Period (PP)
• Recall:
– CP is the “compounding period”
• PP is now introduced:
– PP is the “payment period”
• Why “CP” and “PP”?
– Often the frequency of depositing funds or making payments
does not coincide with the frequency of compounding.
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4.3 Comparisons:
• Example 4.4
Three different interest charging plans. Payments are made
on a loan every 6 months. Three interest plans are
presented:
1. 9% per year, c.q. (compounded quarterly).
2. 3% per quarter, (compounded quarterly).
3. 8.8% per year, c.m. (compounded monthly)
Which Plan has the lowest annual interest rate?
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CP-4
4.3 Comparing 3 Plans: Plan 1
• 9% per year, c.q.
• Payments made every 6 months.
0 1
Payment
9%, c.q. = 0.09/4 = 0.045 per 3 months = 2.25% per 3
months
CP-1 CP-2
Payment
CP-3
Payment Period 1 Payment Period 2
Rule: The interest rate must match the payment
period!
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4.3 The Matching Rule
• Again, the interest must be consistent with the payment
period!
• We need a 6-month effective rate and then calculate the 1
year true, effective rate!
• To compare the 3 plans:
– Compute the true, effective 6-month rate or,
– Compute the true effective 1 year rate.
– Then one can compare the 3 plans!
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4.3 Comparing 3 Plans: Plan 1
• 9% per year, c.q. = 2.25%/quarter
• Payments made every 6 months.
0 1
CP-4
Payment
CP-1 CP-2
Payment
CP-3
Payment Period 1 Payment Period 2
True 6-month rate is:
(1.0225)2 – 1 = 0.0455 = 4.55% per 6-months
EAIR = (1.0225)4 – 1 = 9.31% per year
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4.3 Plan 2
• 3% per quarter, c.q.
• Effective=3%/quarter
• Find the EIR for 6-months
• Calculate:
– For a 6-month effective interest rate -
– (1.03)2 – 1 = 0.0609 = 6.09% per 6-months
– Or, for a 1 year effective interest rate -
– (1.03)4 – 1 = 12.55%/year
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4.3 Plan 3:” 8.8% per year, c.m.”
• “r” = 8.8%
• “m” = 12
• Payments are twice a year
• 6-month nominal rate = 0.088/2 =4.4%/6-months (“r” =
0.044)
• EIR6-months = (1 + 0.044/6)6 – 1= (1.0073)6 – 1= 4.48%/
6-months
• EIR12-months = (1 + 0.088/12)12 – 1 = 9.16%/year
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4.3 Summarizing the 3 plans….
9.16%
4.48%
3
12.55%
6.09%
2
9.31%
4.55%
1
1-year
6-month
Plan No.
Plan 3 presents the lowest interest rate.
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4.3 Can be confusing ???
• The 3 plans state interest differently.
• Difficult to determine the best plan by mere inspection.
• Each plan must be evaluated by:
– Calculating the true, effective 6-month rate
Or,
– Calculating the true, effective 12 month, (1 year) true, effective
annual rate.
– Then all 3 plans can be compared using the EIR or the EAIR.
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Section 4.4:
Equivalence: Comparing PP to CP
• Reality:
– PP and CP’s do not always match up;
– May have monthly cash flows but…
– Compounding period different than monthly.
• Savings Accounts – for example;
– Monthly deposits with,
– Quarterly interest earned or paid;
– They don’t match!
• Make them match! (by adjusting the interest period to match the
payment period.)
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Situations
Situation Text Reference
• PP = CP Sections 4.5 and 4.6
• PP  CP Sections 4.5 and 4.6
• PP  CP Section 4.7
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Section 4.5
Single Amounts: PP = CP
Example1:
• “r” = 15%, c.m. (compounded monthly)
• Let P = $1500.00
• Find F at t = 2 years.
• 15% c.m. = 0.15/12 = 0.0125 = 1.25%/month.
• n = 2 years OR 24 months
• Work in months or in years
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4.5 Single Amounts: PP = CP
• Approach 1. (n relates to months)
• State:
– F24 = $1,500(F/P,0.15/12,24);
– i/month = 0.15/12 = 0.0125 (1.25%);
– F24 = $1,500(F/P,1.25%,24);
– F24 = $1,500(1.0125)24 = $1,500(1.3474);
– F24 = $2,021.03.
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4.5 Single Amounts: CP = CP
• Approach 2. (n relates to years)
• State:
– F2 = $1,500(F/P,i%,2);
– Assume n = 2 (years) we need to apply an annual effective
interest rate.
– i/month =0.0125
– EAIR = (1.0125)12 – 1 = 0.1608 (16.08%)
– F2 = $1,500(F/P,16.08%,2)
– F2 = $1,500(1.1608)2 = $2,021.19
– Slight roundoff compared to approach 1
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4.5 Example 2.
• Consider
0 1 2 3 4 5 6 7 8 9 10
$1,000
$3,000
$1,500
F 10 = ?
r = 12%/yr, c.s.a.
Suggest you work this in 6- month time frames
Count “n” in terms of “6-month” intervals
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4.5 Example 2.
• Renumber the time line
0 2 4 6 8 10 12 14 16 18 20
$1,000
$3,000
$1,500
F 10 = ?
r = 12%/yr, c.s.a.
i/6 months = 0.12/2 = 6%/6 months; n counts 6-
month time periods
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4.5 Example 2.
• Compound Forward
0 2 4 6 8 10 12 14 16 18 20
$1,000
$3,000
$1,500
F 20 = ?
r = 12%/yr, c.s.a.
F20 = $1,000(F/P,6%,20) + $3,000(F/P,6%,12) +
$1,500(F/P,6%,8) = $11,634
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4.5 Example 2.
Let n count years….
• Compound Forward
0 1 2 3 4 5 6 7 8 9 10
$1,000
$3,000
$1,500
F 10 = ?
r = 12%/yr, c.s.a.
IF n counts years, interest must be an annual rate.
EAIR = (1.06)2 - 1 = 12.36%
Compute the FV where n is years and i = 12.36%!
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Section 4.6
Series Analysis – PP = CP
• Find the effective “i” per payment period.
• Determine “n” as the total number of payment
periods.
• “n” will equal the number of cash flow periods in the
particular series.
• Example follows…..
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4.6 Series Example
• Consider:
0 1 2 3 4 5 6 7
A = $500 every 6 months
F7 = ??
Find F7 if “r” = 20%/yr, c.q. (PP  CP)
We need i per 6-months – effective.
i6-months = adjusting the nominal rate to fit.
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4.6 Series Example
• Adjusting the interest
• r = 20%, c.q.
• i/qtr. = 0.20/4 = 0.05 = 5%/qtr.
• 2-qtrs in a 6-month period.
• i6-months = (1.05)2 – 1 = 10.25%/6-months.
• Now, the interest matches the payments.
• Fyear 7 = Fperiod 14 = $500(F/A,10.25%,14)
• F = $500(28.4891) = $14,244.50
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4.6 This Example: Observations
• Interest rate must match the frequency of the
payments.
• In this example – we need effective interest per 6-
months: Payments are every 6-months.
• The effective 6-month rate computed to equal 10.25% -
un-tabulated rate.
• Calculate the F/A factor or interpolate.
• Or, use a spreadsheet that can quickly determine the
correct factor!
EGR2302-Engineering Economics
Al Akhawayn University
70
4.6 This Example: Observations
• Do not attempt to adjust the payments to fit the
interest rate!
• This is Wrong!
• At best a gross approximation – do not do it!
• This type of problem almost always results in an un-
tabulated interest rate
– You have to use your calculator to compute the factor or a
spreadsheet model to achieve exact result.
EGR2302-Engineering Economics
Al Akhawayn University
71
Section 4.7
Single Amounts/Series with PP  CP
• This situation is different than the last.
• Here, PP is less than the compounding period (CP).
• Raises questions?
• Issue of interperiod compounding
• An example follows.
EGR2302-Engineering Economics
Al Akhawayn University
72
4.7 Interperiod Compounding Issues
• Consider a one-year cash flow situation.
• Payments are made at end of a given month.
• Interest rate is “r = 12%/yr, c.q.”
0 1 2 3 4 5 6 7 8 9 10 11 12
$90
$120
$45
$150
$200
$75 $100
$50
EGR2302-Engineering Economics
Al Akhawayn University
73
CP-2
CP-1
4.7 Interperiod Compounding
• r =12%/yr. c.q.
0 1 2 3 4 5 6 7 8 9 10 11 12
$90
$120
$45
$150
$200
$75 $100
$50
CP-3 CP-4
Note where some of the cash flow amounts fall with
respect to the compounding periods!
EGR2302-Engineering Economics
Al Akhawayn University
74
CP-1
4.7 Take the first $200 cash flow
0 1 2 3 4 5 6 7 8 9 10 11 12
$90
$120
$45
$150
$200
$75 $100
$50
• Will any interest be earned/owed on the $200 since
interest is compounded at the end of each quarter?
The $200 is at the end of
month 2 and will it earn
interest for one month to go
to the end of the first
compounding period?
The last month of the first compounding period.
Is this an interest-earning period?
EGR2302-Engineering Economics
Al Akhawayn University
75
4.7 Interperiod Issues
• The $200 occurs 1 month before the end of
compounding period 1.
• Will interest be earned or charged on that $200 for the
one month?
• If not then the revised cash flow diagram for all of the
cash flows should look like…..
EGR2302-Engineering Economics
Al Akhawayn University
76
0 1 2 3 4 5 6 7 8 9 10 11 12
4.7 No interperiod compounding
• Revised CF Diagram
$90
$165
$45
$150
$200
$75 $100
$50
$200
$175
$90
$50
All negative CF’s move to the end of their respective
quarters and all positive CF’s move to the beginning
of their respective quarters.
EGR2302-Engineering Economics
Al Akhawayn University
77
4.7 No interperiod compounding
• Revised CF Diagram
0 1 2 3 4 5 6 7 8 9 10 11 12
$165
$150
$200
$175
$90
$50
Now, determine the future worth of this revised series
using the F/P factor on each cash flow.
EGR2302-Engineering Economics
Al Akhawayn University
78
4.7 Final Results: No interperiod
Comp.
• With the revised CF compute the future worth.
F12 = [-150(F/P3%,4) – 200(F/P,3%,3) + (-175
+90)(F/P,3%,2) + 165(F/P,3%,1) – 50]
= $-357.59
“r” = 12%/year, compounded quarterly
“i” = 0.12/4 = 0.03 = 3% per quarter
EGR2302-Engineering Economics
Al Akhawayn University
79
CP-2
CP-1
4.7 Interperiod Compounding
• r =12%/yr. c.q.
0 1 2 3 4 5 6 7 8 9 10 11 12
$90
$120
$45
$150
$200
$75 $100
$50
CP-3 CP-4
The cash flows are not moved and equivalent P, F,
or A values are determined using the effective
interest rate per payment period
EGR2302-Engineering Economics
Al Akhawayn University
80
CP-2
CP-1
4.7 Interperiod Compounding
• r =12%/yr. c.q.
0 1 2 3 4 5 6 7 8 9 10 11 12
$90
$120
$45
$150
$200
$75 $100
$50
CP-3 CP-4
If the inter-period compounding is earned, then we should
compute the effective interest rate per compounding period.
i=3% is the effective quarterly rate
Imonthly=(1+i)1/3-1=(1.03)1/3-1=0.99%
EGR2302-Engineering Economics
Al Akhawayn University
81
Topics to Be Covered in Today’s Lecture
 Section 4.8: Continuous Compounding
 Section 4.9: Interest Rates that vary over
time
EGR2302-Engineering Economics
Al Akhawayn University
82
Section 4.8
Continuous Compounding
• Recall:
– EAIR = i = (1 + r/m)m – 1
– What happens if we let m approach infinity?
– That means an infinite number of compounding
periods within a year or,
– The time between compounding approaches “0”.
– We will see that a limiting value will be approached
for a given value of “r”
EGR2302-Engineering Economics
Al Akhawayn University
83
4.8 Derivation of Continuous Compounding
• We can state, in general terms for the EAIR:
(1 ) 1
m
r
i
m
= + −
Now, examine the impact of letting “m” approach
infinity.
EGR2302-Engineering Economics
Al Akhawayn University
84
4.8 Derivation of Continuous
Compounding
• We re-define the EAIR general form as:
(1 ) 1 1 1
r
m
r
m
r r
m m
 
 
 
+ − = + −
 
 
 
 
Note – the term in brackets has the exponent
changed but all is still the same….
EGR2302-Engineering Economics
Al Akhawayn University
85
4.8 Derivation of Continuous
Compounding
• There is a reason for the re-definition.
• From the calculus of limits there is an important limit
that is quite useful.
• Specifically:
1
lim 1 2.71828
h
h
e
h
→∞
 
+ = =
 
 
EGR2302-Engineering Economics
Al Akhawayn University
86
4.8 Derivation of Continuous
Compounding
• Substituting we can see:
lim 1 ,
m
r
m
r
e
m
→∞
 
+ =
 
 
EGR2302-Engineering Economics
Al Akhawayn University
87
4.8 Derivation of Continuous
Compounding
• So that:
lim 1 1 1.
r
m
r
r
m
r
i e
m
→∞
 
 
 
= + − = −
 
 
 
 
Summarizing…….
EGR2302-Engineering Economics
Al Akhawayn University
88
4.8 Derivation of Continuous
Compounding
• The EAIR when interest is compounded continuously is
then:
EAIR = er – 1
Where “r” is the nominal rate of
interest compounded continuously.
This is the max. interest rate for any
value of “r” compounded
continuously.
EGR2302-Engineering Economics
Al Akhawayn University
89
4.8 Derivation of Continuous
Compounding
• Example:
• What is the true, effective annual interest rate if the
nominal rate is given as:
– r = 18%, compounded continuously
– Or, r = 18% c.c.
Solve e0.18 – 1 = 1.1972 – 1 = 19.72%/year
The 19.72% represents the MAXIMUM EAIR for
18% compounded anyway you choose!
EGR2302-Engineering Economics
Al Akhawayn University
90
4.8 Finding “r” from the EAIR/cont.
compounding
• To find the equivalent nominal rate given the EAIR
when interest is compounded continuously, apply:
ln(1 )
r i
= +
EGR2302-Engineering Economics
Al Akhawayn University
91
4.8 Example
• Given r = 18% per year, cc, find:
– A. the effective monthly rate
– B. the effective annual rate
a. r/month = 0.18/12 = 1.5%/month
Effective monthly rate is e0.015 – 1 = 1.511%
b. The effective annual interest rate is e0.18 – 1 = 19.72%
per year.
EGR2302-Engineering Economics
Al Akhawayn University
92
4.8 Example
• An investor requires an effective return of at least 15%
per year.
• What is the minimum annual nominal rate that is
acceptable if interest on his investment is compounded
continuously?
To start: er – 1 = 0.15
Solve for “r” ………
EGR2302-Engineering Economics
Al Akhawayn University
93
4.8 Example
• er – 1 = 0.15
• er = 1.15
• ln(er) = ln(1.15)
• r = ln(1.15) = 0.1398 = 13.98%
A rate of 13.98% per year, cc. generates the same
as 15% true effective annual rate.
EGR2302-Engineering Economics
Al Akhawayn University
94
4.8 Final Thoughts
• When comparing different statements of interest rate
one must always compute to true, effective annual rate
(EAIR) for each quotation.
• Only EAIR’s can be compared!
• Various nominal rates cannot be compared unless each
nominal rate is converted to its respective EAIR!
EGR2302-Engineering Economics
Al Akhawayn University
95
Section 4.9
Interest Rates that vary over time
• In practice – interest rates do not stay the same over
time unless by contractual obligation.
• There can exist “variation” of interest rates over time –
quite normal!
• If required, how do you handle that situation?
EGR2302-Engineering Economics
Al Akhawayn University
96
4.9 Interest Rates that vary over time
• Best illustrated by an example.
• Assume the following future profits:
0 1 2 3 4
$70,000 $70,000
$35,000
$25,000
7% 7% 9% 10%
(P/F,7%,1)
(P/F,7%,2)
(P/F,9%,3)
(P/F,10%,4)
EGR2302-Engineering Economics
Al Akhawayn University
97
4.9 Varying Rates: Present Worth
• To find the Present Worth:
– Bring each cash flow amount back to the appropriate point in
time at the interest rate according to:
• P = F1(P/F.i1,1) + F2(P/F,i1)(P/F,i2) + …
• + Fn(P/F,i1)(P/F,i2)(P/F,i3)…(P/F,in,1)
This Process can get computationally involved!
EGR2302-Engineering Economics
Al Akhawayn University
98
4.9 Period-by-Period Analysis
• P0 =:
1. $7000(P/F,7%,1)
2. $7000(P/F,7%,1)(P/F,7%,1)
3. $35000(P/F,9%,1)(P/F,7%,1)2
4. $25000(P/F,10%,1)(P/F,9%,1)(P/F,7%,1)2
Equals: $172,816 at t = 0…
Work backwards one period at a
time until you get to “0”.
EGR2302-Engineering Economics
Al Akhawayn University
99
4.9 Varying Rates: Approximation
• An alternative approach that approximates the present
value:
• Average the interest rates over the appropriate number
of time periods.
• Example:
– {7% + 7% + 9% + 10%}/4 = 8.25%;
– Work the problem with an 8.25% rate;
– Merely an approximation.
EGR2302-Engineering Economics
Al Akhawayn University
100
4.9 Varying Rates: Single, Future Cash
Flow
• Assume the following Cash Flow:
0 1 2 3 4
8% 9% 10% 11%
$10,000
Objective: Find P0 at the varying rates
P0 = $10,000(P/F,8%,1)(P/F,9%,1)(P/F,10%,1)(P/F,11%,1)
= $10,000(0.9259)(0.9174)(0.9091)(0.9009)
= $10,000(0.6957) = $6,957
EGR2302-Engineering Economics
Al Akhawayn University
101
4.9 Varying Rates: Observations
• We seldom evaluate problem models with varying
interest rates except in special cases.
• If required, best to build a spreadsheet model
• A cumbersome task to perform.
EGR2302-Engineering Economics
Al Akhawayn University
102
Chapter 4 Summary
• Many applications use and apply nominal and effective
compounding
• Given a nominal rate – must get the interest rate to
match the frequency of the payments.
• Apply the effective interest rate per payment period.
– PP = CP (adjusting the interest period to match the payment period)
– PP  CP (Consider inter-period compounding or not?)
• When comparing varying interest rates, must calculate
the EAIR in order to compare.
EGR2302-Engineering Economics
Al Akhawayn University
103
Chapter Summary – cont.
• All time value of money interest factors require use of
an effective (true) periodic interest rate.
• The interest rate, i, and the payment or cash flow
periods must have the same time unit.
• One may encounter varying interest rates and an exact
answer requires a sequence of interest rates –
cumbersome!
EGR2302-Engineering Economics
Al Akhawayn University
104
Assignments and Announcements
 Homework 3 due a week from today
 Assignments due at the beginning of next
class:
 Answer the three online quizzes on chapter 4 on
the text’s website.
 Read chapter 5.1, 5.2 and 5.3

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Nominal rate and effective rates primer

  • 1. EGR2302-Engineering Economics Al Akhawayn University 1 Chapter 4: Nominal and Effective Interest Rates Session 9-10-11 Dr Abdelaziz Berrado
  • 2. EGR2302-Engineering Economics Al Akhawayn University 2 Topics to Be Covered in Today’s Lecture Section 4.1: Nominal and Effective Interest Rates statements Section 4.2: Effective Annual Interest Rates
  • 3. EGR2302-Engineering Economics Al Akhawayn University 3 Section 4.1 NOMINAL EFFECTIVE RATES • Review Simple Interest and Compound Interest (from Chapter 1) • Compound Interest – – Interest computed on Interest – For a given interest period • The time standard for interest computations – One Year • One Year: Can be segmented into: – 365 days – 52 Weeks – 12 Months – One quarter: 3 months – 4 quarters/year • Interest can be computed more frequently than one time a year
  • 4. EGR2302-Engineering Economics Al Akhawayn University 4 4.1 Common Compounding Frequencies • Interest May be computed (compounded): – Annually – One time a year (at the end) – Every 6 months – 2 times a year (semi-annual) – Every quarter – 4 times a year (quarterly) – Every Month – 12 times a year (monthly) – Every Day – 365 times a year (daily) – … – Continuous – infinite number of compounding periods in a year.
  • 5. EGR2302-Engineering Economics Al Akhawayn University 5 4.1 Quotation of Interest Rates • Interest rates can be quoted in more than one way. • Example: – Interest equals “5% per 6-months” – Interest is “12%” (12% per what?) – Interest is 1% per month – “Interest is “12.5% per year, compounded monthly” • Thus, one must “decipher” the various ways to state interest and to calculate.
  • 6. EGR2302-Engineering Economics Al Akhawayn University 6 4.1 Two Common Forms of Quotation • Two types of interest quotation – 1. Quotation using a Nominal Interest Rate – 2. Quoting an Effective Periodic Interest Rate • Nominal and Effective Interest rates are common in business, finance, and engineering economy • Each type must be understood in order to solve various problems where interest is stated in various ways.
  • 7. EGR2302-Engineering Economics Al Akhawayn University 7 4.1 Notion of a Nominal Interest Rate • A Nominal Interest Rate, r. • Definition: A Nominal Interest Rate, r, is an interest Rate that does not include any consideration of compounding Nominal means, “in name only”, not the real rate in this case.
  • 8. EGR2302-Engineering Economics Al Akhawayn University 8 4.1 Quoting a Nominal Interest Rate • Interest rates may be quoted (stated – communicated) in terms of a nominal rate. • You will see there are two ways to quote an interest rate: – 1. Quote the Nominal rate – 2. Quote the true, effective rate. • For now – we study the nominal quotation.
  • 9. EGR2302-Engineering Economics Al Akhawayn University 9 4.1 Definition of a Nominal Interest Rate • Mathematically we have the following definition: r = (interest rate per period)(No. of Periods) Examples Follow…..
  • 10. EGR2302-Engineering Economics Al Akhawayn University 10 4.1 Examples – Nominal Interest Rates • 1.5% per month for 24 months – Same as: (1.5%)(24) = 36% per 24 months • 1.5% per month for 12 months – Same as (1.5%)(12 months) = 18%/year • 1.5% per month for 6 months – Same as: (1.5%)(6 months) = 9%/6 months or semiannual period • 1% per week for 1 year – Same as: (1%)(52 weeks) = 52% per year
  • 11. EGR2302-Engineering Economics Al Akhawayn University 11 4.1 Nominal Rates….. • A nominal rate (so quoted) do not reference the frequency of compounding. They all have the format “r% per time period” • Nominal rates can be misleading • We need an alternative way to quote interest rates…. • The true Effective Interest Rate is then applied….
  • 12. EGR2302-Engineering Economics Al Akhawayn University 12 4.1 The Effective Interest Rate (EIR) • When so quoted, an Effective interest rate is a true, periodic interest rate. • It is a rate that applies for a stated period of time • It is conventional to use the year as the time standard • So, the EIR is often referred to as the Effective Annual Interest Rate (EAIR)
  • 13. EGR2302-Engineering Economics Al Akhawayn University 13 4.1 The EAIR • Example: – “12 per cent compounded monthly” • Pick this statement apart: – 12% is the nominal rate – “compounded monthly” conveys the frequency of the compounding throughout the year – This example: 12 compounding periods within a year.
  • 14. EGR2302-Engineering Economics Al Akhawayn University 14 4.1 The EAIR and the Nominal Rate • The EAIR adds to a nominal rate by informing the user of the frequency of compounding within a year. • Notation: • It is conventional to use the following notation for the EAIR – “ia” or, – “i” • The EAIR is an extension of the nominal rate – “r”
  • 15. EGR2302-Engineering Economics Al Akhawayn University 15 4.1 Focus on the Differences • Nominal Rates: – Format: “r% per time period, t” – Ex: 5% per 6-months” • Effective Interest Rates: – Format: “r% per time period, compounded ‘m’ times a year. – ‘m’ denotes or infers the number of times per year that interest is compounded. – Ex: 18% per year, compounded monthly
  • 16. EGR2302-Engineering Economics Al Akhawayn University 16 4.1 Which One to Use: “r” or “i”? • Some problems may state only the nominal interest rate. • Remember: Always apply the Effective Interest Rate in solving problems. • Published interest tables, closed-form time value of money formula, and spreadsheet function assume that only Effective interest is applied in the computations.
  • 17. EGR2302-Engineering Economics Al Akhawayn University 17 4.1 Time Based Units Associated with Interest Rate Statements • Time Period, t - Interest rates are stated as % per time period. (t usually in years) • Compounding Period, (CP) - Length of time between compounding operations. • Compounding Frequency-Let “m” represent the number of times that interest is computed (compounded) within time period “t”.
  • 18. EGR2302-Engineering Economics Al Akhawayn University 18 4.1 Effective Rate per CP • The Effective interest Rate per compounding period, CP is: i effective per CP = r%/time period t m compounding periods/t
  • 19. EGR2302-Engineering Economics Al Akhawayn University 19 4.1 Example: • Given: r = 9% per year, compounded monthly Effective Monthly Rate: 0.09/12 = 0.0075 = 0.75%/month Here, “m” counts months so, m = 12 compounding periods within a year.
  • 20. EGR2302-Engineering Economics Al Akhawayn University 20 4.1 Example 4.1 • Given, “9% per year, compounded quarterly” Qtr. 1 Qtr. 2 Qtr. 3 Qtr. 4 One Year: Equals 4 Quarters CP equals a quarter (3 – months)
  • 21. EGR2302-Engineering Economics Al Akhawayn University 21 4.1 Example 4.1 (9%/yr: Compounded quarterly) • Given, “9% per year, compounded quarterly” Qtr. 1 Qtr. 2 Qtr. 3 Qtr. 4 What is the Effective Rate per Quarter? iQtr. = 0.09/4 = 0.0225 = 2.25%/quarter 9% rate is a nominal rate; The 2.25% rate is a true effective monthly rate
  • 22. EGR2302-Engineering Economics Al Akhawayn University 22 4.1 Example 4.1 (9%/yr: Compounded quarterly) • Given, “9% per year, compounded quarterly” Qtr. 1: 2.25% Qtr. 2:2.25% Qtr. 3:2.25% Qtr. 4:2.25% The effective rate (true rate) per quarter is 2.25% per quarter
  • 23. EGR2302-Engineering Economics Al Akhawayn University 23 4.1 Statement: 9% compounded monthly • r = 9% (the nominal rate). • “compounded monthly means “m” =12. • The true (effective) monthly rate is: – 0.09/12 = 0.0075 = 0.75% per month 0.75% 1 0.75% 2 0.75% 3 0.75% 4 0.75% 5 0.75% 6 0.75% 7 0.75% 8 0.75% 9 0.75% 10 0.75% 11 0.75% 12 One Year Duration (12 months)
  • 24. EGR2302-Engineering Economics Al Akhawayn University 24 4.1 Statement: 4.5% per 6 months – compounded weekly • Nominal Rate: 4.5%. • Time Period: 6 months. • Compounded weekly: – Assume 52 weeks per year – 6-months then equal 52/2 = 26 weeks per 6 months • The true, effective weekly rate is: – (0.045/26) = 0.00173 = 0.173% per week
  • 25. EGR2302-Engineering Economics Al Akhawayn University 25 4.1 Table 4.1 • It can be unclear as to whether a stated rate is a nominal rate or an effective rate. • Three different statements of interest follow………
  • 26. EGR2302-Engineering Economics Al Akhawayn University 26 4.1 Varying Statements of Interest Rates • “8% per year, compounded quarterly” – Nominal rate is stated: 8% – Compounding Frequency is given • Compounded quarterly • True quarterly rate is 0.8/4 = 0.02 = 2% per quarter Here, one must calculate the effective quarterly rate!
  • 27. EGR2302-Engineering Economics Al Akhawayn University 27 4.1 Effective Rate Stated • “Effective rate = 8.243% per year, compounded quarterly: – No nominal rate given (must be calculated) – Compounding periods – m = 4 • No need to calculate the true effective rate! – It is already given: 8.243% per year!
  • 28. EGR2302-Engineering Economics Al Akhawayn University 28 4.1 Only the interest rate is stated • “8% per year”. • Note: – No information on the frequency of compounding. – Must assume it is for one year! – “m” is assumed to equal “1”. • Assume that “8% per year” is a true, effective annual rate! – No other choice!
  • 29. EGR2302-Engineering Economics Al Akhawayn University 29 Section 4.2 Effective Annual Interest Rates • Here, we show how to calculate true, effective, annual interest rates. • We assume the year is the standard of measure for time. • The year can be comprised of various numbers of compounding periods (within the year).
  • 30. EGR2302-Engineering Economics Al Akhawayn University 30 4.2 Typical Compounding Frequencies • Given that one year is the standard: – m = 1: compounded annually (end of the year); – m = 2: semi-annual compounding (every 6 months); – m = 4: quarterly compounding; – m = 12: monthly compounding; – m = 52: weekly compounding; – m = 365: daily compounding; • Could keep sub-dividing the year into smaller and smaller time periods.
  • 31. EGR2302-Engineering Economics Al Akhawayn University 31 4.2 Calculation of the EAIR • EAIR – “the Effective Annual Interest Rate”. • The EAIR is the true, annual rate given a frequency of compounding within the year. • We need the following notation…….
  • 32. EGR2302-Engineering Economics Al Akhawayn University 32 4.2 EAIR Notation • r = the nominal interest rate per year. • m = the number of compounding periods within the year. • i = the effective interest rate per compounding period (r/m) • ia or ie = the true, effective annual rate given the value of m.
  • 33. EGR2302-Engineering Economics Al Akhawayn University 33 4.2 Derivation of the EAIR relationship • Assume $1 of principal at time t = 0. • Conduct a period-by-period Future Worth calculation. • Notation “problem”. – At times, “i” is used in place of “ie” or “ia”. – So, “i” can also represent the true effective annual interest rate!
  • 34. EGR2302-Engineering Economics Al Akhawayn University 34 4.2 Deriving the EAIR… • Consider a one-year time period. 0 1 Invest $1 of principal at time t = 0 at interest rate i per year. $P = $1.00 $F=$P(1+ia)1 One year later, F = P(1+ia)1
  • 35. EGR2302-Engineering Economics Al Akhawayn University 35 m 1 4.2 Deriving the EAIR… • Interest could be compounded more than one time within the year! 0 1 $P = $1.00 $F=$P(1+ia)1 Assume the one year is now divided into “m” compounding periods. 2 3 4 5 Replace “i” with “ia” since m now 1.
  • 36. EGR2302-Engineering Economics Al Akhawayn University 36 4.2 Rewriting…. • F = P + P(ia) • Now, the rate i per CP must be compounded through all “m” periods to obtain F1 • Rewrite as: – F = P + P(ia) = P(1 + ia) – F = P( 1 + i )m
  • 37. EGR2302-Engineering Economics Al Akhawayn University 37 4.2 Two similar expressions for F • We have two expressions for F; • F = P(1 + ia); • F = P( 1 + i )m; • Equate the two expressions; • P(1 + ia) = P( 1 + i )m; • P(1 + ia) = P( 1 + i )m; Solve ia in terms of “i”.
  • 38. EGR2302-Engineering Economics Al Akhawayn University 38 4.2 Expression for ia • Solving for ia yields; 1 + ia = (1+i)m ( 1 ) ia = (1 + i )m – 1 ( 2 ) If we start with a nominal rate, “r” then….
  • 39. EGR2302-Engineering Economics Al Akhawayn University 39 4.2 The EAIR is…… • Given a nominal rate, “r” • iCompounding period = r/m ; • The EAIR is calculated as; EAIR = (1 + r/m)m - 1. ( 3 ) Or, iCompounding period = ( 1+ ia)1/m – 1 Then: Nominal rate – “r” = (i)(m) ( 4 )
  • 40. EGR2302-Engineering Economics Al Akhawayn University 40 4.2 Example: EAIR given a nominal rate. • Given: interest is 8% per year compounded quarterly”. • What is the true annual interest rate? • Calculate: EAIR = (1 + 0.08/4)4 – 1 EAIR = (1.02)4 – 1 = 0.0824 = 8.24%/year
  • 41. EGR2302-Engineering Economics Al Akhawayn University 41 4.2 Example: “18%/year, comp. monthly” • What is the true, effective annual interest rate? r = 0.18/12 = 0.015 = 1.5% per month. 1.5% per month is an effective monthly rate. The effective annual rate is: (1 + 0.18/12)12 – 1 = 0.1956 = 19.56%/year
  • 42. EGR2302-Engineering Economics Al Akhawayn University 42 4.2 Previous Example • “18%, c.m. (compounded monthly) • Note: – Nominal Rate is 18%; – The true effective monthly rate is 1.5%/month; – The true effective annual rate is 19.56%/year. • One nominal rate creates 2 effective rates! – Periodic rate and an effective annual rate.
  • 43. EGR2302-Engineering Economics Al Akhawayn University 43 4.2 EAIR’s for 18% • m = 1 – EAIR = (1 + 0.18/1)1 – 1 = 0.18 (18%) • m = 2 (semiannual compounding) – EAIR = (1 + 0.18/2)2 – 1 = 18.810% • m = 4 (quarterly compounding) – EAIR = (1 + 0.18/4)4 – 1 = 19.252% • m = 12 ( monthly compounding) – EAIR = ( 1 + 0.18/12)12 – 1 = 19.562% • m = 52 ( weekly compounding) – EAIR = (1 + 0.18/52)52 – 1 = 19.684%
  • 44. EGR2302-Engineering Economics Al Akhawayn University 44 4.2 Continuing for 18%..... • m = 365 (daily compounding). – EAIR = ( 1 + 0.18/365)365 – 1 = 19.714% • m = 365(24) (hourly compounding). – EAIR = (1 + 0.18/8760)8760 – 1 = 19.72% • Could keep subdividing the year into smaller time periods. • Note: There is an apparent limit as “m” gets larger and larger…called continuous compounding.
  • 45. EGR2302-Engineering Economics Al Akhawayn University 45 4.2 Example: 12% Nominal No. of EAIR EAIR Comp. Per. (Decimal) (per cent) Annual 1 0.1200000 12.00000% semi-annual 2 0.1236000 12.36000% Quartertly 4 0.1255088 12.55088% Bi-monthly 6 0.1261624 12.61624% Monthly 12 0.1268250 12.68250% Weekly 52 0.1273410 12.73410% Daily 365 0.1274746 12.74746% Hourly 8760 0.1274959 12.74959% Minutes 525600 0.1274968 12.74968% seconds 31536000 0.1274969 12.74969% 12% nominal for various compounding periods
  • 46. EGR2302-Engineering Economics Al Akhawayn University 46 Assignments and Announcements Assignments due at the beginning of next class: Read Sections 4.2, 4.3, 4.4, 4.5,
  • 47. EGR2302-Engineering Economics Al Akhawayn University 47 Topics to Be Covered in Today’s Lecture Section 4.3: Payment Period (PP) Section 4.4: Equivalence: Comparing PP to CP Section 4.5: Single Amounts: CP = PP Section 4.6: Series Analysis – PP = CP Section 4.7: Single Amounts/Series with PP CP
  • 48. EGR2302-Engineering Economics Al Akhawayn University 48 Section 4.3: Payment Period (PP) • Recall: – CP is the “compounding period” • PP is now introduced: – PP is the “payment period” • Why “CP” and “PP”? – Often the frequency of depositing funds or making payments does not coincide with the frequency of compounding.
  • 49. EGR2302-Engineering Economics Al Akhawayn University 49 4.3 Comparisons: • Example 4.4 Three different interest charging plans. Payments are made on a loan every 6 months. Three interest plans are presented: 1. 9% per year, c.q. (compounded quarterly). 2. 3% per quarter, (compounded quarterly). 3. 8.8% per year, c.m. (compounded monthly) Which Plan has the lowest annual interest rate?
  • 50. EGR2302-Engineering Economics Al Akhawayn University 50 CP-4 4.3 Comparing 3 Plans: Plan 1 • 9% per year, c.q. • Payments made every 6 months. 0 1 Payment 9%, c.q. = 0.09/4 = 0.045 per 3 months = 2.25% per 3 months CP-1 CP-2 Payment CP-3 Payment Period 1 Payment Period 2 Rule: The interest rate must match the payment period!
  • 51. EGR2302-Engineering Economics Al Akhawayn University 51 4.3 The Matching Rule • Again, the interest must be consistent with the payment period! • We need a 6-month effective rate and then calculate the 1 year true, effective rate! • To compare the 3 plans: – Compute the true, effective 6-month rate or, – Compute the true effective 1 year rate. – Then one can compare the 3 plans!
  • 52. EGR2302-Engineering Economics Al Akhawayn University 52 4.3 Comparing 3 Plans: Plan 1 • 9% per year, c.q. = 2.25%/quarter • Payments made every 6 months. 0 1 CP-4 Payment CP-1 CP-2 Payment CP-3 Payment Period 1 Payment Period 2 True 6-month rate is: (1.0225)2 – 1 = 0.0455 = 4.55% per 6-months EAIR = (1.0225)4 – 1 = 9.31% per year
  • 53. EGR2302-Engineering Economics Al Akhawayn University 53 4.3 Plan 2 • 3% per quarter, c.q. • Effective=3%/quarter • Find the EIR for 6-months • Calculate: – For a 6-month effective interest rate - – (1.03)2 – 1 = 0.0609 = 6.09% per 6-months – Or, for a 1 year effective interest rate - – (1.03)4 – 1 = 12.55%/year
  • 54. EGR2302-Engineering Economics Al Akhawayn University 54 4.3 Plan 3:” 8.8% per year, c.m.” • “r” = 8.8% • “m” = 12 • Payments are twice a year • 6-month nominal rate = 0.088/2 =4.4%/6-months (“r” = 0.044) • EIR6-months = (1 + 0.044/6)6 – 1= (1.0073)6 – 1= 4.48%/ 6-months • EIR12-months = (1 + 0.088/12)12 – 1 = 9.16%/year
  • 55. EGR2302-Engineering Economics Al Akhawayn University 55 4.3 Summarizing the 3 plans…. 9.16% 4.48% 3 12.55% 6.09% 2 9.31% 4.55% 1 1-year 6-month Plan No. Plan 3 presents the lowest interest rate.
  • 56. EGR2302-Engineering Economics Al Akhawayn University 56 4.3 Can be confusing ??? • The 3 plans state interest differently. • Difficult to determine the best plan by mere inspection. • Each plan must be evaluated by: – Calculating the true, effective 6-month rate Or, – Calculating the true, effective 12 month, (1 year) true, effective annual rate. – Then all 3 plans can be compared using the EIR or the EAIR.
  • 57. EGR2302-Engineering Economics Al Akhawayn University 57 Section 4.4: Equivalence: Comparing PP to CP • Reality: – PP and CP’s do not always match up; – May have monthly cash flows but… – Compounding period different than monthly. • Savings Accounts – for example; – Monthly deposits with, – Quarterly interest earned or paid; – They don’t match! • Make them match! (by adjusting the interest period to match the payment period.)
  • 58. EGR2302-Engineering Economics Al Akhawayn University 58 Situations Situation Text Reference • PP = CP Sections 4.5 and 4.6 • PP CP Sections 4.5 and 4.6 • PP CP Section 4.7
  • 59. EGR2302-Engineering Economics Al Akhawayn University 59 Section 4.5 Single Amounts: PP = CP Example1: • “r” = 15%, c.m. (compounded monthly) • Let P = $1500.00 • Find F at t = 2 years. • 15% c.m. = 0.15/12 = 0.0125 = 1.25%/month. • n = 2 years OR 24 months • Work in months or in years
  • 60. EGR2302-Engineering Economics Al Akhawayn University 60 4.5 Single Amounts: PP = CP • Approach 1. (n relates to months) • State: – F24 = $1,500(F/P,0.15/12,24); – i/month = 0.15/12 = 0.0125 (1.25%); – F24 = $1,500(F/P,1.25%,24); – F24 = $1,500(1.0125)24 = $1,500(1.3474); – F24 = $2,021.03.
  • 61. EGR2302-Engineering Economics Al Akhawayn University 61 4.5 Single Amounts: CP = CP • Approach 2. (n relates to years) • State: – F2 = $1,500(F/P,i%,2); – Assume n = 2 (years) we need to apply an annual effective interest rate. – i/month =0.0125 – EAIR = (1.0125)12 – 1 = 0.1608 (16.08%) – F2 = $1,500(F/P,16.08%,2) – F2 = $1,500(1.1608)2 = $2,021.19 – Slight roundoff compared to approach 1
  • 62. EGR2302-Engineering Economics Al Akhawayn University 62 4.5 Example 2. • Consider 0 1 2 3 4 5 6 7 8 9 10 $1,000 $3,000 $1,500 F 10 = ? r = 12%/yr, c.s.a. Suggest you work this in 6- month time frames Count “n” in terms of “6-month” intervals
  • 63. EGR2302-Engineering Economics Al Akhawayn University 63 4.5 Example 2. • Renumber the time line 0 2 4 6 8 10 12 14 16 18 20 $1,000 $3,000 $1,500 F 10 = ? r = 12%/yr, c.s.a. i/6 months = 0.12/2 = 6%/6 months; n counts 6- month time periods
  • 64. EGR2302-Engineering Economics Al Akhawayn University 64 4.5 Example 2. • Compound Forward 0 2 4 6 8 10 12 14 16 18 20 $1,000 $3,000 $1,500 F 20 = ? r = 12%/yr, c.s.a. F20 = $1,000(F/P,6%,20) + $3,000(F/P,6%,12) + $1,500(F/P,6%,8) = $11,634
  • 65. EGR2302-Engineering Economics Al Akhawayn University 65 4.5 Example 2. Let n count years…. • Compound Forward 0 1 2 3 4 5 6 7 8 9 10 $1,000 $3,000 $1,500 F 10 = ? r = 12%/yr, c.s.a. IF n counts years, interest must be an annual rate. EAIR = (1.06)2 - 1 = 12.36% Compute the FV where n is years and i = 12.36%!
  • 66. EGR2302-Engineering Economics Al Akhawayn University 66 Section 4.6 Series Analysis – PP = CP • Find the effective “i” per payment period. • Determine “n” as the total number of payment periods. • “n” will equal the number of cash flow periods in the particular series. • Example follows…..
  • 67. EGR2302-Engineering Economics Al Akhawayn University 67 4.6 Series Example • Consider: 0 1 2 3 4 5 6 7 A = $500 every 6 months F7 = ?? Find F7 if “r” = 20%/yr, c.q. (PP CP) We need i per 6-months – effective. i6-months = adjusting the nominal rate to fit.
  • 68. EGR2302-Engineering Economics Al Akhawayn University 68 4.6 Series Example • Adjusting the interest • r = 20%, c.q. • i/qtr. = 0.20/4 = 0.05 = 5%/qtr. • 2-qtrs in a 6-month period. • i6-months = (1.05)2 – 1 = 10.25%/6-months. • Now, the interest matches the payments. • Fyear 7 = Fperiod 14 = $500(F/A,10.25%,14) • F = $500(28.4891) = $14,244.50
  • 69. EGR2302-Engineering Economics Al Akhawayn University 69 4.6 This Example: Observations • Interest rate must match the frequency of the payments. • In this example – we need effective interest per 6- months: Payments are every 6-months. • The effective 6-month rate computed to equal 10.25% - un-tabulated rate. • Calculate the F/A factor or interpolate. • Or, use a spreadsheet that can quickly determine the correct factor!
  • 70. EGR2302-Engineering Economics Al Akhawayn University 70 4.6 This Example: Observations • Do not attempt to adjust the payments to fit the interest rate! • This is Wrong! • At best a gross approximation – do not do it! • This type of problem almost always results in an un- tabulated interest rate – You have to use your calculator to compute the factor or a spreadsheet model to achieve exact result.
  • 71. EGR2302-Engineering Economics Al Akhawayn University 71 Section 4.7 Single Amounts/Series with PP CP • This situation is different than the last. • Here, PP is less than the compounding period (CP). • Raises questions? • Issue of interperiod compounding • An example follows.
  • 72. EGR2302-Engineering Economics Al Akhawayn University 72 4.7 Interperiod Compounding Issues • Consider a one-year cash flow situation. • Payments are made at end of a given month. • Interest rate is “r = 12%/yr, c.q.” 0 1 2 3 4 5 6 7 8 9 10 11 12 $90 $120 $45 $150 $200 $75 $100 $50
  • 73. EGR2302-Engineering Economics Al Akhawayn University 73 CP-2 CP-1 4.7 Interperiod Compounding • r =12%/yr. c.q. 0 1 2 3 4 5 6 7 8 9 10 11 12 $90 $120 $45 $150 $200 $75 $100 $50 CP-3 CP-4 Note where some of the cash flow amounts fall with respect to the compounding periods!
  • 74. EGR2302-Engineering Economics Al Akhawayn University 74 CP-1 4.7 Take the first $200 cash flow 0 1 2 3 4 5 6 7 8 9 10 11 12 $90 $120 $45 $150 $200 $75 $100 $50 • Will any interest be earned/owed on the $200 since interest is compounded at the end of each quarter? The $200 is at the end of month 2 and will it earn interest for one month to go to the end of the first compounding period? The last month of the first compounding period. Is this an interest-earning period?
  • 75. EGR2302-Engineering Economics Al Akhawayn University 75 4.7 Interperiod Issues • The $200 occurs 1 month before the end of compounding period 1. • Will interest be earned or charged on that $200 for the one month? • If not then the revised cash flow diagram for all of the cash flows should look like…..
  • 76. EGR2302-Engineering Economics Al Akhawayn University 76 0 1 2 3 4 5 6 7 8 9 10 11 12 4.7 No interperiod compounding • Revised CF Diagram $90 $165 $45 $150 $200 $75 $100 $50 $200 $175 $90 $50 All negative CF’s move to the end of their respective quarters and all positive CF’s move to the beginning of their respective quarters.
  • 77. EGR2302-Engineering Economics Al Akhawayn University 77 4.7 No interperiod compounding • Revised CF Diagram 0 1 2 3 4 5 6 7 8 9 10 11 12 $165 $150 $200 $175 $90 $50 Now, determine the future worth of this revised series using the F/P factor on each cash flow.
  • 78. EGR2302-Engineering Economics Al Akhawayn University 78 4.7 Final Results: No interperiod Comp. • With the revised CF compute the future worth. F12 = [-150(F/P3%,4) – 200(F/P,3%,3) + (-175 +90)(F/P,3%,2) + 165(F/P,3%,1) – 50] = $-357.59 “r” = 12%/year, compounded quarterly “i” = 0.12/4 = 0.03 = 3% per quarter
  • 79. EGR2302-Engineering Economics Al Akhawayn University 79 CP-2 CP-1 4.7 Interperiod Compounding • r =12%/yr. c.q. 0 1 2 3 4 5 6 7 8 9 10 11 12 $90 $120 $45 $150 $200 $75 $100 $50 CP-3 CP-4 The cash flows are not moved and equivalent P, F, or A values are determined using the effective interest rate per payment period
  • 80. EGR2302-Engineering Economics Al Akhawayn University 80 CP-2 CP-1 4.7 Interperiod Compounding • r =12%/yr. c.q. 0 1 2 3 4 5 6 7 8 9 10 11 12 $90 $120 $45 $150 $200 $75 $100 $50 CP-3 CP-4 If the inter-period compounding is earned, then we should compute the effective interest rate per compounding period. i=3% is the effective quarterly rate Imonthly=(1+i)1/3-1=(1.03)1/3-1=0.99%
  • 81. EGR2302-Engineering Economics Al Akhawayn University 81 Topics to Be Covered in Today’s Lecture Section 4.8: Continuous Compounding Section 4.9: Interest Rates that vary over time
  • 82. EGR2302-Engineering Economics Al Akhawayn University 82 Section 4.8 Continuous Compounding • Recall: – EAIR = i = (1 + r/m)m – 1 – What happens if we let m approach infinity? – That means an infinite number of compounding periods within a year or, – The time between compounding approaches “0”. – We will see that a limiting value will be approached for a given value of “r”
  • 83. EGR2302-Engineering Economics Al Akhawayn University 83 4.8 Derivation of Continuous Compounding • We can state, in general terms for the EAIR: (1 ) 1 m r i m = + − Now, examine the impact of letting “m” approach infinity.
  • 84. EGR2302-Engineering Economics Al Akhawayn University 84 4.8 Derivation of Continuous Compounding • We re-define the EAIR general form as: (1 ) 1 1 1 r m r m r r m m       + − = + −         Note – the term in brackets has the exponent changed but all is still the same….
  • 85. EGR2302-Engineering Economics Al Akhawayn University 85 4.8 Derivation of Continuous Compounding • There is a reason for the re-definition. • From the calculus of limits there is an important limit that is quite useful. • Specifically: 1 lim 1 2.71828 h h e h →∞   + = =    
  • 86. EGR2302-Engineering Economics Al Akhawayn University 86 4.8 Derivation of Continuous Compounding • Substituting we can see: lim 1 , m r m r e m →∞   + =    
  • 87. EGR2302-Engineering Economics Al Akhawayn University 87 4.8 Derivation of Continuous Compounding • So that: lim 1 1 1. r m r r m r i e m →∞       = + − = −         Summarizing…….
  • 88. EGR2302-Engineering Economics Al Akhawayn University 88 4.8 Derivation of Continuous Compounding • The EAIR when interest is compounded continuously is then: EAIR = er – 1 Where “r” is the nominal rate of interest compounded continuously. This is the max. interest rate for any value of “r” compounded continuously.
  • 89. EGR2302-Engineering Economics Al Akhawayn University 89 4.8 Derivation of Continuous Compounding • Example: • What is the true, effective annual interest rate if the nominal rate is given as: – r = 18%, compounded continuously – Or, r = 18% c.c. Solve e0.18 – 1 = 1.1972 – 1 = 19.72%/year The 19.72% represents the MAXIMUM EAIR for 18% compounded anyway you choose!
  • 90. EGR2302-Engineering Economics Al Akhawayn University 90 4.8 Finding “r” from the EAIR/cont. compounding • To find the equivalent nominal rate given the EAIR when interest is compounded continuously, apply: ln(1 ) r i = +
  • 91. EGR2302-Engineering Economics Al Akhawayn University 91 4.8 Example • Given r = 18% per year, cc, find: – A. the effective monthly rate – B. the effective annual rate a. r/month = 0.18/12 = 1.5%/month Effective monthly rate is e0.015 – 1 = 1.511% b. The effective annual interest rate is e0.18 – 1 = 19.72% per year.
  • 92. EGR2302-Engineering Economics Al Akhawayn University 92 4.8 Example • An investor requires an effective return of at least 15% per year. • What is the minimum annual nominal rate that is acceptable if interest on his investment is compounded continuously? To start: er – 1 = 0.15 Solve for “r” ………
  • 93. EGR2302-Engineering Economics Al Akhawayn University 93 4.8 Example • er – 1 = 0.15 • er = 1.15 • ln(er) = ln(1.15) • r = ln(1.15) = 0.1398 = 13.98% A rate of 13.98% per year, cc. generates the same as 15% true effective annual rate.
  • 94. EGR2302-Engineering Economics Al Akhawayn University 94 4.8 Final Thoughts • When comparing different statements of interest rate one must always compute to true, effective annual rate (EAIR) for each quotation. • Only EAIR’s can be compared! • Various nominal rates cannot be compared unless each nominal rate is converted to its respective EAIR!
  • 95. EGR2302-Engineering Economics Al Akhawayn University 95 Section 4.9 Interest Rates that vary over time • In practice – interest rates do not stay the same over time unless by contractual obligation. • There can exist “variation” of interest rates over time – quite normal! • If required, how do you handle that situation?
  • 96. EGR2302-Engineering Economics Al Akhawayn University 96 4.9 Interest Rates that vary over time • Best illustrated by an example. • Assume the following future profits: 0 1 2 3 4 $70,000 $70,000 $35,000 $25,000 7% 7% 9% 10% (P/F,7%,1) (P/F,7%,2) (P/F,9%,3) (P/F,10%,4)
  • 97. EGR2302-Engineering Economics Al Akhawayn University 97 4.9 Varying Rates: Present Worth • To find the Present Worth: – Bring each cash flow amount back to the appropriate point in time at the interest rate according to: • P = F1(P/F.i1,1) + F2(P/F,i1)(P/F,i2) + … • + Fn(P/F,i1)(P/F,i2)(P/F,i3)…(P/F,in,1) This Process can get computationally involved!
  • 98. EGR2302-Engineering Economics Al Akhawayn University 98 4.9 Period-by-Period Analysis • P0 =: 1. $7000(P/F,7%,1) 2. $7000(P/F,7%,1)(P/F,7%,1) 3. $35000(P/F,9%,1)(P/F,7%,1)2 4. $25000(P/F,10%,1)(P/F,9%,1)(P/F,7%,1)2 Equals: $172,816 at t = 0… Work backwards one period at a time until you get to “0”.
  • 99. EGR2302-Engineering Economics Al Akhawayn University 99 4.9 Varying Rates: Approximation • An alternative approach that approximates the present value: • Average the interest rates over the appropriate number of time periods. • Example: – {7% + 7% + 9% + 10%}/4 = 8.25%; – Work the problem with an 8.25% rate; – Merely an approximation.
  • 100. EGR2302-Engineering Economics Al Akhawayn University 100 4.9 Varying Rates: Single, Future Cash Flow • Assume the following Cash Flow: 0 1 2 3 4 8% 9% 10% 11% $10,000 Objective: Find P0 at the varying rates P0 = $10,000(P/F,8%,1)(P/F,9%,1)(P/F,10%,1)(P/F,11%,1) = $10,000(0.9259)(0.9174)(0.9091)(0.9009) = $10,000(0.6957) = $6,957
  • 101. EGR2302-Engineering Economics Al Akhawayn University 101 4.9 Varying Rates: Observations • We seldom evaluate problem models with varying interest rates except in special cases. • If required, best to build a spreadsheet model • A cumbersome task to perform.
  • 102. EGR2302-Engineering Economics Al Akhawayn University 102 Chapter 4 Summary • Many applications use and apply nominal and effective compounding • Given a nominal rate – must get the interest rate to match the frequency of the payments. • Apply the effective interest rate per payment period. – PP = CP (adjusting the interest period to match the payment period) – PP CP (Consider inter-period compounding or not?) • When comparing varying interest rates, must calculate the EAIR in order to compare.
  • 103. EGR2302-Engineering Economics Al Akhawayn University 103 Chapter Summary – cont. • All time value of money interest factors require use of an effective (true) periodic interest rate. • The interest rate, i, and the payment or cash flow periods must have the same time unit. • One may encounter varying interest rates and an exact answer requires a sequence of interest rates – cumbersome!
  • 104. EGR2302-Engineering Economics Al Akhawayn University 104 Assignments and Announcements Homework 3 due a week from today Assignments due at the beginning of next class: Answer the three online quizzes on chapter 4 on the text’s website. Read chapter 5.1, 5.2 and 5.3