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11
General
Mathematics
Quarter 1 โ€“ Module 7:
Exponential Functions
General Mathematics โ€“ Grade 11
Self-Learning Module (SLM)
Quarter 1 โ€“ Module 7: Exponential Functions
First Edition, 2020
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Every effort has been exerted to locate and seek permission to use these materials from their
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over them.
Printed in the Philippines by Department of Education โ€“ SOCCSKSARGEN Region
Office Address: Regional Center, Brgy. Carpenter Hill, City of Koronadal
Telefax: (083) 2288825/ (083) 2281893
E-mail Address: region12@deped.gov.ph
Development Team of the Module
Writers: Mariel Villanueva
Editors: Venus P. Enumerables
Reviewers: Venus P. Enumerables
Illustrator: Ian Caesar E. Frondoza
Layout Artist: Maylene F. Grigana
Cover Art Designer: Ian Caesar E. Frondoza
Management Team: Allan G. Farnazo, CESO IV โ€“ Regional Director
Fiel Y. Almendra, CESO V โ€“ Assistant Regional Director
Gildo G. Mosqueda, CEO V
Diosdado F. Ablanido, CPA
Gilbert B. Barrera โ€“ Chief, CLMD
Arturo D. Tingson Jr. โ€“ REPS, LRMS
Peter Van C. Ang-ug โ€“ REPS, ADM
Jade T. Palomar โ€“ REPS, Mathematics
Donna S. Panes โ€“ Chief, CID
Elizabeth G. Torres โ€“ EPS, LRMS
Judith B. Alba โ€“ EPS, ADM
Reynaldo C. Tagala โ€“ EPS, Mathematics
11
General
Mathematics
Quarter 1 โ€“ Module 4:
Exponential Functions
4
Introductory Message
For the facilitator:
Welcome to the Grade 11 General Mathematics Self-Learning Module (SLM) on
Exponential Functions!
This module was collaboratively designed, developed and reviewed by educators both
from public and private institutions to assist you, the teacher or facilitator in helping
the learners meet the standards set by the K to 12 Curriculum while overcoming
their personal, social, and economic constraints in schooling.
This learning resource hopes to engage the learners into guided and independent
learning activities at their own pace and time. Furthermore, this also aims to help
learners acquire the needed 21st century skills while taking into consideration their
needs and circumstances.
In addition to the material in the main text, you will also see this box in the body of
the module:
As a facilitator you are expected to orient the learners on how to use this module.
You also need to keep track of the learners' progress while allowing them to manage
their own learning. Furthermore, you are expected to encourage and assist the
learners as they do the tasks included in the module.
Notes to the Teacher
This contains helpful tips or strategies that
will help you in guiding the learners.
5
For the learner:
Welcome to the Grade 11 General Mathematics Self-Learning Module (SLM) on
Exponential Functions!
The hand is one of the most symbolized part of the human body. It is often used to
depict skill, action and purpose. Through our hands we may learn, create and
accomplish. Hence, the hand in this learning resource signifies that you as a learner
is capable and empowered to successfully achieve the relevant competencies and
skills at your own pace and time. Your academic success lies in your own hands!
This module was designed to provide you with fun and meaningful opportunities for
guided and independent learning at your own pace and time. You will be enabled to
process the contents of the learning resource while being an active learner.
This module has the following parts and corresponding icons:
What I Need to Know This will give you an idea of the skills or
competencies you are expected to learn in the
module.
What I Know This part includes an activity that aims to
check what you already know about the
lesson to take. If you get all the answers
correct (100%), you may decide to skip this
module.
Whatโ€™s In This is a brief drill or review to help you link
the current lesson with the previous one.
Whatโ€™s New In this portion, the new lesson will be
introduced to you in various ways such as a
story, a song, a poem, a problem opener, an
activity or a situation.
What is It This section provides a brief discussion of the
lesson. This aims to help you discover and
understand new concepts and skills.
Whatโ€™s More This comprises activities for independent
practice to solidify your understanding and
skills of the topic. You may check the
answers to the exercises using the Answer
Key at the end of the module.
What I Have Learned This includes questions or blank
sentence/paragraph to be filled in to process
what you learned from the lesson.
What I Can Do This section provides an activity which will
help you transfer your new knowledge or skill
into real life situations or concerns.
6
Assessment This is a task which aims to evaluate your
level of mastery in achieving the learning
competency.
Additional Activities In this portion, another activity will be given
to you to enrich your knowledge or skill of the
lesson learned. This also tends retention of
learned concepts.
Answer Key This contains answers to all activities in the
module.
At the end of this module you will also find:
The following are some reminders in using this module:
1. Use the module with care. Do not put unnecessary mark/s on any part of the
module. Use a separate sheet of paper in answering the exercises.
2. Donโ€™t forget to answer What I Know before moving on to the other activities
included in the module.
3. Read the instruction carefully before doing each task.
4. Observe honesty and integrity in doing the tasks and checking your answers.
5. Finish the task at hand before proceeding to the next.
6. Return this module to your teacher/facilitator once you are through with it.
If you encounter any difficulty in answering the tasks in this module, do not
hesitate to consult your teacher or facilitator. Always bear in mind that you are
not alone.
We hope that through this material, you will experience meaningful learning and
gain deep understanding of the relevant competencies. You can do it!
References This is a list of all sources used in developing
this module.
7
What I Need to Know
This module was designed and written with you in mind. It is here to help you
master illustrating Exponential Functions. The scope of this module permits it to be
used in many different learning situations. The language used recognizes the diverse
vocabulary level of students. The lessons are arranged to follow the standard
sequence of the course. But the order in which you read them can be changed to
correspond with the textbook you are now using.
This module presents the lesson in the following outline:
1. Review: Properties of Exponents
2. Solving exponential equations
3. Solving exponential inequalities
4. Solving problems involving exponential functions
After going through this module, you are expected to:
1. solve exponential equations;
2. solve exponential inequalities; and
3. solve problems involving exponential functions
8
What I Know
Find how much you already know about the topic in this module. Take note of the
items that you were not able to answer correctly and find the right answer as you go
through this module.
A. Determine whether each of the following expression is an exponential equation,
exponential inequality or none of these.
1. ๐‘“(๐‘ฅ) = 2๐‘ฅ3
2. ๐‘”(๐‘ฅ) = 2๐‘ฅ
3. ๐‘ฆ = โ…‡๐‘ฅ
4. 22(5๐‘ฅ+1) = 500
5. 625 โ‰ฅ 5๐‘ฅ+8
B. Match Column A with Column B.
Column A Column B
6. 3๐‘ฅ
= 81 A. {๐‘ฅ โˆˆ โ„|๐‘ฅ โ‰ค โˆ’2}
7. 5๐‘ฅ+7
= 125 B. {๐‘ฅ โˆˆ โ„|๐‘ฅ < โˆ’2}
8. (
4
6
)
๐‘ฅ
โ‰ฅ
36
16
C. ๐‘ฅ = 4
9. 5๐‘ฅ
> 25๐‘ฅ+1
D. ๐‘ฅ = โˆ’4
C. Read and solve the problem below.
10. Coffee contains caffeine. The half-life of caffeine is 5 hours . This means
the amount of caffeine in your bloodstream is reduced by 50% every 5
hours. Suppose you drink a cup of coffee that contains 320 mg of caffeine.
How long will it take until there is 5 mg of caffeine left in your bloodstream?
9
Lesson
7
Solving Exponential
Equations, Inequalities, and
Functions
For this module, you need to review your lessons on the definition of zero and
negative exponents and on the laws of exponent.
Definition of Zero and Negative Exponents. Let ๐‘Ž โ‰  0. We define the following:
1. ๐‘Ž0
= 1
2. ๐‘Žโˆ’๐‘›
=
1
๐‘Ž๐‘›
Theorem. Let ๐‘Ÿ and ๐‘  be rational numbers. Then
1. ๐‘Ž๐‘Ÿ
๐‘Ž๐‘ 
= ๐‘Ž๐‘Ÿ+๐‘ 
2.
๐‘Ž๐‘Ÿ
๐‘Ž๐‘  = ๐‘Ž๐‘Ÿโˆ’๐‘ 
3. (๐‘Ž๐‘Ÿ)๐‘ 
= ๐‘Ž๐‘Ÿ๐‘ 
4. (๐‘Ž๐‘)๐‘Ÿ
= ๐‘Ž๐‘Ÿ
๐‘๐‘Ÿ
5. (
๐‘Ž
๐‘
)
๐‘Ÿ
=
๐‘Ž๐‘Ÿ
๐‘๐‘Ÿ
Whatโ€™s New
Activity 1 Classify Me!
Given:
(a) 49 = 7๐‘ฅ+1
(e) 8๐‘ฅ = ๐‘ฅ2
โˆ’ 9
(b) 7 = 2๐‘ฅ + 3 (f) ๐‘ฅ2
= 3๐‘ฅ3
+ 2๐‘ฅ + 1
(c) 3๐‘ฅ
= 32๐‘ฅโˆ’1
(g) 2๐‘ฅ + 3 > ๐‘ฅ โˆ’ 1
(d) 5๐‘ฅโˆ’1
= 125 (h) 2๐‘ฅโˆ’2
> 8
Questions
1. Which of the given above are exponential equations?
2. Which of the given above are exponential inequalities?
Whatโ€™s In
10
Activity 2 We have something in common
Complete the table below. Identify the base that can be used in expressing the
given pair of numbers in exponential form. The example is done for you.
Example.
First Number Exponential
Form
Second
Number
Exponential
Form
Common
Base
1. 125 53 25 52 5
First Number Exponential
Form
Second
Number
Exponential
Form
Common
Base
1. 8 32
2 36 216
3 1
4
1
32
4 0.0625 0.5
5 1
100
1
10
What is It
Solving Exponential Equation
One โ€“ to โ€“ one Property of Exponential Functions will be used in solving
exponential equations.
One to one Property of Exponential Functions
If ๐‘ฅ1 โ‰  ๐‘ฅ2, then ๐‘๐‘ฅ1 โ‰  ๐‘๐‘ฅ2. Conversely, if ๐‘๐‘ฅ1 = ๐‘๐‘ฅ2then ๐‘ฅ1 = ๐‘ฅ2
Example 1. Solve the equation 4๐‘ฅโˆ’1
= 16
Solution. Write both sides with 4 as the base.
4๐‘ฅโˆ’1
= 42
๐‘ฅ โˆ’ 1 = 2
๐‘ฅ = 2 + 1
๐‘ฅ = 3
11
Alternate Solution. Write both sides with 2 as the base
(22)๐‘ฅโˆ’1
= 24
22(๐‘ฅโˆ’1)
= 24
2(๐‘ฅ โˆ’ 1) = 4
2๐‘ฅ โˆ’ 2 = 4
2๐‘ฅ = 4 + 2
2๐‘ฅ = 6
2๐‘ฅ
2
=
6
2
๐‘ฅ = 3
Example 2. Solve the equation 125๐‘ฅโˆ’1
= 25๐‘ฅ+3
Solution. Both 125 and 25 can be written using 5 as the base.
(53)๐‘ฅโˆ’1
= (52)๐‘ฅ+3
53(๐‘ฅโˆ’1)
= 52(๐‘ฅ+3)
3(๐‘ฅ โˆ’ 1) = 2(๐‘ฅ + 3)
3๐‘ฅ โˆ’ 3 = 2๐‘ฅ + 6
3๐‘ฅ โˆ’ 2๐‘ฅ = 6 + 3
๐‘ฅ = 9
Example 3. Solve 9๐‘ฅ2
= 3๐‘ฅ+3
.
Solution. Both 9 and 3 can be written using 3 as the base.
(32)๐‘ฅ2
= 3๐‘ฅ+3
32๐‘ฅ2
= 3๐‘ฅ+3
2๐‘ฅ2
= ๐‘ฅ + 3
2๐‘ฅ2
โˆ’ ๐‘ฅ โˆ’ 3 = 0
(2๐‘ฅ โˆ’ 3)(๐‘ฅ + 1) = 0
2๐‘ฅ โˆ’ 3 = 0 or ๐‘ฅ + 1 = 0
2๐‘ฅ = 3 ๐‘ฅ = โˆ’1
2๐‘ฅ
2
=
3
2
๐‘ฅ =
3
2
12
Solving Exponential Inequality
Property of Exponential Inequalities
If ๐‘ > 1, then the exponential function ๐‘ฆ = ๐‘๐‘ฅ
is increasing for all x. This means
that ๐‘๐‘ฅ
< ๐‘๐‘ฆ
if and only if ๐‘ฅ < ๐‘ฆ.
If 0 < ๐‘ < 1, then the exponential function ๐‘ฆ = ๐‘๐‘ฅ
is decreasing for all x. This
means that ๐‘๐‘ฅ
> ๐‘๐‘ฆ
if and only if ๐‘ฅ < ๐‘ฆ.
Example 4. Solve the inequality 3๐‘ฅ
< 9๐‘ฅโˆ’2
Solution. Both 9 and 3 can be written using 3 as the base.
3๐‘ฅ
< 9๐‘ฅโˆ’2
3๐‘ฅ
< (32)๐‘ฅโˆ’2
3๐‘ฅ
< 32(๐‘ฅโˆ’2)
3๐‘ฅ
< 32๐‘ฅโˆ’4
Since the base 3 > 1, then the inequality is equivalent to
๐‘ฅ < 2๐‘ฅ โˆ’ 4 (the direction of inequality is retained)
4 < 2๐‘ฅ โˆ’ ๐‘ฅ
4 < ๐‘ฅ
The solution set to the inequality is {๐‘ฅ โˆˆ โ„|๐‘ฅ > 4}
Example 5. Solve the inequality (
1
10
)
๐‘ฅ+5
โ‰ฅ (
1
100
)
3๐‘ฅ
Solution. Since,
1
100
= (
1
10
)
2
, then we write both sides of the inequality with
1
10
as
the base.
(
1
10
)
๐‘ฅ+5
โ‰ฅ (
1
100
)
3๐‘ฅ
(
1
10
)
๐‘ฅ+5
โ‰ฅ (
1
102)
3๐‘ฅ
(
1
10
)
๐‘ฅ+5
โ‰ฅ (
1
10
)
2(3๐‘ฅ)
(
1
10
)
๐‘ฅ+5
โ‰ฅ (
1
10
)
6x)
13
Since the base
1
10
< 1, then this inequality is equivalent to
๐‘ฅ + 5 โ‰ค 6๐‘ฅ (the direction of the inequality is reversed)
5 โ‰ค 6๐‘ฅ โˆ’ ๐‘ฅ
5 โ‰ค 5๐‘ฅ
5x
5
โ‰ค
5
5
1 โ‰ค ๐‘ฅ
The solution set to the inequality is {๐‘ฅ โˆˆ โ„|๐‘ฅ โ‰ฅ 1}
Solving Problems Involving Exponential Function (Half โ€“ Life)
Example 6. The half life of Zn -71 is 2.45 minutes. At ๐‘ก = 0 there were ๐‘ฆ0 grams of
Zn-71, but only
1
256
of this amount remains after some time. How much time has
passed?
Solution. The half โ€“ life of substance can be calculated by the formula ๐‘(๐‘ก) = ๐‘0 (
1
2
)
๐‘ก
๐‘ก
1
2
where ๐‘(๐‘ก) =quantity of the substance remaining
๐‘0 = initial quantity of the substance
๐‘ก = time elapsed
๐‘ก
1
2
= half life of the substance
Given ๐‘ก
1
2
= 45 minutes ๐‘0 = ๐‘ฆ0
๐‘(๐‘ก) =
1
256
๐‘ฆ0 ๐‘ก=?
Substitute
๐‘(๐‘ก) = ๐‘0 (
1
2
)
๐‘ก
๐‘ก
1
2
1
256
๐‘ฆ0 = ๐‘ฆ0 (
1
2
)
๐‘ก
2.45
1
256
= (
1
2
)
๐‘ก
2.45
(
1
2
)
8
= (
1
2
)
๐‘ก
2.45
8 =
๐‘ก
2.45
๐‘ก = (8)(2.45)
๐‘ก = 19.6 minutes
14
Whatโ€™s More
Activity 3 What is that animal?
Solve the following exponential equations and inequalities. Write the letter
code on the box that corresponds to the answer of the given expressions.
What is the only animal that never gets sick?
A
162๐‘ฅโˆ’3
= 4๐‘ฅ+2
H
7๐‘ฅ+4
= 492๐‘ฅโˆ’1
E
4๐‘ฅ+2
= 82๐‘ฅ
K
42๐‘ฅ+7
โ‰ค 322๐‘ฅโˆ’3
R
(
2
5
)
5๐‘ฅโˆ’1
โ‰ฅ
25
4
S
(
2
3
)
5๐‘ฅ+2
< (
3
2
)
2๐‘ฅ
๐‘ฅ >
โˆ’2
7
๐‘ฅ = 2
๐‘ฅ =
8
3
๐‘ฅ โ‰ฅ
โˆ’1
5
๐‘ฅ โ‰ฅ
29
6
15
What I Have Learned
Activity 4 Am I the truth?
Write TRUE if the given statement is correct and write FALSE if the given
statement is wrong.
1. In solving the exponential equation 42๐‘ฅ+7
= 322๐‘ฅโˆ’3
, 4 and 32 can be
written using 2 as the base.
2. In solving the exponential inequality (0.6)๐‘ฅโˆ’3
> (0.6)โˆ’2๐‘ฅโˆ’2
, the inequality
symbol will not be reversed because 0.6 > 1.
3. The expression 5๐‘ฅโˆ’2
> 125 is an example of exponential inequality.
4. The solution of the exponential equation 7๐‘ฅ+4
= 492๐‘ฅโˆ’1
is ๐‘ฅ = 4.
5. The solution set to the inequality 10๐‘ฅ
> 100โˆ’2๐‘ฅโˆ’5
is {๐‘ฅ โˆˆ โ„|๐‘ฅ > โˆ’2}
What I Can Do
Activity 5 Solve Me
Solve the following.
1. 162๐‘ฅโˆ’3
= 4๐‘ฅ+2
2. 42๐‘ฅ+7
โ‰ค 322๐‘ฅโˆ’3
3. Paracetamol is a drug is used to treat mild to moderate pain and to reduce
fever. It has a half โ€“ life in the body of 3 hours. Under a Doctor's care,
Patient N is given a dose of a certain paracetamol. Patient N asks the
doctor for another the same dose of this paracetamol. The doctor agrees to
allow patient N to take dose once there is only 6.25% of the original dose
remaining in the body. How long will patient N have to wait, before taking
another dose of this paracetamol?
16
Assessment
A. Solve for ๐‘ฅ.
1. 53๐‘ฅ+8
= 252๐‘ฅ
2. (
3
5
)
๐‘ฅ+1
=
25
9
3. 43๐‘ฅ+2
< 64
4. (
49
81
)
๐‘ฅ+1
โ‰ฅ
9
7
B. Read and solve the given problem.
5. A certain pain reliever has a half-life of 16 hours. If the initial plasma
level of this pain relieverg, given as a single dose, is 512mg/L, how long
will it take for the plasma level to fall to 16 mg/L?
Additional Activities
Activity 6 Who is right?
1. John and Peter are solving (0.6)๐‘ฅโˆ’3
> (0.36)โˆ’xโˆ’1
. Did anyone get the correct
solution? If not, spot the error or errors.
John Peter
(0.6)๐‘ฅโˆ’3
> (0.36)โˆ’๐‘ฅโˆ’1 (0.6)๐‘ฅโˆ’3
> (0.36)โˆ’๐‘ฅโˆ’1
(0.6)๐‘ฅโˆ’3
> (0.62)โˆ’๐‘ฅโˆ’1 (0.6)๐‘ฅโˆ’3
> (0.62)โˆ’๐‘ฅโˆ’1
(0.6)๐‘ฅโˆ’3
> (0.6)2(โˆ’๐‘ฅโˆ’1) (0.6)๐‘ฅโˆ’3
> (0.6)2(โˆ’๐‘ฅโˆ’1)
(0.6)๐‘ฅโˆ’3
> (0.6)โˆ’2๐‘ฅโˆ’2 (0.6)๐‘ฅโˆ’3
> (0.6)โˆ’2๐‘ฅโˆ’2
๐‘ฅ โˆ’ 3 > โˆ’2๐‘ฅ โˆ’ 2 ๐‘ฅ โˆ’ 3 < โˆ’2๐‘ฅ โˆ’ 2
๐‘ฅ + 2๐‘ฅ > โˆ’2 + 3 ๐‘ฅ + 2๐‘ฅ < โˆ’2 + 3
3๐‘ฅ > 1 3๐‘ฅ < 1
3๐‘ฅ
3
>
1
3
3๐‘ฅ
3
<
1
3
๐‘ฅ >
1
3
๐‘ฅ <
1
3
17
Answer Key
What
I
can
do
1.
๐‘ฅ
=
8
3
2.
๐‘ฅ
โ‰ฅ
29
6
3.
t
=
12
hours
Assessment
1.
๐‘ฅ
=
8
2.
๐‘ฅ
=
โˆ’3
3.
๐‘ฅ
<
1
3
4.
๐‘ฅ
โ‰ค
โˆ’
3
2
5.
t
=
80
hours
Additional
Activities
1.
Peter
is
right.
The
inequality
symbol
should
reversed
since
0
โ‹…
6
<
1
What's
New
1.
(a),
(c),
(d)
2.
(h)
1.
2
3
,
2
5
,
2
2.
6
2
,
6
3
,
6
3.
(
1
2
)
2
,
(
1
2
)
5
,
1
2
4.
(0.5)
2
,
(0.5)
1
,
0.5
5.
(
1
10
)
2
,
(
1
10
)
1
,
1
10
Whatโ€™s
More
A.
๐‘ฅ
=
8
3
H.
๐‘ฅ
=
2
E.
๐‘ฅ
=
1
K.
๐‘ฅ
โ‰ฅ
29
6
R.
๐‘ฅ
โ‰ฅ
โˆ’1
5
S.
๐‘ฅ
>
โˆ’2
7
SHARK
What
I
Have
Learned?
1.
TRUE
2.
FALSE
3.
TRUE
4.
FALSE
5.
TRUE
What
I
Know
1.
None
of
these
2.
None
of
these
3.
None
of
these
4.
Exponential
equation
5.
Exponential
inequality
6.
C
7.
D
8.
A
9.
B
10.
30
hours
18
References
1. Department of Education-Bureau of Learning Resources (DepEd-BLR)
(2016) General Mathematics Learnerโ€™s Material. Lexicon Press Inc.,
Philippines
2. Department of Education-Bureau of Learning Resources (DepEd-BLR) (2016)
General Mathematics
19
DISCLAIMER
This Self-learning Module (SLM) was developed by DepEd SOCCSKSARGEN
with the primary objective of preparing for and addressing the new normal.
Contents of this module were based on DepEdโ€™s Most Essential Learning
Competencies (MELC). This is a supplementary material to be used by all
learners of Region XII in all public schools beginning SY 2020-2021. The
process of LR development was observed in the production of this module.
This is version 1.0. We highly encourage feedback, comments, and
recommendations.
For inquiries or feedback, please write or call:
Department of Education โ€“ SOCCSKSARGEN
Learning Resource Management System (LRMS)
Regional Center, Brgy. Carpenter Hill, City of Koronadal
Telefax No.: (083) 2288825/ (083) 2281893
Email Address: region12@deped.gov.ph

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  • 1. 11 General Mathematics Quarter 1 โ€“ Module 7: Exponential Functions
  • 2. General Mathematics โ€“ Grade 11 Self-Learning Module (SLM) Quarter 1 โ€“ Module 7: Exponential Functions First Edition, 2020 Republic Act 8293, section 176 states that: No copyright shall subsist in any work of the Government of the Philippines. However, prior approval of the government agency or office wherein the work is created shall be necessary for exploitation of such work for profit. Such agency or office may, among other things, impose as a condition the payment of royalties. Borrowed materials (i.e., songs, stories, poems, pictures, photos, brand names, trademarks, etc.) included in this module are owned by their respective copyright holders. Every effort has been exerted to locate and seek permission to use these materials from their respective copyright owners. The publisher and authors do not represent nor claim ownership over them. Printed in the Philippines by Department of Education โ€“ SOCCSKSARGEN Region Office Address: Regional Center, Brgy. Carpenter Hill, City of Koronadal Telefax: (083) 2288825/ (083) 2281893 E-mail Address: region12@deped.gov.ph Development Team of the Module Writers: Mariel Villanueva Editors: Venus P. Enumerables Reviewers: Venus P. Enumerables Illustrator: Ian Caesar E. Frondoza Layout Artist: Maylene F. Grigana Cover Art Designer: Ian Caesar E. Frondoza Management Team: Allan G. Farnazo, CESO IV โ€“ Regional Director Fiel Y. Almendra, CESO V โ€“ Assistant Regional Director Gildo G. Mosqueda, CEO V Diosdado F. Ablanido, CPA Gilbert B. Barrera โ€“ Chief, CLMD Arturo D. Tingson Jr. โ€“ REPS, LRMS Peter Van C. Ang-ug โ€“ REPS, ADM Jade T. Palomar โ€“ REPS, Mathematics Donna S. Panes โ€“ Chief, CID Elizabeth G. Torres โ€“ EPS, LRMS Judith B. Alba โ€“ EPS, ADM Reynaldo C. Tagala โ€“ EPS, Mathematics
  • 3. 11 General Mathematics Quarter 1 โ€“ Module 4: Exponential Functions
  • 4. 4 Introductory Message For the facilitator: Welcome to the Grade 11 General Mathematics Self-Learning Module (SLM) on Exponential Functions! This module was collaboratively designed, developed and reviewed by educators both from public and private institutions to assist you, the teacher or facilitator in helping the learners meet the standards set by the K to 12 Curriculum while overcoming their personal, social, and economic constraints in schooling. This learning resource hopes to engage the learners into guided and independent learning activities at their own pace and time. Furthermore, this also aims to help learners acquire the needed 21st century skills while taking into consideration their needs and circumstances. In addition to the material in the main text, you will also see this box in the body of the module: As a facilitator you are expected to orient the learners on how to use this module. You also need to keep track of the learners' progress while allowing them to manage their own learning. Furthermore, you are expected to encourage and assist the learners as they do the tasks included in the module. Notes to the Teacher This contains helpful tips or strategies that will help you in guiding the learners.
  • 5. 5 For the learner: Welcome to the Grade 11 General Mathematics Self-Learning Module (SLM) on Exponential Functions! The hand is one of the most symbolized part of the human body. It is often used to depict skill, action and purpose. Through our hands we may learn, create and accomplish. Hence, the hand in this learning resource signifies that you as a learner is capable and empowered to successfully achieve the relevant competencies and skills at your own pace and time. Your academic success lies in your own hands! This module was designed to provide you with fun and meaningful opportunities for guided and independent learning at your own pace and time. You will be enabled to process the contents of the learning resource while being an active learner. This module has the following parts and corresponding icons: What I Need to Know This will give you an idea of the skills or competencies you are expected to learn in the module. What I Know This part includes an activity that aims to check what you already know about the lesson to take. If you get all the answers correct (100%), you may decide to skip this module. Whatโ€™s In This is a brief drill or review to help you link the current lesson with the previous one. Whatโ€™s New In this portion, the new lesson will be introduced to you in various ways such as a story, a song, a poem, a problem opener, an activity or a situation. What is It This section provides a brief discussion of the lesson. This aims to help you discover and understand new concepts and skills. Whatโ€™s More This comprises activities for independent practice to solidify your understanding and skills of the topic. You may check the answers to the exercises using the Answer Key at the end of the module. What I Have Learned This includes questions or blank sentence/paragraph to be filled in to process what you learned from the lesson. What I Can Do This section provides an activity which will help you transfer your new knowledge or skill into real life situations or concerns.
  • 6. 6 Assessment This is a task which aims to evaluate your level of mastery in achieving the learning competency. Additional Activities In this portion, another activity will be given to you to enrich your knowledge or skill of the lesson learned. This also tends retention of learned concepts. Answer Key This contains answers to all activities in the module. At the end of this module you will also find: The following are some reminders in using this module: 1. Use the module with care. Do not put unnecessary mark/s on any part of the module. Use a separate sheet of paper in answering the exercises. 2. Donโ€™t forget to answer What I Know before moving on to the other activities included in the module. 3. Read the instruction carefully before doing each task. 4. Observe honesty and integrity in doing the tasks and checking your answers. 5. Finish the task at hand before proceeding to the next. 6. Return this module to your teacher/facilitator once you are through with it. If you encounter any difficulty in answering the tasks in this module, do not hesitate to consult your teacher or facilitator. Always bear in mind that you are not alone. We hope that through this material, you will experience meaningful learning and gain deep understanding of the relevant competencies. You can do it! References This is a list of all sources used in developing this module.
  • 7. 7 What I Need to Know This module was designed and written with you in mind. It is here to help you master illustrating Exponential Functions. The scope of this module permits it to be used in many different learning situations. The language used recognizes the diverse vocabulary level of students. The lessons are arranged to follow the standard sequence of the course. But the order in which you read them can be changed to correspond with the textbook you are now using. This module presents the lesson in the following outline: 1. Review: Properties of Exponents 2. Solving exponential equations 3. Solving exponential inequalities 4. Solving problems involving exponential functions After going through this module, you are expected to: 1. solve exponential equations; 2. solve exponential inequalities; and 3. solve problems involving exponential functions
  • 8. 8 What I Know Find how much you already know about the topic in this module. Take note of the items that you were not able to answer correctly and find the right answer as you go through this module. A. Determine whether each of the following expression is an exponential equation, exponential inequality or none of these. 1. ๐‘“(๐‘ฅ) = 2๐‘ฅ3 2. ๐‘”(๐‘ฅ) = 2๐‘ฅ 3. ๐‘ฆ = โ…‡๐‘ฅ 4. 22(5๐‘ฅ+1) = 500 5. 625 โ‰ฅ 5๐‘ฅ+8 B. Match Column A with Column B. Column A Column B 6. 3๐‘ฅ = 81 A. {๐‘ฅ โˆˆ โ„|๐‘ฅ โ‰ค โˆ’2} 7. 5๐‘ฅ+7 = 125 B. {๐‘ฅ โˆˆ โ„|๐‘ฅ < โˆ’2} 8. ( 4 6 ) ๐‘ฅ โ‰ฅ 36 16 C. ๐‘ฅ = 4 9. 5๐‘ฅ > 25๐‘ฅ+1 D. ๐‘ฅ = โˆ’4 C. Read and solve the problem below. 10. Coffee contains caffeine. The half-life of caffeine is 5 hours . This means the amount of caffeine in your bloodstream is reduced by 50% every 5 hours. Suppose you drink a cup of coffee that contains 320 mg of caffeine. How long will it take until there is 5 mg of caffeine left in your bloodstream?
  • 9. 9 Lesson 7 Solving Exponential Equations, Inequalities, and Functions For this module, you need to review your lessons on the definition of zero and negative exponents and on the laws of exponent. Definition of Zero and Negative Exponents. Let ๐‘Ž โ‰  0. We define the following: 1. ๐‘Ž0 = 1 2. ๐‘Žโˆ’๐‘› = 1 ๐‘Ž๐‘› Theorem. Let ๐‘Ÿ and ๐‘  be rational numbers. Then 1. ๐‘Ž๐‘Ÿ ๐‘Ž๐‘  = ๐‘Ž๐‘Ÿ+๐‘  2. ๐‘Ž๐‘Ÿ ๐‘Ž๐‘  = ๐‘Ž๐‘Ÿโˆ’๐‘  3. (๐‘Ž๐‘Ÿ)๐‘  = ๐‘Ž๐‘Ÿ๐‘  4. (๐‘Ž๐‘)๐‘Ÿ = ๐‘Ž๐‘Ÿ ๐‘๐‘Ÿ 5. ( ๐‘Ž ๐‘ ) ๐‘Ÿ = ๐‘Ž๐‘Ÿ ๐‘๐‘Ÿ Whatโ€™s New Activity 1 Classify Me! Given: (a) 49 = 7๐‘ฅ+1 (e) 8๐‘ฅ = ๐‘ฅ2 โˆ’ 9 (b) 7 = 2๐‘ฅ + 3 (f) ๐‘ฅ2 = 3๐‘ฅ3 + 2๐‘ฅ + 1 (c) 3๐‘ฅ = 32๐‘ฅโˆ’1 (g) 2๐‘ฅ + 3 > ๐‘ฅ โˆ’ 1 (d) 5๐‘ฅโˆ’1 = 125 (h) 2๐‘ฅโˆ’2 > 8 Questions 1. Which of the given above are exponential equations? 2. Which of the given above are exponential inequalities? Whatโ€™s In
  • 10. 10 Activity 2 We have something in common Complete the table below. Identify the base that can be used in expressing the given pair of numbers in exponential form. The example is done for you. Example. First Number Exponential Form Second Number Exponential Form Common Base 1. 125 53 25 52 5 First Number Exponential Form Second Number Exponential Form Common Base 1. 8 32 2 36 216 3 1 4 1 32 4 0.0625 0.5 5 1 100 1 10 What is It Solving Exponential Equation One โ€“ to โ€“ one Property of Exponential Functions will be used in solving exponential equations. One to one Property of Exponential Functions If ๐‘ฅ1 โ‰  ๐‘ฅ2, then ๐‘๐‘ฅ1 โ‰  ๐‘๐‘ฅ2. Conversely, if ๐‘๐‘ฅ1 = ๐‘๐‘ฅ2then ๐‘ฅ1 = ๐‘ฅ2 Example 1. Solve the equation 4๐‘ฅโˆ’1 = 16 Solution. Write both sides with 4 as the base. 4๐‘ฅโˆ’1 = 42 ๐‘ฅ โˆ’ 1 = 2 ๐‘ฅ = 2 + 1 ๐‘ฅ = 3
  • 11. 11 Alternate Solution. Write both sides with 2 as the base (22)๐‘ฅโˆ’1 = 24 22(๐‘ฅโˆ’1) = 24 2(๐‘ฅ โˆ’ 1) = 4 2๐‘ฅ โˆ’ 2 = 4 2๐‘ฅ = 4 + 2 2๐‘ฅ = 6 2๐‘ฅ 2 = 6 2 ๐‘ฅ = 3 Example 2. Solve the equation 125๐‘ฅโˆ’1 = 25๐‘ฅ+3 Solution. Both 125 and 25 can be written using 5 as the base. (53)๐‘ฅโˆ’1 = (52)๐‘ฅ+3 53(๐‘ฅโˆ’1) = 52(๐‘ฅ+3) 3(๐‘ฅ โˆ’ 1) = 2(๐‘ฅ + 3) 3๐‘ฅ โˆ’ 3 = 2๐‘ฅ + 6 3๐‘ฅ โˆ’ 2๐‘ฅ = 6 + 3 ๐‘ฅ = 9 Example 3. Solve 9๐‘ฅ2 = 3๐‘ฅ+3 . Solution. Both 9 and 3 can be written using 3 as the base. (32)๐‘ฅ2 = 3๐‘ฅ+3 32๐‘ฅ2 = 3๐‘ฅ+3 2๐‘ฅ2 = ๐‘ฅ + 3 2๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 3 = 0 (2๐‘ฅ โˆ’ 3)(๐‘ฅ + 1) = 0 2๐‘ฅ โˆ’ 3 = 0 or ๐‘ฅ + 1 = 0 2๐‘ฅ = 3 ๐‘ฅ = โˆ’1 2๐‘ฅ 2 = 3 2 ๐‘ฅ = 3 2
  • 12. 12 Solving Exponential Inequality Property of Exponential Inequalities If ๐‘ > 1, then the exponential function ๐‘ฆ = ๐‘๐‘ฅ is increasing for all x. This means that ๐‘๐‘ฅ < ๐‘๐‘ฆ if and only if ๐‘ฅ < ๐‘ฆ. If 0 < ๐‘ < 1, then the exponential function ๐‘ฆ = ๐‘๐‘ฅ is decreasing for all x. This means that ๐‘๐‘ฅ > ๐‘๐‘ฆ if and only if ๐‘ฅ < ๐‘ฆ. Example 4. Solve the inequality 3๐‘ฅ < 9๐‘ฅโˆ’2 Solution. Both 9 and 3 can be written using 3 as the base. 3๐‘ฅ < 9๐‘ฅโˆ’2 3๐‘ฅ < (32)๐‘ฅโˆ’2 3๐‘ฅ < 32(๐‘ฅโˆ’2) 3๐‘ฅ < 32๐‘ฅโˆ’4 Since the base 3 > 1, then the inequality is equivalent to ๐‘ฅ < 2๐‘ฅ โˆ’ 4 (the direction of inequality is retained) 4 < 2๐‘ฅ โˆ’ ๐‘ฅ 4 < ๐‘ฅ The solution set to the inequality is {๐‘ฅ โˆˆ โ„|๐‘ฅ > 4} Example 5. Solve the inequality ( 1 10 ) ๐‘ฅ+5 โ‰ฅ ( 1 100 ) 3๐‘ฅ Solution. Since, 1 100 = ( 1 10 ) 2 , then we write both sides of the inequality with 1 10 as the base. ( 1 10 ) ๐‘ฅ+5 โ‰ฅ ( 1 100 ) 3๐‘ฅ ( 1 10 ) ๐‘ฅ+5 โ‰ฅ ( 1 102) 3๐‘ฅ ( 1 10 ) ๐‘ฅ+5 โ‰ฅ ( 1 10 ) 2(3๐‘ฅ) ( 1 10 ) ๐‘ฅ+5 โ‰ฅ ( 1 10 ) 6x)
  • 13. 13 Since the base 1 10 < 1, then this inequality is equivalent to ๐‘ฅ + 5 โ‰ค 6๐‘ฅ (the direction of the inequality is reversed) 5 โ‰ค 6๐‘ฅ โˆ’ ๐‘ฅ 5 โ‰ค 5๐‘ฅ 5x 5 โ‰ค 5 5 1 โ‰ค ๐‘ฅ The solution set to the inequality is {๐‘ฅ โˆˆ โ„|๐‘ฅ โ‰ฅ 1} Solving Problems Involving Exponential Function (Half โ€“ Life) Example 6. The half life of Zn -71 is 2.45 minutes. At ๐‘ก = 0 there were ๐‘ฆ0 grams of Zn-71, but only 1 256 of this amount remains after some time. How much time has passed? Solution. The half โ€“ life of substance can be calculated by the formula ๐‘(๐‘ก) = ๐‘0 ( 1 2 ) ๐‘ก ๐‘ก 1 2 where ๐‘(๐‘ก) =quantity of the substance remaining ๐‘0 = initial quantity of the substance ๐‘ก = time elapsed ๐‘ก 1 2 = half life of the substance Given ๐‘ก 1 2 = 45 minutes ๐‘0 = ๐‘ฆ0 ๐‘(๐‘ก) = 1 256 ๐‘ฆ0 ๐‘ก=? Substitute ๐‘(๐‘ก) = ๐‘0 ( 1 2 ) ๐‘ก ๐‘ก 1 2 1 256 ๐‘ฆ0 = ๐‘ฆ0 ( 1 2 ) ๐‘ก 2.45 1 256 = ( 1 2 ) ๐‘ก 2.45 ( 1 2 ) 8 = ( 1 2 ) ๐‘ก 2.45 8 = ๐‘ก 2.45 ๐‘ก = (8)(2.45) ๐‘ก = 19.6 minutes
  • 14. 14 Whatโ€™s More Activity 3 What is that animal? Solve the following exponential equations and inequalities. Write the letter code on the box that corresponds to the answer of the given expressions. What is the only animal that never gets sick? A 162๐‘ฅโˆ’3 = 4๐‘ฅ+2 H 7๐‘ฅ+4 = 492๐‘ฅโˆ’1 E 4๐‘ฅ+2 = 82๐‘ฅ K 42๐‘ฅ+7 โ‰ค 322๐‘ฅโˆ’3 R ( 2 5 ) 5๐‘ฅโˆ’1 โ‰ฅ 25 4 S ( 2 3 ) 5๐‘ฅ+2 < ( 3 2 ) 2๐‘ฅ ๐‘ฅ > โˆ’2 7 ๐‘ฅ = 2 ๐‘ฅ = 8 3 ๐‘ฅ โ‰ฅ โˆ’1 5 ๐‘ฅ โ‰ฅ 29 6
  • 15. 15 What I Have Learned Activity 4 Am I the truth? Write TRUE if the given statement is correct and write FALSE if the given statement is wrong. 1. In solving the exponential equation 42๐‘ฅ+7 = 322๐‘ฅโˆ’3 , 4 and 32 can be written using 2 as the base. 2. In solving the exponential inequality (0.6)๐‘ฅโˆ’3 > (0.6)โˆ’2๐‘ฅโˆ’2 , the inequality symbol will not be reversed because 0.6 > 1. 3. The expression 5๐‘ฅโˆ’2 > 125 is an example of exponential inequality. 4. The solution of the exponential equation 7๐‘ฅ+4 = 492๐‘ฅโˆ’1 is ๐‘ฅ = 4. 5. The solution set to the inequality 10๐‘ฅ > 100โˆ’2๐‘ฅโˆ’5 is {๐‘ฅ โˆˆ โ„|๐‘ฅ > โˆ’2} What I Can Do Activity 5 Solve Me Solve the following. 1. 162๐‘ฅโˆ’3 = 4๐‘ฅ+2 2. 42๐‘ฅ+7 โ‰ค 322๐‘ฅโˆ’3 3. Paracetamol is a drug is used to treat mild to moderate pain and to reduce fever. It has a half โ€“ life in the body of 3 hours. Under a Doctor's care, Patient N is given a dose of a certain paracetamol. Patient N asks the doctor for another the same dose of this paracetamol. The doctor agrees to allow patient N to take dose once there is only 6.25% of the original dose remaining in the body. How long will patient N have to wait, before taking another dose of this paracetamol?
  • 16. 16 Assessment A. Solve for ๐‘ฅ. 1. 53๐‘ฅ+8 = 252๐‘ฅ 2. ( 3 5 ) ๐‘ฅ+1 = 25 9 3. 43๐‘ฅ+2 < 64 4. ( 49 81 ) ๐‘ฅ+1 โ‰ฅ 9 7 B. Read and solve the given problem. 5. A certain pain reliever has a half-life of 16 hours. If the initial plasma level of this pain relieverg, given as a single dose, is 512mg/L, how long will it take for the plasma level to fall to 16 mg/L? Additional Activities Activity 6 Who is right? 1. John and Peter are solving (0.6)๐‘ฅโˆ’3 > (0.36)โˆ’xโˆ’1 . Did anyone get the correct solution? If not, spot the error or errors. John Peter (0.6)๐‘ฅโˆ’3 > (0.36)โˆ’๐‘ฅโˆ’1 (0.6)๐‘ฅโˆ’3 > (0.36)โˆ’๐‘ฅโˆ’1 (0.6)๐‘ฅโˆ’3 > (0.62)โˆ’๐‘ฅโˆ’1 (0.6)๐‘ฅโˆ’3 > (0.62)โˆ’๐‘ฅโˆ’1 (0.6)๐‘ฅโˆ’3 > (0.6)2(โˆ’๐‘ฅโˆ’1) (0.6)๐‘ฅโˆ’3 > (0.6)2(โˆ’๐‘ฅโˆ’1) (0.6)๐‘ฅโˆ’3 > (0.6)โˆ’2๐‘ฅโˆ’2 (0.6)๐‘ฅโˆ’3 > (0.6)โˆ’2๐‘ฅโˆ’2 ๐‘ฅ โˆ’ 3 > โˆ’2๐‘ฅ โˆ’ 2 ๐‘ฅ โˆ’ 3 < โˆ’2๐‘ฅ โˆ’ 2 ๐‘ฅ + 2๐‘ฅ > โˆ’2 + 3 ๐‘ฅ + 2๐‘ฅ < โˆ’2 + 3 3๐‘ฅ > 1 3๐‘ฅ < 1 3๐‘ฅ 3 > 1 3 3๐‘ฅ 3 < 1 3 ๐‘ฅ > 1 3 ๐‘ฅ < 1 3
  • 17. 17 Answer Key What I can do 1. ๐‘ฅ = 8 3 2. ๐‘ฅ โ‰ฅ 29 6 3. t = 12 hours Assessment 1. ๐‘ฅ = 8 2. ๐‘ฅ = โˆ’3 3. ๐‘ฅ < 1 3 4. ๐‘ฅ โ‰ค โˆ’ 3 2 5. t = 80 hours Additional Activities 1. Peter is right. The inequality symbol should reversed since 0 โ‹… 6 < 1 What's New 1. (a), (c), (d) 2. (h) 1. 2 3 , 2 5 , 2 2. 6 2 , 6 3 , 6 3. ( 1 2 ) 2 , ( 1 2 ) 5 , 1 2 4. (0.5) 2 , (0.5) 1 , 0.5 5. ( 1 10 ) 2 , ( 1 10 ) 1 , 1 10 Whatโ€™s More A. ๐‘ฅ = 8 3 H. ๐‘ฅ = 2 E. ๐‘ฅ = 1 K. ๐‘ฅ โ‰ฅ 29 6 R. ๐‘ฅ โ‰ฅ โˆ’1 5 S. ๐‘ฅ > โˆ’2 7 SHARK What I Have Learned? 1. TRUE 2. FALSE 3. TRUE 4. FALSE 5. TRUE What I Know 1. None of these 2. None of these 3. None of these 4. Exponential equation 5. Exponential inequality 6. C 7. D 8. A 9. B 10. 30 hours
  • 18. 18 References 1. Department of Education-Bureau of Learning Resources (DepEd-BLR) (2016) General Mathematics Learnerโ€™s Material. Lexicon Press Inc., Philippines 2. Department of Education-Bureau of Learning Resources (DepEd-BLR) (2016) General Mathematics
  • 19. 19 DISCLAIMER This Self-learning Module (SLM) was developed by DepEd SOCCSKSARGEN with the primary objective of preparing for and addressing the new normal. Contents of this module were based on DepEdโ€™s Most Essential Learning Competencies (MELC). This is a supplementary material to be used by all learners of Region XII in all public schools beginning SY 2020-2021. The process of LR development was observed in the production of this module. This is version 1.0. We highly encourage feedback, comments, and recommendations. For inquiries or feedback, please write or call: Department of Education โ€“ SOCCSKSARGEN Learning Resource Management System (LRMS) Regional Center, Brgy. Carpenter Hill, City of Koronadal Telefax No.: (083) 2288825/ (083) 2281893 Email Address: region12@deped.gov.ph