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Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
Phy cc 10 17-12-unit 5b_help_session_pub
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Phy cc 10 17-12-unit 5b_help_session_pub

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Slides from the Help Session going over the Study Guide for Unit 5.

Slides from the Help Session going over the Study Guide for Unit 5.

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  • 1. Mrs. Reynolds
  • 2. About twenty percent of the National FootballLeague weighs more than 300 pounds. At thisweight, their Body Mass Index (BMI) placesthem at Grade 2 obesity, which is one stepbelow morbid obesity. Determine the mass of a300 pound (1330 N) football player.
  • 3. About twenty percent of the National FootballLeague weighs more than 300 pounds. At thisweight, their Body Mass Index (BMI) placesthem at Grade 2 obesity, which is one stepbelow morbid obesity. Determine the mass of a300 pound (1330 N) football player. Fg = 300 lb. = 1330 N Fg = mg g = 9.8 m/s^2 m = Fg/g m=? m = 1330 N/9.8 m/s^2 m = 136 kg
  • 4. According to the National Center for HealthStatistics, the average mass of an adultAmerican male is 86 kg. Determine the massand the weight of an 86-kg man on the moonwhere the gravitational field is one-sixth that ofthe Earth. mearth = 86 kg Gmoon = (1/6)g = (1/6)*(9.8) mmoon = ? Fg moon = ?
  • 5. According to the National Center for HealthStatistics, the average mass of an adultAmerican male is 86 kg. Determine the massand the weight of an 86-kg man on the moonwhere the gravitational field is one-sixth that ofthe Earth. mearth = 86 kg mass doesn’t change Gmoon = (1/6)g so mmoon = 86 kg = (1/6)*(9.8) mmoon = ? Fg moon = ?
  • 6. According to the National Center for HealthStatistics, the average mass of an adultAmerican male is 86 kg. Determine the massand the weight of an 86-kg man on the moonwhere the gravitational field is one-sixth that ofthe Earth. mearth = 86 kg Fg moon = mmoon Gmoon Gmoon = (1/6)g Fg moon = (86)(9.8/6) = (1/6)*(9.8)Fg moon = 140 N mmoon = ? Fg moon = ?
  • 7. a. Determine the net force required toaccelerate a 540-kg ultralight car from 0 to27 m/s (60 mph) in 10.0 seconds.b. Determine the net force required toaccelerate a 2160-kg Ford Expedition from 0to 27 m/s (60 mph) in 10.0 seconds.
  • 8. a. Determine the net force required toaccelerate a 540-kg ultralight car from 0 to27 m/s (60 mph) in 10.0 seconds. m = 540 kg vi = 0 vf = 27 m/s t = 10.0 s Fnet = ?
  • 9. a. Determine the net force required toaccelerate a 540-kg ultralight car from 0 to 27m/s (60 mph) in 10.0 seconds. m = 540 kg To find Fnet we need vi = 0 mass and accel. We vf = 27 m/s have mass, but not accel. t = 10.0 s So we need to find accel. Fnet = ?
  • 10.
  • 11. a. Determine the net force required toaccelerate a 540-kg ultralight car from 0 to 27m/s (60 mph) in 10.0 seconds. m = 540 kg Fnet = ma vi = 0 Fnet = (540 kg)(2.7 m/s^2) vf = 27 m/s Fnet = 1458 N t = 10.0 s a = 2.7 m/s^2 Fnet = ?
  • 12. b. Determine the net force required toaccelerate a 2160-kg Ford Expedition from 0to 27 m/s (60 mph) in 10.0 seconds. m = 2160 kg vi = 0 vf = 27 m/s t = 10.0 s Fnet = ?
  • 13.
  • 14. b. Determine the net force required toaccelerate a 2160-kg Ford Expedition from 0 to27 m/s (60 mph) in 10.0 seconds. m = 2160 kg Fnet = ma vi = 0 Fnet = (2160 kg)(2.7 m/s^2) vf = 27 m/s Fnet = 5832 N t = 10.0 s a = 2.7 m/s^2 Fnet = ?
  • 15. The Top Thrill Dragster stratacoaster at CedarPoint Amusement Park in Ohio uses a hydrauliclaunching system to accelerate riders from 0 to 54m/s (120 mi/hr) in 3.8 seconds before climbing acompletely vertical 420-foot hill . Determine the netforce required to accelerate an 86-kg man.vi = 0 m/s Fnet = ?vf = 54 m/st = 3.8 s To find Fnet we need to findd = 420 ft acceleration.m = 86 kg
  • 16.
  • 17. The Top Thrill Dragster stratacoaster at CedarPoint Amusement Park in Ohio uses a hydrauliclaunching system to accelerate riders from 0 to 54m/s (120 mi/hr) in 3.8 seconds before climbing acompletely vertical 420-foot hill . Determine the netforce required to accelerate an 86-kg man.vi = 0 m/s Fnet = ?vf = 54 m/st = 3.8 sd = 420 ftm = 86 kga = 14.2 m/s^2
  • 18.  Blake is dragging a bag of grass from the garage to the street on the evening before garbage pick-up day with a force of 40.2 N. The frictional force between the bag and the ground is 5.7 N. What is the net force acting on the bag?
  • 19.  Blake is dragging a bag of grass from the garage to the street on the evening before garbage pick-up day with a force of 40.2 N. The frictional force between the bag and the ground is 5.7 N. What is the net force acting on the bag?5.7 N 40.2 N
  • 20. Silas and Ivey are members of the stage crewfor the Variety Show. Between acts, they mustquickly move a Baby Grand Piano onto stage.After the curtain closes, they exert a suddenforward force of 524 N to budge the piano fromrest and get it up to speed. The 158-kg pianoexperiences 418 N of friction. a. What is the pianos acceleration during this phase of its motion? b. If Silas and Ivey maintain this forward force for 1.44 seconds, then what speed will the piano have?
  • 21. They exert a sudden forward force of 524 N tobudge the piano from rest and get it up tospeed. The 158-kg piano experiences 418 N offriction. a. What is the pianos acceleration during this phase of its motion? F1 = 524 N forward F2 = 418 N backward m = 158 kg a=? 418 N 524 N
  • 22. They exert a sudden forward force of 524 N tobudge the piano from rest and get it up tospeed. The 158-kg piano experiences 418 N offriction. a. What is the pianos acceleration during this phase of its motion? F1 = 524 N forward Fnet = 524 N – 418 N = 106 N F2 = 418 N backward m = 158 kg a=? 418 N 524 N
  • 23. They exert a sudden forward force of 524 N tobudge the piano from rest and get it up tospeed. The 158-kg piano experiences 418 N offriction. a. What is the pianos acceleration during this phase of its motion? F1 = 524 N forward Fnet = 524 N – 418 N = 106 N F2 = 418 N backward Fnet = ma, so a = Fnet/m m = 158 kg a = (106 N)/(158 kg) a=? a = 0.671 m/s^2
  • 24. They exert a sudden forward force of 524 N tobudge the piano from rest and get it up tospeed. The 158-kg piano experiences 418 N offriction. b. If Silas and Ivey maintain this forward force for 1.44 seconds, then what speed will the piano have?
  • 25. They exert a sudden forward force of 524 N tobudge the piano from rest and get it up tospeed. The 158-kg piano experiences 418 N offriction. b. If Silas and Ivey maintain this forward force for 1.44 seconds, then what speed will the piano have? a = 0.671 m/s^2 t = 1.44 s
  • 26. They exert a sudden forward force of 524 N tobudge the piano from rest and get it up tospeed. The 158-kg piano experiences 418 N offriction. b. If Silas and Ivey maintain this forward force for 1.44 seconds, then what speed will the piano have? a = 0.671 m/s^2 t = 1.44 s vi = 0 m/s vf = ?
  • 27. They exert a sudden forward force of 524 N tobudge the piano from rest and get it up tospeed. The 158-kg piano experiences 418 N offriction. b. If Silas and Ivey maintain this forward force for 1.44 seconds, then what speed will the piano have? a = 0.671 m/s^2 t = 1.44 s vi = 0 m/s vf = ?
  • 28. They exert a sudden forward force of 524 N tobudge the piano from rest and get it up tospeed. The 158-kg piano experiences 418 N offriction. b. If Silas and Ivey maintain this forward force for 1.44 seconds, then what speed will the piano have? a = 0.671 m/s^2 vf = vi + at t = 1.44 s vi = 0 m/s vf = ?
  • 29. They exert a sudden forward force of 524 N tobudge the piano from rest and get it up tospeed. The 158-kg piano experiences 418 N offriction. b. If Silas and Ivey maintain this forward force for 1.44 seconds, then what speed will the piano have? a = 0.671 m/s^2 vf = vi + at t = 1.44 s vf = 0 + (0.671 m/s^2)(1.44 s) vi = 0 m/s vf = 0.966 m/s vf = ?

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