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Resistors
Connected in parallel
When a number of resistors are
connected as below they are connected in
PARALLEL.
R1
R2
Battery
In PARALLEL connections, the total
current splits up and divides itself
amongst the different branches of the
circuit.
The pressure that pushes the
electrons along (voltage) will be the same
in each branch of the circuit. So any branch of a
parallel circuit can be disconnected without
affecting the other branches.
These rules apply to parallel
circuits.
• Total current (I) is the sum of the current
through each of the branches.
I = I1 + I2 + I3 + etc……..
The same potential difference will appear
across each branch of the circuit.
V = V1 = V2 = V3 etc….
When working out resistors in parallel it is
easier to group the resistors together
into one large resistor (Rt).
1 1 + 1 + 1
Rt = R1 + R2 + R3
A 16Ω, 24Ω and a 48Ω resistor are connected in parallel
across a 240V supply.
Work out the total current.
240V
16Ω
24Ω
48Ω
Method 1
Find the equivalent resistance (Rt) of all the branches and
use I = V
R
1 = 1 + 1 + 1
Rt 16 24 48
1 = = 3+2+1
Rt 48
48
1
48
2
48
3
++
If 1 = 6
Rt 48 then
Rt = 48
1 6 so
Rt = 8 Ω
Using Ohm’s Law
I = V
R
I = 240
8
I = 30A
Method 2
I1 = V
R1
I1 = 240
16
I1 = 15A
I2 = V
R2
I2 = 240
24
I2 = 10A
I3 = V
R3
I3 = 240
48
I3 = 5A
So
It = I1+ I2 + I3
It = 15+10+5
It = 30A

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Unit 103 power_point_7_resistors_parallel

  • 2. When a number of resistors are connected as below they are connected in PARALLEL. R1 R2 Battery
  • 3. In PARALLEL connections, the total current splits up and divides itself amongst the different branches of the circuit. The pressure that pushes the electrons along (voltage) will be the same in each branch of the circuit. So any branch of a parallel circuit can be disconnected without affecting the other branches.
  • 4. These rules apply to parallel circuits. • Total current (I) is the sum of the current through each of the branches. I = I1 + I2 + I3 + etc……..
  • 5. The same potential difference will appear across each branch of the circuit. V = V1 = V2 = V3 etc….
  • 6. When working out resistors in parallel it is easier to group the resistors together into one large resistor (Rt). 1 1 + 1 + 1 Rt = R1 + R2 + R3
  • 7. A 16Ω, 24Ω and a 48Ω resistor are connected in parallel across a 240V supply. Work out the total current. 240V 16Ω 24Ω 48Ω
  • 8. Method 1 Find the equivalent resistance (Rt) of all the branches and use I = V R 1 = 1 + 1 + 1 Rt 16 24 48 1 = = 3+2+1 Rt 48 48 1 48 2 48 3 ++
  • 9. If 1 = 6 Rt 48 then Rt = 48 1 6 so Rt = 8 Ω
  • 10. Using Ohm’s Law I = V R I = 240 8 I = 30A
  • 11. Method 2 I1 = V R1 I1 = 240 16 I1 = 15A
  • 12. I2 = V R2 I2 = 240 24 I2 = 10A
  • 13. I3 = V R3 I3 = 240 48 I3 = 5A
  • 14. So It = I1+ I2 + I3 It = 15+10+5 It = 30A