6. Geometrically, how can the minima and maxima be
located?
For maxima:
L210 ,,,nnL ±±== λ∆
θ∆ sin12 dLLL =−=
Here, S1 and S2 are the sources, and P is
either a maximum or a minimum.
The difference in path lengths can be
written in terms of the angle ,
assuming that R>>d .
θ
d
n
λ
θ =sin
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7. d
n
λ
θ =sin L210 ,,,n ±±=
00 =→= θn 中央极大
For minima:
( )
2
12
λ
∆ += nL
L210 ,,,n ±±=
θ∆ sin12 dLLL =−=
d
n
λ
θ )
2
1
(sin +=
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8. Two coherent sources are 3.0 cm apart and make
harmonic ripples of the same frequency. Consider
the ripples along a straight line parallel to the
line that connects the sources and 40.0 cm away
from line . If the distance between the central
maximum at and the next maximum on is 8.0
cm, what is the wavelength of the ripples?
1
L
2
L
2
L
1
L 1
L
The angle of the next maximum
is given by
L
D
=θtan
cm040
cm08
.
.
=
= 0.20
o
311.=θ 退出返回
9. d
n
λ
θ =sin
For the next maximum:
= d sinθλ
= (3.0 cm) sin 11.3°
= 0.59 cm
在均匀介质中沿直线传播的波在遇到另外一种介质时,
会发生反射和折射现象。
vZ ρ= 介质的特性阻抗
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14. Two harmonic waves of the same amplitude and wavelength
travel in opposite directions along a stretched string
Their interference with each other produces a standing wave
CAI
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15. 2A
t = 0
y
0 x
0
t = T/ 8 x
x
0t = T/2
0 xt = T/4
波节波腹 λ /4-λ /4
x0
2A
-2A
λ/2
振动范围
xt = 3T/8 0
CAI
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