Arrange the following 0.10 M solutions in order of most acidic to most basic. See Appendix 5 for K a and K b values.
KCl
Sr(OH) 2
HONH 3 ClO 4
HNO 3
KF
Solution
Ka or the acid dissociation constant gives the measure of the strength of a given acid.It is the equilibrium constant for reaction involving weak acids dissociation.
For a weak acid,say,HA
HA<--->H + +A -
Ka=[H + ][A - ]/[HA]
Higher the ka ,stronger is the acid.
for strong acids,ka>1
Similarly,kb or the base dissociation constant gives the measure of the strength of a given weak base.It is the equilibrium constant for reaction involving weak base dissociation.
For a weak base,say,BOH
BOH<--->OH - +B +
Kb=[B + ][OH - ]/[BOH]
Higher the kb ,stronger is the base
KCl is a salt of strong base KOH and strong acid HCl, it is neutral
Sr(OH)2 has ka >0 (weak base)
HONH3ClO4 <---> HONH3 + + ClO4 -
HONH3 + <-->H+ +HONH2 (releases proton so acidic) ka=9.09*10^-7
HNO3 --->H + +NO3- (strong acid ka>1)
KF is a salt of strong base KOH and weak acid HF so it is a basic salt
In solution, F- base hydrolysis takes place as folllows,
KF--->K + +F-
F- +H2O <--> HF +OH-
order from most acidic to most basic:
HNO3>HONH3ClO4>KCl>KF>Sr(OH)2
.
for strong acids,ka>1
for a
.
Arrange the following 0-10 M solutions in order of most acidic to most.docx
1. Arrange the following 0.10 M solutions in order of most acidic to most basic. See Appendix 5 for
K a and K b values.
KCl
Sr(OH) 2
HONH 3 ClO 4
HNO 3
KF
Solution
Ka or the acid dissociation constant gives the measure of the strength of a given acid.It is the
equilibrium constant for reaction involving weak acids dissociation.
For a weak acid,say,HA
HA<--->H +
+A -
Ka=[H +
][A -
]/[HA]
Higher the ka ,stronger is the acid.
for strong acids,ka>1
Similarly,kb or the base dissociation constant gives the measure of the strength of a given weak
base.It is the equilibrium constant for reaction involving weak base dissociation.
For a weak base,say,BOH
BOH<--->OH -
+B +
Kb=[B +
][OH -
]/[BOH]
2. Higher the kb ,stronger is the base
KCl is a salt of strong base KOH and strong acid HCl, it is neutral
Sr(OH)2 has ka >0 (weak base)
HONH3ClO4 <---> HONH3 +
+ ClO4 -
HONH3 +
<-->H+ +HONH2 (releases proton so acidic) ka=9.09*10^-7
HNO3 --->H +
+NO3- (strong acid ka>1)
KF is a salt of strong base KOH and weak acid HF so it is a basic salt
In solution, F- base hydrolysis takes place as folllows,
KF--->K +
+F-
F- +H2O <--> HF +OH-
order from most acidic to most basic:
HNO3>HONH3ClO4>KCl>KF>Sr(OH)2
.
for strong acids,ka>1
for a
![Arrange the following 0.10 M solutions in order of most acidic to most basic. See Appendix 5 for
K a and K b values.
KCl
Sr(OH) 2
HONH 3 ClO 4
HNO 3
KF
Solution
Ka or the acid dissociation constant gives the measure of the strength of a given acid.It is the
equilibrium constant for reaction involving weak acids dissociation.
For a weak acid,say,HA
HA<--->H +
+A -
Ka=[H +
][A -
]/[HA]
Higher the ka ,stronger is the acid.
for strong acids,ka>1
Similarly,kb or the base dissociation constant gives the measure of the strength of a given weak
base.It is the equilibrium constant for reaction involving weak base dissociation.
For a weak base,say,BOH
BOH<--->OH -
+B +
Kb=[B +
][OH -
]/[BOH]](https://image.slidesharecdn.com/arrangethefollowing0-10msolutionsinorderofmostacidictomost-230204001647-5e8fcccd/85/Arrange-the-following-0-10-M-solutions-in-order-of-most-acidic-to-most-docx-1-320.jpg)
