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University Physics with Modern Physics
Fifteenth Edition
Chapter 10
Dynamics of
Rotational Motion
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Learning Outcomes
In this chapter, you’ll learn…
• what is meant by the torque produced by a force.
• how the net torque on an object affects the object’s
rotational motion.
• how to analyze the motion of an object that both rotates
and moves as a whole through space.
• how to solve problems that involve work and power for
rotating objects.
• how the angular momentum of an object can remain
constant even if the object changes shape.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Introduction
• These jugglers toss the pins so that they rotate in midair.
• What does it take to start a stationary object rotating or to
bring a spinning object to a halt?
• We’ll introduce some new concepts, such as torque and
angular momentum, to deepen our understanding of
rotational motion.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Loosen a Bolt
• Which of the three equal-magnitude forces in the
figure is most likely to loosen the bolt?
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Torque
• The line of action of a
force is the line along which
the force vector lies.
• The lever arm for a force is
the perpendicular distance
from O to the line of action
of the force.
• The torque of a force with
respect to O is the product
of the force and its lever
arm.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Three Ways to Calculate Torque
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Torque as a Vector
• Torque can be expressed as a
vector using the vector product.
• If you curl the fingers of your right
hand in the direction of the force
around the rotation axis, your
outstretched thumb points in the
direction of the torque vector.
• Video Tutor Solution: Example 10.1
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Torque and Angular Acceleration for
a Rigid Body
• The rotational analog of Newton’s second law for a
rigid body is:
• Loosening or tightening
a screw requires giving it
an angular acceleration
and hence applying a
torque.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Why Only External Torques Affect a
Rigid Body's Rotation
• Any two particles in the object exert equal and
opposite forces on each other.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Problem-Solving Strategy for
Rotational Dynamics (1 of 2)
• Identify the relevant concept: You must use .
z z
I
 
 
• Set up the problem by using the following steps:
1. Sketch the situation and identify the object or objects to be
analyzed. Indicate the rotation axis.
2. For each object, draw a free-body diagram that shows the
object’s shape, including all dimensions and angles. Label
pertinent quantities with algebraic symbols.
3. Choose coordinate axes for each body and indicate a
positive sense of rotation (clockwise or counterclockwise)
for each rotating object. If you know the sense of αz, pick
that as the positive sense of rotation.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Problem-Solving Strategy for
Rotational Dynamics (2 of 2)
• Execute the solution as follows:
1. For each object, decide whether it undergoes translational motion,
rotational motion, or both. Then apply Newton’s second law, ,
z z
I
 
 
or both to the object.
2. Express in algebraic form any geometrical relationships between
the motions of two or more objects. An example is a string that
unwinds, without slipping, from a pulley or a wheel that rolls
without slipping. These relationships usually appear as
relationships between linear and/or angular accelerations.
3. Ensure that you have as many independent equations as there
are unknowns. Solve the equations to find the target variables.
• Evaluate your answer.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Rigid Body Rotation About a Moving
Axis (1 of 2)
• The kinetic energy of a rotating and translating rigid
body is 2 2
cm cm
1 1
.
2 2
K Mv I 
 
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Rigid Body Rotation About a Moving
Axis (2 of 2)
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Rolling Without Slipping
• The motion of a rolling wheel is the sum of the translational
motion of the center of mass plus the rotational motion of
the wheel around the center of mass.
• The condition for rolling without slipping is cm .
v R

Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Combined Translation and Rotation
• Airflow around the wing of a maple seed slows the
falling seed to about 1 m/s and causes the seed to
rotate about its center of mass.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Rolling with Slipping
• The smoke rising from this drag racer’s rear tires
shows that the tires are slipping on the road, so vcm is
not equal to Rω.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Combined Translation and Rotation:
Dynamics
• The acceleration of the center of mass of a rigid body is:
• The rotational motion about the center of mass is described
by the rotational analog of Newton’s second law:
• This is true as long as the axis through the center of mass
is an axis of symmetry, and the axis does not change
direction.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Rolling Friction
• We can ignore rolling friction if both the rolling object and the
surface over which it rolls are perfectly rigid.
• If the surface or the rolling object deforms, mechanical energy
can be lost, slowing the motion.
• Video Tutor Solution: Example 10.7
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Work in Rotational Motion
• A tangential force applied to a rotating object does work on it.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Work and Power in Rotational Motion
• The total work done on an object by the torque is equal to the
change in rotational kinetic energy of the object, and the power
due to a torque is:
• When a helicopter’s main rotor is
spinning at a constant rate, positive work
is done on the rotor by the engine and
negative work is done on it by air
resistance.
• Hence the net work being done is zero
and the kinetic energy remains constant.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Angular Momentum (1 of 3)
• To find the total angular
momentum of a rigid body
rotating with angular speed
ω, first consider a thin slice
of the object.
• Each particle in the slice
with mass mi has angular
momentum:
2
i i i
L m r 

Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Angular Momentum (2 of 3)
• For a rigid body rotating around an axis of symmetry,
the angular momentum is:
• For any system of particles, the rate of change of the
total angular momentum equals the sum of the
torques of all forces acting on all the particles:
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Angular Momentum (3 of 3)
• The angular momentum of a rigid body rotating about
a symmetry axis is parallel to the angular velocity and
is given by .


L I
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Conservation of Angular
Momentum (1 of 2)
• When the net external torque acting on a system is zero,
the total angular momentum of the system is constant
(conserved).
• Video Tutor Demonstration: Spinning Person Drops Weight
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Conservation of Angular Momentum
(2 of 2)
• A falling cat twists different parts of its body in different
directions so that it lands feet first. At all times during this
process the angular momentum of the cat as a whole
remains zero.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Gyroscopes and Precession (1 of 3)
• For a gyroscope, the axis of rotation changes direction.
• The motion of this axis is called precession.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Gyroscopes and Precession (2 of 3)
• If a flywheel is
initially not spinning,
its initial angular
momentum is zero.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
Gyroscopes and Precession (3 of 3)
• In each successive
time interval dt, the
torque produces a
change in the angular
momentum in the same
direction as the torque,
and the flywheel axis
falls.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
A Rotating Flywheel (1 of 2)
• This flywheel is
initially spinning,
with a large angular
momentum.
Copyright © 2020 Pearson Education, Inc. All Rights Reserved
A Rotating Flywheel (2 of 2)
• Because the initial
angular momentum is
not zero, each change
in angular momentum is
perpendicular to the
angular momentum.
• As a result, the
magnitude L remains
the same but the
angular momentum
changes its direction
continuously.

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Chapter10.pptx

  • 1. University Physics with Modern Physics Fifteenth Edition Chapter 10 Dynamics of Rotational Motion Copyright © 2020 Pearson Education, Inc. All Rights Reserved
  • 2. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Learning Outcomes In this chapter, you’ll learn… • what is meant by the torque produced by a force. • how the net torque on an object affects the object’s rotational motion. • how to analyze the motion of an object that both rotates and moves as a whole through space. • how to solve problems that involve work and power for rotating objects. • how the angular momentum of an object can remain constant even if the object changes shape.
  • 3. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Introduction • These jugglers toss the pins so that they rotate in midair. • What does it take to start a stationary object rotating or to bring a spinning object to a halt? • We’ll introduce some new concepts, such as torque and angular momentum, to deepen our understanding of rotational motion.
  • 4. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Loosen a Bolt • Which of the three equal-magnitude forces in the figure is most likely to loosen the bolt?
  • 5. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Torque • The line of action of a force is the line along which the force vector lies. • The lever arm for a force is the perpendicular distance from O to the line of action of the force. • The torque of a force with respect to O is the product of the force and its lever arm.
  • 6. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Three Ways to Calculate Torque
  • 7. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Torque as a Vector • Torque can be expressed as a vector using the vector product. • If you curl the fingers of your right hand in the direction of the force around the rotation axis, your outstretched thumb points in the direction of the torque vector. • Video Tutor Solution: Example 10.1
  • 8. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Torque and Angular Acceleration for a Rigid Body • The rotational analog of Newton’s second law for a rigid body is: • Loosening or tightening a screw requires giving it an angular acceleration and hence applying a torque.
  • 9. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Why Only External Torques Affect a Rigid Body's Rotation • Any two particles in the object exert equal and opposite forces on each other.
  • 10. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Problem-Solving Strategy for Rotational Dynamics (1 of 2) • Identify the relevant concept: You must use . z z I     • Set up the problem by using the following steps: 1. Sketch the situation and identify the object or objects to be analyzed. Indicate the rotation axis. 2. For each object, draw a free-body diagram that shows the object’s shape, including all dimensions and angles. Label pertinent quantities with algebraic symbols. 3. Choose coordinate axes for each body and indicate a positive sense of rotation (clockwise or counterclockwise) for each rotating object. If you know the sense of αz, pick that as the positive sense of rotation.
  • 11. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Problem-Solving Strategy for Rotational Dynamics (2 of 2) • Execute the solution as follows: 1. For each object, decide whether it undergoes translational motion, rotational motion, or both. Then apply Newton’s second law, , z z I     or both to the object. 2. Express in algebraic form any geometrical relationships between the motions of two or more objects. An example is a string that unwinds, without slipping, from a pulley or a wheel that rolls without slipping. These relationships usually appear as relationships between linear and/or angular accelerations. 3. Ensure that you have as many independent equations as there are unknowns. Solve the equations to find the target variables. • Evaluate your answer.
  • 12. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Rigid Body Rotation About a Moving Axis (1 of 2) • The kinetic energy of a rotating and translating rigid body is 2 2 cm cm 1 1 . 2 2 K Mv I   
  • 13. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Rigid Body Rotation About a Moving Axis (2 of 2)
  • 14. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Rolling Without Slipping • The motion of a rolling wheel is the sum of the translational motion of the center of mass plus the rotational motion of the wheel around the center of mass. • The condition for rolling without slipping is cm . v R 
  • 15. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Combined Translation and Rotation • Airflow around the wing of a maple seed slows the falling seed to about 1 m/s and causes the seed to rotate about its center of mass.
  • 16. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Rolling with Slipping • The smoke rising from this drag racer’s rear tires shows that the tires are slipping on the road, so vcm is not equal to Rω.
  • 17. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Combined Translation and Rotation: Dynamics • The acceleration of the center of mass of a rigid body is: • The rotational motion about the center of mass is described by the rotational analog of Newton’s second law: • This is true as long as the axis through the center of mass is an axis of symmetry, and the axis does not change direction.
  • 18. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Rolling Friction • We can ignore rolling friction if both the rolling object and the surface over which it rolls are perfectly rigid. • If the surface or the rolling object deforms, mechanical energy can be lost, slowing the motion. • Video Tutor Solution: Example 10.7
  • 19. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Work in Rotational Motion • A tangential force applied to a rotating object does work on it.
  • 20. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Work and Power in Rotational Motion • The total work done on an object by the torque is equal to the change in rotational kinetic energy of the object, and the power due to a torque is: • When a helicopter’s main rotor is spinning at a constant rate, positive work is done on the rotor by the engine and negative work is done on it by air resistance. • Hence the net work being done is zero and the kinetic energy remains constant.
  • 21. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Angular Momentum (1 of 3) • To find the total angular momentum of a rigid body rotating with angular speed ω, first consider a thin slice of the object. • Each particle in the slice with mass mi has angular momentum: 2 i i i L m r  
  • 22. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Angular Momentum (2 of 3) • For a rigid body rotating around an axis of symmetry, the angular momentum is: • For any system of particles, the rate of change of the total angular momentum equals the sum of the torques of all forces acting on all the particles:
  • 23. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Angular Momentum (3 of 3) • The angular momentum of a rigid body rotating about a symmetry axis is parallel to the angular velocity and is given by .   L I
  • 24. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Conservation of Angular Momentum (1 of 2) • When the net external torque acting on a system is zero, the total angular momentum of the system is constant (conserved). • Video Tutor Demonstration: Spinning Person Drops Weight
  • 25. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Conservation of Angular Momentum (2 of 2) • A falling cat twists different parts of its body in different directions so that it lands feet first. At all times during this process the angular momentum of the cat as a whole remains zero.
  • 26. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Gyroscopes and Precession (1 of 3) • For a gyroscope, the axis of rotation changes direction. • The motion of this axis is called precession.
  • 27. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Gyroscopes and Precession (2 of 3) • If a flywheel is initially not spinning, its initial angular momentum is zero.
  • 28. Copyright © 2020 Pearson Education, Inc. All Rights Reserved Gyroscopes and Precession (3 of 3) • In each successive time interval dt, the torque produces a change in the angular momentum in the same direction as the torque, and the flywheel axis falls.
  • 29. Copyright © 2020 Pearson Education, Inc. All Rights Reserved A Rotating Flywheel (1 of 2) • This flywheel is initially spinning, with a large angular momentum.
  • 30. Copyright © 2020 Pearson Education, Inc. All Rights Reserved A Rotating Flywheel (2 of 2) • Because the initial angular momentum is not zero, each change in angular momentum is perpendicular to the angular momentum. • As a result, the magnitude L remains the same but the angular momentum changes its direction continuously.