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Pb.1
# Find deflection, shear and moment distribution
1𝐸𝐼𝑉′′′′
= 0
2𝐸𝐼𝑉′′′
= 𝐶1
3𝐸𝐼𝑉′′
= 𝐶1 𝑋 + 𝐶2
𝐸𝐼𝑉′
= 𝐶1
𝑋2
2
+ 𝐶2 𝑋 + 𝐶3 4
𝐸𝐼𝑉 = 𝐶1
𝑋3
6
+ 𝐶2
𝑋2
2
+ 𝐶3 𝑋 + 𝐶4 5
B.CS
At X=0
V (0) = 0
𝑉′
(0) = 0
At x=L
V (L) = 𝛿
M (L) =0
Substituting B.CS in equations 2,3,4,5 we get
i𝐶1 =
−3𝐸𝐼𝛿
𝐿3
ii𝐶2 =
3𝐸𝐼𝛿
𝐿2
𝑉( 𝑥) =
−3𝛿
6𝐿3 𝑋3
+ 3𝛿
2𝐿2 𝑋2
𝑀( 𝑥) =
−3𝐸𝐼𝛿
𝐿3 𝑋 +
3𝐸𝐼𝛿
𝐿2
𝑆 ( 𝑥) =
−3𝐸𝐼𝛿
𝐿3

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Homework2

  • 1. Pb.1 # Find deflection, shear and moment distribution 1𝐸𝐼𝑉′′′′ = 0 2𝐸𝐼𝑉′′′ = 𝐶1 3𝐸𝐼𝑉′′ = 𝐶1 𝑋 + 𝐶2 𝐸𝐼𝑉′ = 𝐶1 𝑋2 2 + 𝐶2 𝑋 + 𝐶3 4 𝐸𝐼𝑉 = 𝐶1 𝑋3 6 + 𝐶2 𝑋2 2 + 𝐶3 𝑋 + 𝐶4 5
  • 2. B.CS At X=0 V (0) = 0 𝑉′ (0) = 0 At x=L V (L) = 𝛿 M (L) =0 Substituting B.CS in equations 2,3,4,5 we get i𝐶1 = −3𝐸𝐼𝛿 𝐿3 ii𝐶2 = 3𝐸𝐼𝛿 𝐿2 𝑉( 𝑥) = −3𝛿 6𝐿3 𝑋3 + 3𝛿 2𝐿2 𝑋2 𝑀( 𝑥) = −3𝐸𝐼𝛿 𝐿3 𝑋 + 3𝐸𝐼𝛿 𝐿2 𝑆 ( 𝑥) = −3𝐸𝐼𝛿 𝐿3