A horizontal rope is tied to a 44.0 kg box on frictionless ice. What is the tension in the rope if: a) The box is at rest? b) The box moves at a steady v x = 4.80 m/s ? c) The box v x = 4.80 m/s and a x = 4.60 m/s^2 ? Solution a) T = tension force in the string a = acceleration = 0 since box is at rest m = mass of the box = 44 kg Using the equation T = ma T = 44 x 0 = 0 N b) T = tension force in the string a = acceleration = 0 since box moves at steady rate m = mass of the box = 44 kg Using the equation T = ma T = 44 x 0 = 0 N c) T = tension force in the string a = acceleration = 4.6 since box is at rest m = mass of the box = 44 kg Using the equation T = ma T = 44 x 4.6 = 202.4 N .

1. A horizontal rope is tied to a 44.0 kg box on frictionless ice. What is the tension in the rope if:
a) The box is at rest?
b) The box moves at a steady
v x = 4.80 m/s ?
c) The box v x = 4.80 m/s and a x = 4.60 m/s^2 ?
Solution
a)
T = tension force in the string
a = acceleration = 0 since box is at rest
m = mass of the box = 44 kg
Using the equation
T = ma
T = 44 x 0 = 0 N
b)
T = tension force in the string
a = acceleration = 0 since box moves at steady rate
m = mass of the box = 44 kg
Using the equation

2. T = ma
T = 44 x 0 = 0 N
c)
T = tension force in the string
a = acceleration = 4.6 since box is at rest
m = mass of the box = 44 kg
Using the equation
T = ma
T = 44 x 4.6 = 202.4 N