ncuma_牛頓法_習題2

1. 1
國立中央大學數學系
牛頓迭代法 : 習題 2
 求出 2 ∗ sin(x) + cos(2x) 之根
1 : x = 6.283185e+00 , f(x) = 1.000000e+00
2 : x = 5.783185e+00 , f(x) = -4.185488e-01
3 : x = 5.904923e+00 , f(x) = -1.138500e-02
4 : x = 5.908447e+00 , f(x) = -1.352360e-05
5 : x = 5.908451e+00 , f(x) = -1.932465e-11
6 : x = 5.908451e+00 , f(x) = -7.771561e-16
設定 ，容許誤差 1 ×