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The Arrhenius Theory of acids and bases The theo.pdf
The Arrhenius Theory of acids and bases The theory Acids are substances which
produce hydrogen ions in solution. Bases are substances which produce hydroxide ions in
solution. HBr------>H+ + Br- since HBr is capable of producing H+ it is an acid
Solution
The Arrhenius Theory of acids and bases The theory Acids are substances which
produce hydrogen ions in solution. Bases are substances which produce hydroxide ions in
solution. HBr------>H+ + Br- since HBr is capable of producing H+ it is an acid.
oxygen in air (O2) reacts with H2 when it burns .pdf
oxygen in air (O2) reacts with H2 when it burns H2 + 2O2 = 2H2O
Solution
oxygen in air (O2) reacts with H2 when it burns H2 + 2O2 = 2H2O.
most of the hydrogens on the benzene were replace.pdf
most of the hydrogens on the benzene were replaced with Deuterium
Solution
most of the hydrogens on the benzene were replaced with Deuterium.
identical is the exact same, this is the top r.pdf
identical: is the exact same, this is the **top right**, which has just been flipped
over so the ups are down and downs are up. enantomer: - mirror image **bottom middle**, flip
it over up and down is the same, but side-to-side is reversed - or leave it how it is and place it
directly on top of the reference and up and down are opposite but the species match exactly
diastereomer: **top left** everything is in the correct order. Not mirror image since para OCH3
and OH are trans in reference molecule structural: different bonding order **bottom left** broke
the ring adds two Hs formed double bond subtracts two Hs conformational:this is basically
identical, just rotation about single bond **top middle** where the top OH just needs to spin
around the top C What is the bottom right? Is is a mirror image with conformational. This would
be diastereomer. different compound that is not isometric: they seem to all be isomers
Solution
identical: is the exact same, this is the **top right**, which has just been flipped
over so the ups are down and downs are up. enantomer: - mirror image **bottom middle**, flip
it over up and down is the same, but side-to-side is reversed - or leave it how it is and place it
directly on top of the reference and up and down are opposite but the species match exactly
diastereomer: **top left** everything is in the correct order. Not mirror image since para OCH3
and OH are trans in reference molecule structural: different bonding order **bottom left** broke
the ring adds two Hs formed double bond subtracts two Hs conformational:this is basically
identical, just rotation about single bond **top middle** where the top OH just needs to spin
around the top C What is the bottom right? Is is a mirror image with conformational. This would
be diastereomer. different compound that is not isometric: they seem to all be isomers.
This is a nucleophilic substitution reaction that.pdf
This is a nucleophilic substitution reaction that proceeds by the SN2 mechanism
since it involves a primary alkyl halide. The faster reaction is the one with the stronger
nucleophile and less protic solvent: b.CH3CH2CH2Br ----SH,RSH---> CH3CH2CH2SH + Br -
S is more polarizable than O making its lone pairs more accessible and is hence a better
nucleophile. Also the lone pairs are less solvated in RSH due to much weaker hydrogen bonding
than in H2O.
Solution
This is a nucleophilic substitution reaction that proceeds by the SN2 mechanism
since it involves a primary alkyl halide. The faster reaction is the one with the stronger
nucleophile and less protic solvent: b.CH3CH2CH2Br ----SH,RSH---> CH3CH2CH2SH + Br -
S is more polarizable than O making its lone pairs more accessible and is hence a better
nucleophile. Also the lone pairs are less solvated in RSH due to much weaker hydrogen bonding
than in H2O..
Sulfur is oxidized and nitrogen is reduced. .pdf
Sulfur is oxidized and nitrogen is reduced.
Solution
Sulfur is oxidized and nitrogen is reduced..
TriangleU210.javapublic class TriangleU210 { Declaring inst.pdf
TriangleU210.java
public class TriangleU210 {
//Declaring instance variables
private double coodX1,coodY1,coodX2,coodY2,coodX3,coodY3;
//Default Constructor
public TriangleU210() {
this.coodX1=0;
this.coodY1=0;
this.coodX2=0;
this.coodY2=10;
this.coodX3=30;
this.coodY3=30;
}
//Parameterized constructor
public TriangleU210(double coodX1, double coodY1, double coodX2, double coodY2,
double coodX3, double coodY3) {
this.coodX1 = coodX1;
this.coodY1 = coodY1;
this.coodX2 = coodX2;
this.coodY2 = coodY2;
this.coodX3 = coodX3;
this.coodY3 = coodY3;
}
//Getters and setters
public double getCoodX1() {
return coodX1;
}
public void setCoodX1(double coodX1) {
this.coodX1 = coodX1;
}
public double getCoodY1() {
return coodY1;
}
public void setCoodY1(double coodY1) {
this.coodY1 = coodY1;
}
public double getCoodX2() {
return coodX2;
}
public void setCoodX2(double coodX2) {
this.coodX2 = coodX2;
}
public double getCoodY2() {
return coodY2;
}
public void setCoodY2(double coodY2) {
this.coodY2 = coodY2;
}
public double getCoodX3() {
return coodX3;
}
public void setCoodX3(double coodX3) {
this.coodX3 = coodX3;
}
public double getCoodY3() {
return coodY3;
}
public void setCoodY3(double coodY3) {
this.coodY3 = coodY3;
}
//This method will calculate the distance between the point
public double distance(double x1,double y1,double x2,double y2)
{
return Math.sqrt(Math.pow((x2-x1),2)+Math.pow((y2-y1),2));
}
//This method will calculate the angle between the two points
public double angleOfPoints(double x1,double y1,double x2,double y2)
{
double xDiff=x2-x1;
double yDiff=y2-y1;
double angle=Math.atan2(yDiff, xDiff)*(180/Math.PI);
return angle;
}
//This method will calculate the area of the triangle
public double getArea()
{
double lengthA=distance(getCoodX1(),getCoodY1(), getCoodX2(), getCoodY2());
double lengthB=distance(getCoodX2(),getCoodY2(), getCoodX3(), getCoodY3());
double lengthC=distance(getCoodX3(),getCoodY3(), getCoodX1(), getCoodY1());
double S=(lengthA+lengthB+lengthC)/2;
//Calculating the area
double area=Math.sqrt(S*(S-lengthA)*(S-lengthB)*(S-lengthC));
return area;
}
//This method will calculate the Perimeter of the triangle
public double getPerimeter()
{
double lengthA=distance(getCoodX1(),getCoodY1(), getCoodX2(), getCoodY2());
double lengthB=distance(getCoodX2(),getCoodY2(), getCoodX3(), getCoodY3());
double lengthC=distance(getCoodX3(),getCoodY3(), getCoodX1(), getCoodY1());
//Calculating the perimter
double S=(lengthA+lengthB+lengthC);
return S;
}
//Displaying the triangle is isosceles triangle or not
public void Isosceles()
{
double lengthA=distance(getCoodX1(),getCoodY1(), getCoodX2(), getCoodY2());
double lengthB=distance(getCoodX2(),getCoodY2(), getCoodX3(), getCoodY3());
double lengthC=distance(getCoodX3(),getCoodY3(), getCoodX1(), getCoodY1());
if((lengthA==lengthB) || (lengthB==lengthC) || (lengthC==lengthA) )
{
System.out.println(\":: The Triangle is Isosceles ::\");
}
else
System.out.println(\":: The Triangle is Not Isosceles ::\");
}
//.
Recommended
The Arrhenius Theory of acids and bases The theo.pdf
The Arrhenius Theory of acids and bases The theory Acids are substances which
produce hydrogen ions in solution. Bases are substances which produce hydroxide ions in
solution. HBr------>H+ + Br- since HBr is capable of producing H+ it is an acid
Solution
The Arrhenius Theory of acids and bases The theory Acids are substances which
produce hydrogen ions in solution. Bases are substances which produce hydroxide ions in
solution. HBr------>H+ + Br- since HBr is capable of producing H+ it is an acid.
oxygen in air (O2) reacts with H2 when it burns .pdf
oxygen in air (O2) reacts with H2 when it burns H2 + 2O2 = 2H2O
Solution
oxygen in air (O2) reacts with H2 when it burns H2 + 2O2 = 2H2O.
most of the hydrogens on the benzene were replace.pdf
most of the hydrogens on the benzene were replaced with Deuterium
Solution
most of the hydrogens on the benzene were replaced with Deuterium.
identical is the exact same, this is the top r.pdf
identical: is the exact same, this is the **top right**, which has just been flipped
over so the ups are down and downs are up. enantomer: - mirror image **bottom middle**, flip
it over up and down is the same, but side-to-side is reversed - or leave it how it is and place it
directly on top of the reference and up and down are opposite but the species match exactly
diastereomer: **top left** everything is in the correct order. Not mirror image since para OCH3
and OH are trans in reference molecule structural: different bonding order **bottom left** broke
the ring adds two Hs formed double bond subtracts two Hs conformational:this is basically
identical, just rotation about single bond **top middle** where the top OH just needs to spin
around the top C What is the bottom right? Is is a mirror image with conformational. This would
be diastereomer. different compound that is not isometric: they seem to all be isomers
Solution
identical: is the exact same, this is the **top right**, which has just been flipped
over so the ups are down and downs are up. enantomer: - mirror image **bottom middle**, flip
it over up and down is the same, but side-to-side is reversed - or leave it how it is and place it
directly on top of the reference and up and down are opposite but the species match exactly
diastereomer: **top left** everything is in the correct order. Not mirror image since para OCH3
and OH are trans in reference molecule structural: different bonding order **bottom left** broke
the ring adds two Hs formed double bond subtracts two Hs conformational:this is basically
identical, just rotation about single bond **top middle** where the top OH just needs to spin
around the top C What is the bottom right? Is is a mirror image with conformational. This would
be diastereomer. different compound that is not isometric: they seem to all be isomers.
This is a nucleophilic substitution reaction that.pdf
This is a nucleophilic substitution reaction that proceeds by the SN2 mechanism
since it involves a primary alkyl halide. The faster reaction is the one with the stronger
nucleophile and less protic solvent: b.CH3CH2CH2Br ----SH,RSH---> CH3CH2CH2SH + Br -
S is more polarizable than O making its lone pairs more accessible and is hence a better
nucleophile. Also the lone pairs are less solvated in RSH due to much weaker hydrogen bonding
than in H2O.
Solution
This is a nucleophilic substitution reaction that proceeds by the SN2 mechanism
since it involves a primary alkyl halide. The faster reaction is the one with the stronger
nucleophile and less protic solvent: b.CH3CH2CH2Br ----SH,RSH---> CH3CH2CH2SH + Br -
S is more polarizable than O making its lone pairs more accessible and is hence a better
nucleophile. Also the lone pairs are less solvated in RSH due to much weaker hydrogen bonding
than in H2O..
Sulfur is oxidized and nitrogen is reduced. .pdf
Sulfur is oxidized and nitrogen is reduced.
Solution
Sulfur is oxidized and nitrogen is reduced..
TriangleU210.javapublic class TriangleU210 { Declaring inst.pdf
TriangleU210.java
public class TriangleU210 {
//Declaring instance variables
private double coodX1,coodY1,coodX2,coodY2,coodX3,coodY3;
//Default Constructor
public TriangleU210() {
this.coodX1=0;
this.coodY1=0;
this.coodX2=0;
this.coodY2=10;
this.coodX3=30;
this.coodY3=30;
}
//Parameterized constructor
public TriangleU210(double coodX1, double coodY1, double coodX2, double coodY2,
double coodX3, double coodY3) {
this.coodX1 = coodX1;
this.coodY1 = coodY1;
this.coodX2 = coodX2;
this.coodY2 = coodY2;
this.coodX3 = coodX3;
this.coodY3 = coodY3;
}
//Getters and setters
public double getCoodX1() {
return coodX1;
}
public void setCoodX1(double coodX1) {
this.coodX1 = coodX1;
}
public double getCoodY1() {
return coodY1;
}
public void setCoodY1(double coodY1) {
this.coodY1 = coodY1;
}
public double getCoodX2() {
return coodX2;
}
public void setCoodX2(double coodX2) {
this.coodX2 = coodX2;
}
public double getCoodY2() {
return coodY2;
}
public void setCoodY2(double coodY2) {
this.coodY2 = coodY2;
}
public double getCoodX3() {
return coodX3;
}
public void setCoodX3(double coodX3) {
this.coodX3 = coodX3;
}
public double getCoodY3() {
return coodY3;
}
public void setCoodY3(double coodY3) {
this.coodY3 = coodY3;
}
//This method will calculate the distance between the point
public double distance(double x1,double y1,double x2,double y2)
{
return Math.sqrt(Math.pow((x2-x1),2)+Math.pow((y2-y1),2));
}
//This method will calculate the angle between the two points
public double angleOfPoints(double x1,double y1,double x2,double y2)
{
double xDiff=x2-x1;
double yDiff=y2-y1;
double angle=Math.atan2(yDiff, xDiff)*(180/Math.PI);
return angle;
}
//This method will calculate the area of the triangle
public double getArea()
{
double lengthA=distance(getCoodX1(),getCoodY1(), getCoodX2(), getCoodY2());
double lengthB=distance(getCoodX2(),getCoodY2(), getCoodX3(), getCoodY3());
double lengthC=distance(getCoodX3(),getCoodY3(), getCoodX1(), getCoodY1());
double S=(lengthA+lengthB+lengthC)/2;
//Calculating the area
double area=Math.sqrt(S*(S-lengthA)*(S-lengthB)*(S-lengthC));
return area;
}
//This method will calculate the Perimeter of the triangle
public double getPerimeter()
{
double lengthA=distance(getCoodX1(),getCoodY1(), getCoodX2(), getCoodY2());
double lengthB=distance(getCoodX2(),getCoodY2(), getCoodX3(), getCoodY3());
double lengthC=distance(getCoodX3(),getCoodY3(), getCoodX1(), getCoodY1());
//Calculating the perimter
double S=(lengthA+lengthB+lengthC);
return S;
}
//Displaying the triangle is isosceles triangle or not
public void Isosceles()
{
double lengthA=distance(getCoodX1(),getCoodY1(), getCoodX2(), getCoodY2());
double lengthB=distance(getCoodX2(),getCoodY2(), getCoodX3(), getCoodY3());
double lengthC=distance(getCoodX3(),getCoodY3(), getCoodX1(), getCoodY1());
if((lengthA==lengthB) || (lengthB==lengthC) || (lengthC==lengthA) )
{
System.out.println(\":: The Triangle is Isosceles ::\");
}
else
System.out.println(\":: The Triangle is Not Isosceles ::\");
}
//.
There is some data missing in the problem.The composition of the m.pdf
There is some data missing in the problem.
The composition of the mixture and the reaction taking place need to be mentioned. The total
experiment might help
Moles of CaC2O4. H2O = mass/ molar mass
= 1.075 g / 146.11 g/mol
= 0.0074 moles
Solution
There is some data missing in the problem.
The composition of the mixture and the reaction taking place need to be mentioned. The total
experiment might help
Moles of CaC2O4. H2O = mass/ molar mass
= 1.075 g / 146.11 g/mol
= 0.0074 moles.
at beginning flask has only NaOH pH = 14 + log [N.pdf
at beginning flask has only NaOH pH = 14 + log [NaOH] =14+log[1] = 14
{[NaOH]= conc. of naoh in Mole/liter = 1 (given)}
Solution
at beginning flask has only NaOH pH = 14 + log [NaOH] =14+log[1] = 14
{[NaOH]= conc. of naoh in Mole/liter = 1 (given)}.
take log on both sides1n lna = ln las a--0.pdf
take log on both sides
1/n lna = ln l
as a--0
l= e^ 0 =1
Solution
take log on both sides
1/n lna = ln l
as a--0
l= e^ 0 =1.
Tested on Eclipse and both class should be in same packageimport.pdf
//Tested on Eclipse and both class should be in same package
import java.util.Scanner;
public class P3 {
/*isInteger method implementation
* @param String type
* while parsing if it throw exception then it is not integer
* else it is integer*/
public static Boolean isDouble(String token){
try {
Double.parseDouble(token);
} catch(NumberFormatException e) {
System.out.println(\"Invalid Operand\");
return false;
} catch(NullPointerException e) {
System.out.println(\"Invalid Operand\");
return false;
}
// only got here if we didn\'t return false
return true;
}
public static String evaluate(String expression) {
// Print expression
System.out.print(expression);
// Declare variables for operands, operator, result, and return value
double operand1=0,operand2 = 0,result=0;
char operator;
Boolean flag=Boolean.FALSE;//for if operators were not listed
String returnString = \"\";
String token[]=new String[expression.length()];//for storing all token from expression
// Create Scanner object to parse expression
// create a new scanner with the specified String Object
int i=0;
Scanner scanner = new Scanner(expression);
while(scanner.hasNext()){
token[i]=scanner.next();
i++;
}
scanner.close();
// Compute a numerical result for the expression
if(isDouble(token[0])){
operand1=Double.parseDouble(token[0]);
}
if(isDouble(token[2])){
operand2=Double.parseDouble(token[2]);
}
operator=token[1].charAt(0);
if(operand1!=0&&operand2!=0){
switch(operator){
case \'+\':
result=operand1+operand2;
break;
case \'-\':
result=operand1-operand2;
break;
case \'*\':
result=operand1*operand2;
break;
case \'/\':
result=operand1/operand2;
break;
case \'%\':
result=operand1%operand2;
break;
case \'^\':
result=Math.pow(operand1, operand2);
break;
default:
System.out.println(\"Invalid Operator\");
flag=Boolean.TRUE;
break;
}
// Convert numerical result to string
returnString=Double.toString(result);
if(flag){
return null;
}
// Return result
return returnString;
}else{
return null;
}
}
}
/*********Calculator class***************/
import java.util.Scanner;
/*Calculator class start*/
public class Calculator {
public static void main(String args[]){
/*Variable declaration*/
String expression;
/*Scanner object for input*/
Scanner input=new Scanner(System.in);
/*Prompt for expression*/
System.out.println(\"Please Enter expression\");
expression=input.nextLine();
input.close();
/*Calling Evaluate method*/
String result=P3.evaluate(expression);
/*Printing result if it is not null*/
if(result!=null) {
System.out.println(result);
}
}
}
/***************output************/
Please Enter expression
11.22 + 3.456 =
11.22 + 3.456 =14.676
Please Enter expression
5.555 - 32.14 =
5.555 - 32.14 =-26.585
Please Enter expression
25634.8 * .32 =
25634.8 * .32 = 8203.136
Please Enter expression
5 ^ 4 =
5 ^ 4 =625.0
Please Enter expression
Whatever + 2 =
Whatever + 2 =Invalid Operand
Please Enter expression
4.0 - 1.2.3 =
4.0 - 1.2.3 =Invalid Operand
Please Enter expression
1.234 $ 0.5 =
1.234 $ 0.5 =Invalid Ope.
Solution A person in perfect health has a utility score of 1.0U.pdf
Solution
:
A person in perfect health has a utility score of 1.0
Utility of a person having some cognitive problems and some social problems = 1 - 0.35 - 0.29
Utility of a person having some cognitive problems and some social problems = 0.36.
Resurgent infection is suggesting that it is viral infection by meas.pdf
Resurgent infection is suggesting that it is viral infection by measles virus S. In this disease
patients have fever above 101 °F with diarrhea.
Possible reason would be the vaccination in 1963 didn’t work properly and some of the patients
got immuned for the virus. The remaining patients latterly increased infection by transmitting
means.
Herd immunity is termed when a large population or a community get immuned to an infection.
In this case 18, 193 cases of 1989 got herd immunity because the next year number increased
largely.
In US the vaccine, Measles, mumps, and rubella (MMR) vaccine, is administered in between 12
months to 4 years age.
Solution
Resurgent infection is suggesting that it is viral infection by measles virus S. In this disease
patients have fever above 101 °F with diarrhea.
Possible reason would be the vaccination in 1963 didn’t work properly and some of the patients
got immuned for the virus. The remaining patients latterly increased infection by transmitting
means.
Herd immunity is termed when a large population or a community get immuned to an infection.
In this case 18, 193 cases of 1989 got herd immunity because the next year number increased
largely.
In US the vaccine, Measles, mumps, and rubella (MMR) vaccine, is administered in between 12
months to 4 years age..
There are only two functional groups in the molec.pdf
There are only two functional groups in the molecule: -OH (alcohol) -COO- (ester)
Any other functional group is not found in the molecule
Solution
There are only two functional groups in the molecule: -OH (alcohol) -COO- (ester)
Any other functional group is not found in the molecule.
PsychoanalysisPsychoanalysis was founded by Sigmund Freud (1856-19.pdf
Psychoanalysis
Psychoanalysis was founded by Sigmund Freud (1856-1939). Freud believed that people could
be cured by making conscious their unconscious thoughts and motivations, thus gaining insight.
The aim of psychoanalysis therapy is to release repressed emotions and experiences, i.e. make
the unconscious conscious.
The basic tenets of psychoanalysis include:
Psychoanalysis designates concomitantly three things:
Confrontation
This is a practice often done prior to an intervention where the patient is encouraged to attend to
experiences that they have been avoiding.
Countertransference
This refers to the analyst’s feelings and attitudes towards the patient: his/her reaction to the
patient’s transference, how his/her own experiences impact his/her understanding of the patient,
and the analyst’s emotional responses to the patient.
Defense Mechanisms
Defense mechanisms are used by the ego as a way to deal with conflict of problems in life.
Operating at an unconscious level, defense mechanisms help to reduce negative feelings (e.g.
anxiety and guilt). Common defense mechanisms include repression, denial, and projection.
Dream
It is a mental event that consists of hallucinations involving imagery and emotions. Dreams
occur during the rapid-eye movement (REM) stage during sleep. According to Freud, current
concerns and unconscious childhood wishes are present during the day and require gratification
and it is dreams that allow us to respond to this demands while continuing to sleep (e.g., a person
who is thirsty dreams about drinking water which allows him to continue sleeping rather than
having to wake up and satisfy his thirst)
Ego
Sigmund Freud theorized that the mind was divided into three parts: id, ego and superego. The
function of the ego can be described as running interference between the id and the superego. It
mediates between the drives of the id and the need for self-preservation. The ego is responsible
for the development of the skills needed to function in the world, for example, impulse control,
perception, evaluation and judgment.
Id
Sigmund Freud theorized that the mind was divided into three parts: id, ego and superego. The id
is the part of the mind that contains one’s most basic and instinctive drives. It is governed by
sexual and aggressive desires and pleasure seeking. The contents of the id are entirely
unconscious; Freud stated that the goal of analysis is to uncover what is repressed in the id so
that, “where id was, there ego shall be.”
Superego
Sigmund Freud theorized that the mind was divided into three parts: id, ego and superego. The
superego can be thought of as the part of the mind that acts as the conscience. Its function is to
stop or punish behaviour that is unacceptable according the ego ideal, i.e., the standards, values,
and images of perfection that begin to develop in childhood, and which some psychoanalysts
believe to develop over a lifetime. Failure to live up to these standards results in feeling of gui.
Product of Cyclopentane + H2O(H+) gives No Reaction.It will simply F.pdf
Product of Cyclopentane + H2O(H+) gives No Reaction.It will simply Float on it.
No reaction
Solution
Product of Cyclopentane + H2O(H+) gives No Reaction.It will simply Float on it.
No reaction.
Of the variedtypes of IPC, sockets arout and awaythe foremostcommon..pdf
Of the variedtypes of IPC, sockets arout and awaythe foremostcommon. On any given platform,
there arprobably to be differenttypes of IPC that arquicker, except for cross-platform
communication, sockets arregardingthe sole game in city.
They were fancied in Berkeley as a part of the BSD flavor of UNIX operating system. They
unfold like inferno withthe web. With sensible reason — the mixture of sockets with INET
makes reprehensionabsolute machines round the world incrediblystraightforward (at least
compared to different schemes).
Creating a Socket
Roughly speaking, once you clicked on the link that brought you to the current page, your
browser did one thingjust like the following:
#create Associate in Nursing INET, STREAMing socket
s = socket.socket(
socket.AF_INET, socket.SOCK_STREAM)
#now connect withthe net server on port eighty
# - the traditionalcommunications protocol port
s.connect((\"www.mcmillan-inc.com\", 80))
When the connect completes, the socket s may beaccustomedsend outa call for participation for
the text of the page. a similar socket canbrowse the reply, so be destroyed. That’s right,
destroyed. shopper sockets arunremarkablysolely used for one exchange (or atiny low set of
sequent exchanges).
What happens within thenet server may be a bit additionalcomplicated. First, the net server
creates a “server socket”:
#create Associate in Nursing INET, STREAMing socket
serversocket = socket.socket(
socket.AF_INET, socket.SOCK_STREAM)
#bind the socket to a public host,
# and a widely known port
serversocket.bind((socket.gethostname(), 80))
#become a server socket
serversocket.listen(5)
A couple things to notice: we tend to used socket.gethostname() in order that the socket would
be visible to the surface world. If we tend to had used s.bind((\'localhost\', 80)) or
s.bind((\'127.0.0.1\', 80)) we\'d still have a “server” socket, however one that was solely visible
insidea similar machine. s.bind((\'\', 80)) specifies that the socket isaccessible by any address the
machine happens to own.
A second issue to note: low range ports arsometimes reserved for “well known” services (HTTP,
SNMP etc). If you’re kidding, use a pleasant high range (4 digits).
Finally, the argument to pay attention tells the socket library that we wish it to queue as several
as five connect requests (the traditional max) before refusing outside connections. If the
remainder of the code is written properly,that ought to be masses.
Now that we\'ve got a “server” socket, listening on port eighty, we will enter the mainloop of the
net server:
while 1:
#accept connections from outside
(clientsocket, address) = serversocket.accept()
#now do one thing with the clientsocket
#in this case, we\'ll fakethis can be a rib server
ct = client_thread(clientsocket)
ct.run()
There’s trulythree general ways thatduring which this loop might work - dispatching a thread to
handle clientsocket, producea replacementmethod to handle clientsocket, or structure this app to
use non-blocking socke.
C2O2 is a bidendate ligand &Cl - is a mono dendat.pdf
C2O2 is a bidendate ligand &Cl - is a mono dendate ligang. ---> The coordination
number of Co is 2*2 + 2 = 6 EDTA is a hexadentate ligang & Br is a mono dentate ligang. --->
The coordination number of Co is 6+1=7
Solution
C2O2 is a bidendate ligand &Cl - is a mono dendate ligang. ---> The coordination
number of Co is 2*2 + 2 = 6 EDTA is a hexadentate ligang & Br is a mono dentate ligang. --->
The coordination number of Co is 6+1=7.
Insulin receptor signaling is represented by figure DEffect of hyp.pdf
Insulin receptor signaling is represented by figure D
Effect of hyper and hypo thyroidism on body temperature is represented by figure E
The effect of thyrotropin on thyroid follicular cells include iodide entrapment and organification
is represented by figure C
Hypovloemia triggers the release of vasopressin in a pulsatile fashion is represented by figure A.
Solution
Insulin receptor signaling is represented by figure D
Effect of hyper and hypo thyroidism on body temperature is represented by figure E
The effect of thyrotropin on thyroid follicular cells include iodide entrapment and organification
is represented by figure C
Hypovloemia triggers the release of vasopressin in a pulsatile fashion is represented by figure A..
let E0 be given=there exists N1, N2 such thatan -am E2.pdf
let E>0 be given
=>
there exists N1, N2 such that
|an -am | < E/2 for n,m >N1
|bn-bm | N2
=>
|an-am| + |bn-bm| N = max{N1,N2}
=>
|an+bn -am-bm| <=|an-am| + |bn-bm| N = max{N1,N2}
=>
|(an+bn) -(am+bm)| N
=>
an+bn is cauchy sequence
thus proved
an, bn are cauchy sequences => an, bn are bounded
let |an| <=A, |bn| <=B
there exists n1 n2 such that
|an-am| < E/2B for n,m >n1, => |an-am||bn| n1 => |anbn -ambn| n1
|bn-bm| < E/2A for n,m >n2 => |bn-bm||am| n2 => |bnam -ambm| n2
=>
|anbn -ambn| + |bnam -ambm| < E for n,m > N = max{n1,n2}
=>
|anbn-ambm| <|anbn -ambn| + |bnam -ambm| < E for n,m > N = max{n1,n2}
=>
|anbn-ambm| < E for n,m > N = max{n1,n2}
=>
anbn is a cauchy sequence
thus proved
Solution
let E>0 be given
=>
there exists N1, N2 such that
|an -am | < E/2 for n,m >N1
|bn-bm | N2
=>
|an-am| + |bn-bm| N = max{N1,N2}
=>
|an+bn -am-bm| <=|an-am| + |bn-bm| N = max{N1,N2}
=>
|(an+bn) -(am+bm)| N
=>
an+bn is cauchy sequence
thus proved
an, bn are cauchy sequences => an, bn are bounded
let |an| <=A, |bn| <=B
there exists n1 n2 such that
|an-am| < E/2B for n,m >n1, => |an-am||bn| n1 => |anbn -ambn| n1
|bn-bm| < E/2A for n,m >n2 => |bn-bm||am| n2 => |bnam -ambm| n2
=>
|anbn -ambn| + |bnam -ambm| < E for n,m > N = max{n1,n2}
=>
|anbn-ambm| <|anbn -ambn| + |bnam -ambm| < E for n,m > N = max{n1,n2}
=>
|anbn-ambm| < E for n,m > N = max{n1,n2}
=>
anbn is a cauchy sequence
thus proved.
import java.util.ArrayList; import java.util.List; .pdf
import java.util.ArrayList;
import java.util.List;
/**
*
*
*/
public class AList {
List list = new ArrayList();
public AList() {
// TODO Auto-generated constructor stub
}
/**
*
*/
public AList(List list) {
this.list = list;
}
/*
* (non-Javadoc)
*
* see java.lang.Object#equals(java.lang.Object)
*/
public boolean equals(Object obj) {
// TODO Auto-generated method stub
AList aList = (AList) obj;
List arrayList = aList.getList();
if (arrayList.size() != list.size()) {
return false;
}
for (int i = 0; i < list.size(); i++) {
if (list.get(i) != arrayList.get(i)) {
return false;
}
}
return true;
}
/**
* return the list
*/
public List getList() {
return list;
}
/**
* param list
* the list to set
*/
public void setList(List list) {
this.list = list;
}
/**
* param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
List integers = new ArrayList();
integers.add(10);
integers.add(20);
integers.add(30);
integers.add(40);
integers.add(50);
List integers1 = new ArrayList();
integers1.add(10);
integers1.add(20);
integers1.add(30);
integers1.add(40);
integers1.add(60);
AList aList1 = new AList(integers);
AList aList2 = new AList(integers);
System.out.println(\"list1 and list2 are equal? \"
+ aList1.equals(aList2));
aList2 = new AList(integers1);
System.out
.println(\"After adding 60 to list2, list1 and list2 are not equal? \"
+ aList1.equals(aList2));
}
}
OUTPUT:
list1 and list2 are equal? true
After adding 60 to list2, list1 and list2 are not equal? false
Solution
import java.util.ArrayList;
import java.util.List;
/**
*
*
*/
public class AList {
List list = new ArrayList();
public AList() {
// TODO Auto-generated constructor stub
}
/**
*
*/
public AList(List list) {
this.list = list;
}
/*
* (non-Javadoc)
*
* see java.lang.Object#equals(java.lang.Object)
*/
public boolean equals(Object obj) {
// TODO Auto-generated method stub
AList aList = (AList) obj;
List arrayList = aList.getList();
if (arrayList.size() != list.size()) {
return false;
}
for (int i = 0; i < list.size(); i++) {
if (list.get(i) != arrayList.get(i)) {
return false;
}
}
return true;
}
/**
* return the list
*/
public List getList() {
return list;
}
/**
* param list
* the list to set
*/
public void setList(List list) {
this.list = list;
}
/**
* param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
List integers = new ArrayList();
integers.add(10);
integers.add(20);
integers.add(30);
integers.add(40);
integers.add(50);
List integers1 = new ArrayList();
integers1.add(10);
integers1.add(20);
integers1.add(30);
integers1.add(40);
integers1.add(60);
AList aList1 = new AList(integers);
AList aList2 = new AList(integers);
System.out.println(\"list1 and list2 are equal? \"
+ aList1.equals(aList2));
aList2 = new AList(integers1);
System.out
.println(\"After adding 60 to list2, list1 and list2 are not equal? \"
+ aList1.equals(aList2));
}
}
OUTPUT:
list1 and list2 are equal? true
After adding 60 to list2, list1 and list2 are not equal? fal.
Given for balanced wye-delta systemSolutionGiven for b.pdf
Given for balanced wye-delta system
Solution
Given for balanced wye-delta system.
Humans generally have polymorphisms where both alleles are found in .pdf
Humans generally have polymorphisms where both alleles are found in both populations. The
alleles may be either most prevalent or least prevalent in the population. Population has
combinationof the polymorphic alleles. This is due to the fact that population is a breeding group
and hence, transmit the genotypes which are broken down and new set/comobination of
genotypes is generated in the progeny. Thus, the polymorphic alleles are also in continuum with
an array of the frequencies of those alleles.
Migration changes the freqency of the alleles since new polymorphisms or alleles are introduced
into the population. If individuals are completely isolated, phenomena like founder effect occurs.
Solution
Humans generally have polymorphisms where both alleles are found in both populations. The
alleles may be either most prevalent or least prevalent in the population. Population has
combinationof the polymorphic alleles. This is due to the fact that population is a breeding group
and hence, transmit the genotypes which are broken down and new set/comobination of
genotypes is generated in the progeny. Thus, the polymorphic alleles are also in continuum with
an array of the frequencies of those alleles.
Migration changes the freqency of the alleles since new polymorphisms or alleles are introduced
into the population. If individuals are completely isolated, phenomena like founder effect occurs..
I cant see the image.. but geometric isomerism .pdf
I can\'t see the image.. but geometric isomerism occurs when there is a double bond
between two carbons. And, the substituents attached to each carbon must be different. So one
carbon cannot have two Hs attached then geometric isomerism is not possible. However, one
carbon can have an H and a CH3 and the other carbon can have H and CH3 and geometric
isomerism will occur, provided there is a double bond.
Solution
I can\'t see the image.. but geometric isomerism occurs when there is a double bond
between two carbons. And, the substituents attached to each carbon must be different. So one
carbon cannot have two Hs attached then geometric isomerism is not possible. However, one
carbon can have an H and a CH3 and the other carbon can have H and CH3 and geometric
isomerism will occur, provided there is a double bond..
H H H-C-N and N has a lone pair of electrons .pdf
H H | | H-C-N and N has a lone pair of electrons | | H H
Solution
H H | | H-C-N and N has a lone pair of electrons | | H H.
DNA DNA is the genetic material of organisms. It contains the gene.pdf
DNA : DNA is the genetic material of organisms. It contains the genetic information coded
within itself . And genetic information is passed onto over generations. Also DNA provides
template for formation of RNA and also replicates itself when cell gets divided. DNA is
composed of purines and pyrimidines connected through hydrogen bonds on a sugar phosphate
backbone. These bases form codon for protein synthesis.
RNA : RNA is ribonucleic acid which differs from DNA in sugar composition and in RNA
thymine is replaced by uracil in RNA. RNA is of three types . mRNA which js useful for
formation of Protein . rRNA OR RIBOSOMAL RNA is useful for ribosomes. and tRNA or
Transfer RNA is important component of protein synthesis. So RNA is the key component of
proteins in the cell.
PROTEINS: Proteins we can say is one of the building blocks of cells in an organism. All
enzymes required for physiological processes are proteinaceous in nature. So they are required
for every minor processes of an organisms.
CARBOHYDRATES : Carbohydrates are also one of the most important biological macro
molecule. Several sugars are involved in energy generation in the cell. So carbohydrates
basically are involved in generation of energy in the cell. ATP is produce by sugar metabolism
only.
LIPIDS : Lipids are also source of energy in cell and equally important biological
macromolecule for teh cell. Stored lipids in the cell provides energy and from from lipids various
metabolic pathways are important.
BUILDING BLOCKS
DNA and RNA : Nitrogenous bases
Proteins : Amino acids
Carbohydreate: Monosaccharide
LIPIDS : Fatty acids.
Solution
DNA : DNA is the genetic material of organisms. It contains the genetic information coded
within itself . And genetic information is passed onto over generations. Also DNA provides
template for formation of RNA and also replicates itself when cell gets divided. DNA is
composed of purines and pyrimidines connected through hydrogen bonds on a sugar phosphate
backbone. These bases form codon for protein synthesis.
RNA : RNA is ribonucleic acid which differs from DNA in sugar composition and in RNA
thymine is replaced by uracil in RNA. RNA is of three types . mRNA which js useful for
formation of Protein . rRNA OR RIBOSOMAL RNA is useful for ribosomes. and tRNA or
Transfer RNA is important component of protein synthesis. So RNA is the key component of
proteins in the cell.
PROTEINS: Proteins we can say is one of the building blocks of cells in an organism. All
enzymes required for physiological processes are proteinaceous in nature. So they are required
for every minor processes of an organisms.
CARBOHYDRATES : Carbohydrates are also one of the most important biological macro
molecule. Several sugars are involved in energy generation in the cell. So carbohydrates
basically are involved in generation of energy in the cell. ATP is produce by sugar metabolism
only.
LIPIDS : Lipids are also source of energy in cell and equally important biological
macromo.
D. A qualitative assessment ranks the seriousness of threats and sen.pdf
D. A qualitative assessment ranks the seriousness of threats and sensitivity of assets into grades
or classes, such as low, medium, and high. It is performed by experts or external consultants and
is based on risk scenarios. Although purely quantitative risk assessment is not possible, purely
qualitative risk analysis is.
Solution
D. A qualitative assessment ranks the seriousness of threats and sensitivity of assets into grades
or classes, such as low, medium, and high. It is performed by experts or external consultants and
is based on risk scenarios. Although purely quantitative risk assessment is not possible, purely
qualitative risk analysis is..
鏘鏘的帶賽人生：從自卑到強運的50年成長屁事然後聊一聊傻瓜型學習歷程分析.pptx
鏘鏘帶賽史
鏘鏘勵志篇
強運就是實力
江湖的暗黑世界
計畫沒過的經驗
寰宇間最後一片淨土
學習成效評量範例
AI式紮根理論質性分析
傻瓜型學習歷程分析
單班實驗
單組研究之資料分析方法
問題導向破題法
自變項與依變項
對實驗組控制組的投入心力
如何寫Introduction和Conclusion
DDLab 實驗室經營分享
大学成绩修改,找黑客改分,修改成绩单,挂科修改,GPA成绩提高黑客常用的邮件入侵方式如何破解Instagram帐户和密码【微oojjiijj信】
→📞 联系方式 📞
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* TG：qoqoqdqd
大学成绩修改，找黑客改分！|成绩单修改、挂科修正...GPA轻松提上来🎉。 想要改写命运？请来找我们吧，本文旨在提供一个安全、可靠的平台，让您可以轻松地修改大学成绩单。我们的黑客改分服务不仅快捷方便，而且非常专业和有效果
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There is some data missing in the problem.The composition of the m.pdf
There is some data missing in the problem.
The composition of the mixture and the reaction taking place need to be mentioned. The total
experiment might help
Moles of CaC2O4. H2O = mass/ molar mass
= 1.075 g / 146.11 g/mol
= 0.0074 moles
Solution
There is some data missing in the problem.
The composition of the mixture and the reaction taking place need to be mentioned. The total
experiment might help
Moles of CaC2O4. H2O = mass/ molar mass
= 1.075 g / 146.11 g/mol
= 0.0074 moles.
at beginning flask has only NaOH pH = 14 + log [N.pdf
at beginning flask has only NaOH pH = 14 + log [NaOH] =14+log[1] = 14
{[NaOH]= conc. of naoh in Mole/liter = 1 (given)}
Solution
at beginning flask has only NaOH pH = 14 + log [NaOH] =14+log[1] = 14
{[NaOH]= conc. of naoh in Mole/liter = 1 (given)}.
take log on both sides1n lna = ln las a--0.pdf
take log on both sides
1/n lna = ln l
as a--0
l= e^ 0 =1
Solution
take log on both sides
1/n lna = ln l
as a--0
l= e^ 0 =1.
Tested on Eclipse and both class should be in same packageimport.pdf
//Tested on Eclipse and both class should be in same package
import java.util.Scanner;
public class P3 {
/*isInteger method implementation
* @param String type
* while parsing if it throw exception then it is not integer
* else it is integer*/
public static Boolean isDouble(String token){
try {
Double.parseDouble(token);
} catch(NumberFormatException e) {
System.out.println(\"Invalid Operand\");
return false;
} catch(NullPointerException e) {
System.out.println(\"Invalid Operand\");
return false;
}
// only got here if we didn\'t return false
return true;
}
public static String evaluate(String expression) {
// Print expression
System.out.print(expression);
// Declare variables for operands, operator, result, and return value
double operand1=0,operand2 = 0,result=0;
char operator;
Boolean flag=Boolean.FALSE;//for if operators were not listed
String returnString = \"\";
String token[]=new String[expression.length()];//for storing all token from expression
// Create Scanner object to parse expression
// create a new scanner with the specified String Object
int i=0;
Scanner scanner = new Scanner(expression);
while(scanner.hasNext()){
token[i]=scanner.next();
i++;
}
scanner.close();
// Compute a numerical result for the expression
if(isDouble(token[0])){
operand1=Double.parseDouble(token[0]);
}
if(isDouble(token[2])){
operand2=Double.parseDouble(token[2]);
}
operator=token[1].charAt(0);
if(operand1!=0&&operand2!=0){
switch(operator){
case \'+\':
result=operand1+operand2;
break;
case \'-\':
result=operand1-operand2;
break;
case \'*\':
result=operand1*operand2;
break;
case \'/\':
result=operand1/operand2;
break;
case \'%\':
result=operand1%operand2;
break;
case \'^\':
result=Math.pow(operand1, operand2);
break;
default:
System.out.println(\"Invalid Operator\");
flag=Boolean.TRUE;
break;
}
// Convert numerical result to string
returnString=Double.toString(result);
if(flag){
return null;
}
// Return result
return returnString;
}else{
return null;
}
}
}
/*********Calculator class***************/
import java.util.Scanner;
/*Calculator class start*/
public class Calculator {
public static void main(String args[]){
/*Variable declaration*/
String expression;
/*Scanner object for input*/
Scanner input=new Scanner(System.in);
/*Prompt for expression*/
System.out.println(\"Please Enter expression\");
expression=input.nextLine();
input.close();
/*Calling Evaluate method*/
String result=P3.evaluate(expression);
/*Printing result if it is not null*/
if(result!=null) {
System.out.println(result);
}
}
}
/***************output************/
Please Enter expression
11.22 + 3.456 =
11.22 + 3.456 =14.676
Please Enter expression
5.555 - 32.14 =
5.555 - 32.14 =-26.585
Please Enter expression
25634.8 * .32 =
25634.8 * .32 = 8203.136
Please Enter expression
5 ^ 4 =
5 ^ 4 =625.0
Please Enter expression
Whatever + 2 =
Whatever + 2 =Invalid Operand
Please Enter expression
4.0 - 1.2.3 =
4.0 - 1.2.3 =Invalid Operand
Please Enter expression
1.234 $ 0.5 =
1.234 $ 0.5 =Invalid Ope.
Solution A person in perfect health has a utility score of 1.0U.pdf
Solution
:
A person in perfect health has a utility score of 1.0
Utility of a person having some cognitive problems and some social problems = 1 - 0.35 - 0.29
Utility of a person having some cognitive problems and some social problems = 0.36.
Resurgent infection is suggesting that it is viral infection by meas.pdf
Resurgent infection is suggesting that it is viral infection by measles virus S. In this disease
patients have fever above 101 °F with diarrhea.
Possible reason would be the vaccination in 1963 didn’t work properly and some of the patients
got immuned for the virus. The remaining patients latterly increased infection by transmitting
means.
Herd immunity is termed when a large population or a community get immuned to an infection.
In this case 18, 193 cases of 1989 got herd immunity because the next year number increased
largely.
In US the vaccine, Measles, mumps, and rubella (MMR) vaccine, is administered in between 12
months to 4 years age.
Solution
Resurgent infection is suggesting that it is viral infection by measles virus S. In this disease
patients have fever above 101 °F with diarrhea.
Possible reason would be the vaccination in 1963 didn’t work properly and some of the patients
got immuned for the virus. The remaining patients latterly increased infection by transmitting
means.
Herd immunity is termed when a large population or a community get immuned to an infection.
In this case 18, 193 cases of 1989 got herd immunity because the next year number increased
largely.
In US the vaccine, Measles, mumps, and rubella (MMR) vaccine, is administered in between 12
months to 4 years age..
There are only two functional groups in the molec.pdf
There are only two functional groups in the molecule: -OH (alcohol) -COO- (ester)
Any other functional group is not found in the molecule
Solution
There are only two functional groups in the molecule: -OH (alcohol) -COO- (ester)
Any other functional group is not found in the molecule.
PsychoanalysisPsychoanalysis was founded by Sigmund Freud (1856-19.pdf
Psychoanalysis
Psychoanalysis was founded by Sigmund Freud (1856-1939). Freud believed that people could
be cured by making conscious their unconscious thoughts and motivations, thus gaining insight.
The aim of psychoanalysis therapy is to release repressed emotions and experiences, i.e. make
the unconscious conscious.
The basic tenets of psychoanalysis include:
Psychoanalysis designates concomitantly three things:
Confrontation
This is a practice often done prior to an intervention where the patient is encouraged to attend to
experiences that they have been avoiding.
Countertransference
This refers to the analyst’s feelings and attitudes towards the patient: his/her reaction to the
patient’s transference, how his/her own experiences impact his/her understanding of the patient,
and the analyst’s emotional responses to the patient.
Defense Mechanisms
Defense mechanisms are used by the ego as a way to deal with conflict of problems in life.
Operating at an unconscious level, defense mechanisms help to reduce negative feelings (e.g.
anxiety and guilt). Common defense mechanisms include repression, denial, and projection.
Dream
It is a mental event that consists of hallucinations involving imagery and emotions. Dreams
occur during the rapid-eye movement (REM) stage during sleep. According to Freud, current
concerns and unconscious childhood wishes are present during the day and require gratification
and it is dreams that allow us to respond to this demands while continuing to sleep (e.g., a person
who is thirsty dreams about drinking water which allows him to continue sleeping rather than
having to wake up and satisfy his thirst)
Ego
Sigmund Freud theorized that the mind was divided into three parts: id, ego and superego. The
function of the ego can be described as running interference between the id and the superego. It
mediates between the drives of the id and the need for self-preservation. The ego is responsible
for the development of the skills needed to function in the world, for example, impulse control,
perception, evaluation and judgment.
Id
Sigmund Freud theorized that the mind was divided into three parts: id, ego and superego. The id
is the part of the mind that contains one’s most basic and instinctive drives. It is governed by
sexual and aggressive desires and pleasure seeking. The contents of the id are entirely
unconscious; Freud stated that the goal of analysis is to uncover what is repressed in the id so
that, “where id was, there ego shall be.”
Superego
Sigmund Freud theorized that the mind was divided into three parts: id, ego and superego. The
superego can be thought of as the part of the mind that acts as the conscience. Its function is to
stop or punish behaviour that is unacceptable according the ego ideal, i.e., the standards, values,
and images of perfection that begin to develop in childhood, and which some psychoanalysts
believe to develop over a lifetime. Failure to live up to these standards results in feeling of gui.
Product of Cyclopentane + H2O(H+) gives No Reaction.It will simply F.pdf
Product of Cyclopentane + H2O(H+) gives No Reaction.It will simply Float on it.
No reaction
Solution
Product of Cyclopentane + H2O(H+) gives No Reaction.It will simply Float on it.
No reaction.
Of the variedtypes of IPC, sockets arout and awaythe foremostcommon..pdf
Of the variedtypes of IPC, sockets arout and awaythe foremostcommon. On any given platform,
there arprobably to be differenttypes of IPC that arquicker, except for cross-platform
communication, sockets arregardingthe sole game in city.
They were fancied in Berkeley as a part of the BSD flavor of UNIX operating system. They
unfold like inferno withthe web. With sensible reason — the mixture of sockets with INET
makes reprehensionabsolute machines round the world incrediblystraightforward (at least
compared to different schemes).
Creating a Socket
Roughly speaking, once you clicked on the link that brought you to the current page, your
browser did one thingjust like the following:
#create Associate in Nursing INET, STREAMing socket
s = socket.socket(
socket.AF_INET, socket.SOCK_STREAM)
#now connect withthe net server on port eighty
# - the traditionalcommunications protocol port
s.connect((\"www.mcmillan-inc.com\", 80))
When the connect completes, the socket s may beaccustomedsend outa call for participation for
the text of the page. a similar socket canbrowse the reply, so be destroyed. That’s right,
destroyed. shopper sockets arunremarkablysolely used for one exchange (or atiny low set of
sequent exchanges).
What happens within thenet server may be a bit additionalcomplicated. First, the net server
creates a “server socket”:
#create Associate in Nursing INET, STREAMing socket
serversocket = socket.socket(
socket.AF_INET, socket.SOCK_STREAM)
#bind the socket to a public host,
# and a widely known port
serversocket.bind((socket.gethostname(), 80))
#become a server socket
serversocket.listen(5)
A couple things to notice: we tend to used socket.gethostname() in order that the socket would
be visible to the surface world. If we tend to had used s.bind((\'localhost\', 80)) or
s.bind((\'127.0.0.1\', 80)) we\'d still have a “server” socket, however one that was solely visible
insidea similar machine. s.bind((\'\', 80)) specifies that the socket isaccessible by any address the
machine happens to own.
A second issue to note: low range ports arsometimes reserved for “well known” services (HTTP,
SNMP etc). If you’re kidding, use a pleasant high range (4 digits).
Finally, the argument to pay attention tells the socket library that we wish it to queue as several
as five connect requests (the traditional max) before refusing outside connections. If the
remainder of the code is written properly,that ought to be masses.
Now that we\'ve got a “server” socket, listening on port eighty, we will enter the mainloop of the
net server:
while 1:
#accept connections from outside
(clientsocket, address) = serversocket.accept()
#now do one thing with the clientsocket
#in this case, we\'ll fakethis can be a rib server
ct = client_thread(clientsocket)
ct.run()
There’s trulythree general ways thatduring which this loop might work - dispatching a thread to
handle clientsocket, producea replacementmethod to handle clientsocket, or structure this app to
use non-blocking socke.
C2O2 is a bidendate ligand &Cl - is a mono dendat.pdf
C2O2 is a bidendate ligand &Cl - is a mono dendate ligang. ---> The coordination
number of Co is 2*2 + 2 = 6 EDTA is a hexadentate ligang & Br is a mono dentate ligang. --->
The coordination number of Co is 6+1=7
Solution
C2O2 is a bidendate ligand &Cl - is a mono dendate ligang. ---> The coordination
number of Co is 2*2 + 2 = 6 EDTA is a hexadentate ligang & Br is a mono dentate ligang. --->
The coordination number of Co is 6+1=7.
Insulin receptor signaling is represented by figure DEffect of hyp.pdf
Insulin receptor signaling is represented by figure D
Effect of hyper and hypo thyroidism on body temperature is represented by figure E
The effect of thyrotropin on thyroid follicular cells include iodide entrapment and organification
is represented by figure C
Hypovloemia triggers the release of vasopressin in a pulsatile fashion is represented by figure A.
Solution
Insulin receptor signaling is represented by figure D
Effect of hyper and hypo thyroidism on body temperature is represented by figure E
The effect of thyrotropin on thyroid follicular cells include iodide entrapment and organification
is represented by figure C
Hypovloemia triggers the release of vasopressin in a pulsatile fashion is represented by figure A..
let E0 be given=there exists N1, N2 such thatan -am E2.pdf
let E>0 be given
=>
there exists N1, N2 such that
|an -am | < E/2 for n,m >N1
|bn-bm | N2
=>
|an-am| + |bn-bm| N = max{N1,N2}
=>
|an+bn -am-bm| <=|an-am| + |bn-bm| N = max{N1,N2}
=>
|(an+bn) -(am+bm)| N
=>
an+bn is cauchy sequence
thus proved
an, bn are cauchy sequences => an, bn are bounded
let |an| <=A, |bn| <=B
there exists n1 n2 such that
|an-am| < E/2B for n,m >n1, => |an-am||bn| n1 => |anbn -ambn| n1
|bn-bm| < E/2A for n,m >n2 => |bn-bm||am| n2 => |bnam -ambm| n2
=>
|anbn -ambn| + |bnam -ambm| < E for n,m > N = max{n1,n2}
=>
|anbn-ambm| <|anbn -ambn| + |bnam -ambm| < E for n,m > N = max{n1,n2}
=>
|anbn-ambm| < E for n,m > N = max{n1,n2}
=>
anbn is a cauchy sequence
thus proved
Solution
let E>0 be given
=>
there exists N1, N2 such that
|an -am | < E/2 for n,m >N1
|bn-bm | N2
=>
|an-am| + |bn-bm| N = max{N1,N2}
=>
|an+bn -am-bm| <=|an-am| + |bn-bm| N = max{N1,N2}
=>
|(an+bn) -(am+bm)| N
=>
an+bn is cauchy sequence
thus proved
an, bn are cauchy sequences => an, bn are bounded
let |an| <=A, |bn| <=B
there exists n1 n2 such that
|an-am| < E/2B for n,m >n1, => |an-am||bn| n1 => |anbn -ambn| n1
|bn-bm| < E/2A for n,m >n2 => |bn-bm||am| n2 => |bnam -ambm| n2
=>
|anbn -ambn| + |bnam -ambm| < E for n,m > N = max{n1,n2}
=>
|anbn-ambm| <|anbn -ambn| + |bnam -ambm| < E for n,m > N = max{n1,n2}
=>
|anbn-ambm| < E for n,m > N = max{n1,n2}
=>
anbn is a cauchy sequence
thus proved.
import java.util.ArrayList; import java.util.List; .pdf
import java.util.ArrayList;
import java.util.List;
/**
*
*
*/
public class AList {
List list = new ArrayList();
public AList() {
// TODO Auto-generated constructor stub
}
/**
*
*/
public AList(List list) {
this.list = list;
}
/*
* (non-Javadoc)
*
* see java.lang.Object#equals(java.lang.Object)
*/
public boolean equals(Object obj) {
// TODO Auto-generated method stub
AList aList = (AList) obj;
List arrayList = aList.getList();
if (arrayList.size() != list.size()) {
return false;
}
for (int i = 0; i < list.size(); i++) {
if (list.get(i) != arrayList.get(i)) {
return false;
}
}
return true;
}
/**
* return the list
*/
public List getList() {
return list;
}
/**
* param list
* the list to set
*/
public void setList(List list) {
this.list = list;
}
/**
* param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
List integers = new ArrayList();
integers.add(10);
integers.add(20);
integers.add(30);
integers.add(40);
integers.add(50);
List integers1 = new ArrayList();
integers1.add(10);
integers1.add(20);
integers1.add(30);
integers1.add(40);
integers1.add(60);
AList aList1 = new AList(integers);
AList aList2 = new AList(integers);
System.out.println(\"list1 and list2 are equal? \"
+ aList1.equals(aList2));
aList2 = new AList(integers1);
System.out
.println(\"After adding 60 to list2, list1 and list2 are not equal? \"
+ aList1.equals(aList2));
}
}
OUTPUT:
list1 and list2 are equal? true
After adding 60 to list2, list1 and list2 are not equal? false
Solution
import java.util.ArrayList;
import java.util.List;
/**
*
*
*/
public class AList {
List list = new ArrayList();
public AList() {
// TODO Auto-generated constructor stub
}
/**
*
*/
public AList(List list) {
this.list = list;
}
/*
* (non-Javadoc)
*
* see java.lang.Object#equals(java.lang.Object)
*/
public boolean equals(Object obj) {
// TODO Auto-generated method stub
AList aList = (AList) obj;
List arrayList = aList.getList();
if (arrayList.size() != list.size()) {
return false;
}
for (int i = 0; i < list.size(); i++) {
if (list.get(i) != arrayList.get(i)) {
return false;
}
}
return true;
}
/**
* return the list
*/
public List getList() {
return list;
}
/**
* param list
* the list to set
*/
public void setList(List list) {
this.list = list;
}
/**
* param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
List integers = new ArrayList();
integers.add(10);
integers.add(20);
integers.add(30);
integers.add(40);
integers.add(50);
List integers1 = new ArrayList();
integers1.add(10);
integers1.add(20);
integers1.add(30);
integers1.add(40);
integers1.add(60);
AList aList1 = new AList(integers);
AList aList2 = new AList(integers);
System.out.println(\"list1 and list2 are equal? \"
+ aList1.equals(aList2));
aList2 = new AList(integers1);
System.out
.println(\"After adding 60 to list2, list1 and list2 are not equal? \"
+ aList1.equals(aList2));
}
}
OUTPUT:
list1 and list2 are equal? true
After adding 60 to list2, list1 and list2 are not equal? fal.
Given for balanced wye-delta systemSolutionGiven for b.pdf
Given for balanced wye-delta system
Solution
Given for balanced wye-delta system.
Humans generally have polymorphisms where both alleles are found in .pdf
Humans generally have polymorphisms where both alleles are found in both populations. The
alleles may be either most prevalent or least prevalent in the population. Population has
combinationof the polymorphic alleles. This is due to the fact that population is a breeding group
and hence, transmit the genotypes which are broken down and new set/comobination of
genotypes is generated in the progeny. Thus, the polymorphic alleles are also in continuum with
an array of the frequencies of those alleles.
Migration changes the freqency of the alleles since new polymorphisms or alleles are introduced
into the population. If individuals are completely isolated, phenomena like founder effect occurs.
Solution
Humans generally have polymorphisms where both alleles are found in both populations. The
alleles may be either most prevalent or least prevalent in the population. Population has
combinationof the polymorphic alleles. This is due to the fact that population is a breeding group
and hence, transmit the genotypes which are broken down and new set/comobination of
genotypes is generated in the progeny. Thus, the polymorphic alleles are also in continuum with
an array of the frequencies of those alleles.
Migration changes the freqency of the alleles since new polymorphisms or alleles are introduced
into the population. If individuals are completely isolated, phenomena like founder effect occurs..
I cant see the image.. but geometric isomerism .pdf
I can\'t see the image.. but geometric isomerism occurs when there is a double bond
between two carbons. And, the substituents attached to each carbon must be different. So one
carbon cannot have two Hs attached then geometric isomerism is not possible. However, one
carbon can have an H and a CH3 and the other carbon can have H and CH3 and geometric
isomerism will occur, provided there is a double bond.
Solution
I can\'t see the image.. but geometric isomerism occurs when there is a double bond
between two carbons. And, the substituents attached to each carbon must be different. So one
carbon cannot have two Hs attached then geometric isomerism is not possible. However, one
carbon can have an H and a CH3 and the other carbon can have H and CH3 and geometric
isomerism will occur, provided there is a double bond..
H H H-C-N and N has a lone pair of electrons .pdf
H H | | H-C-N and N has a lone pair of electrons | | H H
Solution
H H | | H-C-N and N has a lone pair of electrons | | H H.
DNA DNA is the genetic material of organisms. It contains the gene.pdf
DNA : DNA is the genetic material of organisms. It contains the genetic information coded
within itself . And genetic information is passed onto over generations. Also DNA provides
template for formation of RNA and also replicates itself when cell gets divided. DNA is
composed of purines and pyrimidines connected through hydrogen bonds on a sugar phosphate
backbone. These bases form codon for protein synthesis.
RNA : RNA is ribonucleic acid which differs from DNA in sugar composition and in RNA
thymine is replaced by uracil in RNA. RNA is of three types . mRNA which js useful for
formation of Protein . rRNA OR RIBOSOMAL RNA is useful for ribosomes. and tRNA or
Transfer RNA is important component of protein synthesis. So RNA is the key component of
proteins in the cell.
PROTEINS: Proteins we can say is one of the building blocks of cells in an organism. All
enzymes required for physiological processes are proteinaceous in nature. So they are required
for every minor processes of an organisms.
CARBOHYDRATES : Carbohydrates are also one of the most important biological macro
molecule. Several sugars are involved in energy generation in the cell. So carbohydrates
basically are involved in generation of energy in the cell. ATP is produce by sugar metabolism
only.
LIPIDS : Lipids are also source of energy in cell and equally important biological
macromolecule for teh cell. Stored lipids in the cell provides energy and from from lipids various
metabolic pathways are important.
BUILDING BLOCKS
DNA and RNA : Nitrogenous bases
Proteins : Amino acids
Carbohydreate: Monosaccharide
LIPIDS : Fatty acids.
Solution
DNA : DNA is the genetic material of organisms. It contains the genetic information coded
within itself . And genetic information is passed onto over generations. Also DNA provides
template for formation of RNA and also replicates itself when cell gets divided. DNA is
composed of purines and pyrimidines connected through hydrogen bonds on a sugar phosphate
backbone. These bases form codon for protein synthesis.
RNA : RNA is ribonucleic acid which differs from DNA in sugar composition and in RNA
thymine is replaced by uracil in RNA. RNA is of three types . mRNA which js useful for
formation of Protein . rRNA OR RIBOSOMAL RNA is useful for ribosomes. and tRNA or
Transfer RNA is important component of protein synthesis. So RNA is the key component of
proteins in the cell.
PROTEINS: Proteins we can say is one of the building blocks of cells in an organism. All
enzymes required for physiological processes are proteinaceous in nature. So they are required
for every minor processes of an organisms.
CARBOHYDRATES : Carbohydrates are also one of the most important biological macro
molecule. Several sugars are involved in energy generation in the cell. So carbohydrates
basically are involved in generation of energy in the cell. ATP is produce by sugar metabolism
only.
LIPIDS : Lipids are also source of energy in cell and equally important biological
macromo.
D. A qualitative assessment ranks the seriousness of threats and sen.pdf
D. A qualitative assessment ranks the seriousness of threats and sensitivity of assets into grades
or classes, such as low, medium, and high. It is performed by experts or external consultants and
is based on risk scenarios. Although purely quantitative risk assessment is not possible, purely
qualitative risk analysis is.
Solution
D. A qualitative assessment ranks the seriousness of threats and sensitivity of assets into grades
or classes, such as low, medium, and high. It is performed by experts or external consultants and
is based on risk scenarios. Although purely quantitative risk assessment is not possible, purely
qualitative risk analysis is..
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There is some data missing in the problem.The composition of the m.pdf
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Tested on Eclipse and both class should be in same packageimport.pdf
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Product of Cyclopentane + H2O(H+) gives No Reaction.It will simply F.pdf
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Of the variedtypes of IPC, sockets arout and awaythe foremostcommon..pdf
Of the variedtypes of IPC, sockets arout and awaythe foremostcommon..pdf
C2O2 is a bidendate ligand &Cl - is a mono dendat.pdf
C2O2 is a bidendate ligand &Cl - is a mono dendat.pdf
Insulin receptor signaling is represented by figure DEffect of hyp.pdf
Insulin receptor signaling is represented by figure DEffect of hyp.pdf
let E0 be given=there exists N1, N2 such thatan -am E2.pdf
let E0 be given=there exists N1, N2 such thatan -am E2.pdf
import java.util.ArrayList; import java.util.List; .pdf
import java.util.ArrayList; import java.util.List; .pdf
Given for balanced wye-delta systemSolutionGiven for b.pdf
Given for balanced wye-delta systemSolutionGiven for b.pdf
Humans generally have polymorphisms where both alleles are found in .pdf
Humans generally have polymorphisms where both alleles are found in .pdf
I cant see the image.. but geometric isomerism .pdf
I cant see the image.. but geometric isomerism .pdf
DNA DNA is the genetic material of organisms. It contains the gene.pdf
DNA DNA is the genetic material of organisms. It contains the gene.pdf
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标题：国外学历认证办理与留信网认证详解，以及应对留学GPA不足的策略
正文：
随着国际化教育的深入发展，越来越多的学生选择出国留学深造。在这个过程中，国外学历认证和留信网认证成为了必不可少的环节。同时，对于部分留学生来说，如何提升GPA以顺利进入心仪的国外名牌大学也是一个关键问题。然而，需要明确的是，任何关于修改国外大学成绩单或GPA的行为都是不道德和非法的，因此本文不会涉及相关内容。
一、国外学历认证办理
国外学历认证是对在国外获得的学历学位进行真实性和合法性的确认，这是国内用人单位和各类机构评估个人教育背景的重要依据。一般来说，学历认证的流程包括提交申请材料、在线注册并提交认证申请、支付相关费用等步骤。具体的办理流程和所需材料可能因国家和认证机构的不同而有所差异，因此建议学生在办理前仔细了解相关规定和要求。
二、留信网认证办理
留信网是一个为留学生提供服务的平台，其中包括留信认证服务。留信认证主要是对学生出国留学前的身份、学历、成绩等进行核实，并出具相应的认证报告。这一认证过程有助于增加留学生信息的可信度，提高申请国外大学的成功率。留信网认证的具体办理流程通常包括在线填写个人信息、上传相关证明材料、等待审核等环节。同样地，不同国家和地区的留信网认证可能存在差异，因此学生在办理前应详细了解所在地区的具体规定。
三、应对留学GPA不足的策略
在申请国外名牌大学时，高GPA是重要竞争力之一。然而，并非所有学生都能一开始就保持优秀的学术表现。针对这种情况，以下是一些建议帮助学生提升GPA：
1. 制定合理的学习计划：提前规划好每学期的课程和学习目标，合理分配时间和精力用于学习和复习。
2. 寻求学术指导：参加学校提供的学术辅导课程或咨询老师、同学以获取帮助和支持。
3. 参与课外活动：除了学术成绩外，综合素质也是国外大学考察的重要方面。积极参与各类社团活动、志愿服务等能够丰富个人简历的内容。
4. 考虑转学分或延期申请：如果发现自己的GPA距离理想目标还有较大差距，可以考虑在国内或其他国家先读一些相关课程积累学分，或者推迟一年申请以争取更多的时间提升成绩。
需要注意的是，以上策略仅供参考，并不能代替非法行为如成绩单修改或黑客改绩点等。这些做法不仅违反道德和法律规范，而且会对学生的未来产生严重后果。因此，学生们应该秉持诚信原则，通过自己的努力来提升自己的综合实力和申请竞争力。
一比一原版(Ryerson毕业证书)瑞尔森大学毕业证成绩单如何办理
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◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
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四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
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◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
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◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
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一、GMAT考试概述
1. GMAT考试的定义与重要性
GMAT（Graduate Management Admission Test）是研究生管理科学入学考试，主要用于评估申请者在商业和管理研究生项目中的潜在能力。在申请全球顶尖商学院时，GMAT成绩往往成为录取委员会评估申请者的重要依据。
2. GMAT考试内容与结构
GMAT考试包含分析性写作（Analytical Writing Assessment, AWA）、综合推理（Integrated Reasoning, IR）、定量推理（Quantitative Reasoning）和语言推理（Verbal Reasoning）四个部分。各部分侧重点不同，共同构成对考生综合能力的全面考察。
二、提升GMAT成绩的策略与方法
1. 制定合理的学习计划
考生应根据自己的实际情况，制定切实可行的学习计划。确保在学习过程中充分掌握各部分知识点，提高解题速度和正确率。
2. 深入了解考试内容与题型
对GMAT考试的各部分内容进行深入研究，了解题型特点与解题技巧。通过模拟考试和真题练习，熟悉考试流程，提高应试能力。
3. 拓展词汇量与提高阅读速度
语言推理部分对考生的词汇量和阅读速度要求较高。考生应通过背单词、阅读英文材料等方式，提高词汇量；同时，通过训练提高阅读速度和理解能力。
4. 加强数学基础与解题技巧
定量推理部分主要考察数学知识和解题技巧。考生应回顾数学知识，掌握常用公式和解题方法；同时，通过大量练习，提高解题速度和正确率。
5. 注重写作能力的培养
分析性写作部分要求考生具备良好的逻辑思维能力和表达能力。考生应多阅读优秀的范文，学习写作技巧；同时，通过实际写作练习，提高自己的写作水平。
三、备考资源与技巧分享
1. 备考资料的选择与使用
考生可根据自己的需求选择适合的备考资料，如官方指南、模拟题集、在线课程等。在使用过程中，注意合理分配时间，充分利用资源，提高备考效率。
2. 备考过程中的心态调整
备考过程中，考生应保持积极的心态，避免过度焦虑。遇到困难和挫折时，及时调整心态，寻求帮助和支持。同时，保持充足的睡眠和适当的运动，有助于保持良好的学习状态。
3. 备考技巧分享
考生可以分享一些备考过程中的实用技巧，如如何高效记忆单词、如何提高阅读速度、如何运用解题技巧等。这些技巧有助于其他考生提高备考效率，提升GMAT成绩。
四、总结与展望
通过本文的详实介绍，相信读者对GMAT考试有了更深入的了解，并掌握了提升成绩的有效策略与方法。在未来的备考过程中，希望考生能够充分利用这些资源和技巧，取得优异的GMAT成绩，为申请理想的商学院奠定坚实的基础。同时，也希望本文能为广大考生提供有益的参考和启示，助力他们在留学申请的道路上取得更好的成果。
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**黑客入侵实测大纲**
一、黑客入侵概述
1. 黑客入侵定义与类型
- 黑客入侵是指未经授权地进入计算机系统或网络，执行非法操作的行为。
- 常见的黑客入侵类型包括：网络钓鱼、恶意软件攻击、漏洞利用等。
2. 黑客入侵的危害
- 数据泄露与隐私侵犯
- 系统瘫痪与服务中断
- 经济损失与声誉受损
二、黑客入侵实测准备
1. 合法性与道德考量
- 强调实测活动必须在合法、合规的框架内进行。
- 遵循网络安全伦理，尊重他人隐私与权益。
2. 工具与资源准备
- 选择合适的黑客入侵模拟工具与平台。
- 收集目标系统的相关信息，如IP地址、端口开放情况等。
3. 安全防护措施
- 确保实测环境的安全性，避免对真实系统造成损害。
- 制定紧急预案，应对可能出现的意外情况。
三、黑客入侵实测过程
1. 初步侦查与信息收集
- 利用网络扫描工具探测目标系统的网络拓扑结构。
- 收集目标系统的漏洞信息，为入侵提供突破口。
2. 入侵手段与技巧
- 利用社会工程学手段获取目标系统的登录凭证。
- 利用漏洞利用技术执行远程代码执行或权限提升。
3. 入侵后的操作与行为分析
- 在目标系统中执行非法操作，如查看文件、修改配置等。
- 分析入侵过程中的行为模式，识别安全漏洞与风险点。
四、黑客入侵实测结果与反思
1. 实测结果分析
- 总结实测过程中的成功与失败案例。
- 分析目标系统的安全漏洞与防御机制。
2. 安全建议与改进措施
- 针对实测结果提出针对性的安全建议。
- 强调加强系统安全防护与漏洞修补的重要性。
3. 反思与总结
- 回顾实测过程中的经验教训，提升黑客防御能力。
- 强调网络安全意识的培养与提升。
（注：本大纲仅为示例，具体内容需根据实际情况进行调整和补充。）
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三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
◇在校期间，因各种原因未能顺利毕业……拿不到官方毕业证【q/微6496090】
◇面对父母的压力，希望尽快拿到；
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◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
◇需要报考公务员、购买免税车、落转户口
◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
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本公司拥有海外各大学样板无数，能完美还原。
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微6496090
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一.毕业证【q微6496090】成绩单、使馆认证、教育部认证、雅思托福成绩单、学生卡等！
二.真实使馆公证(即留学回国人员证明,不成功不收费)
三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
◇在校期间，因各种原因未能顺利毕业……拿不到官方毕业证【q/微6496090】
◇面对父母的压力，希望尽快拿到；
◇不清楚认证流程以及材料该如何准备；
◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
◇需要报考公务员、购买免税车、落转户口
◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
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本公司拥有海外各大学样板无数，能完美还原。
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微6496090
【主营项目】
一.毕业证【q微6496090】成绩单、使馆认证、教育部认证、雅思托福成绩单、学生卡等！
二.真实使馆公证(即留学回国人员证明,不成功不收费)
三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
◇在校期间，因各种原因未能顺利毕业……拿不到官方毕业证【q/微6496090】
◇面对父母的压力，希望尽快拿到；
◇不清楚认证流程以及材料该如何准备；
◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
◇需要报考公务员、购买免税车、落转户口
◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
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