Write a BFS algorithm using only arrays and no other data structure..pdf
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Write a BFS algorithm using only arrays and no other data structure. Solution #include #include #include //For boolean char que[20]; int front=0, rear=0, n; char arr[20]; int bfs(int ); char ajMat[20][20]; char b[20]; void display(); int p=0; int main() { char v; int i, j; printf(\"Enter the number of nodes in a graph\"); scanf(\"%d\",&n); printf(\"Enter the value of node of graph\"); for( i=0; i.
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![Write a BFS algorithm using only arrays and no other data structure.
Solution
#include
#include
#include //For boolean
char que[20];
int front=0, rear=0, n;
char arr[20];
int bfs(int );
char ajMat[20][20];
char b[20];
void display();
int p=0;
int main()
{
char v;
int i, j;
printf("Enter the number of nodes in a graph");
scanf("%d",&n);
printf("Enter the value of node of graph");
for( i=0; i](https://image.slidesharecdn.com/writeabfsalgorithmusingonlyarraysandnootherdatastructure-230703180843-8a68b1ec/85/Write-a-BFS-algorithm-using-only-arrays-and-no-other-data-structure-pdf-1-320.jpg)
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Carbon dioxide (CO_2) is a non-polar molecule. Is this consistent with your classification of the
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Solution
In C-O the oxygen is more electronegative than carbon , so the shared electrons are more close to
oxygen make it more negative and carbon becomes more positive.The polarity is determined by
the difference in electronegativity, since electronegativity of oxygen is more here it makes C-O a
polar component.
But in Co2 the two oxygen lies linearly ie O=C=O
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I find Dr. Jekyll\'s use of science to have at least a bit more integrity than Victor Frankenstein\'s.
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glory and fame, and because he acts without integrity, behaving selfishly and unethically, he
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Dr. Jekyll, on the other hand, doesn\'t exploit science in order to achieve fame. In essence, he
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Solution
Darwin\'s explanation for the appearance of design:
Darwin discovered natural selection; it is a critical phenomenon that reveals the secret behind the
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diversity of organisms by natural laws.
According to Darwin\'s design the creative power behind of evolution are arisen due to the
interaction among chance & necessity and between the natural selection & random mutations.
Darwin\'s The Origin of Species book was published in 1859. In this he mainly explains how the
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A router receives a message addressed 172.16.15.75. The relevant rou.pdf
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A. Serial 0.
B. Serial 1.
C. Ethernet 0.
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Yellow Fever virus
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#include
#include
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Solution
Darwin\'s explanation for the appearance of design:
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cause an interrupt after every conversion. Write only the initialization code using atmega328p?
Solution
#include
#include
ISR(ADC_vect)
{
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Write a JAVA LinkedListRec class that has the following methods: size, empty, insertBefore,
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removeEnd, toString. Use recursion to implement most of these methods. Write a driver to test
your implemented LinkedListRec class methods.
Solution
import java.util.Scanner;
public class LinkedListRec {
int data;
LinkedListRec prev=null,next=null;
int size(LinkedListRec l)//method which returns the length of the list
{
if(l==null)return 0;
return 1+size(l.next);
}
boolean empty(LinkedListRec l)//method checks whether the list is empty or not...
{
if(l==null)return true;
else return false;
}
LinkedListRec insertBefore(LinkedListRec l,int value,int num_insertbefore)//method which
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{
if(l==null)return l;
if(l.data == num_insertbefore)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.prev==null)
{
n.next = l;
l=n;
}
else
{
n.prev = l.prev;
n.next= l;
l.prev = n;
}
return l;
}
return insertBefore(l.next,value,num_insertbefore);
}
LinkedListRec insertAfter(LinkedListRec l,int value,int num_insertafter)//method which adds
the new number after the given number
{
if(l==null)return l;
if(l.data == num_insertafter)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.next==null)
{
l.next = n;
n.prev = l;
}
else
{
n.next = l.next;
l.next.prev = n;
n.prev = l;
}
return l;
}
return insertAfter(l.next,value,num_insertafter);
}
LinkedListRec addAtHead(LinkedListRec l,int value)//method which adds a new number at
the head position of the list...
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.next = l;
l=n;
return l;
}
LinkedListRec addAtEnd(LinkedListRec l,int value)//method which adds a new number at
the end position of the list...
{
if(l==null){ l = new LinkedListRec();l.data = value;return l;}
if(l.next==null)
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.prev = l;
l.next = n;
return l;
}
return addAtEnd(l.next,value);
}
LinkedListRec remove(LinkedListRec l,int value)//method which removes given numbet
from the list....
{
if(l==null)return l;
if(l.data == value)
{
if(l.prev!=null){
l.prev = l.next;
}
else
l=l.next;
return l;
}
return remove(l.next,value);
}
boolean replace(LinkedListRec l,int value,int newvalue)//method which replaces current
number with new number,...
{
if(l==null)return false;
if(l.data == value)
{
l.data = newvalue;
return true;
}
return replace(l.next,value,newvalue);
}
int peekFront(LinkedListRec l)//method which returns the first value of the list...
{
if(l!=null)
return l.data;
else return -1;
}
int peekEnd(LinkedListRec l)//method which returns the last value of the list........
{
if(l==null)return -1;
if(l.next == null)return l.data;
return peekEnd(l.next);
}
LinkedListRec removeFront(LinkedListRec l)//method which removes the first element of the
list..
{
if(l==null)return l;
l=l.next;
return l;
}
boolean removeEnd(LinkedListRec l)//method which removes the last element o.
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Why has one prominent textbook author described I/O management as the \"messiest aspect of
operating system design\"? Using at least three distinct points, describe the evolution of I/O
controllers, and describe how their support for I/O has increased in complexity over time.
Solution
Dear Student.
Answer No-5a)
The above asked question is from the book \"Opererating System by william Stalling\" according
to the william stalling I/O management is the messiest aspect of an operating system.
Let\'s discuss this in detail.. how I/O management is the messiest aspect of an operating system?
There are wide variety of devices and their application. So it is very difficult to develop a generel
consistant common solution for every device.The devices which are engaged with I/O are
generally false in three different categories...
1-Human Readable- The human readable are the devices which are suitable for comuter user as
printers, video display, mouse and keyboard.These are all input/output devices.
2-Machine Readable- The devices which are suitable for communication with electronic devices
as disk drive, magnetic tapes and sensors and actuators.
3-Communication-The devices which are suitable for communicating with remote devices like a
Modem.
So above are the types of I/O devices, each device has their own functionality and design.Further
more every device has different data transfer rate, and different applications.
for example a disk used for file management requires support of file management
software.
Complexty in design is different in each device.Unit of data transfer may differ in each I/O
device.Some are programmed I/O devices and some devices are interrupt driven, some requires
DMA controller for data exchange between main memory and I/O module.Error conditions also
differ from one device to another, So this kind of diversity makes uniform and consistant
approach to I/O devices.
So by the above explanation it is clear that is I/O is the messiest aspect of an operating system.
Answer No-5b)
As the coputer system is evoled there has been a pattern of increasing complexity and
shopistication of each individual component.the evolutionarry steps in I/O controller are
described below...
The best example of I/O controller is DMA(Direct Memory Access).It controlles the data
transfer between memoy and I/O device.The evolution of I/O controller is as follows..
1- Previously processor directly controlled a peripheral device.Then a controller or I/O is added
for smooth and fast data transmission.
2-Then I/O controller given direct memory controll via DMA controllers.And now the DMA
controller can move a block of data without involving the processor.
3- Further I/O controller enhanced to become a seperate processor the central processing unit
direcly direct the I/O processor to execute an I/O program in memory.
So as the envolved continues in I/O Controller, more and more I/O functions is performed
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which is true of the data shown in the histogram Which is true of th.pdf
which is true of the data shown in the histogram Which is true of the data shown in the
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approximately equal. The median and IQR summarize the data better than the mean and
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Solution
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Solution
Having learned more about the myths and stories of Western civilization, I am understanding
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understand and communicate with one another. It is obvious that the study of humanities is not
just a college course, but it is an ongoing process and practice in life.
The humanities can first be used to understand the past which has created the present. The
culture which we have was shaped by the past. Facts, findings, and literature of even thousands
of years ago have influenced our world today. Knowing this past can allow people to understand
our present; knowing how we came to this present helps us to communicate about it and the
future.
The study of the humanities can also be used to realize differing interpretations of life and
history. Studying facts of the past helps to understand literature of the past. Art reflects the
cultures of the past, and shows how we achieved what we have today. For example, the Song of
Roland was very biased about the Saracens (Muslims). If one only studied literature, they would
have a totally skewed interpretation of who the Muslims were. By studying history though, we
know that the battle in this literature wasn\'t even against Muslims. Also by studying history and
religion we can see how Islam developed and what it really is. This is just one example of how
the comprehensive study of the humanities can be used to understand the world, and to
communicate fairly and intelligently with others in the world.
The humanities are not just part of the college\'s curriculum. The study of the humanities teaches
one how to study and look at how the past developed and how it has impacted today\'s world.
The humanities allows people of different cultures to communicate and understand their
sometimes common pasts but present differences. The humanities shows how different
disciplines affect and complement one another. Finally, the study of the humanities shows that
this study is ongoing and continual, constantly evolving and shaping.
Highly successful executives, entrepreneurs and policy makers offer words of wisdom about the
practical value of studying the humanities. “I think if you have a good background in what it is to
be human, an understanding of life, culture and society, it gives you a good perspective on
starting a business, instead of an education purely in business...You can always pick up how to
read a balance sheet and how to figure out profit and loss, but it\'s harder to pick up the other
stuff on the fly. ”
1. The humanities prepare you to fulfill your civic and cultural responsibilities.
The
reason that John Harvard left his library to the college in Cambridge,
Massachusetts, that Jane and Leland Stanford founded Stanford University, and
that states established land-grant colleges was to educate cultured and
useful citizens. T.
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Solution
Dynamic pressure is a defined property of a moving flow of gas or liquid and can be expressed
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pd = 1/2 v2 (1)
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Implement the quicksort optimization median-of-three, i.e., first, middle, and last, as pivot for
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private static void quicksort(int low, int high) {
int i = low, j = high;
// Get the pivot element from the middle of the list
int pivot = arr[(high+low)/2];
// Divide into two lists
while (i <= j) {
// If the current value from the left list is smaller then the pivot
// element then get the next element from the left list
while (arr[i] < pivot) i++;
// If the current value from the right list is larger then the pivot
// element then get the next element from the right list
while (arr[j] > pivot) j--;
// If we have found a value in the left list which is larger than
// the pivot element and if we have found a value in the right list
// which is smaller then the pivot element then we exchange the
// values.
// As we are done we can increase i and j
if (i < j) {
exchange(i, j);
i++;
j--;
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}
// Recursion
if (low < j)
quicksort(low, j);
if (i < high)
quicksort(i, high);
}
Solution
Hi, Please find my program:
private static void quicksort(int low, int high) {
if (low >= high)
return;
// Selecting the pivot
int first = low;
int second = arr[(high+low)/2];
int third = arr[high];
// median for first three
int pivot = Math.max(
Math.min(
array[first],
array[second]),
Math.min(
Math.max(
array[first],
array[second]
),
array[third]
)
);
while (low <= high)
{
while (array[low] < pivot)
{
low++;
}
while (array[high] > pivot)
{
high--;
}
if (low <= high)
{
// swapping
int temp = array[low];
array[low] = array[high];
array[high] = temp;
low++;
high--;
}
}
// Recursion
if (low < j)
quicksort(low, j);
if (i < high)
quicksort(i, high);
}.
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There are 40 students in our class. How many ways they can be lined up such that two fixed
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Solution
So now that X and Y are always beside each other, then you can treat them as just ONE
PERSON.
Thus, it\'s like there are now just 39 people to permute.
As n! = number of ways to permute n objects in a line, then the number of ways is
#ways = 39! = 2.03979*10^46 [ANSWER].
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The Task
For this assignment you will write a rudimentary text editor that allows the user to edit 5 lines of
text, where each line is no longer than 80 characters. The editor should allow the user to
continue editing as long as desired and should print the current state of the edit buffer after each
edit.
The editor is a \'line editor\' in that the user must edit one line at a time. The user can specify
which line should be edited by choosing a line number from a menu.
The only two editing operations possible are to replace an entire line with a new line, or to
replace a substring in the line with a new substring.
Musts
The program should not accept incorrect menu choices from the user. If the user creates a string
that is longer than 80 characters the string should be truncated to fit the 80 character limit. The
program should simply make no changes if the user tries to replace a substring that does not exist
in the string.
Your program must use functions. Some functions are required, but you may make other
functions as you see fit. You may not change the name, return type, or the parameter list types
for required functions.
Required Function One
int replaceInString(char[] original, char[] substring, char[] replace);
This function causes the original string to be modified such that the first occurrence of substring
is removed from the original string and the contents of replace are inserted in its place.
replaceInString calls findSubString and insertString. The function returns 0 if the operation
fails and 1 if the operation is successful.
Required Function Two:
int findSubString(char[] original, char[] toFind);
This function finds the first occurrence of toFind in original and returns an integer representing
the index of the first element of the toFind substring in original. For example if toFind was \'cat\'
and original was \'thundercat\' the function would return 7 since the begining of \'cat\' in
\'thundercat\' is position 7. If the function does not find a substring it should return -1
note: do not use existing substring functions such as strstr as a solution for this function. Solve
the algorithm yourself. You may use basic string functions such as strlen and strcat.
Required Function Three:
int insertString(char[] original, int start, int length, char[] toInsert);
This function replaces the contents of original with the following sequence of characters:
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the characters from original starting at the character immediately after length.
Solution
#include
#include
#define ROW_LENTH 81
#define NUM_ROWS 5
void replaceLine(char line[]);
void printText(char text[][ROW_LENTH]);
int readFile(char filePath[], char text[][ROW_LENTH]);
int writeFile(char filePath[], char text[][ROW_LENTH]);
void removeTrailingHardReturn(char line[]);
void flushBuffer();
int getLine();
int replaceInString(char original[], char substring[], char replace[]);
int findSubString(char origina.
The SIP handles what functionsA.) establishes a call through the .pdf
The SIP handles what functions?
A.) establishes a call through the network.
B) tears down a call through the network
C) rings the phone
D) applies features to the line.
E) converts the IP signal into a G.711 flow.
F.) a, b, and c
G.) a and b
H.) a, b, c, and e
I.) all of the above
Solution
sip has main five functions: session initiation protocal
1. User location
2.User availibilty
3 User capabilities
4 session setup
5 session management
so sip provides five function it uses layered approach
sip used for real timetransport protocal .it is used for delivering voice and video over IPnetwork
This type of server does not store any information of a call transactios.
so sip has above questioN
answer is : (I )ALL OF THE ABOVE.
The NBA decides to look into the use of meldonium in the league foll.pdf
The NBA decides to look into the use of meldonium in the league following the same protocol as
the WADA. Which of the following will be randomly tested?urine samplesblood samplesskin
samplesplasma samples
Solution
Answer: According to WADA (World Anti-Doping Agency), the quantity of Meldonium or
Mildronate (trade-name) in athlete\'s/Patient\'s body used to measure from the urine samples.
NBA is going to follow the same protocol as WADA to estimate the Meldonium content. So, the
answer is \'Urine Samples\'..
The organelle that serves as the digestive system in the cell is the .pdf
The organelle that serves as the digestive system in the cell is the ____. polysome; endosome;
lysosome; ribosome; intestine.
Solution
LYSOSOME:
In the cell line: lysosome secretes thye lytic enzymes, and promotes the phagocytosis and digests
the unwanted materials like bacteria etc, leading to formation of phagolysosomes.
Therefore it can be called as the digestive system of the cell..
The major type of interactive forces between molecules of NH_3 are .pdf
The major type of interactive forces between molecules of NH_3 are: ionic covalent hydrogen
bonding dipole-dipole attractions dispersion forces
Solution
Answer 18: The major type of interactive force that lie between molecule of ammonia (NH3) are
covalent bond. The single Nitrogen atom in an ammonia molecule is bonded to three atoms of
Hydrogen through the sharing of three electron pairs, one with each atom of Hydrogen. Thus,
finally said that the ammonia molecule is formed by covalent bonding between one Nitrogen
atom and three Hydrogen atoms..
The group of taxa that have fully developed appendages can be best de.pdf
The group of taxa that have fully developed appendages can be best described as: Convergent
evolution Monophyletic A species Polyphyletic
Solution
A.convergent evolution.
Note- convergent evolution is evolution of similar feature or characters in sDifferent species.
These structures are analogous structure which have similar form and function but are not
present in last common ancestors.
Here appendages are similar feature which different taxas has evolved independentally, and have
similar functions..
The Law of Independent Assortment states thatA. Two different gene.pdf
The Law of Independent Assortment states that
A. Two different genes will randomly assort their alleles during the formation of haploid cells
B. Two different genes will randomly assort their alleles during the formation of diploid cells
C. Two different genes will NOT randomly assort their alleles during the formation of haploid
cells
D. Two different alleles will randomly assort during the formation of haploid cells
Solution
Answer:
D. Two different alleles will randomly assort during the formation of haploid cells
The law of independent assortment states that the alleles of one gene sort into gametes
independently of the alleles of another gene..
The following results were obtained in the patient from Case Study 25.pdf
The following results were obtained in the patient from Case Study 25-2 (Case Study Table 25-
4.1). What is the most likely diagnosis? What is the prognosis? What complications may
develop?
Solution
Ques-1
Diagnosis: From the laboratory diagnosis, it seems that the patient is suffering from multiple
infections from hepatitis, including A and B. Both of these forms of hepatitis infections occur
due to infected food/water and direct physical contact
Ques-2: The major prognosis of hepatitis A & B is to infect liver because cirrhosis finally lasts
for 3 to 4 months. Under chronic conditions, it lasts for 6 months due to hepatic cell infection
due to hepatitis B virus replication. This is leading to higher incidence of hepatitis core antibody
(lgM) so that it is positive
Ques-3:
Complications:
Hepatitis or jaundice is the medical term for yellow discoloration of the sclera and mucous
membranes. Heme moiety of hemoglobin is breakdown into iron and bilivirdin in the body.
During jaundice, excess breakdown of hemoglobin results in the accumulation of bilirubin (made
from bilivirdin), which gives yellow coloration to the mucous membranes.
The most common symptoms include flu-like asscoaited with aches, liver dysfunction finally
tiredness, diarrhea. The main pain and ache observed in the liver region due to viral invasion of
hepatocytes causes inhibition of metabolic enzyme synthesis and metabolic enzyme activity.
These symptoms are leading to severe ache below the ribs and near to abdomen specifically in
liver.
Security National Bank is quoting 1-year certificates of deposit wit.pdf
Security National Bank is quoting 1-year certificates of deposit with an interest rate of 10%
compounded semiannually. Joe Saver purchased a $5,200 CD.
What is the CD
What is the CD
Solution
Hi,
Please find the detailed answer as follows:
Effective Rate = (1+Annual Rate/2)^2 -1 = (1+10%/2)^2 - 1 = $10.25%
Answer is 10.25%
Thanks..
Recently, the stock market took big swings up and down. A survey .pdf
Recently, the stock market took big swings up and down. A survey of 1011 adult investors
asked how often they tracked their portfolio.The table shows the investor responses. what is the
probability that an adult investor tracks his or her portfolio daily? Express your answer as a
simplified fraction and as a decimal rounded to three decimal places.
Solution
P(daily) = 222/total = 222/(222+281+297+144+67) = 222/1011 = 0.21958 ~= 0.22
Option (A) is correct..
Profit is the difference betweena. the assets purchased with cash.pdf
Profit is the difference between:
a. the assets purchased with cash contributed by the owner and the cash spent to operate the
business
b. assets and liabilities
c. the amounts received from customers for goods or services and the amounts paid for the inputs
used to provide the goods and services
d. the incoming cash and outgoing cash
Solution
Profit is the difference of the enterprises\'s revenues and expenses.
Revenue is always taken as normal revenue which is earned from normal course of bussiness.
Expenses is always taken as normal expenses which is incurred from normal course of bussiness.
so answer is c) the amounts received from customers for goods or services and the amounts paid
for the inputs used to provide the goods and services.
Problem 4.7. Tuberculosis is a rare disease in developing countries. .pdf
Problem 4.7. Tuberculosis is a rare disease in developing countries. However, it is the most
common cause of death in HIV - positive adults living in these countries (sec [16]). Consider a
country in which 0.045% of its adult population has tuberculosis. It is estimated that 8% of all
tuberculosis cases in this country are co - infected with HIV. Compute the probability that a
randomly selected adult from this country has both tuberculosis and HIV.
Solution
P(both) = P(tuberculosis) * P(HIV | tuberculosis) = 0.00045 * 0.08 = 0.000036.
Please help with this genetics problems The intermediates that build.pdf
Please help with this genetics problems The intermediates that build up in Serratia mutant X can
feed mutant Y to produce red pigment. However, mutant Y cannot feed mutant X to produce red
pigment. Which of the following is correct? (Select all that apply) Enzymes X and Y are in
parallel biochemical pathways for red pigment production Enzymes X and Y are in the same
branch of the pathway for red pigment production Enzyme X is downstream from enzyme Y
Enzyme X is upstream from enzyme Y Serratia marescens are, while Saccharomyces cerevisiae
are. archaea, mammalian bacteria, algae bacteria, eukaryotes fungi, prokaryotes In our
Serratia experiment we plated different mutant strains next to one another. When those mutant
strains exhibited complementation (were able to produce prodigiosin), what was being shared
between them? (Put another way, what are the strains providing to each another?) Enzymes
Intermediates Both enzymes and intermediates Serial dilutions are used because it is an
accurate way to determine the number of cells in a highly concentrated solution of cells to
accurately increase the concentration of cells to disperse the cells evenly in the tubes before
streaking the cells on the sterile plates to lyse the cells so we can streak the cytoplasm on the
plates Under what conditions does diploid yeast undergo meiosis to produce haploids?
Resource poor Resource rich Yeasts undergo meiosis whenever they want None of the above.
Solution
7. Answer: A & D
Enzyme X and Y are in parallel biochemical pathways for red pigment production. Enzyme X is
upstream from enzyme Y.
8. Answer: C
Serratia marescens are bacteria and Saccharomyces cerevisiae are eukaryotes.
9. Answer: C
They shared enzymes between them by complementation and able to produce prodigiosin.
10. Answer: A
Serial dilution is an accurate way to determine the number of cells in a highly concentrated
solution of cells.
11. Answer: A
Under resource poor condition, diploid yeast undergo meiosis to produce haploids..
How to Create a More Engaging and Human Online Learning Experience
How to Create a More Engaging and Human Online Learning Experience Wahiba Chair Training & Consulting
Wahiba Chair's Talk at the 2024 Learning Ideas Conference. More Related Content
More from info785431
Write a JAVA LinkedListRec class that has the following methods siz.pdf
Write a JAVA LinkedListRec class that has the following methods: size, empty, insertBefore,
insertAfter, addAtHead, addAtEnd, remove, replace, peekFront, peekEnd, removeFront,
removeEnd, toString. Use recursion to implement most of these methods. Write a driver to test
your implemented LinkedListRec class methods.
Solution
import java.util.Scanner;
public class LinkedListRec {
int data;
LinkedListRec prev=null,next=null;
int size(LinkedListRec l)//method which returns the length of the list
{
if(l==null)return 0;
return 1+size(l.next);
}
boolean empty(LinkedListRec l)//method checks whether the list is empty or not...
{
if(l==null)return true;
else return false;
}
LinkedListRec insertBefore(LinkedListRec l,int value,int num_insertbefore)//method which
adds a new number before the given number..
{
if(l==null)return l;
if(l.data == num_insertbefore)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.prev==null)
{
n.next = l;
l=n;
}
else
{
n.prev = l.prev;
n.next= l;
l.prev = n;
}
return l;
}
return insertBefore(l.next,value,num_insertbefore);
}
LinkedListRec insertAfter(LinkedListRec l,int value,int num_insertafter)//method which adds
the new number after the given number
{
if(l==null)return l;
if(l.data == num_insertafter)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.next==null)
{
l.next = n;
n.prev = l;
}
else
{
n.next = l.next;
l.next.prev = n;
n.prev = l;
}
return l;
}
return insertAfter(l.next,value,num_insertafter);
}
LinkedListRec addAtHead(LinkedListRec l,int value)//method which adds a new number at
the head position of the list...
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.next = l;
l=n;
return l;
}
LinkedListRec addAtEnd(LinkedListRec l,int value)//method which adds a new number at
the end position of the list...
{
if(l==null){ l = new LinkedListRec();l.data = value;return l;}
if(l.next==null)
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.prev = l;
l.next = n;
return l;
}
return addAtEnd(l.next,value);
}
LinkedListRec remove(LinkedListRec l,int value)//method which removes given numbet
from the list....
{
if(l==null)return l;
if(l.data == value)
{
if(l.prev!=null){
l.prev = l.next;
}
else
l=l.next;
return l;
}
return remove(l.next,value);
}
boolean replace(LinkedListRec l,int value,int newvalue)//method which replaces current
number with new number,...
{
if(l==null)return false;
if(l.data == value)
{
l.data = newvalue;
return true;
}
return replace(l.next,value,newvalue);
}
int peekFront(LinkedListRec l)//method which returns the first value of the list...
{
if(l!=null)
return l.data;
else return -1;
}
int peekEnd(LinkedListRec l)//method which returns the last value of the list........
{
if(l==null)return -1;
if(l.next == null)return l.data;
return peekEnd(l.next);
}
LinkedListRec removeFront(LinkedListRec l)//method which removes the first element of the
list..
{
if(l==null)return l;
l=l.next;
return l;
}
boolean removeEnd(LinkedListRec l)//method which removes the last element o.
Why has one prominent textbook author described IO management as the.pdf
Why has one prominent textbook author described I/O management as the \"messiest aspect of
operating system design\"? Using at least three distinct points, describe the evolution of I/O
controllers, and describe how their support for I/O has increased in complexity over time.
Solution
Dear Student.
Answer No-5a)
The above asked question is from the book \"Opererating System by william Stalling\" according
to the william stalling I/O management is the messiest aspect of an operating system.
Let\'s discuss this in detail.. how I/O management is the messiest aspect of an operating system?
There are wide variety of devices and their application. So it is very difficult to develop a generel
consistant common solution for every device.The devices which are engaged with I/O are
generally false in three different categories...
1-Human Readable- The human readable are the devices which are suitable for comuter user as
printers, video display, mouse and keyboard.These are all input/output devices.
2-Machine Readable- The devices which are suitable for communication with electronic devices
as disk drive, magnetic tapes and sensors and actuators.
3-Communication-The devices which are suitable for communicating with remote devices like a
Modem.
So above are the types of I/O devices, each device has their own functionality and design.Further
more every device has different data transfer rate, and different applications.
for example a disk used for file management requires support of file management
software.
Complexty in design is different in each device.Unit of data transfer may differ in each I/O
device.Some are programmed I/O devices and some devices are interrupt driven, some requires
DMA controller for data exchange between main memory and I/O module.Error conditions also
differ from one device to another, So this kind of diversity makes uniform and consistant
approach to I/O devices.
So by the above explanation it is clear that is I/O is the messiest aspect of an operating system.
Answer No-5b)
As the coputer system is evoled there has been a pattern of increasing complexity and
shopistication of each individual component.the evolutionarry steps in I/O controller are
described below...
The best example of I/O controller is DMA(Direct Memory Access).It controlles the data
transfer between memoy and I/O device.The evolution of I/O controller is as follows..
1- Previously processor directly controlled a peripheral device.Then a controller or I/O is added
for smooth and fast data transmission.
2-Then I/O controller given direct memory controll via DMA controllers.And now the DMA
controller can move a block of data without involving the processor.
3- Further I/O controller enhanced to become a seperate processor the central processing unit
direcly direct the I/O processor to execute an I/O program in memory.
So as the envolved continues in I/O Controller, more and more I/O functions is performed
without processor involvement.Thats is why the complexity h.
which is true of the data shown in the histogram Which is true of th.pdf
which is true of the data shown in the histogram Which is true of the data shown in the
histogram? The distribution is approximately symmetric. The mean and median arc
approximately equal. The median and IQR summarize the data better than the mean and
standard deviation. Click the icon to view the histogram.
Solution
A ) I and II.
What is the value of studying humanities in a business or technical .pdf
What is the value of studying humanities in a business or technical curriculum?
Solution
Having learned more about the myths and stories of Western civilization, I am understanding
more how study of the humanities (art, history, and literature) can be used to help people better
understand and communicate with one another. It is obvious that the study of humanities is not
just a college course, but it is an ongoing process and practice in life.
The humanities can first be used to understand the past which has created the present. The
culture which we have was shaped by the past. Facts, findings, and literature of even thousands
of years ago have influenced our world today. Knowing this past can allow people to understand
our present; knowing how we came to this present helps us to communicate about it and the
future.
The study of the humanities can also be used to realize differing interpretations of life and
history. Studying facts of the past helps to understand literature of the past. Art reflects the
cultures of the past, and shows how we achieved what we have today. For example, the Song of
Roland was very biased about the Saracens (Muslims). If one only studied literature, they would
have a totally skewed interpretation of who the Muslims were. By studying history though, we
know that the battle in this literature wasn\'t even against Muslims. Also by studying history and
religion we can see how Islam developed and what it really is. This is just one example of how
the comprehensive study of the humanities can be used to understand the world, and to
communicate fairly and intelligently with others in the world.
The humanities are not just part of the college\'s curriculum. The study of the humanities teaches
one how to study and look at how the past developed and how it has impacted today\'s world.
The humanities allows people of different cultures to communicate and understand their
sometimes common pasts but present differences. The humanities shows how different
disciplines affect and complement one another. Finally, the study of the humanities shows that
this study is ongoing and continual, constantly evolving and shaping.
Highly successful executives, entrepreneurs and policy makers offer words of wisdom about the
practical value of studying the humanities. “I think if you have a good background in what it is to
be human, an understanding of life, culture and society, it gives you a good perspective on
starting a business, instead of an education purely in business...You can always pick up how to
read a balance sheet and how to figure out profit and loss, but it\'s harder to pick up the other
stuff on the fly. ”
1. The humanities prepare you to fulfill your civic and cultural responsibilities.
The
reason that John Harvard left his library to the college in Cambridge,
Massachusetts, that Jane and Leland Stanford founded Stanford University, and
that states established land-grant colleges was to educate cultured and
useful citizens. T.
What are the two components of dynamic pressureVelocity and densi.pdf
What are the two components of dynamic pressure?
Velocity and density
Viscosity and velocity
Angle of attack and density
Lift and Drag
Solution
Dynamic pressure is a defined property of a moving flow of gas or liquid and can be expressed
as
pd = 1/2 v2 (1)
where
pd = dynamic pressure (Pa)
= density of fluid (kg/m3)
v = velocity (m/s)
so, according to this relation the two components of dynamic pressure areVelocity and density..
USING JAVAImplement the quicksort optimization median-of-three, i.pdf
USING JAVA:
Implement the quicksort optimization median-of-three, i.e., first, middle, and last, as pivot for
partition. Into this working quicksort algorithm: ( the spacing is bad, sorry)
private static void quicksort(int low, int high) {
int i = low, j = high;
// Get the pivot element from the middle of the list
int pivot = arr[(high+low)/2];
// Divide into two lists
while (i <= j) {
// If the current value from the left list is smaller then the pivot
// element then get the next element from the left list
while (arr[i] < pivot) i++;
// If the current value from the right list is larger then the pivot
// element then get the next element from the right list
while (arr[j] > pivot) j--;
// If we have found a value in the left list which is larger than
// the pivot element and if we have found a value in the right list
// which is smaller then the pivot element then we exchange the
// values.
// As we are done we can increase i and j
if (i < j) {
exchange(i, j);
i++;
j--;
} else if (i == j) { i++; j--; }
}
// Recursion
if (low < j)
quicksort(low, j);
if (i < high)
quicksort(i, high);
}
Solution
Hi, Please find my program:
private static void quicksort(int low, int high) {
if (low >= high)
return;
// Selecting the pivot
int first = low;
int second = arr[(high+low)/2];
int third = arr[high];
// median for first three
int pivot = Math.max(
Math.min(
array[first],
array[second]),
Math.min(
Math.max(
array[first],
array[second]
),
array[third]
)
);
while (low <= high)
{
while (array[low] < pivot)
{
low++;
}
while (array[high] > pivot)
{
high--;
}
if (low <= high)
{
// swapping
int temp = array[low];
array[low] = array[high];
array[high] = temp;
low++;
high--;
}
}
// Recursion
if (low < j)
quicksort(low, j);
if (i < high)
quicksort(i, high);
}.
There are 40 students in our class. How many ways they can be lined .pdf
There are 40 students in our class. How many ways they can be lined up such that two fixed
students X and Y are next to each other (order of the two fixed students does not matter).
Solution
So now that X and Y are always beside each other, then you can treat them as just ONE
PERSON.
Thus, it\'s like there are now just 39 people to permute.
As n! = number of ways to permute n objects in a line, then the number of ways is
#ways = 39! = 2.03979*10^46 [ANSWER].
The Task For this assignment you will write a rudimentary text edi.pdf
The Task
For this assignment you will write a rudimentary text editor that allows the user to edit 5 lines of
text, where each line is no longer than 80 characters. The editor should allow the user to
continue editing as long as desired and should print the current state of the edit buffer after each
edit.
The editor is a \'line editor\' in that the user must edit one line at a time. The user can specify
which line should be edited by choosing a line number from a menu.
The only two editing operations possible are to replace an entire line with a new line, or to
replace a substring in the line with a new substring.
Musts
The program should not accept incorrect menu choices from the user. If the user creates a string
that is longer than 80 characters the string should be truncated to fit the 80 character limit. The
program should simply make no changes if the user tries to replace a substring that does not exist
in the string.
Your program must use functions. Some functions are required, but you may make other
functions as you see fit. You may not change the name, return type, or the parameter list types
for required functions.
Required Function One
int replaceInString(char[] original, char[] substring, char[] replace);
This function causes the original string to be modified such that the first occurrence of substring
is removed from the original string and the contents of replace are inserted in its place.
replaceInString calls findSubString and insertString. The function returns 0 if the operation
fails and 1 if the operation is successful.
Required Function Two:
int findSubString(char[] original, char[] toFind);
This function finds the first occurrence of toFind in original and returns an integer representing
the index of the first element of the toFind substring in original. For example if toFind was \'cat\'
and original was \'thundercat\' the function would return 7 since the begining of \'cat\' in
\'thundercat\' is position 7. If the function does not find a substring it should return -1
note: do not use existing substring functions such as strstr as a solution for this function. Solve
the algorithm yourself. You may use basic string functions such as strlen and strcat.
Required Function Three:
int insertString(char[] original, int start, int length, char[] toInsert);
This function replaces the contents of original with the following sequence of characters:
the characters from original up to position start-
the characters from toInsert
the characters from original starting at the character immediately after length.
Solution
#include
#include
#define ROW_LENTH 81
#define NUM_ROWS 5
void replaceLine(char line[]);
void printText(char text[][ROW_LENTH]);
int readFile(char filePath[], char text[][ROW_LENTH]);
int writeFile(char filePath[], char text[][ROW_LENTH]);
void removeTrailingHardReturn(char line[]);
void flushBuffer();
int getLine();
int replaceInString(char original[], char substring[], char replace[]);
int findSubString(char origina.
The SIP handles what functionsA.) establishes a call through the .pdf
The SIP handles what functions?
A.) establishes a call through the network.
B) tears down a call through the network
C) rings the phone
D) applies features to the line.
E) converts the IP signal into a G.711 flow.
F.) a, b, and c
G.) a and b
H.) a, b, c, and e
I.) all of the above
Solution
sip has main five functions: session initiation protocal
1. User location
2.User availibilty
3 User capabilities
4 session setup
5 session management
so sip provides five function it uses layered approach
sip used for real timetransport protocal .it is used for delivering voice and video over IPnetwork
This type of server does not store any information of a call transactios.
so sip has above questioN
answer is : (I )ALL OF THE ABOVE.
The NBA decides to look into the use of meldonium in the league foll.pdf
The NBA decides to look into the use of meldonium in the league following the same protocol as
the WADA. Which of the following will be randomly tested?urine samplesblood samplesskin
samplesplasma samples
Solution
Answer: According to WADA (World Anti-Doping Agency), the quantity of Meldonium or
Mildronate (trade-name) in athlete\'s/Patient\'s body used to measure from the urine samples.
NBA is going to follow the same protocol as WADA to estimate the Meldonium content. So, the
answer is \'Urine Samples\'..
The organelle that serves as the digestive system in the cell is the .pdf
The organelle that serves as the digestive system in the cell is the ____. polysome; endosome;
lysosome; ribosome; intestine.
Solution
LYSOSOME:
In the cell line: lysosome secretes thye lytic enzymes, and promotes the phagocytosis and digests
the unwanted materials like bacteria etc, leading to formation of phagolysosomes.
Therefore it can be called as the digestive system of the cell..
The major type of interactive forces between molecules of NH_3 are .pdf
The major type of interactive forces between molecules of NH_3 are: ionic covalent hydrogen
bonding dipole-dipole attractions dispersion forces
Solution
Answer 18: The major type of interactive force that lie between molecule of ammonia (NH3) are
covalent bond. The single Nitrogen atom in an ammonia molecule is bonded to three atoms of
Hydrogen through the sharing of three electron pairs, one with each atom of Hydrogen. Thus,
finally said that the ammonia molecule is formed by covalent bonding between one Nitrogen
atom and three Hydrogen atoms..
The group of taxa that have fully developed appendages can be best de.pdf
The group of taxa that have fully developed appendages can be best described as: Convergent
evolution Monophyletic A species Polyphyletic
Solution
A.convergent evolution.
Note- convergent evolution is evolution of similar feature or characters in sDifferent species.
These structures are analogous structure which have similar form and function but are not
present in last common ancestors.
Here appendages are similar feature which different taxas has evolved independentally, and have
similar functions..
The Law of Independent Assortment states thatA. Two different gene.pdf
The Law of Independent Assortment states that
A. Two different genes will randomly assort their alleles during the formation of haploid cells
B. Two different genes will randomly assort their alleles during the formation of diploid cells
C. Two different genes will NOT randomly assort their alleles during the formation of haploid
cells
D. Two different alleles will randomly assort during the formation of haploid cells
Solution
Answer:
D. Two different alleles will randomly assort during the formation of haploid cells
The law of independent assortment states that the alleles of one gene sort into gametes
independently of the alleles of another gene..
The following results were obtained in the patient from Case Study 25.pdf
The following results were obtained in the patient from Case Study 25-2 (Case Study Table 25-
4.1). What is the most likely diagnosis? What is the prognosis? What complications may
develop?
Solution
Ques-1
Diagnosis: From the laboratory diagnosis, it seems that the patient is suffering from multiple
infections from hepatitis, including A and B. Both of these forms of hepatitis infections occur
due to infected food/water and direct physical contact
Ques-2: The major prognosis of hepatitis A & B is to infect liver because cirrhosis finally lasts
for 3 to 4 months. Under chronic conditions, it lasts for 6 months due to hepatic cell infection
due to hepatitis B virus replication. This is leading to higher incidence of hepatitis core antibody
(lgM) so that it is positive
Ques-3:
Complications:
Hepatitis or jaundice is the medical term for yellow discoloration of the sclera and mucous
membranes. Heme moiety of hemoglobin is breakdown into iron and bilivirdin in the body.
During jaundice, excess breakdown of hemoglobin results in the accumulation of bilirubin (made
from bilivirdin), which gives yellow coloration to the mucous membranes.
The most common symptoms include flu-like asscoaited with aches, liver dysfunction finally
tiredness, diarrhea. The main pain and ache observed in the liver region due to viral invasion of
hepatocytes causes inhibition of metabolic enzyme synthesis and metabolic enzyme activity.
These symptoms are leading to severe ache below the ribs and near to abdomen specifically in
liver.
Security National Bank is quoting 1-year certificates of deposit wit.pdf
Security National Bank is quoting 1-year certificates of deposit with an interest rate of 10%
compounded semiannually. Joe Saver purchased a $5,200 CD.
What is the CD
What is the CD
Solution
Hi,
Please find the detailed answer as follows:
Effective Rate = (1+Annual Rate/2)^2 -1 = (1+10%/2)^2 - 1 = $10.25%
Answer is 10.25%
Thanks..
Recently, the stock market took big swings up and down. A survey .pdf
Recently, the stock market took big swings up and down. A survey of 1011 adult investors
asked how often they tracked their portfolio.The table shows the investor responses. what is the
probability that an adult investor tracks his or her portfolio daily? Express your answer as a
simplified fraction and as a decimal rounded to three decimal places.
Solution
P(daily) = 222/total = 222/(222+281+297+144+67) = 222/1011 = 0.21958 ~= 0.22
Option (A) is correct..
Profit is the difference betweena. the assets purchased with cash.pdf
Profit is the difference between:
a. the assets purchased with cash contributed by the owner and the cash spent to operate the
business
b. assets and liabilities
c. the amounts received from customers for goods or services and the amounts paid for the inputs
used to provide the goods and services
d. the incoming cash and outgoing cash
Solution
Profit is the difference of the enterprises\'s revenues and expenses.
Revenue is always taken as normal revenue which is earned from normal course of bussiness.
Expenses is always taken as normal expenses which is incurred from normal course of bussiness.
so answer is c) the amounts received from customers for goods or services and the amounts paid
for the inputs used to provide the goods and services.
Problem 4.7. Tuberculosis is a rare disease in developing countries. .pdf
Problem 4.7. Tuberculosis is a rare disease in developing countries. However, it is the most
common cause of death in HIV - positive adults living in these countries (sec [16]). Consider a
country in which 0.045% of its adult population has tuberculosis. It is estimated that 8% of all
tuberculosis cases in this country are co - infected with HIV. Compute the probability that a
randomly selected adult from this country has both tuberculosis and HIV.
Solution
P(both) = P(tuberculosis) * P(HIV | tuberculosis) = 0.00045 * 0.08 = 0.000036.
Please help with this genetics problems The intermediates that build.pdf
Please help with this genetics problems The intermediates that build up in Serratia mutant X can
feed mutant Y to produce red pigment. However, mutant Y cannot feed mutant X to produce red
pigment. Which of the following is correct? (Select all that apply) Enzymes X and Y are in
parallel biochemical pathways for red pigment production Enzymes X and Y are in the same
branch of the pathway for red pigment production Enzyme X is downstream from enzyme Y
Enzyme X is upstream from enzyme Y Serratia marescens are, while Saccharomyces cerevisiae
are. archaea, mammalian bacteria, algae bacteria, eukaryotes fungi, prokaryotes In our
Serratia experiment we plated different mutant strains next to one another. When those mutant
strains exhibited complementation (were able to produce prodigiosin), what was being shared
between them? (Put another way, what are the strains providing to each another?) Enzymes
Intermediates Both enzymes and intermediates Serial dilutions are used because it is an
accurate way to determine the number of cells in a highly concentrated solution of cells to
accurately increase the concentration of cells to disperse the cells evenly in the tubes before
streaking the cells on the sterile plates to lyse the cells so we can streak the cytoplasm on the
plates Under what conditions does diploid yeast undergo meiosis to produce haploids?
Resource poor Resource rich Yeasts undergo meiosis whenever they want None of the above.
Solution
7. Answer: A & D
Enzyme X and Y are in parallel biochemical pathways for red pigment production. Enzyme X is
upstream from enzyme Y.
8. Answer: C
Serratia marescens are bacteria and Saccharomyces cerevisiae are eukaryotes.
9. Answer: C
They shared enzymes between them by complementation and able to produce prodigiosin.
10. Answer: A
Serial dilution is an accurate way to determine the number of cells in a highly concentrated
solution of cells.
11. Answer: A
Under resource poor condition, diploid yeast undergo meiosis to produce haploids..
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