The group of taxa that have fully developed appendages can be best de.pdf

•

0 likes•2 views

The group of taxa that have fully developed appendages can be best described as: Convergent evolution Monophyletic A species Polyphyletic Solution A.convergent evolution. Note- convergent evolution is evolution of similar feature or characters in sDifferent species. These structures are analogous structure which have similar form and function but are not present in last common ancestors. Here appendages are similar feature which different taxas has evolved independentally, and have similar functions..

Education

More from info785431

Write a JAVA LinkedListRec class that has the following methods siz.pdf

info785431

Write a BFS algorithm using only arrays and no other data structure. Solution #include #include #include //For boolean char que[20]; int front=0, rear=0, n; char arr[20]; int bfs(int ); char ajMat[20][20]; char b[20]; void display(); int p=0; int main() { char v; int i, j; printf(\"Enter the number of nodes in a graph\"); scanf(\"%d\",&n); printf(\"Enter the value of node of graph\"); for( i=0; i.

Write a BFS algorithm using only arrays and no other data structure..pdf

info785431

Why has one prominent textbook author described I/O management as the \"messiest aspect of operating system design\"? Using at least three distinct points, describe the evolution of I/O controllers, and describe how their support for I/O has increased in complexity over time. Solution Dear Student. Answer No-5a) The above asked question is from the book \"Opererating System by william Stalling\" according to the william stalling I/O management is the messiest aspect of an operating system. Let\'s discuss this in detail.. how I/O management is the messiest aspect of an operating system? There are wide variety of devices and their application. So it is very difficult to develop a generel consistant common solution for every device.The devices which are engaged with I/O are generally false in three different categories... 1-Human Readable- The human readable are the devices which are suitable for comuter user as printers, video display, mouse and keyboard.These are all input/output devices. 2-Machine Readable- The devices which are suitable for communication with electronic devices as disk drive, magnetic tapes and sensors and actuators. 3-Communication-The devices which are suitable for communicating with remote devices like a Modem. So above are the types of I/O devices, each device has their own functionality and design.Further more every device has different data transfer rate, and different applications. for example a disk used for file management requires support of file management software. Complexty in design is different in each device.Unit of data transfer may differ in each I/O device.Some are programmed I/O devices and some devices are interrupt driven, some requires DMA controller for data exchange between main memory and I/O module.Error conditions also differ from one device to another, So this kind of diversity makes uniform and consistant approach to I/O devices. So by the above explanation it is clear that is I/O is the messiest aspect of an operating system. Answer No-5b) As the coputer system is evoled there has been a pattern of increasing complexity and shopistication of each individual component.the evolutionarry steps in I/O controller are described below... The best example of I/O controller is DMA(Direct Memory Access).It controlles the data transfer between memoy and I/O device.The evolution of I/O controller is as follows.. 1- Previously processor directly controlled a peripheral device.Then a controller or I/O is added for smooth and fast data transmission. 2-Then I/O controller given direct memory controll via DMA controllers.And now the DMA controller can move a block of data without involving the processor. 3- Further I/O controller enhanced to become a seperate processor the central processing unit direcly direct the I/O processor to execute an I/O program in memory. So as the envolved continues in I/O Controller, more and more I/O functions is performed without processor involvement.Thats is why the complexity h.

Why has one prominent textbook author described IO management as the.pdf

info785431

which is true of the data shown in the histogram Which is true of th.pdf

info785431

What is the value of studying humanities in a business or technical curriculum? Solution Having learned more about the myths and stories of Western civilization, I am understanding more how study of the humanities (art, history, and literature) can be used to help people better understand and communicate with one another. It is obvious that the study of humanities is not just a college course, but it is an ongoing process and practice in life. The humanities can first be used to understand the past which has created the present. The culture which we have was shaped by the past. Facts, findings, and literature of even thousands of years ago have influenced our world today. Knowing this past can allow people to understand our present; knowing how we came to this present helps us to communicate about it and the future. The study of the humanities can also be used to realize differing interpretations of life and history. Studying facts of the past helps to understand literature of the past. Art reflects the cultures of the past, and shows how we achieved what we have today. For example, the Song of Roland was very biased about the Saracens (Muslims). If one only studied literature, they would have a totally skewed interpretation of who the Muslims were. By studying history though, we know that the battle in this literature wasn\'t even against Muslims. Also by studying history and religion we can see how Islam developed and what it really is. This is just one example of how the comprehensive study of the humanities can be used to understand the world, and to communicate fairly and intelligently with others in the world. The humanities are not just part of the college\'s curriculum. The study of the humanities teaches one how to study and look at how the past developed and how it has impacted today\'s world. The humanities allows people of different cultures to communicate and understand their sometimes common pasts but present differences. The humanities shows how different disciplines affect and complement one another. Finally, the study of the humanities shows that this study is ongoing and continual, constantly evolving and shaping. Highly successful executives, entrepreneurs and policy makers offer words of wisdom about the practical value of studying the humanities. “I think if you have a good background in what it is to be human, an understanding of life, culture and society, it gives you a good perspective on starting a business, instead of an education purely in business...You can always pick up how to read a balance sheet and how to figure out profit and loss, but it\'s harder to pick up the other stuff on the fly. ” 1. The humanities prepare you to fulfill your civic and cultural responsibilities. The reason that John Harvard left his library to the college in Cambridge, Massachusetts, that Jane and Leland Stanford founded Stanford University, and that states established land-grant colleges was to educate cultured and useful citizens. T.

What is the value of studying humanities in a business or technical .pdf

info785431

What are the two components of dynamic pressure? Velocity and density Viscosity and velocity Angle of attack and density Lift and Drag Solution Dynamic pressure is a defined property of a moving flow of gas or liquid and can be expressed as pd = 1/2 v2 (1) where pd = dynamic pressure (Pa) = density of fluid (kg/m3) v = velocity (m/s) so, according to this relation the two components of dynamic pressure areVelocity and density..

What are the two components of dynamic pressureVelocity and densi.pdf

info785431

USING JAVA: Implement the quicksort optimization median-of-three, i.e., first, middle, and last, as pivot for partition. Into this working quicksort algorithm: ( the spacing is bad, sorry) private static void quicksort(int low, int high) { int i = low, j = high; // Get the pivot element from the middle of the list int pivot = arr[(high+low)/2]; // Divide into two lists while (i <= j) { // If the current value from the left list is smaller then the pivot // element then get the next element from the left list while (arr[i] < pivot) i++; // If the current value from the right list is larger then the pivot // element then get the next element from the right list while (arr[j] > pivot) j--; // If we have found a value in the left list which is larger than // the pivot element and if we have found a value in the right list // which is smaller then the pivot element then we exchange the // values. // As we are done we can increase i and j if (i < j) { exchange(i, j); i++; j--; } else if (i == j) { i++; j--; } } // Recursion if (low < j) quicksort(low, j); if (i < high) quicksort(i, high); } Solution Hi, Please find my program: private static void quicksort(int low, int high) { if (low >= high) return; // Selecting the pivot int first = low; int second = arr[(high+low)/2]; int third = arr[high]; // median for first three int pivot = Math.max( Math.min( array[first], array[second]), Math.min( Math.max( array[first], array[second] ), array[third] ) ); while (low <= high) { while (array[low] < pivot) { low++; } while (array[high] > pivot) { high--; } if (low <= high) { // swapping int temp = array[low]; array[low] = array[high]; array[high] = temp; low++; high--; } } // Recursion if (low < j) quicksort(low, j); if (i < high) quicksort(i, high); }.

USING JAVAImplement the quicksort optimization median-of-three, i.pdf

info785431

There are 40 students in our class. How many ways they can be lined up such that two fixed students X and Y are next to each other (order of the two fixed students does not matter). Solution So now that X and Y are always beside each other, then you can treat them as just ONE PERSON. Thus, it\'s like there are now just 39 people to permute. As n! = number of ways to permute n objects in a line, then the number of ways is #ways = 39! = 2.03979*10^46 [ANSWER].

There are 40 students in our class. How many ways they can be lined .pdf

info785431

The Task For this assignment you will write a rudimentary text editor that allows the user to edit 5 lines of text, where each line is no longer than 80 characters. The editor should allow the user to continue editing as long as desired and should print the current state of the edit buffer after each edit. The editor is a \'line editor\' in that the user must edit one line at a time. The user can specify which line should be edited by choosing a line number from a menu. The only two editing operations possible are to replace an entire line with a new line, or to replace a substring in the line with a new substring. Musts The program should not accept incorrect menu choices from the user. If the user creates a string that is longer than 80 characters the string should be truncated to fit the 80 character limit. The program should simply make no changes if the user tries to replace a substring that does not exist in the string. Your program must use functions. Some functions are required, but you may make other functions as you see fit. You may not change the name, return type, or the parameter list types for required functions. Required Function One int replaceInString(char[] original, char[] substring, char[] replace); This function causes the original string to be modified such that the first occurrence of substring is removed from the original string and the contents of replace are inserted in its place. replaceInString calls findSubString and insertString. The function returns 0 if the operation fails and 1 if the operation is successful. Required Function Two: int findSubString(char[] original, char[] toFind); This function finds the first occurrence of toFind in original and returns an integer representing the index of the first element of the toFind substring in original. For example if toFind was \'cat\' and original was \'thundercat\' the function would return 7 since the begining of \'cat\' in \'thundercat\' is position 7. If the function does not find a substring it should return -1 note: do not use existing substring functions such as strstr as a solution for this function. Solve the algorithm yourself. You may use basic string functions such as strlen and strcat. Required Function Three: int insertString(char[] original, int start, int length, char[] toInsert); This function replaces the contents of original with the following sequence of characters: the characters from original up to position start- the characters from toInsert the characters from original starting at the character immediately after length. Solution #include #include #define ROW_LENTH 81 #define NUM_ROWS 5 void replaceLine(char line[]); void printText(char text[][ROW_LENTH]); int readFile(char filePath[], char text[][ROW_LENTH]); int writeFile(char filePath[], char text[][ROW_LENTH]); void removeTrailingHardReturn(char line[]); void flushBuffer(); int getLine(); int replaceInString(char original[], char substring[], char replace[]); int findSubString(char origina.

The Task For this assignment you will write a rudimentary text edi.pdf

info785431

The SIP handles what functions? A.) establishes a call through the network. B) tears down a call through the network C) rings the phone D) applies features to the line. E) converts the IP signal into a G.711 flow. F.) a, b, and c G.) a and b H.) a, b, c, and e I.) all of the above Solution sip has main five functions: session initiation protocal 1. User location 2.User availibilty 3 User capabilities 4 session setup 5 session management so sip provides five function it uses layered approach sip used for real timetransport protocal .it is used for delivering voice and video over IPnetwork This type of server does not store any information of a call transactios. so sip has above questioN answer is : (I )ALL OF THE ABOVE.

The SIP handles what functionsA.) establishes a call through the .pdf

info785431

The NBA decides to look into the use of meldonium in the league following the same protocol as the WADA. Which of the following will be randomly tested?urine samplesblood samplesskin samplesplasma samples Solution Answer: According to WADA (World Anti-Doping Agency), the quantity of Meldonium or Mildronate (trade-name) in athlete\'s/Patient\'s body used to measure from the urine samples. NBA is going to follow the same protocol as WADA to estimate the Meldonium content. So, the answer is \'Urine Samples\'..

The NBA decides to look into the use of meldonium in the league foll.pdf

info785431

The organelle that serves as the digestive system in the cell is the .pdf

info785431

The major type of interactive forces between molecules of NH_3 are: ionic covalent hydrogen bonding dipole-dipole attractions dispersion forces Solution Answer 18: The major type of interactive force that lie between molecule of ammonia (NH3) are covalent bond. The single Nitrogen atom in an ammonia molecule is bonded to three atoms of Hydrogen through the sharing of three electron pairs, one with each atom of Hydrogen. Thus, finally said that the ammonia molecule is formed by covalent bonding between one Nitrogen atom and three Hydrogen atoms..

The major type of interactive forces between molecules of NH_3 are .pdf

info785431

The Law of Independent Assortment states that A. Two different genes will randomly assort their alleles during the formation of haploid cells B. Two different genes will randomly assort their alleles during the formation of diploid cells C. Two different genes will NOT randomly assort their alleles during the formation of haploid cells D. Two different alleles will randomly assort during the formation of haploid cells Solution Answer: D. Two different alleles will randomly assort during the formation of haploid cells The law of independent assortment states that the alleles of one gene sort into gametes independently of the alleles of another gene..

The Law of Independent Assortment states thatA. Two different gene.pdf

info785431

The following results were obtained in the patient from Case Study 25-2 (Case Study Table 25- 4.1). What is the most likely diagnosis? What is the prognosis? What complications may develop? Solution Ques-1 Diagnosis: From the laboratory diagnosis, it seems that the patient is suffering from multiple infections from hepatitis, including A and B. Both of these forms of hepatitis infections occur due to infected food/water and direct physical contact Ques-2: The major prognosis of hepatitis A & B is to infect liver because cirrhosis finally lasts for 3 to 4 months. Under chronic conditions, it lasts for 6 months due to hepatic cell infection due to hepatitis B virus replication. This is leading to higher incidence of hepatitis core antibody (lgM) so that it is positive Ques-3: Complications: Hepatitis or jaundice is the medical term for yellow discoloration of the sclera and mucous membranes. Heme moiety of hemoglobin is breakdown into iron and bilivirdin in the body. During jaundice, excess breakdown of hemoglobin results in the accumulation of bilirubin (made from bilivirdin), which gives yellow coloration to the mucous membranes. The most common symptoms include flu-like asscoaited with aches, liver dysfunction finally tiredness, diarrhea. The main pain and ache observed in the liver region due to viral invasion of hepatocytes causes inhibition of metabolic enzyme synthesis and metabolic enzyme activity. These symptoms are leading to severe ache below the ribs and near to abdomen specifically in liver.

The following results were obtained in the patient from Case Study 25.pdf

info785431

Security National Bank is quoting 1-year certificates of deposit wit.pdf

info785431

Recently, the stock market took big swings up and down. A survey of 1011 adult investors asked how often they tracked their portfolio.The table shows the investor responses. what is the probability that an adult investor tracks his or her portfolio daily? Express your answer as a simplified fraction and as a decimal rounded to three decimal places. Solution P(daily) = 222/total = 222/(222+281+297+144+67) = 222/1011 = 0.21958 ~= 0.22 Option (A) is correct..

Recently, the stock market took big swings up and down. A survey .pdf

info785431

Profit is the difference between: a. the assets purchased with cash contributed by the owner and the cash spent to operate the business b. assets and liabilities c. the amounts received from customers for goods or services and the amounts paid for the inputs used to provide the goods and services d. the incoming cash and outgoing cash Solution Profit is the difference of the enterprises\'s revenues and expenses. Revenue is always taken as normal revenue which is earned from normal course of bussiness. Expenses is always taken as normal expenses which is incurred from normal course of bussiness. so answer is c) the amounts received from customers for goods or services and the amounts paid for the inputs used to provide the goods and services.

Profit is the difference betweena. the assets purchased with cash.pdf

info785431

Problem 4.7. Tuberculosis is a rare disease in developing countries. However, it is the most common cause of death in HIV - positive adults living in these countries (sec [16]). Consider a country in which 0.045% of its adult population has tuberculosis. It is estimated that 8% of all tuberculosis cases in this country are co - infected with HIV. Compute the probability that a randomly selected adult from this country has both tuberculosis and HIV. Solution P(both) = P(tuberculosis) * P(HIV | tuberculosis) = 0.00045 * 0.08 = 0.000036.

Problem 4.7. Tuberculosis is a rare disease in developing countries. .pdf

info785431

Please help with this genetics problems The intermediates that build up in Serratia mutant X can feed mutant Y to produce red pigment. However, mutant Y cannot feed mutant X to produce red pigment. Which of the following is correct? (Select all that apply) Enzymes X and Y are in parallel biochemical pathways for red pigment production Enzymes X and Y are in the same branch of the pathway for red pigment production Enzyme X is downstream from enzyme Y Enzyme X is upstream from enzyme Y Serratia marescens are, while Saccharomyces cerevisiae are. archaea, mammalian bacteria, algae bacteria, eukaryotes fungi, prokaryotes In our Serratia experiment we plated different mutant strains next to one another. When those mutant strains exhibited complementation (were able to produce prodigiosin), what was being shared between them? (Put another way, what are the strains providing to each another?) Enzymes Intermediates Both enzymes and intermediates Serial dilutions are used because it is an accurate way to determine the number of cells in a highly concentrated solution of cells to accurately increase the concentration of cells to disperse the cells evenly in the tubes before streaking the cells on the sterile plates to lyse the cells so we can streak the cytoplasm on the plates Under what conditions does diploid yeast undergo meiosis to produce haploids? Resource poor Resource rich Yeasts undergo meiosis whenever they want None of the above. Solution 7. Answer: A & D Enzyme X and Y are in parallel biochemical pathways for red pigment production. Enzyme X is upstream from enzyme Y. 8. Answer: C Serratia marescens are bacteria and Saccharomyces cerevisiae are eukaryotes. 9. Answer: C They shared enzymes between them by complementation and able to produce prodigiosin. 10. Answer: A Serial dilution is an accurate way to determine the number of cells in a highly concentrated solution of cells. 11. Answer: A Under resource poor condition, diploid yeast undergo meiosis to produce haploids..

Please help with this genetics problems The intermediates that build.pdf

info785431

More from info785431 (20)