USING JAVAImplement the quicksort optimization median-of-three, i.pdf
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USING JAVA: Implement the quicksort optimization median-of-three, i.e., first, middle, and last, as pivot for partition. Into this working quicksort algorithm: ( the spacing is bad, sorry) private static void quicksort(int low, int high) { int i = low, j = high; // Get the pivot element from the middle of the list int pivot = arr[(high+low)/2]; // Divide into two lists while (i <= j) { // If the current value from the left list is smaller then the pivot // element then get the next element from the left list while (arr[i] < pivot) i++; // If the current value from the right list is larger then the pivot // element then get the next element from the right list while (arr[j] > pivot) j--; // If we have found a value in the left list which is larger than // the pivot element and if we have found a value in the right list // which is smaller then the pivot element then we exchange the // values. // As we are done we can increase i and j if (i < j) { exchange(i, j); i++; j--; } else if (i == j) { i++; j--; } } // Recursion if (low < j) quicksort(low, j); if (i < high) quicksort(i, high); } Solution Hi, Please find my program: private static void quicksort(int low, int high) { if (low >= high) return; // Selecting the pivot int first = low; int second = arr[(high+low)/2]; int third = arr[high]; // median for first three int pivot = Math.max( Math.min( array[first], array[second]), Math.min( Math.max( array[first], array[second] ), array[third] ) ); while (low <= high) { while (array[low] < pivot) { low++; } while (array[high] > pivot) { high--; } if (low <= high) { // swapping int temp = array[low]; array[low] = array[high]; array[high] = temp; low++; high--; } } // Recursion if (low < j) quicksort(low, j); if (i < high) quicksort(i, high); }.
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![USING JAVA:
Implement the quicksort optimization median-of-three, i.e., first, middle, and last, as pivot for
partition. Into this working quicksort algorithm: ( the spacing is bad, sorry)
private static void quicksort(int low, int high) {
int i = low, j = high;
// Get the pivot element from the middle of the list
int pivot = arr[(high+low)/2];
// Divide into two lists
while (i <= j) {
// If the current value from the left list is smaller then the pivot
// element then get the next element from the left list
while (arr[i] < pivot) i++;
// If the current value from the right list is larger then the pivot
// element then get the next element from the right list
while (arr[j] > pivot) j--;
// If we have found a value in the left list which is larger than
// the pivot element and if we have found a value in the right list
// which is smaller then the pivot element then we exchange the
// values.
// As we are done we can increase i and j
if (i < j) {
exchange(i, j);
i++;
j--;
} else if (i == j) { i++; j--; }
}
// Recursion
if (low < j)
quicksort(low, j);
if (i < high)
quicksort(i, high);
}
Solution](https://image.slidesharecdn.com/usingjavaimplementthequicksortoptimizationmedian-of-threei-230703180845-caf1bb01/85/USING-JAVAImplement-the-quicksort-optimization-median-of-three-i-pdf-1-320.jpg)
![Hi, Please find my program:
private static void quicksort(int low, int high) {
if (low >= high)
return;
// Selecting the pivot
int first = low;
int second = arr[(high+low)/2];
int third = arr[high];
// median for first three
int pivot = Math.max(
Math.min(
array[first],
array[second]),
Math.min(
Math.max(
array[first],
array[second]
),
array[third]
)
);
while (low <= high)
{
while (array[low] < pivot)
{
low++;
}
while (array[high] > pivot)
{
high--;
}
if (low <= high)
{
// swapping
int temp = array[low];](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
Recommended
DAA Lab Work.docx
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Maxima Finding problem In the 2-dimension space, we shall say that .pdf
Maxima Finding problem: In the 2-dimension space, we shall say that a point A=(A1,A2)
dominates a point B=(b1,B2) if A1>B1 and A2>B2. Design an algorithm to find all maximal
points
Solution
we will use a divide and conquer algorithm of O(n log n) complexity which is merge sort.This
will ensure that each recursive call marks the maximal points among those that it is returning, or
return the maximal points as an additional part of the return value, and produce a merged and
corrected list of maximal points, in order, for its caller.The merge sort can be implemented in
c++
MERGE SORT:
/*This is basically a helper function which is used for finding the maximum of two numbers */
int maximum(int x, int y)
{
if(x > y)
{
return x;
}
else
{
return y;
}
}
/* The left is defined as the index of the leftmost element of the subarray;
On the other hand the right is one past the index of the rightmost element */
void merge_helper_function(int *input, int left, int right, int *scratch1)
{
/* This is the base case: one element */
if(right == left + 1)
{
return;
}
else
{
int i = 0;
int length = right - left;
int midpoint_distance = length/2;
/* The l and r are to the positions in the left and right subarrays */
int l = left, r = left + midpoint_distance;
/* now we will sort each subarray */
merge_helper)function(input, left, left + midpoint_distance, scratch);
merge_helper_function(input, left + midpoint_distance, right, scratch);
/* Finally we will merge the arrays together using scratch for temporary storage */
for(i = 0; i < length; i++)
{
/* First we will check to see if any elements remain in the left array; if so,
The next we check if there are any elements left in the right array; if so, we compare
them. Otherwise, we know that the merge must
* use take the element from the left array */
if(l < left + midpoint_distance &&
(r == right || maximum(input[l], input[r]) == input[l]))
{
scratch1[i] = input[l];
l++;
}
else
{
scratch1[i] = input[r];
r++;
}
}
/*Finally we copy the sorted subarray back to the input */
for(i = left; i < right; i++)
{
input[i] = scratch1[i - left];
}
}
}
/*The mergesort function returns true on success
*/
int mergesortfunction(int *input, int size)
{
int *scratchone = (int *)malloc(size * sizeof(int));
if(scratchone != NULL)
{
merge_helper_function(input, 0, size, scratchone);
free(scratchone);
return 1;
}
else
{
return 0;
}
}.
Below is a given ArrayList class and Main class Your Dreams Our Mission/tuto...
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Below is a given ArrayList class and Main class in search algorithms. Please modify the existing program so it can time the sequential search and the binary search methods several times each for randomly generated values, and record the results in a table. Do not time individual searches, but groups of them. For example, time 100 searches together or 1,000 searches together. Compare the running times of these two search methods that are obtained during the experiment.
All code should be in C++Using the UnsortedList class (UnsortedLis.pdf
All code should be in C++
Using the UnsortedList class (UnsortedList.h file below) write a function sublist which extracts
elements that are smaller than a given item from the given list and forms a new list. The
precondition of the function is: the list has been initialized and is not empty. The postconditions
are: newList contains all the items of the list whose values are less than the given item.
Implement the sublist function as a friend function of the UnsortedList class whose declaration
is:
friend void sublist(const UnsortedList& list,
const ItemType& item,
UnsortedList& newList);
(Hint: The UnsortedList class has private members
ItemType list[MAX_LENGTH];
int length;
and the member functions getLength, resetList, insert, remove, etc.)
//**********************************************************
// SPECIFICATION FILE (UnsortedList.h)
// This file gives the specification of a basic class
// template for unsorted array-based lists.
// The list components are not assumed to be in order by
// value.
//**********************************************************
#ifndef UNSORTEDLIST_H
#define UNSORTEDLIST_H
#include
#include // Needed for the exit function
using namespace std;
const int MAX_LENGTH = 100; // Maximum number of components
template // You may also choose to use
// typedef statement
class UnsortedList
{
public:
// Constructor
UnsortedList();
// Post: Empty list has been created. length has been set to zero.
// Knowledge responsibilities
int getLength() const;
// Post: Returns the length of the list
bool isEmpty() const;
// Post: Returns true if list is empty; false otherwise
bool isFull() const;
// Post: Returns true if list is full; false otherwise
bool isInList(const ItemType& item) const;
// Post: Returns true if item is int the list; false otherwise
int seqSearch(const ItemType& item) const;
// Function to search the list for a given item.
// Post: If item is found, returns the index in the array where
// item is found; otherwise, return -1.
// Action Responsibilities
void resetList();
// Post: The list becomes empty. length has been set to zero.
void insert(const ItemType& item);
// Function to insert item to the end of the list. However, first
// the list is searched to see whether the item to be inserted is
// already in the list.
// Post: list[length] = item and length++. If item is already in
// the list or the list is already full, an appropriate message is
// displayed.
void remove(const ItemType& item);
// Function to remove item from the list.
// Post: If item is found in the list, it is removed from the list
// and length is decremented by one.
// Overloaded [] operator declaration.
// This function returns a reference to the element in the
// array indexed by index.
ItemType& operator[](const int& index);
// Additional operations
void sort();
// Post: list items have been put into ascending order by selection sort
void selectionSort();
// Function to sort the items in the list.
// Post: list items have been put int.
Ds notes
This document contains lecture notes on data structures from Einstein College of Engineering. It discusses various abstract data types like lists, trees, stacks, and sets. It then focuses on list abstract data type, describing lists as sequences of elements and their basic operations like insertion, deletion, finding etc. It provides array-based and linked list-based implementations of lists and compares their advantages and disadvantages. It also discusses stack abstract data type, implementations of stacks using arrays and linked lists, and basic stack operations like push, pop etc.
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helpInstructionsAdd the function max as an abstract function to .pdf
help
Instructions
Add the function max as an abstract function to the class arrayListType to return the largest
element of the list.
Also, write the definition of the function max in the class unorderedArrayListType and write a
program to test this function.
files:
main.cpp:
//Data: 18 42 78 22 42 5 42 57
arrayListType.h:
#ifndef H_arrayListType
#define H_arrayListType
class arrayListType
{
public:
bool isEmpty() const;
//Function to determine whether the list is empty
//Postcondition: Returns true if the list is empty;
// otherwise, returns false.
bool isFull() const;
//Function to determine whether the list is full
//Postcondition: Returns true if the list is full;
// otherwise, returns false.
int listSize() const;
//Function to determine the number of elements in
//the list.
//Postcondition: Returns the value of length.
int maxListSize() const;
//Function to determine the maximum size of the list
//Postcondition: Returns the value of maxSize.
void print() const;
//Function to output the elements of the list
//Postcondition: Elements of the list are output on the
// standard output device.
bool isItemAtEqual(int location, int item) const;
//Function to determine whether item is the same as
//the item in the list at the position specified
//by location.
//Postcondition: Returns true if list[location]
// is the same as item; otherwise,
// returns false.
// If location is out of range, an
// appropriate message is displayed.
virtual void insertAt(int location, int insertItem) = 0;
//Function to insert insertItem in the list at the
//position specified by location.
//Note that this is an abstract function.
//Postcondition: Starting at location, the elements of
// the list are shifted down,
// list[location] = insertItem; length++;
// If the list is full or location is out of
// range, an appropriate message is displayed.
virtual void insertEnd(int insertItem) = 0;
//Function to insert insertItem at the end of
//the list. Note that this is an abstract function.
//Postcondition: list[length] = insertItem; and length++;
// If the list is full, an appropriate
// message is displayed.
void removeAt(int location);
//Function to remove the item from the list at the
//position specified by location
//Postcondition: The list element at list[location] is
// removed and length is decremented by 1.
// If location is out of range, an
// appropriate message is displayed.
void retrieveAt(int location, int& retItem) const;
//Function to retrieve the element from the list at the
//position specified by location
//Postcondition: retItem = list[location]
// If location is out of range, an
// appropriate message is displayed.
virtual void replaceAt(int location, int repItem) = 0;
//Function to replace the elements in the list
//at the position specified by location.
//Note that this is an abstract function.
//Postcondition: list[location] = repItem
// If location is out of range, an
// appropriate message is displayed.
void clearList();
//Function to remove all th.
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DAA Lab Work.docx
The document describes code for four sorting algorithms: insertion sort, selection sort, merge sort, and heap sort. For each algorithm, it provides the code, explains the algorithm's approach for sorting an array, and includes a main function that takes user input for an array and prints the sorted output.
Maxima Finding problem In the 2-dimension space, we shall say that .pdf
Maxima Finding problem: In the 2-dimension space, we shall say that a point A=(A1,A2)
dominates a point B=(b1,B2) if A1>B1 and A2>B2. Design an algorithm to find all maximal
points
Solution
we will use a divide and conquer algorithm of O(n log n) complexity which is merge sort.This
will ensure that each recursive call marks the maximal points among those that it is returning, or
return the maximal points as an additional part of the return value, and produce a merged and
corrected list of maximal points, in order, for its caller.The merge sort can be implemented in
c++
MERGE SORT:
/*This is basically a helper function which is used for finding the maximum of two numbers */
int maximum(int x, int y)
{
if(x > y)
{
return x;
}
else
{
return y;
}
}
/* The left is defined as the index of the leftmost element of the subarray;
On the other hand the right is one past the index of the rightmost element */
void merge_helper_function(int *input, int left, int right, int *scratch1)
{
/* This is the base case: one element */
if(right == left + 1)
{
return;
}
else
{
int i = 0;
int length = right - left;
int midpoint_distance = length/2;
/* The l and r are to the positions in the left and right subarrays */
int l = left, r = left + midpoint_distance;
/* now we will sort each subarray */
merge_helper)function(input, left, left + midpoint_distance, scratch);
merge_helper_function(input, left + midpoint_distance, right, scratch);
/* Finally we will merge the arrays together using scratch for temporary storage */
for(i = 0; i < length; i++)
{
/* First we will check to see if any elements remain in the left array; if so,
The next we check if there are any elements left in the right array; if so, we compare
them. Otherwise, we know that the merge must
* use take the element from the left array */
if(l < left + midpoint_distance &&
(r == right || maximum(input[l], input[r]) == input[l]))
{
scratch1[i] = input[l];
l++;
}
else
{
scratch1[i] = input[r];
r++;
}
}
/*Finally we copy the sorted subarray back to the input */
for(i = left; i < right; i++)
{
input[i] = scratch1[i - left];
}
}
}
/*The mergesort function returns true on success
*/
int mergesortfunction(int *input, int size)
{
int *scratchone = (int *)malloc(size * sizeof(int));
if(scratchone != NULL)
{
merge_helper_function(input, 0, size, scratchone);
free(scratchone);
return 1;
}
else
{
return 0;
}
}.
Below is a given ArrayList class and Main class Your Dreams Our Mission/tuto...
FOR MORE CLASSES VISIT
www.tutorialoutlet.com
Below is a given ArrayList class and Main class in search algorithms. Please modify the existing program so it can time the sequential search and the binary search methods several times each for randomly generated values, and record the results in a table. Do not time individual searches, but groups of them. For example, time 100 searches together or 1,000 searches together. Compare the running times of these two search methods that are obtained during the experiment.
All code should be in C++Using the UnsortedList class (UnsortedLis.pdf
All code should be in C++
Using the UnsortedList class (UnsortedList.h file below) write a function sublist which extracts
elements that are smaller than a given item from the given list and forms a new list. The
precondition of the function is: the list has been initialized and is not empty. The postconditions
are: newList contains all the items of the list whose values are less than the given item.
Implement the sublist function as a friend function of the UnsortedList class whose declaration
is:
friend void sublist(const UnsortedList& list,
const ItemType& item,
UnsortedList& newList);
(Hint: The UnsortedList class has private members
ItemType list[MAX_LENGTH];
int length;
and the member functions getLength, resetList, insert, remove, etc.)
//**********************************************************
// SPECIFICATION FILE (UnsortedList.h)
// This file gives the specification of a basic class
// template for unsorted array-based lists.
// The list components are not assumed to be in order by
// value.
//**********************************************************
#ifndef UNSORTEDLIST_H
#define UNSORTEDLIST_H
#include
#include // Needed for the exit function
using namespace std;
const int MAX_LENGTH = 100; // Maximum number of components
template // You may also choose to use
// typedef statement
class UnsortedList
{
public:
// Constructor
UnsortedList();
// Post: Empty list has been created. length has been set to zero.
// Knowledge responsibilities
int getLength() const;
// Post: Returns the length of the list
bool isEmpty() const;
// Post: Returns true if list is empty; false otherwise
bool isFull() const;
// Post: Returns true if list is full; false otherwise
bool isInList(const ItemType& item) const;
// Post: Returns true if item is int the list; false otherwise
int seqSearch(const ItemType& item) const;
// Function to search the list for a given item.
// Post: If item is found, returns the index in the array where
// item is found; otherwise, return -1.
// Action Responsibilities
void resetList();
// Post: The list becomes empty. length has been set to zero.
void insert(const ItemType& item);
// Function to insert item to the end of the list. However, first
// the list is searched to see whether the item to be inserted is
// already in the list.
// Post: list[length] = item and length++. If item is already in
// the list or the list is already full, an appropriate message is
// displayed.
void remove(const ItemType& item);
// Function to remove item from the list.
// Post: If item is found in the list, it is removed from the list
// and length is decremented by one.
// Overloaded [] operator declaration.
// This function returns a reference to the element in the
// array indexed by index.
ItemType& operator[](const int& index);
// Additional operations
void sort();
// Post: list items have been put into ascending order by selection sort
void selectionSort();
// Function to sort the items in the list.
// Post: list items have been put int.
Ds notes
This document contains lecture notes on data structures from Einstein College of Engineering. It discusses various abstract data types like lists, trees, stacks, and sets. It then focuses on list abstract data type, describing lists as sequences of elements and their basic operations like insertion, deletion, finding etc. It provides array-based and linked list-based implementations of lists and compares their advantages and disadvantages. It also discusses stack abstract data type, implementations of stacks using arrays and linked lists, and basic stack operations like push, pop etc.
linked list (c#)
The document discusses list data structures and their implementation using arrays and linked memory. It describes common list operations like insertion, removal, searching, and provides examples of how to implement them with arrays and linked lists. Key list operations include adding and removing elements from different positions, accessing elements by index or pointer, and traversing the list forward and backward. Linked lists offer more flexibility than arrays by not requiring predefined memory allocation.
helpInstructionsAdd the function max as an abstract function to .pdf
help
Instructions
Add the function max as an abstract function to the class arrayListType to return the largest
element of the list.
Also, write the definition of the function max in the class unorderedArrayListType and write a
program to test this function.
files:
main.cpp:
//Data: 18 42 78 22 42 5 42 57
arrayListType.h:
#ifndef H_arrayListType
#define H_arrayListType
class arrayListType
{
public:
bool isEmpty() const;
//Function to determine whether the list is empty
//Postcondition: Returns true if the list is empty;
// otherwise, returns false.
bool isFull() const;
//Function to determine whether the list is full
//Postcondition: Returns true if the list is full;
// otherwise, returns false.
int listSize() const;
//Function to determine the number of elements in
//the list.
//Postcondition: Returns the value of length.
int maxListSize() const;
//Function to determine the maximum size of the list
//Postcondition: Returns the value of maxSize.
void print() const;
//Function to output the elements of the list
//Postcondition: Elements of the list are output on the
// standard output device.
bool isItemAtEqual(int location, int item) const;
//Function to determine whether item is the same as
//the item in the list at the position specified
//by location.
//Postcondition: Returns true if list[location]
// is the same as item; otherwise,
// returns false.
// If location is out of range, an
// appropriate message is displayed.
virtual void insertAt(int location, int insertItem) = 0;
//Function to insert insertItem in the list at the
//position specified by location.
//Note that this is an abstract function.
//Postcondition: Starting at location, the elements of
// the list are shifted down,
// list[location] = insertItem; length++;
// If the list is full or location is out of
// range, an appropriate message is displayed.
virtual void insertEnd(int insertItem) = 0;
//Function to insert insertItem at the end of
//the list. Note that this is an abstract function.
//Postcondition: list[length] = insertItem; and length++;
// If the list is full, an appropriate
// message is displayed.
void removeAt(int location);
//Function to remove the item from the list at the
//position specified by location
//Postcondition: The list element at list[location] is
// removed and length is decremented by 1.
// If location is out of range, an
// appropriate message is displayed.
void retrieveAt(int location, int& retItem) const;
//Function to retrieve the element from the list at the
//position specified by location
//Postcondition: retItem = list[location]
// If location is out of range, an
// appropriate message is displayed.
virtual void replaceAt(int location, int repItem) = 0;
//Function to replace the elements in the list
//at the position specified by location.
//Note that this is an abstract function.
//Postcondition: list[location] = repItem
// If location is out of range, an
// appropriate message is displayed.
void clearList();
//Function to remove all th.
Carbon dioxide (CO_2) is a non-polar molecule. Is this consistent wit.pdf
Carbon dioxide (CO_2) is a non-polar molecule. Is this consistent with your classification of the
C - O bond in #2 above? Why is CO_2 nonpolar?
Solution
In C-O the oxygen is more electronegative than carbon , so the shared electrons are more close to
oxygen make it more negative and carbon becomes more positive.The polarity is determined by
the difference in electronegativity, since electronegativity of oxygen is more here it makes C-O a
polar component.
But in Co2 the two oxygen lies linearly ie O=C=O
Since the two oxygen atoms lies in 180 degree angle their electronegativity cancel each other ,
doesn\'t make any effect on the electronegativity of carbon, so CO2 becomes non polar in nature..
Compare and contrast the messages about science and integrity in Fra.pdf
Compare and contrast the messages about science and integrity in Frankenstein and Dr. Jekyll
and Mr. Hyde. (You must discuss both science and integrity).
Solution
I find Dr. Jekyll\'s use of science to have at least a bit more integrity than Victor Frankenstein\'s.
Frankenstein dreams of being \"blessed\" by a race of men which he will have created and
\"hailed\" as something of a hero by them. He puts science to use in order to achieve personal
glory and fame, and because he acts without integrity, behaving selfishly and unethically, he
ruins many more lives than just his own.
Dr. Jekyll, on the other hand, doesn\'t exploit science in order to achieve fame. In essence, he
succumbs to Victorian societal pressure to conform to an incredibly repressive moral code. His
intention is to better himself by making it easier for him to always do the right thing, as defined
by his society. Despite the problems we might find with his rationale (if we take issue with his
attempt to rid himself of a fundamental part of being human), his intentions, I would argue, are
less self-serving than Frankenstein\'s. Jekyll is actually attempting to change himself in order to
better fit the (unreasonable) demands of his society, and so his use of science smacks more
clearly of integrity than does Frankenstein\'s. He shows that it is possible to put science to use in
a more ethical way than Shelley\'s \"hero.\".
Briely, what was Darwins explanation for the appearance of design.pdf
Briely, what was Darwin\'s explanation for the appearance of design? How does it explain the
appearance of design? (please answer this in short) thank you
Solution
Darwin\'s explanation for the appearance of design:
Darwin discovered natural selection; it is a critical phenomenon that reveals the secret behind the
“design” of organisms. It explains the orderly process of origin, complexity, adaptation and
diversity of organisms by natural laws.
According to Darwin\'s design the creative power behind of evolution are arisen due to the
interaction among chance & necessity and between the natural selection & random mutations.
Darwin\'s The Origin of Species book was published in 1859. In this he mainly explains how the
evolution is demonstrating by natural selection.
Three main aspects of evolution theory:
1. Evolution: Descent of living things with modification.
2. Evolutionary history: The reconstruction of the universal tree of life (Thesis of common
ancestry).
3. Darwinism: The mechanism behind the evolutionary change is natural selection operating on
random variations in living things.
Darwin\'snatural selection evidences:
The beaks of Darwin finches. The finches of the Galapagos Islands were adapted to the island in
different ways, but are believed to share a common ancestor..
A router receives a message addressed 172.16.15.75. The relevant rou.pdf
A router receives a message addressed 172.16.15.75. The relevant routing table entries are
172.16.0.0 /20 – Serial 0, 172.16.0.0 /23 – Ethernet 0, and 172.16.15.64 /26 – Ethernet 1. Which
interface will the router forward the packet to?
A. Serial 0.
B. Serial 1.
C. Ethernet 0.
D. Ethernet 1.
E. None of the above. The packet will be dropped.
Solution
When message is passed through router the address wont alter, So in router, the address is
matching with router table. So this message wont pass and packet will be dropped.
So correct option is E. None of the above. The packet will be dropped..
A study of sandflies in Panama classified flies caught in light traps.pdf
A study of sandflies in Panama classified flies caught in light traps by sex (male, female) and
height of trap (3 and 35 feet above ground), resulting in the following 2 Times 2 contingency
table:^8 Do these data provide evidence that the sex ratio of Panamanian sandflies varies with
height above ground?
Solution.
___Tissue found in the brain, spinal cord, and peripheral nerves. The.pdf
___Tissue found in the brain, spinal cord, and peripheral nerves. The basic cells are the___
Types of Membranes ___ membranes (3 types are A. ___ line the body cavities that do not open
to the outside, reducing friction between organs and cavity walls, and secrete serous fluid, B. ___
line the cavities of epithelial and underlying connective tissues.) Some membranes are
composed entirely of connected tissue include ___ and___
Solution
The epithelial cells are the outermost cells. They have nerve supply but no blood supply. These
cells receive nutrition from substances diffusing from the underlying blood vessels.Below the
epithelial cells is the basement membrane which provides nutrition and new epithelial cells arise
from the basement membrane..
You have been exposed to each of the 8 microbes below. One of them h.pdf
You have been exposed to each of the 8 microbes below. One of them has infected you and is
causing the symptom of Fever. Given this symptom, select all of the likely causative agents.
Helicobacter pylori
Yellow Fever virus
Aliivibrio fischeri
Rhizobium spp.
Epstein Barr Virus
Rickettsia rickettsii
Burkholderia mallei
Klebsiella pneumoniae
Helicobacter pylori
Yellow Fever virus
Aliivibrio fischeri
Rhizobium spp.
Epstein Barr Virus
Rickettsia rickettsii
Burkholderia mallei
Klebsiella pneumoniae
Solution
Yellow Fever virus symptoms include fever, chills, loss of appetite, nausea, muscle pains
particularly in the back, and headaches. This disease is spread by the bite of female mosquito..
Write a snippet of C code that will enable the ADC to continuously r.pdf
Write a snippet of C code that will enable the ADC to continuously run as fast as possible and
cause an interrupt after every conversion. Write only the initialization code using atmega328p?
Solution
#include
#include
ISR(ADC_vect)
{
PORTD = ADCL; // give the low byte to PORTD
PORTB = ADCH; // give the high byte to PORTB
ADCSRA | =(1<.
Write a JAVA LinkedListRec class that has the following methods siz.pdf
Write a JAVA LinkedListRec class that has the following methods: size, empty, insertBefore,
insertAfter, addAtHead, addAtEnd, remove, replace, peekFront, peekEnd, removeFront,
removeEnd, toString. Use recursion to implement most of these methods. Write a driver to test
your implemented LinkedListRec class methods.
Solution
import java.util.Scanner;
public class LinkedListRec {
int data;
LinkedListRec prev=null,next=null;
int size(LinkedListRec l)//method which returns the length of the list
{
if(l==null)return 0;
return 1+size(l.next);
}
boolean empty(LinkedListRec l)//method checks whether the list is empty or not...
{
if(l==null)return true;
else return false;
}
LinkedListRec insertBefore(LinkedListRec l,int value,int num_insertbefore)//method which
adds a new number before the given number..
{
if(l==null)return l;
if(l.data == num_insertbefore)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.prev==null)
{
n.next = l;
l=n;
}
else
{
n.prev = l.prev;
n.next= l;
l.prev = n;
}
return l;
}
return insertBefore(l.next,value,num_insertbefore);
}
LinkedListRec insertAfter(LinkedListRec l,int value,int num_insertafter)//method which adds
the new number after the given number
{
if(l==null)return l;
if(l.data == num_insertafter)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.next==null)
{
l.next = n;
n.prev = l;
}
else
{
n.next = l.next;
l.next.prev = n;
n.prev = l;
}
return l;
}
return insertAfter(l.next,value,num_insertafter);
}
LinkedListRec addAtHead(LinkedListRec l,int value)//method which adds a new number at
the head position of the list...
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.next = l;
l=n;
return l;
}
LinkedListRec addAtEnd(LinkedListRec l,int value)//method which adds a new number at
the end position of the list...
{
if(l==null){ l = new LinkedListRec();l.data = value;return l;}
if(l.next==null)
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.prev = l;
l.next = n;
return l;
}
return addAtEnd(l.next,value);
}
LinkedListRec remove(LinkedListRec l,int value)//method which removes given numbet
from the list....
{
if(l==null)return l;
if(l.data == value)
{
if(l.prev!=null){
l.prev = l.next;
}
else
l=l.next;
return l;
}
return remove(l.next,value);
}
boolean replace(LinkedListRec l,int value,int newvalue)//method which replaces current
number with new number,...
{
if(l==null)return false;
if(l.data == value)
{
l.data = newvalue;
return true;
}
return replace(l.next,value,newvalue);
}
int peekFront(LinkedListRec l)//method which returns the first value of the list...
{
if(l!=null)
return l.data;
else return -1;
}
int peekEnd(LinkedListRec l)//method which returns the last value of the list........
{
if(l==null)return -1;
if(l.next == null)return l.data;
return peekEnd(l.next);
}
LinkedListRec removeFront(LinkedListRec l)//method which removes the first element of the
list..
{
if(l==null)return l;
l=l.next;
return l;
}
boolean removeEnd(LinkedListRec l)//method which removes the last element o.
Write a BFS algorithm using only arrays and no other data structure..pdf
Write a BFS algorithm using only arrays and no other data structure.
Solution
#include
#include
#include //For boolean
char que[20];
int front=0, rear=0, n;
char arr[20];
int bfs(int );
char ajMat[20][20];
char b[20];
void display();
int p=0;
int main()
{
char v;
int i, j;
printf(\"Enter the number of nodes in a graph\");
scanf(\"%d\",&n);
printf(\"Enter the value of node of graph\");
for( i=0; i.
Why has one prominent textbook author described IO management as the.pdf
Why has one prominent textbook author described I/O management as the \"messiest aspect of
operating system design\"? Using at least three distinct points, describe the evolution of I/O
controllers, and describe how their support for I/O has increased in complexity over time.
Solution
Dear Student.
Answer No-5a)
The above asked question is from the book \"Opererating System by william Stalling\" according
to the william stalling I/O management is the messiest aspect of an operating system.
Let\'s discuss this in detail.. how I/O management is the messiest aspect of an operating system?
There are wide variety of devices and their application. So it is very difficult to develop a generel
consistant common solution for every device.The devices which are engaged with I/O are
generally false in three different categories...
1-Human Readable- The human readable are the devices which are suitable for comuter user as
printers, video display, mouse and keyboard.These are all input/output devices.
2-Machine Readable- The devices which are suitable for communication with electronic devices
as disk drive, magnetic tapes and sensors and actuators.
3-Communication-The devices which are suitable for communicating with remote devices like a
Modem.
So above are the types of I/O devices, each device has their own functionality and design.Further
more every device has different data transfer rate, and different applications.
for example a disk used for file management requires support of file management
software.
Complexty in design is different in each device.Unit of data transfer may differ in each I/O
device.Some are programmed I/O devices and some devices are interrupt driven, some requires
DMA controller for data exchange between main memory and I/O module.Error conditions also
differ from one device to another, So this kind of diversity makes uniform and consistant
approach to I/O devices.
So by the above explanation it is clear that is I/O is the messiest aspect of an operating system.
Answer No-5b)
As the coputer system is evoled there has been a pattern of increasing complexity and
shopistication of each individual component.the evolutionarry steps in I/O controller are
described below...
The best example of I/O controller is DMA(Direct Memory Access).It controlles the data
transfer between memoy and I/O device.The evolution of I/O controller is as follows..
1- Previously processor directly controlled a peripheral device.Then a controller or I/O is added
for smooth and fast data transmission.
2-Then I/O controller given direct memory controll via DMA controllers.And now the DMA
controller can move a block of data without involving the processor.
3- Further I/O controller enhanced to become a seperate processor the central processing unit
direcly direct the I/O processor to execute an I/O program in memory.
So as the envolved continues in I/O Controller, more and more I/O functions is performed
without processor involvement.Thats is why the complexity h.
which is true of the data shown in the histogram Which is true of th.pdf
which is true of the data shown in the histogram Which is true of the data shown in the
histogram? The distribution is approximately symmetric. The mean and median arc
approximately equal. The median and IQR summarize the data better than the mean and
standard deviation. Click the icon to view the histogram.
Solution
A ) I and II.
What is the value of studying humanities in a business or technical .pdf
What is the value of studying humanities in a business or technical curriculum?
Solution
Having learned more about the myths and stories of Western civilization, I am understanding
more how study of the humanities (art, history, and literature) can be used to help people better
understand and communicate with one another. It is obvious that the study of humanities is not
just a college course, but it is an ongoing process and practice in life.
The humanities can first be used to understand the past which has created the present. The
culture which we have was shaped by the past. Facts, findings, and literature of even thousands
of years ago have influenced our world today. Knowing this past can allow people to understand
our present; knowing how we came to this present helps us to communicate about it and the
future.
The study of the humanities can also be used to realize differing interpretations of life and
history. Studying facts of the past helps to understand literature of the past. Art reflects the
cultures of the past, and shows how we achieved what we have today. For example, the Song of
Roland was very biased about the Saracens (Muslims). If one only studied literature, they would
have a totally skewed interpretation of who the Muslims were. By studying history though, we
know that the battle in this literature wasn\'t even against Muslims. Also by studying history and
religion we can see how Islam developed and what it really is. This is just one example of how
the comprehensive study of the humanities can be used to understand the world, and to
communicate fairly and intelligently with others in the world.
The humanities are not just part of the college\'s curriculum. The study of the humanities teaches
one how to study and look at how the past developed and how it has impacted today\'s world.
The humanities allows people of different cultures to communicate and understand their
sometimes common pasts but present differences. The humanities shows how different
disciplines affect and complement one another. Finally, the study of the humanities shows that
this study is ongoing and continual, constantly evolving and shaping.
Highly successful executives, entrepreneurs and policy makers offer words of wisdom about the
practical value of studying the humanities. “I think if you have a good background in what it is to
be human, an understanding of life, culture and society, it gives you a good perspective on
starting a business, instead of an education purely in business...You can always pick up how to
read a balance sheet and how to figure out profit and loss, but it\'s harder to pick up the other
stuff on the fly. ”
1. The humanities prepare you to fulfill your civic and cultural responsibilities.
The
reason that John Harvard left his library to the college in Cambridge,
Massachusetts, that Jane and Leland Stanford founded Stanford University, and
that states established land-grant colleges was to educate cultured and
useful citizens. T.
What are the two components of dynamic pressureVelocity and densi.pdf
What are the two components of dynamic pressure?
Velocity and density
Viscosity and velocity
Angle of attack and density
Lift and Drag
Solution
Dynamic pressure is a defined property of a moving flow of gas or liquid and can be expressed
as
pd = 1/2 v2 (1)
where
pd = dynamic pressure (Pa)
= density of fluid (kg/m3)
v = velocity (m/s)
so, according to this relation the two components of dynamic pressure areVelocity and density..
There are 40 students in our class. How many ways they can be lined .pdf
There are 40 students in our class. How many ways they can be lined up such that two fixed
students X and Y are next to each other (order of the two fixed students does not matter).
Solution
So now that X and Y are always beside each other, then you can treat them as just ONE
PERSON.
Thus, it\'s like there are now just 39 people to permute.
As n! = number of ways to permute n objects in a line, then the number of ways is
#ways = 39! = 2.03979*10^46 [ANSWER].
The Task For this assignment you will write a rudimentary text edi.pdf
The Task
For this assignment you will write a rudimentary text editor that allows the user to edit 5 lines of
text, where each line is no longer than 80 characters. The editor should allow the user to
continue editing as long as desired and should print the current state of the edit buffer after each
edit.
The editor is a \'line editor\' in that the user must edit one line at a time. The user can specify
which line should be edited by choosing a line number from a menu.
The only two editing operations possible are to replace an entire line with a new line, or to
replace a substring in the line with a new substring.
Musts
The program should not accept incorrect menu choices from the user. If the user creates a string
that is longer than 80 characters the string should be truncated to fit the 80 character limit. The
program should simply make no changes if the user tries to replace a substring that does not exist
in the string.
Your program must use functions. Some functions are required, but you may make other
functions as you see fit. You may not change the name, return type, or the parameter list types
for required functions.
Required Function One
int replaceInString(char[] original, char[] substring, char[] replace);
This function causes the original string to be modified such that the first occurrence of substring
is removed from the original string and the contents of replace are inserted in its place.
replaceInString calls findSubString and insertString. The function returns 0 if the operation
fails and 1 if the operation is successful.
Required Function Two:
int findSubString(char[] original, char[] toFind);
This function finds the first occurrence of toFind in original and returns an integer representing
the index of the first element of the toFind substring in original. For example if toFind was \'cat\'
and original was \'thundercat\' the function would return 7 since the begining of \'cat\' in
\'thundercat\' is position 7. If the function does not find a substring it should return -1
note: do not use existing substring functions such as strstr as a solution for this function. Solve
the algorithm yourself. You may use basic string functions such as strlen and strcat.
Required Function Three:
int insertString(char[] original, int start, int length, char[] toInsert);
This function replaces the contents of original with the following sequence of characters:
the characters from original up to position start-
the characters from toInsert
the characters from original starting at the character immediately after length.
Solution
#include
#include
#define ROW_LENTH 81
#define NUM_ROWS 5
void replaceLine(char line[]);
void printText(char text[][ROW_LENTH]);
int readFile(char filePath[], char text[][ROW_LENTH]);
int writeFile(char filePath[], char text[][ROW_LENTH]);
void removeTrailingHardReturn(char line[]);
void flushBuffer();
int getLine();
int replaceInString(char original[], char substring[], char replace[]);
int findSubString(char origina.
The SIP handles what functionsA.) establishes a call through the .pdf
The SIP handles what functions?
A.) establishes a call through the network.
B) tears down a call through the network
C) rings the phone
D) applies features to the line.
E) converts the IP signal into a G.711 flow.
F.) a, b, and c
G.) a and b
H.) a, b, c, and e
I.) all of the above
Solution
sip has main five functions: session initiation protocal
1. User location
2.User availibilty
3 User capabilities
4 session setup
5 session management
so sip provides five function it uses layered approach
sip used for real timetransport protocal .it is used for delivering voice and video over IPnetwork
This type of server does not store any information of a call transactios.
so sip has above questioN
answer is : (I )ALL OF THE ABOVE.
The NBA decides to look into the use of meldonium in the league foll.pdf
The NBA decides to look into the use of meldonium in the league following the same protocol as
the WADA. Which of the following will be randomly tested?urine samplesblood samplesskin
samplesplasma samples
Solution
Answer: According to WADA (World Anti-Doping Agency), the quantity of Meldonium or
Mildronate (trade-name) in athlete\'s/Patient\'s body used to measure from the urine samples.
NBA is going to follow the same protocol as WADA to estimate the Meldonium content. So, the
answer is \'Urine Samples\'..
The organelle that serves as the digestive system in the cell is the .pdf
The organelle that serves as the digestive system in the cell is the ____. polysome; endosome;
lysosome; ribosome; intestine.
Solution
LYSOSOME:
In the cell line: lysosome secretes thye lytic enzymes, and promotes the phagocytosis and digests
the unwanted materials like bacteria etc, leading to formation of phagolysosomes.
Therefore it can be called as the digestive system of the cell..
The major type of interactive forces between molecules of NH_3 are .pdf
The major type of interactive forces between molecules of NH_3 are: ionic covalent hydrogen
bonding dipole-dipole attractions dispersion forces
Solution
Answer 18: The major type of interactive force that lie between molecule of ammonia (NH3) are
covalent bond. The single Nitrogen atom in an ammonia molecule is bonded to three atoms of
Hydrogen through the sharing of three electron pairs, one with each atom of Hydrogen. Thus,
finally said that the ammonia molecule is formed by covalent bonding between one Nitrogen
atom and three Hydrogen atoms..
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https://app.box.com/s/tacvl9ekroe9hqupdnjruiypvm9rdaneMore Related Content
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Carbon dioxide (CO_2) is a non-polar molecule. Is this consistent wit.pdf
Carbon dioxide (CO_2) is a non-polar molecule. Is this consistent with your classification of the
C - O bond in #2 above? Why is CO_2 nonpolar?
Solution
In C-O the oxygen is more electronegative than carbon , so the shared electrons are more close to
oxygen make it more negative and carbon becomes more positive.The polarity is determined by
the difference in electronegativity, since electronegativity of oxygen is more here it makes C-O a
polar component.
But in Co2 the two oxygen lies linearly ie O=C=O
Since the two oxygen atoms lies in 180 degree angle their electronegativity cancel each other ,
doesn\'t make any effect on the electronegativity of carbon, so CO2 becomes non polar in nature..
Compare and contrast the messages about science and integrity in Fra.pdf
Compare and contrast the messages about science and integrity in Frankenstein and Dr. Jekyll
and Mr. Hyde. (You must discuss both science and integrity).
Solution
I find Dr. Jekyll\'s use of science to have at least a bit more integrity than Victor Frankenstein\'s.
Frankenstein dreams of being \"blessed\" by a race of men which he will have created and
\"hailed\" as something of a hero by them. He puts science to use in order to achieve personal
glory and fame, and because he acts without integrity, behaving selfishly and unethically, he
ruins many more lives than just his own.
Dr. Jekyll, on the other hand, doesn\'t exploit science in order to achieve fame. In essence, he
succumbs to Victorian societal pressure to conform to an incredibly repressive moral code. His
intention is to better himself by making it easier for him to always do the right thing, as defined
by his society. Despite the problems we might find with his rationale (if we take issue with his
attempt to rid himself of a fundamental part of being human), his intentions, I would argue, are
less self-serving than Frankenstein\'s. Jekyll is actually attempting to change himself in order to
better fit the (unreasonable) demands of his society, and so his use of science smacks more
clearly of integrity than does Frankenstein\'s. He shows that it is possible to put science to use in
a more ethical way than Shelley\'s \"hero.\".
Briely, what was Darwins explanation for the appearance of design.pdf
Briely, what was Darwin\'s explanation for the appearance of design? How does it explain the
appearance of design? (please answer this in short) thank you
Solution
Darwin\'s explanation for the appearance of design:
Darwin discovered natural selection; it is a critical phenomenon that reveals the secret behind the
“design” of organisms. It explains the orderly process of origin, complexity, adaptation and
diversity of organisms by natural laws.
According to Darwin\'s design the creative power behind of evolution are arisen due to the
interaction among chance & necessity and between the natural selection & random mutations.
Darwin\'s The Origin of Species book was published in 1859. In this he mainly explains how the
evolution is demonstrating by natural selection.
Three main aspects of evolution theory:
1. Evolution: Descent of living things with modification.
2. Evolutionary history: The reconstruction of the universal tree of life (Thesis of common
ancestry).
3. Darwinism: The mechanism behind the evolutionary change is natural selection operating on
random variations in living things.
Darwin\'snatural selection evidences:
The beaks of Darwin finches. The finches of the Galapagos Islands were adapted to the island in
different ways, but are believed to share a common ancestor..
A router receives a message addressed 172.16.15.75. The relevant rou.pdf
A router receives a message addressed 172.16.15.75. The relevant routing table entries are
172.16.0.0 /20 – Serial 0, 172.16.0.0 /23 – Ethernet 0, and 172.16.15.64 /26 – Ethernet 1. Which
interface will the router forward the packet to?
A. Serial 0.
B. Serial 1.
C. Ethernet 0.
D. Ethernet 1.
E. None of the above. The packet will be dropped.
Solution
When message is passed through router the address wont alter, So in router, the address is
matching with router table. So this message wont pass and packet will be dropped.
So correct option is E. None of the above. The packet will be dropped..
A study of sandflies in Panama classified flies caught in light traps.pdf
A study of sandflies in Panama classified flies caught in light traps by sex (male, female) and
height of trap (3 and 35 feet above ground), resulting in the following 2 Times 2 contingency
table:^8 Do these data provide evidence that the sex ratio of Panamanian sandflies varies with
height above ground?
Solution.
___Tissue found in the brain, spinal cord, and peripheral nerves. The.pdf
___Tissue found in the brain, spinal cord, and peripheral nerves. The basic cells are the___
Types of Membranes ___ membranes (3 types are A. ___ line the body cavities that do not open
to the outside, reducing friction between organs and cavity walls, and secrete serous fluid, B. ___
line the cavities of epithelial and underlying connective tissues.) Some membranes are
composed entirely of connected tissue include ___ and___
Solution
The epithelial cells are the outermost cells. They have nerve supply but no blood supply. These
cells receive nutrition from substances diffusing from the underlying blood vessels.Below the
epithelial cells is the basement membrane which provides nutrition and new epithelial cells arise
from the basement membrane..
You have been exposed to each of the 8 microbes below. One of them h.pdf
You have been exposed to each of the 8 microbes below. One of them has infected you and is
causing the symptom of Fever. Given this symptom, select all of the likely causative agents.
Helicobacter pylori
Yellow Fever virus
Aliivibrio fischeri
Rhizobium spp.
Epstein Barr Virus
Rickettsia rickettsii
Burkholderia mallei
Klebsiella pneumoniae
Helicobacter pylori
Yellow Fever virus
Aliivibrio fischeri
Rhizobium spp.
Epstein Barr Virus
Rickettsia rickettsii
Burkholderia mallei
Klebsiella pneumoniae
Solution
Yellow Fever virus symptoms include fever, chills, loss of appetite, nausea, muscle pains
particularly in the back, and headaches. This disease is spread by the bite of female mosquito..
Write a snippet of C code that will enable the ADC to continuously r.pdf
Write a snippet of C code that will enable the ADC to continuously run as fast as possible and
cause an interrupt after every conversion. Write only the initialization code using atmega328p?
Solution
#include
#include
ISR(ADC_vect)
{
PORTD = ADCL; // give the low byte to PORTD
PORTB = ADCH; // give the high byte to PORTB
ADCSRA | =(1<.
Write a JAVA LinkedListRec class that has the following methods siz.pdf
Write a JAVA LinkedListRec class that has the following methods: size, empty, insertBefore,
insertAfter, addAtHead, addAtEnd, remove, replace, peekFront, peekEnd, removeFront,
removeEnd, toString. Use recursion to implement most of these methods. Write a driver to test
your implemented LinkedListRec class methods.
Solution
import java.util.Scanner;
public class LinkedListRec {
int data;
LinkedListRec prev=null,next=null;
int size(LinkedListRec l)//method which returns the length of the list
{
if(l==null)return 0;
return 1+size(l.next);
}
boolean empty(LinkedListRec l)//method checks whether the list is empty or not...
{
if(l==null)return true;
else return false;
}
LinkedListRec insertBefore(LinkedListRec l,int value,int num_insertbefore)//method which
adds a new number before the given number..
{
if(l==null)return l;
if(l.data == num_insertbefore)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.prev==null)
{
n.next = l;
l=n;
}
else
{
n.prev = l.prev;
n.next= l;
l.prev = n;
}
return l;
}
return insertBefore(l.next,value,num_insertbefore);
}
LinkedListRec insertAfter(LinkedListRec l,int value,int num_insertafter)//method which adds
the new number after the given number
{
if(l==null)return l;
if(l.data == num_insertafter)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.next==null)
{
l.next = n;
n.prev = l;
}
else
{
n.next = l.next;
l.next.prev = n;
n.prev = l;
}
return l;
}
return insertAfter(l.next,value,num_insertafter);
}
LinkedListRec addAtHead(LinkedListRec l,int value)//method which adds a new number at
the head position of the list...
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.next = l;
l=n;
return l;
}
LinkedListRec addAtEnd(LinkedListRec l,int value)//method which adds a new number at
the end position of the list...
{
if(l==null){ l = new LinkedListRec();l.data = value;return l;}
if(l.next==null)
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.prev = l;
l.next = n;
return l;
}
return addAtEnd(l.next,value);
}
LinkedListRec remove(LinkedListRec l,int value)//method which removes given numbet
from the list....
{
if(l==null)return l;
if(l.data == value)
{
if(l.prev!=null){
l.prev = l.next;
}
else
l=l.next;
return l;
}
return remove(l.next,value);
}
boolean replace(LinkedListRec l,int value,int newvalue)//method which replaces current
number with new number,...
{
if(l==null)return false;
if(l.data == value)
{
l.data = newvalue;
return true;
}
return replace(l.next,value,newvalue);
}
int peekFront(LinkedListRec l)//method which returns the first value of the list...
{
if(l!=null)
return l.data;
else return -1;
}
int peekEnd(LinkedListRec l)//method which returns the last value of the list........
{
if(l==null)return -1;
if(l.next == null)return l.data;
return peekEnd(l.next);
}
LinkedListRec removeFront(LinkedListRec l)//method which removes the first element of the
list..
{
if(l==null)return l;
l=l.next;
return l;
}
boolean removeEnd(LinkedListRec l)//method which removes the last element o.
Write a BFS algorithm using only arrays and no other data structure..pdf
Write a BFS algorithm using only arrays and no other data structure.
Solution
#include
#include
#include //For boolean
char que[20];
int front=0, rear=0, n;
char arr[20];
int bfs(int );
char ajMat[20][20];
char b[20];
void display();
int p=0;
int main()
{
char v;
int i, j;
printf(\"Enter the number of nodes in a graph\");
scanf(\"%d\",&n);
printf(\"Enter the value of node of graph\");
for( i=0; i.
Why has one prominent textbook author described IO management as the.pdf
Why has one prominent textbook author described I/O management as the \"messiest aspect of
operating system design\"? Using at least three distinct points, describe the evolution of I/O
controllers, and describe how their support for I/O has increased in complexity over time.
Solution
Dear Student.
Answer No-5a)
The above asked question is from the book \"Opererating System by william Stalling\" according
to the william stalling I/O management is the messiest aspect of an operating system.
Let\'s discuss this in detail.. how I/O management is the messiest aspect of an operating system?
There are wide variety of devices and their application. So it is very difficult to develop a generel
consistant common solution for every device.The devices which are engaged with I/O are
generally false in three different categories...
1-Human Readable- The human readable are the devices which are suitable for comuter user as
printers, video display, mouse and keyboard.These are all input/output devices.
2-Machine Readable- The devices which are suitable for communication with electronic devices
as disk drive, magnetic tapes and sensors and actuators.
3-Communication-The devices which are suitable for communicating with remote devices like a
Modem.
So above are the types of I/O devices, each device has their own functionality and design.Further
more every device has different data transfer rate, and different applications.
for example a disk used for file management requires support of file management
software.
Complexty in design is different in each device.Unit of data transfer may differ in each I/O
device.Some are programmed I/O devices and some devices are interrupt driven, some requires
DMA controller for data exchange between main memory and I/O module.Error conditions also
differ from one device to another, So this kind of diversity makes uniform and consistant
approach to I/O devices.
So by the above explanation it is clear that is I/O is the messiest aspect of an operating system.
Answer No-5b)
As the coputer system is evoled there has been a pattern of increasing complexity and
shopistication of each individual component.the evolutionarry steps in I/O controller are
described below...
The best example of I/O controller is DMA(Direct Memory Access).It controlles the data
transfer between memoy and I/O device.The evolution of I/O controller is as follows..
1- Previously processor directly controlled a peripheral device.Then a controller or I/O is added
for smooth and fast data transmission.
2-Then I/O controller given direct memory controll via DMA controllers.And now the DMA
controller can move a block of data without involving the processor.
3- Further I/O controller enhanced to become a seperate processor the central processing unit
direcly direct the I/O processor to execute an I/O program in memory.
So as the envolved continues in I/O Controller, more and more I/O functions is performed
without processor involvement.Thats is why the complexity h.
which is true of the data shown in the histogram Which is true of th.pdf
which is true of the data shown in the histogram Which is true of the data shown in the
histogram? The distribution is approximately symmetric. The mean and median arc
approximately equal. The median and IQR summarize the data better than the mean and
standard deviation. Click the icon to view the histogram.
Solution
A ) I and II.
What is the value of studying humanities in a business or technical .pdf
What is the value of studying humanities in a business or technical curriculum?
Solution
Having learned more about the myths and stories of Western civilization, I am understanding
more how study of the humanities (art, history, and literature) can be used to help people better
understand and communicate with one another. It is obvious that the study of humanities is not
just a college course, but it is an ongoing process and practice in life.
The humanities can first be used to understand the past which has created the present. The
culture which we have was shaped by the past. Facts, findings, and literature of even thousands
of years ago have influenced our world today. Knowing this past can allow people to understand
our present; knowing how we came to this present helps us to communicate about it and the
future.
The study of the humanities can also be used to realize differing interpretations of life and
history. Studying facts of the past helps to understand literature of the past. Art reflects the
cultures of the past, and shows how we achieved what we have today. For example, the Song of
Roland was very biased about the Saracens (Muslims). If one only studied literature, they would
have a totally skewed interpretation of who the Muslims were. By studying history though, we
know that the battle in this literature wasn\'t even against Muslims. Also by studying history and
religion we can see how Islam developed and what it really is. This is just one example of how
the comprehensive study of the humanities can be used to understand the world, and to
communicate fairly and intelligently with others in the world.
The humanities are not just part of the college\'s curriculum. The study of the humanities teaches
one how to study and look at how the past developed and how it has impacted today\'s world.
The humanities allows people of different cultures to communicate and understand their
sometimes common pasts but present differences. The humanities shows how different
disciplines affect and complement one another. Finally, the study of the humanities shows that
this study is ongoing and continual, constantly evolving and shaping.
Highly successful executives, entrepreneurs and policy makers offer words of wisdom about the
practical value of studying the humanities. “I think if you have a good background in what it is to
be human, an understanding of life, culture and society, it gives you a good perspective on
starting a business, instead of an education purely in business...You can always pick up how to
read a balance sheet and how to figure out profit and loss, but it\'s harder to pick up the other
stuff on the fly. ”
1. The humanities prepare you to fulfill your civic and cultural responsibilities.
The
reason that John Harvard left his library to the college in Cambridge,
Massachusetts, that Jane and Leland Stanford founded Stanford University, and
that states established land-grant colleges was to educate cultured and
useful citizens. T.
What are the two components of dynamic pressureVelocity and densi.pdf
What are the two components of dynamic pressure?
Velocity and density
Viscosity and velocity
Angle of attack and density
Lift and Drag
Solution
Dynamic pressure is a defined property of a moving flow of gas or liquid and can be expressed
as
pd = 1/2 v2 (1)
where
pd = dynamic pressure (Pa)
= density of fluid (kg/m3)
v = velocity (m/s)
so, according to this relation the two components of dynamic pressure areVelocity and density..
There are 40 students in our class. How many ways they can be lined .pdf
There are 40 students in our class. How many ways they can be lined up such that two fixed
students X and Y are next to each other (order of the two fixed students does not matter).
Solution
So now that X and Y are always beside each other, then you can treat them as just ONE
PERSON.
Thus, it\'s like there are now just 39 people to permute.
As n! = number of ways to permute n objects in a line, then the number of ways is
#ways = 39! = 2.03979*10^46 [ANSWER].
The Task For this assignment you will write a rudimentary text edi.pdf
The Task
For this assignment you will write a rudimentary text editor that allows the user to edit 5 lines of
text, where each line is no longer than 80 characters. The editor should allow the user to
continue editing as long as desired and should print the current state of the edit buffer after each
edit.
The editor is a \'line editor\' in that the user must edit one line at a time. The user can specify
which line should be edited by choosing a line number from a menu.
The only two editing operations possible are to replace an entire line with a new line, or to
replace a substring in the line with a new substring.
Musts
The program should not accept incorrect menu choices from the user. If the user creates a string
that is longer than 80 characters the string should be truncated to fit the 80 character limit. The
program should simply make no changes if the user tries to replace a substring that does not exist
in the string.
Your program must use functions. Some functions are required, but you may make other
functions as you see fit. You may not change the name, return type, or the parameter list types
for required functions.
Required Function One
int replaceInString(char[] original, char[] substring, char[] replace);
This function causes the original string to be modified such that the first occurrence of substring
is removed from the original string and the contents of replace are inserted in its place.
replaceInString calls findSubString and insertString. The function returns 0 if the operation
fails and 1 if the operation is successful.
Required Function Two:
int findSubString(char[] original, char[] toFind);
This function finds the first occurrence of toFind in original and returns an integer representing
the index of the first element of the toFind substring in original. For example if toFind was \'cat\'
and original was \'thundercat\' the function would return 7 since the begining of \'cat\' in
\'thundercat\' is position 7. If the function does not find a substring it should return -1
note: do not use existing substring functions such as strstr as a solution for this function. Solve
the algorithm yourself. You may use basic string functions such as strlen and strcat.
Required Function Three:
int insertString(char[] original, int start, int length, char[] toInsert);
This function replaces the contents of original with the following sequence of characters:
the characters from original up to position start-
the characters from toInsert
the characters from original starting at the character immediately after length.
Solution
#include
#include
#define ROW_LENTH 81
#define NUM_ROWS 5
void replaceLine(char line[]);
void printText(char text[][ROW_LENTH]);
int readFile(char filePath[], char text[][ROW_LENTH]);
int writeFile(char filePath[], char text[][ROW_LENTH]);
void removeTrailingHardReturn(char line[]);
void flushBuffer();
int getLine();
int replaceInString(char original[], char substring[], char replace[]);
int findSubString(char origina.
The SIP handles what functionsA.) establishes a call through the .pdf
The SIP handles what functions?
A.) establishes a call through the network.
B) tears down a call through the network
C) rings the phone
D) applies features to the line.
E) converts the IP signal into a G.711 flow.
F.) a, b, and c
G.) a and b
H.) a, b, c, and e
I.) all of the above
Solution
sip has main five functions: session initiation protocal
1. User location
2.User availibilty
3 User capabilities
4 session setup
5 session management
so sip provides five function it uses layered approach
sip used for real timetransport protocal .it is used for delivering voice and video over IPnetwork
This type of server does not store any information of a call transactios.
so sip has above questioN
answer is : (I )ALL OF THE ABOVE.
The NBA decides to look into the use of meldonium in the league foll.pdf
The NBA decides to look into the use of meldonium in the league following the same protocol as
the WADA. Which of the following will be randomly tested?urine samplesblood samplesskin
samplesplasma samples
Solution
Answer: According to WADA (World Anti-Doping Agency), the quantity of Meldonium or
Mildronate (trade-name) in athlete\'s/Patient\'s body used to measure from the urine samples.
NBA is going to follow the same protocol as WADA to estimate the Meldonium content. So, the
answer is \'Urine Samples\'..
The organelle that serves as the digestive system in the cell is the .pdf
The organelle that serves as the digestive system in the cell is the ____. polysome; endosome;
lysosome; ribosome; intestine.
Solution
LYSOSOME:
In the cell line: lysosome secretes thye lytic enzymes, and promotes the phagocytosis and digests
the unwanted materials like bacteria etc, leading to formation of phagolysosomes.
Therefore it can be called as the digestive system of the cell..
The major type of interactive forces between molecules of NH_3 are .pdf
The major type of interactive forces between molecules of NH_3 are: ionic covalent hydrogen
bonding dipole-dipole attractions dispersion forces
Solution
Answer 18: The major type of interactive force that lie between molecule of ammonia (NH3) are
covalent bond. The single Nitrogen atom in an ammonia molecule is bonded to three atoms of
Hydrogen through the sharing of three electron pairs, one with each atom of Hydrogen. Thus,
finally said that the ammonia molecule is formed by covalent bonding between one Nitrogen
atom and three Hydrogen atoms..
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Compare and contrast the messages about science and integrity in Fra.pdf
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USING JAVAImplement the quicksort optimization median-of-three, i.pdf
- 1. USING JAVA: Implement the quicksort optimization median-of-three, i.e., first, middle, and last, as pivot for partition. Into this working quicksort algorithm: ( the spacing is bad, sorry) private static void quicksort(int low, int high) { int i = low, j = high; // Get the pivot element from the middle of the list int pivot = arr[(high+low)/2]; // Divide into two lists while (i <= j) { // If the current value from the left list is smaller then the pivot // element then get the next element from the left list while (arr[i] < pivot) i++; // If the current value from the right list is larger then the pivot // element then get the next element from the right list while (arr[j] > pivot) j--; // If we have found a value in the left list which is larger than // the pivot element and if we have found a value in the right list // which is smaller then the pivot element then we exchange the // values. // As we are done we can increase i and j if (i < j) { exchange(i, j); i++; j--; } else if (i == j) { i++; j--; } } // Recursion if (low < j) quicksort(low, j); if (i < high) quicksort(i, high); } Solution
- 2. Hi, Please find my program: private static void quicksort(int low, int high) { if (low >= high) return; // Selecting the pivot int first = low; int second = arr[(high+low)/2]; int third = arr[high]; // median for first three int pivot = Math.max( Math.min( array[first], array[second]), Math.min( Math.max( array[first], array[second] ), array[third] ) ); while (low <= high) { while (array[low] < pivot) { low++; } while (array[high] > pivot) { high--; } if (low <= high) { // swapping int temp = array[low];
- 3. array[low] = array[high]; array[high] = temp; low++; high--; } } // Recursion if (low < j) quicksort(low, j); if (i < high) quicksort(i, high); }