Introduction to Convolutional Codes
Convolutional Encoder Structure
Convolutional Encoder Representation(Vector, Polynomial, State Diagram and Trellis Representations )
Maximum Likelihood Decoder
Viterbi Algorithm
MATLAB Simulation
Hard and Soft Decisions
Bit Error Rate Tradeoff
Consumed Time Tradeoff
Std 10 chapter 11 data type, expression and operators important MCQsNuzhat Memon
Std 10 chapter 11 data type, expression and operators important MCQsby Nuzhat Memon
std 10 english medium Computer
Computer std 10 Chapter 10 Important MCQs
std 10 computer important questions
std 10 computer chapter 11 mcq english medium
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Introduction to Convolutional Codes
Convolutional Encoder Structure
Convolutional Encoder Representation(Vector, Polynomial, State Diagram and Trellis Representations )
Maximum Likelihood Decoder
Viterbi Algorithm
MATLAB Simulation
Hard and Soft Decisions
Bit Error Rate Tradeoff
Consumed Time Tradeoff
Std 10 chapter 11 data type, expression and operators important MCQsNuzhat Memon
Std 10 chapter 11 data type, expression and operators important MCQsby Nuzhat Memon
std 10 english medium Computer
Computer std 10 Chapter 10 Important MCQs
std 10 computer important questions
std 10 computer chapter 11 mcq english medium
For further details, please pay a visit at:
http://www.assignmentpedia.com/econometrics-homework-assignment-help.html
We also have an exclusive website for our Econometrics Asignment Help:
http://www.statisticsassignmentexperts.com/econometrics-assignment-help.html
Do have a look for Online Economics Help, Economics Assignment Tutor, Econometrics Assignment Help, Econometrics Homework Help, Econometrics Solutions using softwares like SPSS, R, STATA, SAS, Minitab, Excel.
stackconf 2022: Are all programming languages in english?NETWAYS
After some time searching for the best programming language for my projects, I wondered: is there a programming language that does not use any English keyword? Of course, the short answer is no, but where do all the other non-English-based programming languages hide? How did we end up using that idiom for writing code? Let’s explore these questions during this talk!
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The slides from the C++ and OOPS Crash Course conducted for ACM DBIT by Grejo Joby.
Learn the concepts of OOPS and C++ Programming in the shortest time with these notes.
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Excellence Academy Is The Renowned & Best Python Training Institute In Chandigarh That Provides 100% Job-Oriented .Python Training Institute In Mohali Our Course Is Designed Especially For Students, Housewives & Other Who Are Looking For Python Training In Chandigarh.
Excellence Academy Is The Renowned & Best Python Training Institute In Chandigarh That Provides 100% Job-Oriented .Python Training Institute In Mohali Our Course Is Designed Especially For Students, Housewives & Other Who Are Looking For Python Training In Chandigarh.
20145-5SumII_CSC407_assign1.htmlCSC 407 Computer Systems II.docxeugeniadean34240
20145-5SumII_CSC407_assign1.html
CSC 407: Computer Systems II: 2015 Summer II, Assignment #1
Last Modified 2015 July 21Purpose:
To go over issues related to how the compiler and the linker
serve you, the programmer.
Computing
Please ssh into ctilinux1.cstcis.cti.depaul.edu, or use your own Linux machine.
Compiler optimization (45 Points)
Consider the following program.
/* q1.c
*/
#include <stdlib.h>
#include <stdio.h>
#define unsigned int uint
#define LENGTH ((uint) 512*64)
int initializeArray (uint len,
int* intArray
)
{
uint i;
for (i = 0; i < len; i++)
intArray[i] = (rand() % 64);
}
uint countAdjacent (int maxIndex,
int* intArray,
int direction
)
{
uint i;
uint sum = 0;
for (i = 0; i < maxIndex; i++)
if ( ( intArray[i] == (intArray[i+1] + direction) ) &&
( intArray[i] == (intArray[i+2] + 2*direction) )
)
sum++;
return(sum);
}
uint funkyFunction (uint len,
int* intArray
)
{
uint i;
uint sum = 0;
for (i = 0; i < len-1; i++)
if ( (i % 8) == 0x3 )
sum += 7*countAdjacent(len-2,intArray,+1);
else
sum += 17*countAdjacent(len-2,intArray,-1);
return(sum);
}
int main ()
{
int* intArray = (int*)calloc(LENGTH,sizeof(int));
initializeArray(LENGTH,intArray);
printf("funkyFunction() == %d\n",funkyFunction(LENGTH,intArray));
free(intArray);
return(EXIT_SUCCESS);
}
(8 Points) Compile it for profiling but with no extra optimization with:
$ gcc -o q1None -pg q1.c # Compiles q1.c to write q1None to make profile info
$ ./q1None # Runs q1None
$ gprof q1None # Gives profile info on q1None
Be sure to scroll all the way to the top of gprof output!
What are the number of self seconds taken by:
FunctionSelf secondsinitializeBigArray()__________countAdjaceent()__________funkyFunction()__________
(8 Points)
How did it do the operation (i % 8) == 0x3?
Was it done as a modulus (the same as an expensive division, but returns the remainder instead of the quotient) or something else?
Show the assembly language for this C code
using gdb to dissassemble
funkyFunction() of q1None.
Hint: do:
$ gdb q1None
. . .
(gdb) disass funkyFunction
Dump of assembler code for function funkyFunction:
. . .
and then look for the code that sets up the calls to countAdjacent().
The (i % 8) == 0x3 test is done before either countAdjacent() call.
(8 Points) Compile it for profiling but with optimization with:
$ gcc -o q1Compiler -O1 -pg q1.c # Compiles q1.c to write q1Compiler to make profile info
$ ./q1Compiler # Runs q1Compiler
$ gprof q1Compiler # Gives profile info on q1Compiler
What are the number of self seconds taken by:
FunctionSelf secondsinitializeBigArray()__________countAdjacent()__________funkyFunction()__________(8 Points) Use gdb to dissassemble countAdjacent() of both q1None and q1.
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After some time searching for the best programming language for my projects, I wondered: is there a programming language that does not use any English keyword? Of course, the short answer is no, but where do all the other non-English-based programming languages hide? How did we end up using that idiom for writing code? Let’s explore these questions during this talk!
C++ and OOPS Crash Course by ACM DBIT | Grejo JobyGrejoJoby1
The slides from the C++ and OOPS Crash Course conducted for ACM DBIT by Grejo Joby.
Learn the concepts of OOPS and C++ Programming in the shortest time with these notes.
Computer Project For Class XII Topic - The Snake Game Pritam Samanta
This was a group project but it was completely made by me. The program is fully working. There are no bugs. This will not work in OLD C++ COMPILERS namely turbo-c++,etc., but it will work in latest ANSI COMPLIERS namely Dev-c++, Code-blocks, ellipse, etc. If any one has any suggestion for correction or improvement please contact: appleball@inbound.plus. Every suggestions are valuable. Feel free to share this with your friends to share the happiness.
Excellence Academy Is The Renowned & Best Python Training Institute In Chandigarh That Provides 100% Job-Oriented .Python Training Institute In Mohali Our Course Is Designed Especially For Students, Housewives & Other Who Are Looking For Python Training In Chandigarh.
Excellence Academy Is The Renowned & Best Python Training Institute In Chandigarh That Provides 100% Job-Oriented .Python Training Institute In Mohali Our Course Is Designed Especially For Students, Housewives & Other Who Are Looking For Python Training In Chandigarh.
20145-5SumII_CSC407_assign1.htmlCSC 407 Computer Systems II.docxeugeniadean34240
20145-5SumII_CSC407_assign1.html
CSC 407: Computer Systems II: 2015 Summer II, Assignment #1
Last Modified 2015 July 21Purpose:
To go over issues related to how the compiler and the linker
serve you, the programmer.
Computing
Please ssh into ctilinux1.cstcis.cti.depaul.edu, or use your own Linux machine.
Compiler optimization (45 Points)
Consider the following program.
/* q1.c
*/
#include <stdlib.h>
#include <stdio.h>
#define unsigned int uint
#define LENGTH ((uint) 512*64)
int initializeArray (uint len,
int* intArray
)
{
uint i;
for (i = 0; i < len; i++)
intArray[i] = (rand() % 64);
}
uint countAdjacent (int maxIndex,
int* intArray,
int direction
)
{
uint i;
uint sum = 0;
for (i = 0; i < maxIndex; i++)
if ( ( intArray[i] == (intArray[i+1] + direction) ) &&
( intArray[i] == (intArray[i+2] + 2*direction) )
)
sum++;
return(sum);
}
uint funkyFunction (uint len,
int* intArray
)
{
uint i;
uint sum = 0;
for (i = 0; i < len-1; i++)
if ( (i % 8) == 0x3 )
sum += 7*countAdjacent(len-2,intArray,+1);
else
sum += 17*countAdjacent(len-2,intArray,-1);
return(sum);
}
int main ()
{
int* intArray = (int*)calloc(LENGTH,sizeof(int));
initializeArray(LENGTH,intArray);
printf("funkyFunction() == %d\n",funkyFunction(LENGTH,intArray));
free(intArray);
return(EXIT_SUCCESS);
}
(8 Points) Compile it for profiling but with no extra optimization with:
$ gcc -o q1None -pg q1.c # Compiles q1.c to write q1None to make profile info
$ ./q1None # Runs q1None
$ gprof q1None # Gives profile info on q1None
Be sure to scroll all the way to the top of gprof output!
What are the number of self seconds taken by:
FunctionSelf secondsinitializeBigArray()__________countAdjaceent()__________funkyFunction()__________
(8 Points)
How did it do the operation (i % 8) == 0x3?
Was it done as a modulus (the same as an expensive division, but returns the remainder instead of the quotient) or something else?
Show the assembly language for this C code
using gdb to dissassemble
funkyFunction() of q1None.
Hint: do:
$ gdb q1None
. . .
(gdb) disass funkyFunction
Dump of assembler code for function funkyFunction:
. . .
and then look for the code that sets up the calls to countAdjacent().
The (i % 8) == 0x3 test is done before either countAdjacent() call.
(8 Points) Compile it for profiling but with optimization with:
$ gcc -o q1Compiler -O1 -pg q1.c # Compiles q1.c to write q1Compiler to make profile info
$ ./q1Compiler # Runs q1Compiler
$ gprof q1Compiler # Gives profile info on q1Compiler
What are the number of self seconds taken by:
FunctionSelf secondsinitializeBigArray()__________countAdjacent()__________funkyFunction()__________(8 Points) Use gdb to dissassemble countAdjacent() of both q1None and q1.
Intel IPP Samples for Windows - error correctionPVS-Studio
This is one of my posts on how PVS-Studio makes programs safer. That is where and what types of errors it detects. This time it is samples demonstrating handling of the IPP 7.0 library (Intel Performance Primitives Library) we are going to examine.
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This is one of my posts on how PVS-Studio makes programs safer. That is where and what types of errors it detects. This time it is samples demonstrating handling of the IPP 7.0 library (Intel Performance Primitives Library) we are going to examine.
For further details, do visit our page:
http://www.assignmentpedia.com/computer-networking-assignment-help.html
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Impact of Ethnobotany in traditional medicine,
New development in herbals,
Bio-prospecting tools for drug discovery,
Role of Ethnopharmacology in drug evaluation,
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Video Codec
1. VIDEO CODEC USING MATLAB
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H.264 BASELINE CODEC V2
This sample assignment shows slightly updated version 2 of H.264 baseline codec.
dec_cavlc(bits,nL,nU)
function [data,i] = dec_cavlc(bits,nL,nU)
%% CAVLC Decoder
% By A. A. Muhit
% It takes bitstream and decodes 4x4 block of data
% Load the table containing all the tables
% load table.mat;
global Table_coeff0 Table_coeff1 Table_coeff2 Table_coeff3
global Table_run Table_zeros
% test data
% bits =
'00000000001000101000000011001011111001011101010000000010000111111111111111001110';
% nL = 0;
% nU = 0;
% find n parameter (context adaptive)
if (nL>0)&(nU>0)
n = (nL + nU)/2;
elseif (nL>0)|(nU>0)
n = nL + nU;
else
n = 0;
end
% Coeff_token mapping
% Rows are the total coefficient(0-16) and columns are the trailing ones(0-3)
% TABLE_COEFF0,1,2,3 ARE STORED IN TABLE.MAT OR CAVLC_TABLES.M FILE
% Choose proper Table_coeff based on n value
if 0<=n<2
Table_coeff = Table_coeff0;
elseif 2<=n<4
2. Table_coeff = Table_coeff1;
elseif 4<=n<8
Table_coeff = Table_coeff2;
elseif 8<=n
Table_coeff = Table_coeff3;
end
i = 1;
coeff_token = '';
% Find total coefficients and trailing ones
while (i<=length(bits))
coeff_token = [coeff_token bits(i)];
x = strcmp(Table_coeff,coeff_token);
[r,c]=find(x==1);
i = i + 1;
if (r>0)&(c>0)
break;
end
end
% Find total coefficients and trailing ones
i_total = r - 1;
i_trailing = c - 1;
% if no coefficients return 4x4 empty blocks of data
if i_total==0
data = zeros(4,4);
return;
end
k = 1;
m = i_trailing;
while m>0
if bits(i)=='0'
level(k)=1;
elseif bits(i)=='1'
level(k)=-1;
end
k = k + 1;
m = m - 1;
i = i + 1;
end
%% Decode the non-zero coefficient/level values
if (i_total>10)&(i_trailing<3)
i_sufx_len = 1;
3. else
i_sufx_len = 0;
end
while k<=i_total
% Decode level prefix
[level_prfx,i]= dec_prfx(bits,i);
% Decode level suffix
level_sufx_size = 0;
if (i_sufx_len>0)||(level_prfx>=14)
if (level_prfx==14)&(i_sufx_len==0)
level_sufx_size = 4;
elseif level_prfx>=15
level_sufx_size = level_prfx - 3;
else
level_sufx_size = i_sufx_len;
end
end
if level_sufx_size==0
level_sufx = 0;
else
sufx = bits(i : i + level_sufx_size -1);
level_sufx = bin2dec(sufx);
i = i + level_sufx_size;
end
i_level_code = bitshift(min(15,level_prfx),i_sufx_len) + level_sufx;
if (level_prfx>=15)&(i_sufx_len==0)
i_level_code = i_level_code + 15;
end
if level_prfx>=16
i_level_code = i_level_code + (bitshift(1,level_prfx - 3) - 4096);
end
if (k == i_trailing + 1)&(i_trailing<3)
i_level_code = i_level_code + 2;
end
if rem(i_level_code,2)==0 % i_level_code is even
level(k) = bitshift(i_level_code + 2,-1);
else % odd number
level(k) = bitshift(-i_level_code - 1, -1);
end
if i_sufx_len==0
4. i_sufx_len = 1;
end
if ((abs(level(k)))>bitshift(3,i_sufx_len - 1))&(i_sufx_len<6)
i_sufx_len = i_sufx_len + 1;
end
k = k + 1;
end
%% Decode total zeros
s='';
i_total_zero = 0;
if i_total==16
i_zero_left = 0;
else
while (i<=length(bits))
s = [s bits(i)];
x = strcmp(Table_zeros(i_total,:),s);
r = find(x==1);
i = i + 1;
if r>0
i_total_zero = r-1;
break;
end
end
end
%% Decode run information
i_zero_left = i_total_zero;
j=1;
ss = '';
run = zeros(1,length(level));
while i_zero_left>0
while (j<i_total)&(i_zero_left>0)
ss = [ss bits(i)];
i_zl = min(i_zero_left,7);
x = strcmp(Table_run(:,i_zl),ss);
r = find(x==1);
i = i + 1;
if r>0
run(j)=r-1;
i_zero_left = i_zero_left - run(j);
j = j + 1;
5. ss = '';
end
end
if i_zero_left>0
run(j)=i_zero_left;
i_zero_left = 0;
end
end
%% Combine level and run information
k = i_total + i_total_zero;
l = zeros(1,16);
while k>0
for j=1:length(level)
l(k)=level(j);
k = k - 1;
k = k - run(j);
end
end
%% Reorder the data into 4x4 block
scan = [1,1;1,2;2,1;3,1;2,2;1,3;1,4;2,3;3,2;4,1;4,2;3,3;2,4;3,4;4,3;4,4];
for k=16:-1:1
m=scan(k,1);
n=scan(k,2);
data(m,n)=l(k); % l contains the reordered data
end
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