Use the given discrete probability distribution for the number of head.pdf
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Use the given discrete probability distribution for the number of heads in 4 flips. Sample Data Calculate the probabilities A. P ( 2 ) B. P ( less than 2) C. P (at least 2 ) D. P ( 0 x 3 ).
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#define DOUBLYLIST_H
#include <string>
#include <iostream>
class DLLNode
{
public:
DLLNode() : data(0), prev(nullptr), next(nullptr) {}
DLLNode(int theData, DLLNode* prevLink, DLLNode* nextLink)
: data(theData), prev(prevLink), next(nextLink) {}
int getData() const { return data; }
DLLNode* getPrev() const { return prev; }
DLLNode* getNext() const { return next; }
void setData(int theData) { data = theData; }
void setPrev(DLLNode* prevLink) { prev = prevLink; }
void setNext(DLLNode* nextLink) { next = nextLink; }
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{
public:
DoublyList() : first(nullptr), last(nullptr), count(0) {}
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void printReverse() const;
void rotateNodesRight(int);
void clearList();
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private:
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int count;
};
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#include "DoublyList.h"
#include <iostream>
#include <vector>
using namespace std;
int main()
{
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{1, 2, 3, 4, 5, 6, 7, 8, 9},
{10, 20},
{34, 56, 78, 12, 89, 34, 76, 28, 54, 22, 41},
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};
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{
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then output is:
Main.cpp
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#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
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// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
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#include "DoublyList.h"
using namespace std;
void DoublyList::insertFront(int newData)
{
if (first == nullptr)
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first = new DLLNode(newData, nullptr, nullptr);
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DLLNode* current = first;
while (current != nullptr)
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}
}
void DoublyList::printReverse() const
{
DLLNode* current = last;
while (current != nullptr)
{
cout << current->getData() << " ";
current = current->getPrev();
}
}
void DoublyList::clearList()
{
DLLNode* temp = first;
while (first != nullptr)
{
first = first->getNext();
delete temp;
temp = first;
}
last = nullptr;
// Don't forget to reset pointer last to nullptr.
count = 0;
}
DoublyList::~DoublyList()
{
if (first != nullptr)
clearList();
}
DoublyList.h
#ifndef DOUBLYLIST_H
#define DOUBLYLIST_H
#include <string>
#include <iostream>
class DLLNode
{
public:
DLLNode() : data(0), prev(nullptr), next(nullptr) {}
DLLNode(int theData, DLLNode* prevLink, DLLNode* nextLink)
: data(theData), prev(prevLink), next(nextLink) {}
int getData() const { return data; }
DLLNode* getPrev() const { return prev; }
DLLNode* getNext() const { return next; }
void setData(int theData) { data = theData; }
void setPrev(DLLNode* prevLink) { prev = prevLink; }
void setNext(DLLNode* nextLink) { next = nextLink; }
~DLLNode(){}
private:
int data; // To simplify, we are using only one piece of data.
DLLNode* prev;
DLLNode* next;
};
class DoublyList
{
public:
DoublyList() : first(nullptr), last(nullptr), count(0) {}
void insertFront(int newData);
void printForward() const;
void printReverse() const;
void rotateNodesRight(int);
void clearList();
~DoublyList();
private:
// Pointer to the first node in the list.
DLLNode*first;
// Pointer to the last node in the list.
DLLNode*last;
// Number of nodes in the list.
int count;
};
#endif
Main.cpp
#include "DoublyList.h"
#include <iostream>
#include <vector>
using namespace std;
int main()
{
vector<vector<int>> data = {
{25, 76, 35, 67, 15, 98},
{1, 2, 3, 4, 5, 6, 7, 8, 9},
{10, 20},
{34, 56, 78, 12, 89, 34, 76, 28, 54, 22, 41},
{123, 873, 619},
};
vector<int> nodesToRotate = { 2, 3, 1, 9, 2 };
{
DoublyList doublyList;
int vectorSize = static_cast<int>(data.size());
for (int i = 0; i < vectorSize; ++i)
{
int innerSize = static_cast<int>(data[i].size());
for (int j = innerSize - 1; j >= 0; --j)
doublyList.insertFront(data[i].at(j));
cout << "Rotate right: " << nodesToRotate[i] << "\n";
cout << " List is: ";
doublyList.printForward();
cout << "\n";
doublyList.rotateNodesRight(nodesToRotate[i]);
cout << "After rotating:";
cout << "\n Print forward: ";
doublyList.printForward();
cout << "\nPrint backwards: ";
doublyList.printReverse(.
On July 31- 2022- Sunland Company engaged Duval Tooling Company to con.pdf
On July 31, 2022, Sunland Company engaged Duval Tooling Company to construct a special-
purpose piece of factory machinery. Construction began immediately and was completed on
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Need to be done in C++ Please Sorted number list implementation wit.pdf
Need to be done in C++ Please
Sorted number list implementation with linked lists
Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking
on the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables:
a double data value,
a pointer to the next node, and
a pointer to the previous node.
Each member variable is protected. So code outside of the class must use the provided getter and
setter member functions to get or set a member variable.
Node.h is read only, since no changes are required.
Step 2: Implement the Insert() member function
A class for a sorted, doubly-linked list is declared in SortedNumberList.h. Implement the
SortedNumberList class's Insert() member function. The function must create a new node with
the parameter value, then insert the node into the proper sorted position in the linked list. Ex:
Suppose a SortedNumberList's current list is 23 47.25 86, then Insert(33.5) is called. A new node
with data value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's
sorted order and yielding: 23 35.5 47.25 86
Step 3: Test in develop mode
Code in main() takes a space-separated list of numbers and inserts each into a SortedNumberList.
The list is displayed after each insertion. Ex: If input is
then output is:
Try various program inputs, ensuring that each outputs a sorted list.
Step 4: Implement the Remove() member function
Implement the SortedNumberList class's Remove() member function. The function takes a
parameter for the number to be removed from the list. If the number does not exist in the list, the
list is not changed and false is returned. Otherwise, the first instance of the number is removed
from the list and true is returned.
Uncomment the commented-out part in main() that reads a second input line and removes
numbers from the list. Test in develop mode to ensure that insertion and removal both work
properly, then submit code for grading. Ex: If input is
then output is:
Main.cpp
#include <iostream>
#include <string>
#include <vector>
#include "Node.h"
#include "SortedNumberList.h"
using namespace std;
void PrintList(SortedNumberList& list);
vector<string> SpaceSplit(string source);
int main(int argc, char *argv[]) {
// Read the line of input numbers
string inputLine;
getline(cin, inputLine);
// Split on space character
vector<string> terms = SpaceSplit(inputLine);
// Insert each value and show the sorted list's contents after each insertion
SortedNumberList list;
for (auto term : terms) {
double number = stod(term);
cout << "List after inserting " << number << ": " << endl;
list.Insert(number);
PrintList(list);
}
/*
// Read the input line with numbers to remove
getline(cin, inputLine);
terms = SpaceSplit(inputLine);
// Remove each value
for (auto term : terms) {
double number = stod(term);
cout << "List after removing " << number << ": " << endl;
list.Remove(number);
PrintList(list).
Meosis and mitosis are both forms of cell division- However- the outco.pdf
Meosis and mitosis are both forms of cell division. However, the outcomes of these processes
differ. Consider a diploid organism with two sexes. Select the reasons why meosis typically
produces genetic variation, whereas mitosis does not.
1n gametes produced in mitosis fuse to produce 2n cells in meiosis
Sister chromatids are not genetically identical as a result of crossing over during meiosis
Gametic chromosomes have a different combination of alleles than parental chromosomes as a
result of independent assortment
Meiosis produces four genetically different haploid cells
1n gametes produced in mitosis fuse to produce 2n cells in meiosis
Sister chromatids are not genetically identical as a result of crossing over during meiosis
Gametic chromosomes have a different combination of alleles than parental chromosomes as a
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Meiosis produces four genetically different haploid cells.
(b) Let P-C-K denote respectively the plaintext space- ciphertext spac.pdf
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Let A and B be two events defined on a sample space S of an experiment.pdf
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Let X be a discrete random variable with moment generating function given by: M X ( t ) = 1
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