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TUGAS 3
NAMA KELOMPOK : 1.SUSANDI 2.RAFIS 3.GERIAN
KELAS : 1EA
LATIHAN 7.1
1. โˆซ 100 ๐‘‘๐‘ฅ = 100๐‘ฅ + ๐‘
2. โˆซ 6๐‘ฅ ๐‘‘๐‘ฅ = 3๐‘ฅ2
+ ๐‘
3. โˆซ( 3๐‘ฅ2
+ 4๐‘ฅ โˆ’ 5) ๐‘‘๐‘ฅ = ๐‘ฅ3
+ 2๐‘ฅ โˆ’
5๐‘ฅ + ๐‘
4. โˆซ( ๐‘ฅ2
+ 1)โˆš ๐‘ฅ ๐‘‘๐‘ฅ =
2
7
๐‘ฅ2
1
+
2
3
๐‘ฅ2
3
+ ๐‘
5. โˆซ( ๐‘ฅ ๐‘’
+ ๐‘’ ๐‘ฅ ) ๐‘‘๐‘ฅ =
๐‘ฅ ๐‘’+1
๐‘’+1
+ ๐‘’ ๐‘ฅ
+ ๐‘
6. โˆซ(10๐‘ฅ + 30)3
10 ๐‘‘๐‘ฅ =
(10๐‘ฅ+30)4
4
+ ๐‘
7. โˆซ(๐‘ฅ2
โˆ’ 3)4
2๐‘ฅ ๐‘‘๐‘ฅ =
(๐‘ฅ2โˆ’3)5
5
+ ๐‘
8. โˆซ(๐‘ ๐‘–๐‘›2
๐‘ฅcos ๐‘ฅ) ๐‘‘๐‘ฅ =
๐‘ ๐‘–๐‘›3
3
๐‘ฅ + ๐‘
9. โˆซ ๐‘ฅ2
โˆ’ ๐‘ ๐‘–๐‘› ๐‘ฅ3
๐‘‘๐‘ฅ =
โˆ’ cos ๐‘ฅ3
3
+ ๐‘
10. โˆซ ๐ผ๐‘› ๐‘ฅ ๐‘‘๐‘ฅ = ๐‘ฅ ๐ผ๐‘› ๐‘ฅ = ๐‘ฅ ๐ผ๐‘› ๐‘ฅ โˆ’ ๐‘ฅ +
๐‘
penyelesaian :
1. =
๐‘‘
๐‘‘๐‘ฅ
(100๐‘ฅ + ๐‘) = 100๐‘ฅ + ๐‘
2. =
๐‘‘
๐‘‘๐‘ฅ
(3๐‘ฅ2
+ ๐‘) = 6๐‘ฅ + 0 = 100
3. =
๐‘‘
๐‘‘๐‘ฅ
(๐‘ฅ3
+ 2๐‘ฅ2
โˆ’ 5๐‘ฅ + ๐‘) = 3๐‘ฅ2
+ 4๐‘ฅ โˆ’ 5 + 0 = 3๐‘ฅ2
+4x-5
4. =
๐‘‘
๐‘‘๐‘ฅ
(
2๐‘ฅ
1
2
7
+
2๐‘ฅ
3
2
3
+ c)=
2๐‘ฅ
โˆ’1
2
14
+
6๐‘ฅ
1
2
6
+ 0 =
1๐‘ฅ
โˆ’1
2
7
+ ๐‘ฅ
1
2
5. =
๐‘‘
๐‘‘๐‘ฅ
(
๐‘ฅ ๐‘’+1
๐‘’+1
+ ๐‘’ ๐‘ฅ
+ ๐‘) =
๐‘’+1.๐‘ฅ ๐‘’+1โˆ’1
1๐‘’1โˆ’1+0
+ ๐‘ฅ๐‘’ ๐‘ฅโˆ’1
+ ๐‘ =
๐‘’+๐‘ฅ ๐‘’
1
+ ๐‘ฅ๐‘’ ๐‘ฅโˆ’1
+ 0 = ๐‘’ + ๐‘ฅ ๐‘’
+
๐‘ฅ๐‘’ ๐‘ฅโˆ’1
6. =
๐‘‘
๐‘‘๐‘ฅ
(10๐‘ฅ+30)4
4
+ ๐‘ =
10๐‘ฅ4
4
+
304
4
+ ๐‘ =
40๐‘ฅ3
4
+ 0 = 10๐‘ฅ3
7. =
๐‘‘
๐‘‘๐‘ฅ
(๐‘ฅ2โˆ’3)5
5
+ c =
๐‘ฅ10
5
โˆ’
35
5
+ ๐‘ =
10๐‘ฅ9
5
+ 0 = 2๐‘ฅ9
8. =
๐‘‘
๐‘‘๐‘ฅ
(
๐‘ ๐‘–๐‘›3
3
๐‘ฅ + ๐‘) =
๐‘ ๐‘–๐‘›2 ๐‘ฅ
3
.
sin ๐‘ฅ
3
+ 0 =
(1โˆ’๐‘๐‘œ๐‘ 2 ๐‘ฅ) .
3
sin ๐‘ฅ
3
9. =
๐‘‘
๐‘‘๐‘ฅ
(
โˆ’ cos ๐‘ฅ3
3
+ ๐‘) =
โˆ’3 sin ๐‘ฅ2
3
+ 0 = โˆ’sin ๐‘ฅ2
10. =
๐‘‘
๐‘‘๐‘ฅ
( ๐‘ฅ ๐ผ๐‘› ๐‘ฅ โˆ’ ๐‘ฅ + ๐‘) = ๐‘ฅ.
๐‘‘๐‘ฅ
๐‘ฅ
โˆ’ 1 =
๐‘ฅโˆ’1๐‘‘๐‘ฅ
๐‘ฅ
LATIHAN 7.2
1. โˆซ8 ๐‘‘๐‘ฅ
2. โˆซ
3
4
๐‘‘๐‘ฅ
3. โˆซ9.75 ๐‘‘๐‘ฅ
4. โˆซโˆš3๐‘‘๐‘ฅ
5. โˆซ(
โˆš40
3
โˆš10+15
)๐‘‘๐‘ฅ
6. โˆซ16 โˆš2 ๐‘‘๐‘ก
7. โˆซ ๐‘’2
๐‘‘๐‘ฅ
8. โˆซ2๐œ‹ ๐‘‘๐‘Ÿ
9. โˆซโˆ’21๐‘‘๐‘ข
10.โˆซ
6
๐‘’
๐‘‘๐‘ฅ
Penyelesaian :
1. = 8x+c
2. =
3
4
๐‘ฅ + ๐‘
3. = 9๐‘ฅ. 75๐‘ฅ + ๐‘
4. = โˆš3 x+c
5. =
40๐‘ฅ
2
3
10๐‘ฅ
1
2+15๐‘ฅ
+ ๐‘
6. = 16๐‘ก. โˆš2 ๐‘ก + c
7. = ๐‘’๐‘ฅ2
+ c
8. = 2๐‘Ÿ. ๐œ‹๐‘Ÿ + c
9. = -21 u + c
10.=
6๐‘ฅ
๐‘’๐‘ฅ
+ c
LATIHAN 7.3
1. โˆซ ๐‘ฅ5
๐‘‘๐‘ฅ
2. โˆซ โˆš ๐‘ฅ34
๐‘‘๐‘ฅ
3. โˆซ ๐‘ฅโˆš2
๐‘‘๐‘ฅ
4. โˆซ
1
๐‘ฅ2
๐‘‘๐‘ฅ
5. โˆซ ๐‘ก100
๐‘‘๐‘ก
6. โˆซ ๐‘ข2๐œ‹
๐‘‘๐‘ข
7. โˆซ
1
โˆš๐‘ฅ
๐‘‘๐‘ฅ
8. โˆซ
๐‘ฅ5
๐‘ฅ2
๐‘‘๐‘ฅ
9. โˆซ ๐‘Ÿโˆ’1
๐‘‘๐‘Ÿ
10.โˆซ
1
๐‘ก
๐‘‘๐‘ก
Penyelesaian :
1. =
๐‘ฅ6
6
+ ๐‘
2. = โˆซ ๐‘ฅ
3
4 ๐‘‘๐‘ฅ =
๐‘ฅ
7
4
7
4
+ c =
4๐‘ฅ
7
4
7
+ ๐‘
3. =
๐‘ฅโˆš2+1
โˆš2+1
+ ๐‘
4. =โˆซ ๐‘ฅโˆ’2
๐‘‘๐‘ฅ =
๐‘ฅโˆ’1
โˆ’1
+ ๐‘ = โˆ’
1
๐‘ฅ
+ ๐‘
5. =
๐‘ก101
101
+ ๐‘
6. =
42๐œ‹+1
2๐œ‹+1
+ ๐‘
7. = โˆซ ๐‘ฅ
โˆ’1
2 ๐‘‘๐‘ฅ =
๐‘ฅ
1
2
1
2
+ ๐‘ =
2๐‘ฅ
1
2
1
+ ๐‘
8. =
๐‘ฅ6
๐‘ฅ3
+ ๐‘
9. =
๐‘Ÿโˆ’1+1
โˆ’1+1
+ ๐‘ = โˆž
10.โˆซ ๐‘กโˆ’1
๐‘‘๐‘ก =
๐‘กโˆ’1+1
โˆ’1+1
+ ๐‘ = โˆž
LATIHAN 7.4
1. โˆซ ๐‘’ ๐‘ก
๐‘‘๐‘ก
2. โˆซ ๐‘’20๐‘ฅ
๐‘‘๐‘ฅ
3. โˆซ ๐‘’ ๐œ‹๐‘ฅ
๐‘‘๐‘ฅ
4. โˆซ ๐‘’0,25๐‘ฅ
๐‘‘๐‘ฅ
5. โˆซ ๐‘’
๐‘ฅ
5 ๐‘‘๐‘ฅ
6. โˆซ ๐‘’โˆš3๐‘ฅ
๐‘‘๐‘ฅ
7. โˆซ4 ๐‘ฅ
๐‘‘๐‘ฅ
8. โˆซ23๐‘ฅ
๐‘‘๐‘ฅ
9. โˆซ1000,25๐‘ฅ
๐‘‘๐‘ฅ
10.โˆซ ๐œ‹
๐‘ฅ
5 ๐‘‘๐‘ฅ
Penyelesaian :
1. = ๐‘’ ๐‘ก
+ ๐‘
2. =
1
20
๐‘’20๐‘ฅ
+ ๐‘ =
๐‘’20๐‘ฅ
5
+ ๐‘
3. =
1
๐œ‹
๐‘’ ๐œ‹๐‘ฅ
+ ๐‘ =
๐‘’ ๐œ‹๐‘ฅ
๐œ‹
+ ๐‘
4. =
1
0,25
๐‘’0,25๐‘ฅ
+ ๐‘ =
๐‘’0,25๐‘ฅ
0,25
+ ๐‘
5. =
1
๐‘ฅ
5
๐‘’
๐‘ฅ
5 + ๐‘ =
5
๐‘ฅ
๐‘’
๐‘ฅ
5 + ๐‘
6. =
1
โˆš3
๐‘’โˆš3๐‘ฅ
+ ๐‘ =
๐‘’โˆš3๐‘ฅ
โˆš3
+ c
7. =
1
๐ผ๐‘› 4
4 ๐‘ฅ
+ ๐‘ =
4 ๐‘ฅ
๐ผ๐‘› 4
+ ๐‘
8. =
1
3 ๐ผ๐‘› 2
23๐‘ฅ
+ ๐‘ =
23๐‘ฅ
3 ๐ผ๐‘› 2
+ ๐‘
9. =
1
0,25 ๐ผ๐‘› 100
1000,25๐‘ฅ
+ ๐‘ =
1000,25๐‘ฅ
0,25 ๐ผ๐‘› 100
+ ๐‘
10.=
1
๐‘ฅ
5
๐œ‹
๐‘ฅ
5 + ๐‘ =
5
๐‘ฅ
๐œ‹
๐‘ฅ
5 + ๐‘
LATIHAN 7.5
1. โˆซcos ๐‘ฃ ๐‘‘๐‘ฃ
2. โˆซsin(
1
2
๐œ‹๐‘ฅ)๐‘‘๐‘ฅ
3. โˆซcos(18) ๐‘‘๐‘ฅ
4. โˆซ ๐‘ ๐‘’๐‘2
(โˆš3๐‘ฅ)๐‘‘๐‘ฅ
5. โˆซ ๐‘๐‘ ๐‘2
(2,5) ๐‘‘๐‘ฅ
6. โˆซsec (
5
6
๐‘ฅ)tan(
5
6
๐‘ฅ)๐‘‘๐‘ฅ
7. โˆซcsc
x
3
๐‘๐‘œ๐‘ก
๐‘ฅ
3
๐‘‘๐‘ฅ
8. โˆซcsc(ex) cot(๐‘’๐‘ฅ)๐‘‘๐‘ฅ
9. โˆซsin 3๐œƒ ๐‘‘๐œƒ
10.โˆซcos(25๐œ‹๐‘ฅ) ๐‘‘๐‘ฅ
Penyelesaian :
1. = Sin v + c
2. = โˆ’
1
1
2๐œ‹
cos (
1
2
๐œ‹๐‘ฅ) + ๐‘ = โˆ’2๐œ‹cos (
1
2
๐œ‹๐‘ฅ) + ๐‘
3. =
1
8
sin(18๐‘ฅ) + ๐‘
4. =
1
โˆš3
tan(โˆš3๐‘ฅ) + ๐‘ =
tan(โˆš3๐‘ฅ)
โˆš3
+ ๐‘
5. = โˆ’
1
2,5
cot(2,5 ๐‘ฅ) + ๐‘ =
โˆ’cot(2,5๐‘ฅ)
2,5
+ ๐‘
6. =
1
5
6
sec(
5
6
๐‘ฅ) + ๐‘ =
6
5
sec (
5
6
๐‘ฅ) + ๐‘
7. =
1
1
3
csc(
x
3
) + c = 3 csc (
๐‘ฅ
3
) + ๐‘
8. = โˆ’
1
๐‘’
csc (ex) + c =
โˆ’ csc( ๐‘’๐‘ฅ)
๐‘’
+ ๐‘
9. = โˆ’
1
3
cos(3๐œƒ) + ๐‘ =
โˆ’cos(3๐œƒ)
3
+ c
10.=
1
25๐œ‹
sin(25๐œ‹๐‘ฅ) + ๐‘ =
sin(25 ๐œ‹๐‘ฅ)
25๐œ‹
+ c
LATIHAN 7.6
1. โˆซ
1
1+๐œƒ2
๐‘‘๐œƒ
2. โˆซ
๐‘‘๐‘ฅ
โˆš16โˆ’๐‘ฅ2
3. โˆซ
1
49+๐‘ฅ2
๐‘‘๐‘ฅ
4. โˆซ
๐‘‘๐‘ก
0,25+๐‘ก2
5. โˆซ
๐‘‘๐‘ข
โˆš๐‘ข2(๐‘ข2โˆ’1)
6. โˆซ
1
|๐‘ฅ|โˆš๐‘ฅ2โˆ’41
๐‘‘๐‘ฅ
7. โˆซ
1
โˆš
81
100
โˆ’๐‘ฅ2
๐‘‘๐‘ฅ
8. โˆซ
1
๐œ‹2+๐‘ฅ2
๐‘‘๐‘ฅ
9. โˆซ
๐‘‘๐‘ก
โˆš๐‘ก2(๐‘ก2โˆ’
1
4
)
10.โˆซ
1
|๐‘ฅ|โˆš๐‘ฅ2โˆ’7
๐‘‘๐‘ฅ
Penyelesaian :
1. = ๐‘ก๐‘Ž๐‘›โˆ’1
๐œƒ + ๐‘ = โˆ’๐‘๐‘œ๐‘กโˆ’1
๐œƒ + ๐‘
2. = โˆซ
1
โˆš42โˆ’โˆš๐‘ฅ2
๐‘‘๐‘ฅ = ๐‘ ๐‘–๐‘›โˆ’1
(
๐‘ฅ
4
) + ๐‘
3. = โˆซ
1
โˆš492+๐‘ฅ2
๐‘‘๐‘ฅ =
1
โˆš49
๐‘ก๐‘Ž๐‘›โˆ’1
(
๐‘ฅ
โˆš49
) + ๐‘
4. = โˆซ
1
โˆš0,252+๐‘ก2
๐‘‘๐‘ก =
1
โˆš0,25
๐‘ก๐‘Ž๐‘›โˆ’1
(
๐‘ก
โˆš0,25
)+ ๐‘
5. = โˆซ
1
|๐‘ข|โˆš๐‘ข2โˆ’โˆš12
๐‘‘๐‘ข =
1
1
๐‘ ๐‘’๐‘โˆ’1
(
๐‘ข
1
) + ๐‘ = ๐‘ ๐‘’๐‘โˆ’1( ๐‘ข) + ๐‘
6. = ๐‘ ๐‘’๐‘โˆ’1
(
๐‘ฅ
41
) + c = - ๐‘๐‘ ๐‘โˆ’1
(
๐‘ฅ
41
) + c
7. = โˆซ
1
โˆš
(9)2
10
โˆ’๐‘ฅ2
๐‘‘๐‘ฅ = ๐‘ ๐‘–๐‘›โˆ’1
(
๐‘ฅ
9
10
) + ๐‘ =๐‘ ๐‘–๐‘›โˆ’1
(
10๐‘ฅ
9
) + ๐‘ = โˆ’๐‘๐‘œ๐‘ โˆ’1
(
10๐‘ฅ
9
) + ๐‘
8.
1
๐œ‹
๐‘ก๐‘Ž๐‘›โˆ’1 ๐‘ฅ
๐œ‹
+ ๐‘ = โˆ’
1
๐œ‹
๐‘๐‘œ๐‘กโˆ’1
(
๐‘ฅ
๐œ‹
)+c
9.= โˆซ
1
| ๐‘ก|โˆš ๐‘ก2โˆ’
(1)
2
2
๐‘‘๐‘ฅ =
1
1
2
๐‘ ๐‘’๐‘โˆ’1
(
๐‘ก
1
2
) + ๐‘ = 2๐‘ ๐‘’๐‘โˆ’1(2๐‘ก) + ๐‘
10.๐‘ ๐‘’๐‘โˆ’1
(
๐‘ฅ
7
) + ๐‘ = โˆ’๐‘๐‘ ๐‘โˆ’1
(
๐‘ฅ
7
) + ๐‘

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Tugas 3

  • 1. TUGAS 3 NAMA KELOMPOK : 1.SUSANDI 2.RAFIS 3.GERIAN KELAS : 1EA LATIHAN 7.1 1. โˆซ 100 ๐‘‘๐‘ฅ = 100๐‘ฅ + ๐‘ 2. โˆซ 6๐‘ฅ ๐‘‘๐‘ฅ = 3๐‘ฅ2 + ๐‘ 3. โˆซ( 3๐‘ฅ2 + 4๐‘ฅ โˆ’ 5) ๐‘‘๐‘ฅ = ๐‘ฅ3 + 2๐‘ฅ โˆ’ 5๐‘ฅ + ๐‘ 4. โˆซ( ๐‘ฅ2 + 1)โˆš ๐‘ฅ ๐‘‘๐‘ฅ = 2 7 ๐‘ฅ2 1 + 2 3 ๐‘ฅ2 3 + ๐‘ 5. โˆซ( ๐‘ฅ ๐‘’ + ๐‘’ ๐‘ฅ ) ๐‘‘๐‘ฅ = ๐‘ฅ ๐‘’+1 ๐‘’+1 + ๐‘’ ๐‘ฅ + ๐‘ 6. โˆซ(10๐‘ฅ + 30)3 10 ๐‘‘๐‘ฅ = (10๐‘ฅ+30)4 4 + ๐‘ 7. โˆซ(๐‘ฅ2 โˆ’ 3)4 2๐‘ฅ ๐‘‘๐‘ฅ = (๐‘ฅ2โˆ’3)5 5 + ๐‘ 8. โˆซ(๐‘ ๐‘–๐‘›2 ๐‘ฅcos ๐‘ฅ) ๐‘‘๐‘ฅ = ๐‘ ๐‘–๐‘›3 3 ๐‘ฅ + ๐‘ 9. โˆซ ๐‘ฅ2 โˆ’ ๐‘ ๐‘–๐‘› ๐‘ฅ3 ๐‘‘๐‘ฅ = โˆ’ cos ๐‘ฅ3 3 + ๐‘ 10. โˆซ ๐ผ๐‘› ๐‘ฅ ๐‘‘๐‘ฅ = ๐‘ฅ ๐ผ๐‘› ๐‘ฅ = ๐‘ฅ ๐ผ๐‘› ๐‘ฅ โˆ’ ๐‘ฅ + ๐‘ penyelesaian : 1. = ๐‘‘ ๐‘‘๐‘ฅ (100๐‘ฅ + ๐‘) = 100๐‘ฅ + ๐‘ 2. = ๐‘‘ ๐‘‘๐‘ฅ (3๐‘ฅ2 + ๐‘) = 6๐‘ฅ + 0 = 100 3. = ๐‘‘ ๐‘‘๐‘ฅ (๐‘ฅ3 + 2๐‘ฅ2 โˆ’ 5๐‘ฅ + ๐‘) = 3๐‘ฅ2 + 4๐‘ฅ โˆ’ 5 + 0 = 3๐‘ฅ2 +4x-5 4. = ๐‘‘ ๐‘‘๐‘ฅ ( 2๐‘ฅ 1 2 7 + 2๐‘ฅ 3 2 3 + c)= 2๐‘ฅ โˆ’1 2 14 + 6๐‘ฅ 1 2 6 + 0 = 1๐‘ฅ โˆ’1 2 7 + ๐‘ฅ 1 2 5. = ๐‘‘ ๐‘‘๐‘ฅ ( ๐‘ฅ ๐‘’+1 ๐‘’+1 + ๐‘’ ๐‘ฅ + ๐‘) = ๐‘’+1.๐‘ฅ ๐‘’+1โˆ’1 1๐‘’1โˆ’1+0 + ๐‘ฅ๐‘’ ๐‘ฅโˆ’1 + ๐‘ = ๐‘’+๐‘ฅ ๐‘’ 1 + ๐‘ฅ๐‘’ ๐‘ฅโˆ’1 + 0 = ๐‘’ + ๐‘ฅ ๐‘’ + ๐‘ฅ๐‘’ ๐‘ฅโˆ’1 6. = ๐‘‘ ๐‘‘๐‘ฅ (10๐‘ฅ+30)4 4 + ๐‘ = 10๐‘ฅ4 4 + 304 4 + ๐‘ = 40๐‘ฅ3 4 + 0 = 10๐‘ฅ3 7. = ๐‘‘ ๐‘‘๐‘ฅ (๐‘ฅ2โˆ’3)5 5 + c = ๐‘ฅ10 5 โˆ’ 35 5 + ๐‘ = 10๐‘ฅ9 5 + 0 = 2๐‘ฅ9 8. = ๐‘‘ ๐‘‘๐‘ฅ ( ๐‘ ๐‘–๐‘›3 3 ๐‘ฅ + ๐‘) = ๐‘ ๐‘–๐‘›2 ๐‘ฅ 3 . sin ๐‘ฅ 3 + 0 = (1โˆ’๐‘๐‘œ๐‘ 2 ๐‘ฅ) . 3 sin ๐‘ฅ 3 9. = ๐‘‘ ๐‘‘๐‘ฅ ( โˆ’ cos ๐‘ฅ3 3 + ๐‘) = โˆ’3 sin ๐‘ฅ2 3 + 0 = โˆ’sin ๐‘ฅ2 10. = ๐‘‘ ๐‘‘๐‘ฅ ( ๐‘ฅ ๐ผ๐‘› ๐‘ฅ โˆ’ ๐‘ฅ + ๐‘) = ๐‘ฅ. ๐‘‘๐‘ฅ ๐‘ฅ โˆ’ 1 = ๐‘ฅโˆ’1๐‘‘๐‘ฅ ๐‘ฅ
  • 2. LATIHAN 7.2 1. โˆซ8 ๐‘‘๐‘ฅ 2. โˆซ 3 4 ๐‘‘๐‘ฅ 3. โˆซ9.75 ๐‘‘๐‘ฅ 4. โˆซโˆš3๐‘‘๐‘ฅ 5. โˆซ( โˆš40 3 โˆš10+15 )๐‘‘๐‘ฅ 6. โˆซ16 โˆš2 ๐‘‘๐‘ก 7. โˆซ ๐‘’2 ๐‘‘๐‘ฅ 8. โˆซ2๐œ‹ ๐‘‘๐‘Ÿ 9. โˆซโˆ’21๐‘‘๐‘ข 10.โˆซ 6 ๐‘’ ๐‘‘๐‘ฅ Penyelesaian : 1. = 8x+c 2. = 3 4 ๐‘ฅ + ๐‘ 3. = 9๐‘ฅ. 75๐‘ฅ + ๐‘ 4. = โˆš3 x+c 5. = 40๐‘ฅ 2 3 10๐‘ฅ 1 2+15๐‘ฅ + ๐‘ 6. = 16๐‘ก. โˆš2 ๐‘ก + c 7. = ๐‘’๐‘ฅ2 + c 8. = 2๐‘Ÿ. ๐œ‹๐‘Ÿ + c 9. = -21 u + c 10.= 6๐‘ฅ ๐‘’๐‘ฅ + c
  • 3. LATIHAN 7.3 1. โˆซ ๐‘ฅ5 ๐‘‘๐‘ฅ 2. โˆซ โˆš ๐‘ฅ34 ๐‘‘๐‘ฅ 3. โˆซ ๐‘ฅโˆš2 ๐‘‘๐‘ฅ 4. โˆซ 1 ๐‘ฅ2 ๐‘‘๐‘ฅ 5. โˆซ ๐‘ก100 ๐‘‘๐‘ก 6. โˆซ ๐‘ข2๐œ‹ ๐‘‘๐‘ข 7. โˆซ 1 โˆš๐‘ฅ ๐‘‘๐‘ฅ 8. โˆซ ๐‘ฅ5 ๐‘ฅ2 ๐‘‘๐‘ฅ 9. โˆซ ๐‘Ÿโˆ’1 ๐‘‘๐‘Ÿ 10.โˆซ 1 ๐‘ก ๐‘‘๐‘ก Penyelesaian : 1. = ๐‘ฅ6 6 + ๐‘ 2. = โˆซ ๐‘ฅ 3 4 ๐‘‘๐‘ฅ = ๐‘ฅ 7 4 7 4 + c = 4๐‘ฅ 7 4 7 + ๐‘ 3. = ๐‘ฅโˆš2+1 โˆš2+1 + ๐‘ 4. =โˆซ ๐‘ฅโˆ’2 ๐‘‘๐‘ฅ = ๐‘ฅโˆ’1 โˆ’1 + ๐‘ = โˆ’ 1 ๐‘ฅ + ๐‘ 5. = ๐‘ก101 101 + ๐‘ 6. = 42๐œ‹+1 2๐œ‹+1 + ๐‘ 7. = โˆซ ๐‘ฅ โˆ’1 2 ๐‘‘๐‘ฅ = ๐‘ฅ 1 2 1 2 + ๐‘ = 2๐‘ฅ 1 2 1 + ๐‘ 8. = ๐‘ฅ6 ๐‘ฅ3 + ๐‘ 9. = ๐‘Ÿโˆ’1+1 โˆ’1+1 + ๐‘ = โˆž
  • 4. 10.โˆซ ๐‘กโˆ’1 ๐‘‘๐‘ก = ๐‘กโˆ’1+1 โˆ’1+1 + ๐‘ = โˆž LATIHAN 7.4 1. โˆซ ๐‘’ ๐‘ก ๐‘‘๐‘ก 2. โˆซ ๐‘’20๐‘ฅ ๐‘‘๐‘ฅ 3. โˆซ ๐‘’ ๐œ‹๐‘ฅ ๐‘‘๐‘ฅ 4. โˆซ ๐‘’0,25๐‘ฅ ๐‘‘๐‘ฅ 5. โˆซ ๐‘’ ๐‘ฅ 5 ๐‘‘๐‘ฅ 6. โˆซ ๐‘’โˆš3๐‘ฅ ๐‘‘๐‘ฅ 7. โˆซ4 ๐‘ฅ ๐‘‘๐‘ฅ 8. โˆซ23๐‘ฅ ๐‘‘๐‘ฅ 9. โˆซ1000,25๐‘ฅ ๐‘‘๐‘ฅ 10.โˆซ ๐œ‹ ๐‘ฅ 5 ๐‘‘๐‘ฅ Penyelesaian : 1. = ๐‘’ ๐‘ก + ๐‘ 2. = 1 20 ๐‘’20๐‘ฅ + ๐‘ = ๐‘’20๐‘ฅ 5 + ๐‘ 3. = 1 ๐œ‹ ๐‘’ ๐œ‹๐‘ฅ + ๐‘ = ๐‘’ ๐œ‹๐‘ฅ ๐œ‹ + ๐‘ 4. = 1 0,25 ๐‘’0,25๐‘ฅ + ๐‘ = ๐‘’0,25๐‘ฅ 0,25 + ๐‘ 5. = 1 ๐‘ฅ 5 ๐‘’ ๐‘ฅ 5 + ๐‘ = 5 ๐‘ฅ ๐‘’ ๐‘ฅ 5 + ๐‘ 6. = 1 โˆš3 ๐‘’โˆš3๐‘ฅ + ๐‘ = ๐‘’โˆš3๐‘ฅ โˆš3 + c 7. = 1 ๐ผ๐‘› 4 4 ๐‘ฅ + ๐‘ = 4 ๐‘ฅ ๐ผ๐‘› 4 + ๐‘ 8. = 1 3 ๐ผ๐‘› 2 23๐‘ฅ + ๐‘ = 23๐‘ฅ 3 ๐ผ๐‘› 2 + ๐‘ 9. = 1 0,25 ๐ผ๐‘› 100 1000,25๐‘ฅ + ๐‘ = 1000,25๐‘ฅ 0,25 ๐ผ๐‘› 100 + ๐‘ 10.= 1 ๐‘ฅ 5 ๐œ‹ ๐‘ฅ 5 + ๐‘ = 5 ๐‘ฅ ๐œ‹ ๐‘ฅ 5 + ๐‘
  • 5. LATIHAN 7.5 1. โˆซcos ๐‘ฃ ๐‘‘๐‘ฃ 2. โˆซsin( 1 2 ๐œ‹๐‘ฅ)๐‘‘๐‘ฅ 3. โˆซcos(18) ๐‘‘๐‘ฅ 4. โˆซ ๐‘ ๐‘’๐‘2 (โˆš3๐‘ฅ)๐‘‘๐‘ฅ 5. โˆซ ๐‘๐‘ ๐‘2 (2,5) ๐‘‘๐‘ฅ 6. โˆซsec ( 5 6 ๐‘ฅ)tan( 5 6 ๐‘ฅ)๐‘‘๐‘ฅ 7. โˆซcsc x 3 ๐‘๐‘œ๐‘ก ๐‘ฅ 3 ๐‘‘๐‘ฅ 8. โˆซcsc(ex) cot(๐‘’๐‘ฅ)๐‘‘๐‘ฅ 9. โˆซsin 3๐œƒ ๐‘‘๐œƒ 10.โˆซcos(25๐œ‹๐‘ฅ) ๐‘‘๐‘ฅ Penyelesaian : 1. = Sin v + c 2. = โˆ’ 1 1 2๐œ‹ cos ( 1 2 ๐œ‹๐‘ฅ) + ๐‘ = โˆ’2๐œ‹cos ( 1 2 ๐œ‹๐‘ฅ) + ๐‘ 3. = 1 8 sin(18๐‘ฅ) + ๐‘ 4. = 1 โˆš3 tan(โˆš3๐‘ฅ) + ๐‘ = tan(โˆš3๐‘ฅ) โˆš3 + ๐‘ 5. = โˆ’ 1 2,5 cot(2,5 ๐‘ฅ) + ๐‘ = โˆ’cot(2,5๐‘ฅ) 2,5 + ๐‘ 6. = 1 5 6 sec( 5 6 ๐‘ฅ) + ๐‘ = 6 5 sec ( 5 6 ๐‘ฅ) + ๐‘ 7. = 1 1 3 csc( x 3 ) + c = 3 csc ( ๐‘ฅ 3 ) + ๐‘ 8. = โˆ’ 1 ๐‘’ csc (ex) + c = โˆ’ csc( ๐‘’๐‘ฅ) ๐‘’ + ๐‘ 9. = โˆ’ 1 3 cos(3๐œƒ) + ๐‘ = โˆ’cos(3๐œƒ) 3 + c 10.= 1 25๐œ‹ sin(25๐œ‹๐‘ฅ) + ๐‘ = sin(25 ๐œ‹๐‘ฅ) 25๐œ‹ + c
  • 6. LATIHAN 7.6 1. โˆซ 1 1+๐œƒ2 ๐‘‘๐œƒ 2. โˆซ ๐‘‘๐‘ฅ โˆš16โˆ’๐‘ฅ2 3. โˆซ 1 49+๐‘ฅ2 ๐‘‘๐‘ฅ 4. โˆซ ๐‘‘๐‘ก 0,25+๐‘ก2 5. โˆซ ๐‘‘๐‘ข โˆš๐‘ข2(๐‘ข2โˆ’1) 6. โˆซ 1 |๐‘ฅ|โˆš๐‘ฅ2โˆ’41 ๐‘‘๐‘ฅ 7. โˆซ 1 โˆš 81 100 โˆ’๐‘ฅ2 ๐‘‘๐‘ฅ 8. โˆซ 1 ๐œ‹2+๐‘ฅ2 ๐‘‘๐‘ฅ 9. โˆซ ๐‘‘๐‘ก โˆš๐‘ก2(๐‘ก2โˆ’ 1 4 ) 10.โˆซ 1 |๐‘ฅ|โˆš๐‘ฅ2โˆ’7 ๐‘‘๐‘ฅ Penyelesaian : 1. = ๐‘ก๐‘Ž๐‘›โˆ’1 ๐œƒ + ๐‘ = โˆ’๐‘๐‘œ๐‘กโˆ’1 ๐œƒ + ๐‘ 2. = โˆซ 1 โˆš42โˆ’โˆš๐‘ฅ2 ๐‘‘๐‘ฅ = ๐‘ ๐‘–๐‘›โˆ’1 ( ๐‘ฅ 4 ) + ๐‘ 3. = โˆซ 1 โˆš492+๐‘ฅ2 ๐‘‘๐‘ฅ = 1 โˆš49 ๐‘ก๐‘Ž๐‘›โˆ’1 ( ๐‘ฅ โˆš49 ) + ๐‘ 4. = โˆซ 1 โˆš0,252+๐‘ก2 ๐‘‘๐‘ก = 1 โˆš0,25 ๐‘ก๐‘Ž๐‘›โˆ’1 ( ๐‘ก โˆš0,25 )+ ๐‘ 5. = โˆซ 1 |๐‘ข|โˆš๐‘ข2โˆ’โˆš12 ๐‘‘๐‘ข = 1 1 ๐‘ ๐‘’๐‘โˆ’1 ( ๐‘ข 1 ) + ๐‘ = ๐‘ ๐‘’๐‘โˆ’1( ๐‘ข) + ๐‘ 6. = ๐‘ ๐‘’๐‘โˆ’1 ( ๐‘ฅ 41 ) + c = - ๐‘๐‘ ๐‘โˆ’1 ( ๐‘ฅ 41 ) + c 7. = โˆซ 1 โˆš (9)2 10 โˆ’๐‘ฅ2 ๐‘‘๐‘ฅ = ๐‘ ๐‘–๐‘›โˆ’1 ( ๐‘ฅ 9 10 ) + ๐‘ =๐‘ ๐‘–๐‘›โˆ’1 ( 10๐‘ฅ 9 ) + ๐‘ = โˆ’๐‘๐‘œ๐‘ โˆ’1 ( 10๐‘ฅ 9 ) + ๐‘ 8. 1 ๐œ‹ ๐‘ก๐‘Ž๐‘›โˆ’1 ๐‘ฅ ๐œ‹ + ๐‘ = โˆ’ 1 ๐œ‹ ๐‘๐‘œ๐‘กโˆ’1 ( ๐‘ฅ ๐œ‹ )+c
  • 7. 9.= โˆซ 1 | ๐‘ก|โˆš ๐‘ก2โˆ’ (1) 2 2 ๐‘‘๐‘ฅ = 1 1 2 ๐‘ ๐‘’๐‘โˆ’1 ( ๐‘ก 1 2 ) + ๐‘ = 2๐‘ ๐‘’๐‘โˆ’1(2๐‘ก) + ๐‘ 10.๐‘ ๐‘’๐‘โˆ’1 ( ๐‘ฅ 7 ) + ๐‘ = โˆ’๐‘๐‘ ๐‘โˆ’1 ( ๐‘ฅ 7 ) + ๐‘