TUGAS MATEMATIKA PAK OPAN

1. 𝑋=
𝑓𝑖𝑥𝑖
𝑓𝑖
=
114
32
=34,8
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2. 𝑄3= tb𝑄3+
3
4
𝑁−𝐹𝑘𝑢𝑚
𝐹𝑄3
p
= 85,5 +
15−12
5
5
= 85,5 + 0,6.5
𝑄3= 88,5
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3. a. a=8 b=15
b. 26,94
c. 26,57
d. kuartil bawah=24,05
kuartil atas= 30,03
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8.
10!+5𝑥9!
9!10!
atau
10.9!−5𝑥9!
9!10!
=
9!(15)
9!10!
=
15
10!
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12. BOROKOKOK
B=1 9𝑃(4,3) =
9!
4!3!
R=1 =
9𝑋8𝑋7𝑋6𝑋5𝑋4!
4!3!
O=4 =
15.120
6
K=3 = 2.520
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23. x= 2𝑦2
−3y-6
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24.
𝑥′
𝑦′
=
𝑘 𝑜
𝑜 𝑘
𝑥 − 𝑎
𝑦 − 𝑏 +
𝑎
𝑏
𝑥′−9
2
−
10
2
2
+
𝑦′+4
2
2
=25
𝑥′
𝑦′
=
2 0
0 2
𝑥 − 1
𝑦 − 2
+
1
2
(𝑥′−9)2
4
+
(𝑦′+4)
4
=25
𝑥′
𝑦′
=
2𝑥 − 2
2𝑦 − 4
+
1
2
(𝑥 − 9)2
+(𝑦 + 4)2
= 100
𝑥′+1
2
𝑦′+2
2
=
𝑥
𝑦
(𝑥 − 5)2+(𝑦 + 1)2=25
𝑥′+1
2
−
10
2
2
+
𝑦′+2
2
+
2
2
2
=25
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26. lim
𝑥→∞
=
𝑥3−2𝑥2−5
2𝑥3−𝑥
lim
𝑥→∞
=
𝑥3−2𝑥2−5
𝑥3
2𝑥3−𝑥
𝑥3
lim
𝑥→∞
=
1−
2
𝑥
−
5
𝑥3
2−
1
𝑥2
=
1−0−0
2−0
=
1
2
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32. lim
𝑥→2
𝑥 tan(𝑥−2)
𝑥2−4
lim
𝑥→2
𝑥
𝑥+2
.
tan(𝑥−2)
(𝑥−2)
lim
𝑥→2
2
4
. 1 =
1
2
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34. lim
𝑥→0
=
sin 7𝑥 −tan 5𝑥
tan 4𝑥 −3𝑥
lim
𝑥→0
=
sin 7𝑥
tan 4𝑥
−
tan 5𝑥
3𝑥
=
7
4
-
5
3
=
21−20
12
=
1
12
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Dikerjakan oleh: kelompok genius
Kelas XI MIA 5
ANANDIKA RAMADHANI: 1,2,6,12,24,26,32
ANTHONI CAHYADI: 3,8,13,17,21,27,31
M. ALFARHANDI: 4,9,14,18,22,28,33
M. FANNY ANANTA:5,10,15,19,23,29,34
YOKO ALKAIZAR: 7,11,16,20,25,30,35
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TUGAS MATEMATIKA PAK OPAN

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TUGAS MATEMATIKA PAK OPAN