1) The length of the diagonal of a square with sides of 7cm is 9.9cm. 2) The height of an equilateral triangle with a side of 15cm is 12.99cm. 3) The two numbers that sum to 84, where one is 12 more than the other, are 36 and 48.

1. MATHS FOR GRADE 6

2. What is the length of the diagonal
of a square of side 7cm?
7cm
7cm
7cm
7cm
X
QUESTION 1

3. = X2 = 72 + 72
X2 = 49 + 49
X2 = 98
X = 98 cm
X = 9.89
X = 9.9cm
9 x9 = 81
10 x 10 = 100
9.89 x 9.89 =97.8121
9.9 x 9.9 = 98.01

4. Calculate the height of an equilateral
triangle of side 15cm
15cm
15cm
7.5cm 7.5cm
Question 2
15cm
7.5cm
y cm

5. = y2 = 152 – 7.52
y2 = 225 – 56.25
y= 168.75
y= 12.99 cm
12 x12 = 144
13 x13 = 169
12.99 x12.99 =
168.7401
So approximately
= 168.74

6. The sum of two numbers is 84, and one of them is
12 more than the other. What are the two
numbers?
Question 3
= x + x + 12 = 84
= 2x = 84 -12
= 72
= x = 72/2
=x = 36
1st number x = 36
X+ 12 = 36 + 12 = 48
Therefore, the sum of 36 + 48 = 84

7. Find the altitude of an equilateral
triangle of side 6cm
6cm
Question 4
3cm
X cm
6cm
6cm
6cm
Equilateral
triangle

8. = X2 = 62 - 32
= 36 - 9
X = 27
X = 5.2 cm

9. A ladder 5m high leans against a
wall to a height of 4m. How far
away from the wall is the foot of
the ladder?
Question 5
5cm
4cm
X cm

10. X2 = 52 - 42
X2 = 25 - 16
X = 9
X = 3cm

11. THANK YOU