Suppose N=80,000, n=20,000, and s=50. a. Compute the standard error of x using the finite population correction factor. b. Repeat part a assuming n=40,000. c. n=80,000. Solution standard error = s/sqrt(n) [ sqrt((N - n )/(N - 1)) ] a) 50/sqrt(20000) [ sqrt(60000/79999)] => 50 * 0.866 / 141.421 = 0.306 b) 50/sqrt(40000) [ sqrt(40000/79999)] => 50 * 0.707 / 200 = 0.17675 c)50/sqrt(80000) [ sqrt(0/79999)] => 50 / 282.842 = 0.17677.