Step1 Error lies ; .125/2 =.0625 Mole of O2 will remain unreacted. Step2 We have .125 mole NO2 and .0625 mole unreacted O2 Step3 P= nRT/V ; n=.1875; P= .1875x.0821x300/4.5 =1.02625 atm=1.03 atm Solution Step1 Error lies ; .125/2 =.0625 Mole of O2 will remain unreacted. Step2 We have .125 mole NO2 and .0625 mole unreacted O2 Step3 P= nRT/V ; n=.1875; P= .1875x.0821x300/4.5 =1.02625 atm=1.03 atm.