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பல பரிமாணத்தில் 
அமமந்துள்ள இரண்டாம் 
அடுக்கு வர்க்க ததாடர் 
எண்களின் கூட்டு ததாடர் 
காணும் தபாதுவான 
சூத்திரம் 
[இரண்டாம் பரிமாணம், மூன்றாம் பரிமாணம் , 
...... ,பல பரிமாணம் அல்லது முடிவில்லா 
பரிமாணம்]
சூத்திரம் 
A.P [(N-D)^2] 
= H(N) * [ F+L ] + [ μ + H(N)*[ F * (F+(H(N)-3 ) ) ]]
சூத்திரத்தில் உள்ள 
குறியீடுகளின் விளக்கம் 
H(N) = R * C * Face * Cube * …. * N ஆவது 
பரிமாணம் 
F = முதல் வர்க்க எண் 
L = கமடசி வர்க்க எண் 
μ = பல பரிமாண மாறிலி
பல பரிமாண மாறிலி 
1. H (N ) இன் மதிப்பு 5 க்கு 
இமணயாகவும் அல்லது அதற்கு 
மமலானதாகவும் இருக்குமாயின் ; 
μ = 2[ H(N) -3 ] + 퐻(푁)[ 퐴 ∗ 퐴 − 4 + 1] 
퐴=5 
2. H (N ) இன் மதிப்பு 1 இல் இருந்து 4 
வமர இருக்குமாயின் 
then ; {H(N), μ} => { 1, 0} , {2,-1},{3,-1},{4,2}
எடுத்துகாட்டு மூன்றாம் 
பரிமாணம் 
A.P [(N-D)^2] 
= H(N) * [ F+L ] + [ μ + H(N)*[ F * (F+(H(N)-3 ) ) ]] 
A.P [(3-D)^2] 
= [R*C*Face] * [ F+L ] + [ μ + [R*C*Face] *[ F * 
(F+([R*C *Face] -3 ) ) ]]
எடுத்துகாட்டு மூன்றாம் 
பரிமாணம்
எடுத்துகாட்டு மூன்றாம் 
பரிமாணம் கணக்கிடும் 
முமறகள் 
A.P [(3-D)^2] 
= [R*C*Face] * [ F+L ] + [ μ + [R*C*Face] *[ F * (F+([R*C *Face] -3 ) ) ]] 
Here R=2, C= 2, Face =2 , F= 2, L =9 
so H(N) = R*C*Face = 2* 2 * 2 
μ condition, H(N) = 8, H(N)>= 5 
퐻(푁)[ 퐴 ∗ 퐴 − 4 + 1] 
μ = 2[ H(N) -3 ] + 퐴=5 
8 [ 퐴 ∗ 퐴 − 4 + 1] 
= 2[ 8 -3 ] + 퐴=5 
= 2[5] + [5+1] +[12+1]+[21+1]+[33+1] 
=10+6+13+22+33 
= 84
எடுத்துகாட்டு மூன்றாம் 
பரிமாணம் கணக்கிடும் 
முமறகள் 
A.P [(3-D)^2] 
= [R*C*Face] * [ F+L ] + [ μ + [R*C*Face] *[ F * (F+([R*C *Face] -3 ) ) ]] 
= [8] *[2+9] + [84 + [8*[2* 2+(8-3)]]] 
= 88+[84+8*[14]] 
= 88 + 84+ 112 = 88 + 196 
= 284
சரிபார்த்தல் 
2^2+ 3 ^2 + 4^2 + 5^2 + 6^2 + 7^2 + 8^2 + 9^2 
= 4+9+16+25+36+49+64+81 
=284 
 Finally …. Happy

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பல பரிமாணத்தில் அமைந்துள்ள இரண்டாம் அடுக்கு வர்க்க தொடர் எண்களின் கூட்டு தொடர் காணும் பொதுவா