The document discusses speed, distance, and time calculations for different transportation scenarios. It provides examples of calculating speed for a girl cycling, a car traveling, and a runner sprinting. It also gives scenarios to calculate speed based on a given distance and time. Finally, it asks who would arrive home first between two people driving different distances at different speeds and the time difference between their arrivals.

1. Speed, Distance, Time
1.A girl cycles for 3hrs at a speed of 40 km/h. What
distance did she travel?
D=s x t =40x3=120 km
2.A car travels a distance of 540km in 6 hours.
What speed did it travel at?
S= d/t=540/6= 90km/hr
3.John is a runner. He runs the 50m sprint in 12s.
What speed did he travel at? (in m/s)
S=d/t=50/12=4.16m/s
4.The distance between two cities is 144 km, it
takes me 3hours to travel between these cities.
What speed did I travel at?
S=d/t=144/3= 48km/hr
5. Lauren walks 100m in half a minute. What must
her speed have been to travel this distance?
S=d/t=100/30=3.33m/s
6.Mr Dunn drives 64.8km from work at a speed of 48km/h.
Mrs Dunn drives 81.2km from work at a speed of 58km/h.
They both leave work at the same time.
a) Who arrives home first?
b) How many minutes later is it before the second person
gets home?

2. Mr. Dunn t=d/s=64.8/48=1.35hr
Mrs. Dunn t= d/s= 81.2/58=1.40 hr
Mr Dunn arrives first.
1.40-1.35=0.05 hr =0.05x60 = 3 minutes