The document appears to be a series of math problems and solutions worked out by Fauziah Ahmad on March 21, 2012. It includes problems on ratios, percentages, calculations with measurements in different units, geometry topics like area and perimeter, word problems involving time and money conversions. The document contains 21 pages of worked math examples and solutions.

2. ribu sa
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3. 32 745
30 000
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4. 2 x2 4
=
5 x2 10
= 0.4
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5. 2.3 kg /2.35 kg
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6. 5 0· 32 ÷ 4 = ( 1 markah )
0. 0 8
4 0. 3 2
- 0
3
- 0
3 2
- 3 2
0
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7. 4 1 x3 = 4 3
1 9
+
3 x3
19 +
9
7
= 1 9
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8. silinder
2
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9. 1
1. 4 3
x 4
1 7 2
9
2 10 10
2. 3 0 0
− 1 7 2
1 2 8
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10. Jam Minit
8 15
+ + 40
8 55
Rajah 3
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11. 30 x RM125
100 RM 3 7 . 5 0
RM125 10 RM 3 7 5 . 0 0
= 3 x RM125 x 3 - 3 0
10 7 5
RM375
= RM375 -7 0
5 0
10
- 5 0
= RM37.50 0
- 0
0
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12. 3 10
4.05 m = 4.05 x 100 405 cm
= 405.00 cm − 155 cm
250 cm
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13. 50 + 20 + 20 = 90 sen
RM5 X 2 = RM10.00 RM16.00
RM2 X 2 = RM 4.00 + RM 0.90
RM1 X 2 = RM 2.00 + RM16.90
RM16.00
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14. 750 ÷ 1000 = 0.750 kg
2 . 2 4
Purata = 750 g + 3.9 kg + 2.07 kg 3 6 . 7 2
Purata = 750 g + 3.9 kg + 2.07 kg
3 6
= 6.720 3kg 0.750 7
3 3.900 6
= 2.24 kg + 2.070 1 2
6.720 1 2
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15. 1 cm
7 cm
5 1 6 cm
7 cm
5 5 cm
5 cm
5 7 + 5 cm
36 cm
Perimeter = ( 1 + 7 + 6 + 7 + 5 + 5 + 5 ) cm
= 36 cm
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16. 1 minggu = 7 hari
6 minggu
7 4 5 hari
- 4 2
3 hari
45 hari = 6 minggu 3 hari
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17. 2
2 2 cm
3 6 cm
6
0
Luas 1 petak = 2 cm x 2 cm
= 4 cm²
Luas kawasan yang tidak berlorek = 4 cm² x 6
= 24 cm²
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18. RM2.50 ÷ 10 x 6 =
RM 0 . 2 5
1 3
10 RM 2 . 5 0 RM 0.25
- 0 x 6
2 5 RM 1.50
- 2 0
5 0
- 5 0
0
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19. CARA 1 CARA 2
2.6 l = 2.6 x 1000 850 ml = 850 ÷ 1000
= 2600.0 ml = 0.850 l
2600 ml 2.600 l
− 850 ml − 0.850 l
1750 ml 1.750 l
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20. 2 2
RM 0.65
x 4
RM 2.60
+ RM 2.00
RM 4.60
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21. Kawasan berlorek =5
Kawasan tidak berlorek = 5
Seluruh rajah = 10
5 x 100 %
Peratus kawasan berlorek =
10
= 50 %
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