Salito
- 1. 𝐹 =
𝑘𝑞1𝑞2
𝑟2
1. Halle lafuerzaejercidaentre doscargasq1=5c y q2=10c. separadosenel aire a una
distanciade unmetro
Q1=5c
Q2=10c
R=1m
𝑘 = 9𝑥109
𝑁𝑚2
𝐶2
F=?
𝐹 =
(9𝑥109 𝑁𝑚2
𝐶2 ) ∗ (5C) ∗ (10c)
(1𝑚)2
𝐹 =
(9𝑥109 𝑁𝑚2
𝐶2 ) ∗ 50𝐶2
1𝑚2
𝐹 =
(9𝑥109) ∗ 50
1
𝑁
𝐹 =
450𝑥109
1
𝑁
𝐹 = 450𝑋109 𝑁
𝐹 = 450000000000𝑁
2. Halle lafuerzade repulsiónentre doscargasq1=15C y q2=4C a unadistanciade 0,05m
Q1= 15C
Q2= 4C
R=0,05m
F=?
𝐹 =
𝑘𝑞1𝑞2
𝑟2
𝐹 =
(9𝑥109 𝑁𝑚2
𝐶2 )(15𝐶)(4𝐶)
(0,05𝑚)2
𝐹 =
(9𝑥109 𝑁𝑚2
𝐶2 ) ∗ (60𝐶2 )
(0,0025𝑚2)