reactant is Ozone Catalyst is Nitrogen monoxide I.pdf
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reactant is Ozone Catalyst is Nitrogen monoxide Intermediate is Nitrogen dioxide Product is O2(g) Solution reactant is Ozone Catalyst is Nitrogen monoxide Intermediate is Nitrogen dioxide Product is O2(g).
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MOLARITY = No. of moles Lit of Sol 3 = n.25 .pdf
MOLARITY = No. of moles / Lit of Sol 3 = n/.25 0.75 is correct answer
Solution
MOLARITY = No. of moles / Lit of Sol 3 = n/.25 0.75 is correct answer.
let x = molL of water that dissociate at equilib.pdf
let x = mol/L of water that dissociate at equilibrium [OH-]= [H3O+]= x Kw = 3.3 x
10^-14 = (x)(x) = x^2 x = [H3O+]= [OH-]= square root Kw= 1.82 x 10^-7 M pH = - log 1.82 x
10^-7 =6.74
Solution
let x = mol/L of water that dissociate at equilibrium [OH-]= [H3O+]= x Kw = 3.3 x
10^-14 = (x)(x) = x^2 x = [H3O+]= [OH-]= square root Kw= 1.82 x 10^-7 M pH = - log 1.82 x
10^-7 =6.74.
Wind Turbine - Wind power has been used as long as humans have p.pdf
Wind Turbine :-
Wind power has been used as long as humans have put sails into the wind. For more than two
millennia wind-powered machines have ground grain and pumped water. Wind power was
widely available and not confined to the banks of fast-flowing streams, or later, requiring sources
of fuel. Wind-powered pumps drained the polders of the Netherlands, and in arid regions such as
the American mid-west or the Australian outback, wind pumps provided water for live stock and
steam engines.
The first windmill used for the production of electricity was built in Scotland in July 1887 by
Prof James Blyth of Anderson\'s College, Glasgow ( the precursor of Strathclyde University ) .
Blyth\'s 10 m high, cloth-sailed wind turbine was installed in the garden of his holiday cottage at
Marykirk in Kincardineshire and was used to charge accumulators developed by the Frenchman
Camille Alphonse Faure, to power the lighting in the cottage, thus making it the first house in the
world to have its electricity supplied by wind power. Blyth offered the surplus electricity to the
people of Marykirk for lighting the main street, however, they turned down the offer as they
thought electricity was \"the work of the devil.\" Although he later built a wind turbine to supply
emergency power to the local Lunatic Asylum, Infirmary and Dispensary of Montrose the
invention never really caught on as the technology was not considered to be economically viable.
Across the Atlantic, in Cleveland, Ohio a larger and heavily engineered machine was designed
and constructed in the winter of 1887 – 1888 by Charles F. Brush, this was built by his
engineering company at his home and operated from 1886 until 1900. The Brush wind turbine
had a rotor 17 m ( 56 foot ) in diameter and was mounted on an 18 m ( 60 foot ) tower. Although
large by today\'s standards, the machine was only rated at 12 kW. The connected dynamo was
used either to charge a bank of batteries or to operate up to 100 incandescent light bulbs, three
arc lamps, and various motors in Brush\'s laboratory.
With the development of electric power, wind power found new applications in lighting
buildings remote from centrally-generated power. Throughout the 20th century parallel paths
developed small wind stations suitable for farms or residences, and larger utility-scale wind
generators that could be connected to electricity grids for remote use of power. Today wind
powered generators operate in every size range between tiny stations for battery charging at
isolated residences, up to near-gigawatt sized offshore wind farms that provide electricity to
national electrical networks.
PHOTO VOLTAIC POWER PLANT :-
In August 2006 there was widespread news coverage in the United Kingdom of the major high
street electrical retailers (Currys) decision to stock PV modules, manufactured by Sharp, at a cost
of £1,000 per module. The retailer also provides an installation service.
The introduction of the Feed-in-Tariff (FiT) in 2010 saw ra.
YearAccounts Title and ExplanationsDebitCredit2011Income T.pdf
Year
Accounts Title and Explanations
Debit
Credit
2011
Income Tax Expense
Income Tax Payable
( tax payable on taxable income)
28,455
28,455
2012
Income Tax Refund Receivable
Benefit due to Loss carried back
(refund on account of loss carried back to 2010)
170200*.04
68,080
68,080
2013
Income Tax Refund Receivable
Benefit due to loss carried back
(refund on account of loss carried back to 2011)
81300*0.35
28,455
28,455
2013
Deferred Tax Asset
Benefit due to loss carried forward
(loss carried forward to future years)
309800*.35
108,430
108,430
2014
Income Tax Expense
Deferred Tax Asset
(tax payable for the year adjusted against deferred tax credit) 138000*.35
48,300
48,300
2015
Income Tax Expense
Deferred Tax Asset
(tax for the year 0.35*116500)
40,775
40,775
Year
Accounts Title and Explanations
Debit
Credit
2011
Income Tax Expense
Income Tax Payable
( tax payable on taxable income)
28,455
28,455
2012
Income Tax Refund Receivable
Benefit due to Loss carried back
(refund on account of loss carried back to 2010)
170200*.04
68,080
68,080
2013
Income Tax Refund Receivable
Benefit due to loss carried back
(refund on account of loss carried back to 2011)
81300*0.35
28,455
28,455
2013
Deferred Tax Asset
Benefit due to loss carried forward
(loss carried forward to future years)
309800*.35
108,430
108,430
2014
Income Tax Expense
Deferred Tax Asset
(tax payable for the year adjusted against deferred tax credit) 138000*.35
48,300
48,300
2015
Income Tax Expense
Deferred Tax Asset
(tax for the year 0.35*116500)
40,775
40,775
Solution
Year
Accounts Title and Explanations
Debit
Credit
2011
Income Tax Expense
Income Tax Payable
( tax payable on taxable income)
28,455
28,455
2012
Income Tax Refund Receivable
Benefit due to Loss carried back
(refund on account of loss carried back to 2010)
170200*.04
68,080
68,080
2013
Income Tax Refund Receivable
Benefit due to loss carried back
(refund on account of loss carried back to 2011)
81300*0.35
28,455
28,455
2013
Deferred Tax Asset
Benefit due to loss carried forward
(loss carried forward to future years)
309800*.35
108,430
108,430
2014
Income Tax Expense
Deferred Tax Asset
(tax payable for the year adjusted against deferred tax credit) 138000*.35
48,300
48,300
2015
Income Tax Expense
Deferred Tax Asset
(tax for the year 0.35*116500)
40,775
40,775
Year
Accounts Title and Explanations
Debit
Credit
2011
Income Tax Expense
Income Tax Payable
( tax payable on taxable income)
28,455
28,455
2012
Income Tax Refund Receivable
Benefit due to Loss carried back
(refund on account of loss carried back to 2010)
170200*.04
68,080
68,080
2013
Income Tax Refund Receivable
Benefit due to loss carried back
(refund on account of loss carried back to 2011)
81300*0.35
28,455
28,455
2013
Deferred Tax Asset
Benefit due to loss carried forward
(loss carried forward to future years)
309800*.35
108,430
108,430
2014
Income Tax Expense
Deferred Tax Asset
(tax payable for the year adjusted against deferred tax credit) 138000*.35
48,300
48,300
201.
When the plant has water------ solvent in surrounding area of root .pdf
When the plant has water------> solvent in surrounding area of root is higher than root epidermis
-------------> solvent (water + minerals) move from a region of higher concentration to a region
of lower concentration through cell membrane, which is semi-permeable. This phenomenon is
known as osmosis. This solvent moves from root epidermal cells to root cortex because now
solvent concentration in root cortex is lower than that in root epidermis------------> to root
xylem-------> to shoot xylem------> to leaves. This phenomenon is known as Transpiration pull-
cohesion- adhesion theory. It is important to note that osmotic pressure, solute potential,
cohesion and adhesion forces, and transpiration pull, all, are collectively important in transport of
this water from soil to plant leaves.
On the other hand, when water is not there------> solvent does not move from soil to plant
epidermis------> infact solvent moves from plant epidermal cells to soil because of exosmosis.
Exosmosis occurs because solvent is higher is plant cells in comparison to the surroundings. So,
the plant wilts.
Solution
When the plant has water------> solvent in surrounding area of root is higher than root epidermis
-------------> solvent (water + minerals) move from a region of higher concentration to a region
of lower concentration through cell membrane, which is semi-permeable. This phenomenon is
known as osmosis. This solvent moves from root epidermal cells to root cortex because now
solvent concentration in root cortex is lower than that in root epidermis------------> to root
xylem-------> to shoot xylem------> to leaves. This phenomenon is known as Transpiration pull-
cohesion- adhesion theory. It is important to note that osmotic pressure, solute potential,
cohesion and adhesion forces, and transpiration pull, all, are collectively important in transport of
this water from soil to plant leaves.
On the other hand, when water is not there------> solvent does not move from soil to plant
epidermis------> infact solvent moves from plant epidermal cells to soil because of exosmosis.
Exosmosis occurs because solvent is higher is plant cells in comparison to the surroundings. So,
the plant wilts..
The set T - R is same as T as they have no point in common.T - R =.pdf
The set T - R is same as T as they have no point in common.
T - R = T
Solution
The set T - R is same as T as they have no point in common.
T - R = T.
The zero force members are AH, HG, CD, DESolutionThe zero forc.pdf
The zero force members are AH, HG, CD, DE
Solution
The zero force members are AH, HG, CD, DE.
The equation for copper(II) sulfate dissolving in water isCuSO4(s.pdf
The equation for copper(II) sulfate dissolving in water is:
CuSO4(s) => Cu2+(aq) + SO42-(aq)
There is no need to add water to the equation. By writing the states (aq = aqueous) of the ions, it
is understood that water has been added.
Thus the species present in solution are:
Cu2+(copper (II) ion) and SO42- (sulfate ion).
The color of a solution is determined by the characteristic color of the species present in the
solution.
Cu2+ has a characteristic blue color, while SO42- is colorless.
Thus the solution appears blue overall.
Solution
The equation for copper(II) sulfate dissolving in water is:
CuSO4(s) => Cu2+(aq) + SO42-(aq)
There is no need to add water to the equation. By writing the states (aq = aqueous) of the ions, it
is understood that water has been added.
Thus the species present in solution are:
Cu2+(copper (II) ion) and SO42- (sulfate ion).
The color of a solution is determined by the characteristic color of the species present in the
solution.
Cu2+ has a characteristic blue color, while SO42- is colorless.
Thus the solution appears blue overall..
Recommended
MOLARITY = No. of moles Lit of Sol 3 = n.25 .pdf
MOLARITY = No. of moles / Lit of Sol 3 = n/.25 0.75 is correct answer
Solution
MOLARITY = No. of moles / Lit of Sol 3 = n/.25 0.75 is correct answer.
let x = molL of water that dissociate at equilib.pdf
let x = mol/L of water that dissociate at equilibrium [OH-]= [H3O+]= x Kw = 3.3 x
10^-14 = (x)(x) = x^2 x = [H3O+]= [OH-]= square root Kw= 1.82 x 10^-7 M pH = - log 1.82 x
10^-7 =6.74
Solution
let x = mol/L of water that dissociate at equilibrium [OH-]= [H3O+]= x Kw = 3.3 x
10^-14 = (x)(x) = x^2 x = [H3O+]= [OH-]= square root Kw= 1.82 x 10^-7 M pH = - log 1.82 x
10^-7 =6.74.
Wind Turbine - Wind power has been used as long as humans have p.pdf
Wind Turbine :-
Wind power has been used as long as humans have put sails into the wind. For more than two
millennia wind-powered machines have ground grain and pumped water. Wind power was
widely available and not confined to the banks of fast-flowing streams, or later, requiring sources
of fuel. Wind-powered pumps drained the polders of the Netherlands, and in arid regions such as
the American mid-west or the Australian outback, wind pumps provided water for live stock and
steam engines.
The first windmill used for the production of electricity was built in Scotland in July 1887 by
Prof James Blyth of Anderson\'s College, Glasgow ( the precursor of Strathclyde University ) .
Blyth\'s 10 m high, cloth-sailed wind turbine was installed in the garden of his holiday cottage at
Marykirk in Kincardineshire and was used to charge accumulators developed by the Frenchman
Camille Alphonse Faure, to power the lighting in the cottage, thus making it the first house in the
world to have its electricity supplied by wind power. Blyth offered the surplus electricity to the
people of Marykirk for lighting the main street, however, they turned down the offer as they
thought electricity was \"the work of the devil.\" Although he later built a wind turbine to supply
emergency power to the local Lunatic Asylum, Infirmary and Dispensary of Montrose the
invention never really caught on as the technology was not considered to be economically viable.
Across the Atlantic, in Cleveland, Ohio a larger and heavily engineered machine was designed
and constructed in the winter of 1887 – 1888 by Charles F. Brush, this was built by his
engineering company at his home and operated from 1886 until 1900. The Brush wind turbine
had a rotor 17 m ( 56 foot ) in diameter and was mounted on an 18 m ( 60 foot ) tower. Although
large by today\'s standards, the machine was only rated at 12 kW. The connected dynamo was
used either to charge a bank of batteries or to operate up to 100 incandescent light bulbs, three
arc lamps, and various motors in Brush\'s laboratory.
With the development of electric power, wind power found new applications in lighting
buildings remote from centrally-generated power. Throughout the 20th century parallel paths
developed small wind stations suitable for farms or residences, and larger utility-scale wind
generators that could be connected to electricity grids for remote use of power. Today wind
powered generators operate in every size range between tiny stations for battery charging at
isolated residences, up to near-gigawatt sized offshore wind farms that provide electricity to
national electrical networks.
PHOTO VOLTAIC POWER PLANT :-
In August 2006 there was widespread news coverage in the United Kingdom of the major high
street electrical retailers (Currys) decision to stock PV modules, manufactured by Sharp, at a cost
of £1,000 per module. The retailer also provides an installation service.
The introduction of the Feed-in-Tariff (FiT) in 2010 saw ra.
YearAccounts Title and ExplanationsDebitCredit2011Income T.pdf
Year
Accounts Title and Explanations
Debit
Credit
2011
Income Tax Expense
Income Tax Payable
( tax payable on taxable income)
28,455
28,455
2012
Income Tax Refund Receivable
Benefit due to Loss carried back
(refund on account of loss carried back to 2010)
170200*.04
68,080
68,080
2013
Income Tax Refund Receivable
Benefit due to loss carried back
(refund on account of loss carried back to 2011)
81300*0.35
28,455
28,455
2013
Deferred Tax Asset
Benefit due to loss carried forward
(loss carried forward to future years)
309800*.35
108,430
108,430
2014
Income Tax Expense
Deferred Tax Asset
(tax payable for the year adjusted against deferred tax credit) 138000*.35
48,300
48,300
2015
Income Tax Expense
Deferred Tax Asset
(tax for the year 0.35*116500)
40,775
40,775
Year
Accounts Title and Explanations
Debit
Credit
2011
Income Tax Expense
Income Tax Payable
( tax payable on taxable income)
28,455
28,455
2012
Income Tax Refund Receivable
Benefit due to Loss carried back
(refund on account of loss carried back to 2010)
170200*.04
68,080
68,080
2013
Income Tax Refund Receivable
Benefit due to loss carried back
(refund on account of loss carried back to 2011)
81300*0.35
28,455
28,455
2013
Deferred Tax Asset
Benefit due to loss carried forward
(loss carried forward to future years)
309800*.35
108,430
108,430
2014
Income Tax Expense
Deferred Tax Asset
(tax payable for the year adjusted against deferred tax credit) 138000*.35
48,300
48,300
2015
Income Tax Expense
Deferred Tax Asset
(tax for the year 0.35*116500)
40,775
40,775
Solution
Year
Accounts Title and Explanations
Debit
Credit
2011
Income Tax Expense
Income Tax Payable
( tax payable on taxable income)
28,455
28,455
2012
Income Tax Refund Receivable
Benefit due to Loss carried back
(refund on account of loss carried back to 2010)
170200*.04
68,080
68,080
2013
Income Tax Refund Receivable
Benefit due to loss carried back
(refund on account of loss carried back to 2011)
81300*0.35
28,455
28,455
2013
Deferred Tax Asset
Benefit due to loss carried forward
(loss carried forward to future years)
309800*.35
108,430
108,430
2014
Income Tax Expense
Deferred Tax Asset
(tax payable for the year adjusted against deferred tax credit) 138000*.35
48,300
48,300
2015
Income Tax Expense
Deferred Tax Asset
(tax for the year 0.35*116500)
40,775
40,775
Year
Accounts Title and Explanations
Debit
Credit
2011
Income Tax Expense
Income Tax Payable
( tax payable on taxable income)
28,455
28,455
2012
Income Tax Refund Receivable
Benefit due to Loss carried back
(refund on account of loss carried back to 2010)
170200*.04
68,080
68,080
2013
Income Tax Refund Receivable
Benefit due to loss carried back
(refund on account of loss carried back to 2011)
81300*0.35
28,455
28,455
2013
Deferred Tax Asset
Benefit due to loss carried forward
(loss carried forward to future years)
309800*.35
108,430
108,430
2014
Income Tax Expense
Deferred Tax Asset
(tax payable for the year adjusted against deferred tax credit) 138000*.35
48,300
48,300
201.
When the plant has water------ solvent in surrounding area of root .pdf
When the plant has water------> solvent in surrounding area of root is higher than root epidermis
-------------> solvent (water + minerals) move from a region of higher concentration to a region
of lower concentration through cell membrane, which is semi-permeable. This phenomenon is
known as osmosis. This solvent moves from root epidermal cells to root cortex because now
solvent concentration in root cortex is lower than that in root epidermis------------> to root
xylem-------> to shoot xylem------> to leaves. This phenomenon is known as Transpiration pull-
cohesion- adhesion theory. It is important to note that osmotic pressure, solute potential,
cohesion and adhesion forces, and transpiration pull, all, are collectively important in transport of
this water from soil to plant leaves.
On the other hand, when water is not there------> solvent does not move from soil to plant
epidermis------> infact solvent moves from plant epidermal cells to soil because of exosmosis.
Exosmosis occurs because solvent is higher is plant cells in comparison to the surroundings. So,
the plant wilts.
Solution
When the plant has water------> solvent in surrounding area of root is higher than root epidermis
-------------> solvent (water + minerals) move from a region of higher concentration to a region
of lower concentration through cell membrane, which is semi-permeable. This phenomenon is
known as osmosis. This solvent moves from root epidermal cells to root cortex because now
solvent concentration in root cortex is lower than that in root epidermis------------> to root
xylem-------> to shoot xylem------> to leaves. This phenomenon is known as Transpiration pull-
cohesion- adhesion theory. It is important to note that osmotic pressure, solute potential,
cohesion and adhesion forces, and transpiration pull, all, are collectively important in transport of
this water from soil to plant leaves.
On the other hand, when water is not there------> solvent does not move from soil to plant
epidermis------> infact solvent moves from plant epidermal cells to soil because of exosmosis.
Exosmosis occurs because solvent is higher is plant cells in comparison to the surroundings. So,
the plant wilts..
The set T - R is same as T as they have no point in common.T - R =.pdf
The set T - R is same as T as they have no point in common.
T - R = T
Solution
The set T - R is same as T as they have no point in common.
T - R = T.
The zero force members are AH, HG, CD, DESolutionThe zero forc.pdf
The zero force members are AH, HG, CD, DE
Solution
The zero force members are AH, HG, CD, DE.
The equation for copper(II) sulfate dissolving in water isCuSO4(s.pdf
The equation for copper(II) sulfate dissolving in water is:
CuSO4(s) => Cu2+(aq) + SO42-(aq)
There is no need to add water to the equation. By writing the states (aq = aqueous) of the ions, it
is understood that water has been added.
Thus the species present in solution are:
Cu2+(copper (II) ion) and SO42- (sulfate ion).
The color of a solution is determined by the characteristic color of the species present in the
solution.
Cu2+ has a characteristic blue color, while SO42- is colorless.
Thus the solution appears blue overall.
Solution
The equation for copper(II) sulfate dissolving in water is:
CuSO4(s) => Cu2+(aq) + SO42-(aq)
There is no need to add water to the equation. By writing the states (aq = aqueous) of the ions, it
is understood that water has been added.
Thus the species present in solution are:
Cu2+(copper (II) ion) and SO42- (sulfate ion).
The color of a solution is determined by the characteristic color of the species present in the
solution.
Cu2+ has a characteristic blue color, while SO42- is colorless.
Thus the solution appears blue overall..
The balanced equation isFe + CuSO4 = FeSO4 + CuReducing agent .pdf
The balanced equation is:
Fe + CuSO4 => FeSO4 + Cu
Reducing agent is Fe since it is oxidized (oxidation state of Fe increases from 0 to +2)
Oxidizing agent is CuSO4 since it is reduced (oxidation state of Cu decreases from +2 to 0)
Solution
The balanced equation is:
Fe + CuSO4 => FeSO4 + Cu
Reducing agent is Fe since it is oxidized (oxidation state of Fe increases from 0 to +2)
Oxidizing agent is CuSO4 since it is reduced (oxidation state of Cu decreases from +2 to 0).
The acid associated with gastric acidity is hydrochloric acid (HCl)..pdf
The acid associated with gastric acidity is hydrochloric acid (HCl).
The two ions formed are the hydrogen ion (H+) and the chloride ion (Cl-):
HCl(aq) => H+(aq) + Cl-(aq)
Solution
The acid associated with gastric acidity is hydrochloric acid (HCl).
The two ions formed are the hydrogen ion (H+) and the chloride ion (Cl-):
HCl(aq) => H+(aq) + Cl-(aq).
Teacher.javaimport java.util.Arrays; import java.util.Scanner;.pdf
Teacher.java
import java.util.Arrays;
import java.util.Scanner;
public class Teacher {
//Creating Arrays
String names[]=new String[5];
char grades[]=new char[5];
double tests[][]=new double[5][4];
double avgarr[]=new double[5];
Scanner sc=null;
//Default constructor
public Teacher() {
sc=new Scanner(System.in);
}
/*this method will get each student information
* and populates that information into an array
*/
public void getStudentsTestScore()
{
for(int i=0;i<5;i++)
{
//getting the name of each student
System.out.print(\"Enter Name of Student \"+(i+1)+\" :\");
names[i]=sc.next();
for(int j=0;j<4;j++)
{
//Getting the test score in each test of every student
System.out.print(\" Test \"+(j+1)+\" score :\");
tests[i][j]=sc.nextDouble();
}
System.out.println(\" \");
}
}
/* this method will display the grade of the student
* based on user entered name which is passed
* as parameter to this method
*/
public char getStudentGrade(String name)
{
char grade = 0;
double sum,avg=0.0;
for(int h=0;h<5;h++)
{
sum=0.0;
for(int m=0;m<4;m++)
{
//calculating the total score in all 4 tests of each student
sum+=tests[h][m];
}
//calculating average
avg=sum/4;
//Populating into an array
avgarr[h]=avg;
//based on the average test score corresponding grade will be given
if(avg>=90 && avg<=100)
{
grade=\'A\';
}
else if(avg>=80 && avg<=89)
{
grade=\'B\';
}
else if(avg>=70 && avg<=79)
{
grade=\'C\';
}
else if(avg>=60 && avg<=69)
{
grade=\'D\';
}
else if(avg<=59)
{
grade=\'F\';
}
grades[h]=grade;
}
//Getting the corresponding student grade
for(int i=0;i<5;i++)
if(names[i].equalsIgnoreCase(name))
{
grade=grades[i];
}
return grade;
}
/* This will return the average test score of a student
* whose name is passed as parameter to this method
*/
public double getStudentAvgTestScore(String name)
{
double sum=0.0,avg=0.0;
for(int i=0;i<5;i++)
if(names[i].equalsIgnoreCase(name))
{
for(int k=0;k<4;k++)
{
sum+=tests[i][k];
}
}
avg=sum/4;
return avg;
}
//toString(0 method displays each student name,average test score and grade
@Override
public String toString() {
for(int i=0;i<5;i++)
{
System.out.println(\"\ \ Student Name :\"+names[i]);
System.out.println(\"Average Test Score :\"+avgarr[i]);
System.out.println(\"Grade :\"+grades[i]);
}
return \"\";
}
}
___________________________________________
TestClass.java
import java.util.Scanner;
public class TestClass {
public static void main(String[] args) {
//Scanner class object is sued to read th inputs entered by the user.
Scanner sc=new Scanner(System.in);
//Creating Teacher class Object
Teacher t=new Teacher();
/*calling the method on the Teacher class
* Which will read the data of every student entered by the user
*/
t.getStudentsTestScore();
//Getting the name of the student for which he want to display the grade
System.out.print(\"Enter Student Name for Grade :\");
String name=sc.next();
//Displaying particular student\'s Average test score
System.out.println(name +\" Average test score is :\"+t.getStudentAvgTestScore(name));
//Dis.
H2SO4(aq)+HNO3(aq)--HNO3(aq)+SO2(g)+H2O(l) .pdf
H2SO4(aq)+HNO3(aq)-->HNO3(aq)+SO2(g)+H2O(l)
Solution
H2SO4(aq)+HNO3(aq)-->HNO3(aq)+SO2(g)+H2O(l).
Since evolution of mammals followed a linear pattern of evolution ra.pdf
Since evolution of mammals followed a linear pattern of evolution rather than rapid
advancements and spontaneous spurts of fast evolution, gradualism evolution has most likely
happened in mammalian evolution.Gradualism evolutionPunctuated evolutionSpecies with a
longer evolution are evolved mostly by gradualism.Species with a shorter evolution are evolved
mostly by punctuated evolution.In Gradualism, the changes in species are slow and gradual,
occurring in small periodic changes in the gene pool.In Punctuated evolution, the evolution
occurs in spurts of relatively rapid change.To sum up, Gradualism evolution is considered as a
slow steady process in which organisms change and develop slowly over time.To sum up,
Punctuated evolution is considered as prolonged periods of no evolutionary change followed by
swift periods of change.
Solution
Since evolution of mammals followed a linear pattern of evolution rather than rapid
advancements and spontaneous spurts of fast evolution, gradualism evolution has most likely
happened in mammalian evolution.Gradualism evolutionPunctuated evolutionSpecies with a
longer evolution are evolved mostly by gradualism.Species with a shorter evolution are evolved
mostly by punctuated evolution.In Gradualism, the changes in species are slow and gradual,
occurring in small periodic changes in the gene pool.In Punctuated evolution, the evolution
occurs in spurts of relatively rapid change.To sum up, Gradualism evolution is considered as a
slow steady process in which organisms change and develop slowly over time.To sum up,
Punctuated evolution is considered as prolonged periods of no evolutionary change followed by
swift periods of change..
Polarity is measured on a scale of electronegativity (the electron d.pdf
Polarity is measured on a scale of electronegativity (the electron disparity between two elements
that are combined in a compound). The more electrons you take from your partner element in the
bonding process, the greater your negative charge, and the greater your electronegativity.
There are three terms to describe the polarity of a given molecular bond:
Ionic
Polar covalent
Non-polar covalent
Ionic is the most polar - essentially, one atom physically takes electrons from another atom,
creating a huge electron disparity between the two atoms. This tends to happen in molecules
where one atom has very few valence electrons and the other has a lot of valence electrons.
Sodium chloride (NaCl) is a good example of an ionic bond.
Polar covalent is the mid-range - technically closer to ionic. This happens when one atom
attempts to take electrons from its partner, but cannot quite attract them all to itself. The result is
a covalent bond between the two atoms where the valence electrons are \"shared,\" but the
sharing is unequal. One atom pulls the \"shared\" electrons a little closer to itself. Polar covalent
bonds usually occur between very electronegative elements; hydrogen paired with elements like
oxygen and fluorine almost always creates polar covalent bonds. A good example of a polar
covalent bond is found in water (H2O).
Non-polar covalent is the least polar - in fact, it is not polar at all. This occurs when valence
electrons are shared equally between two atoms. There is little or no tendency for either atom to
pull any of the electrons toward itself. Non-polar covalent bonds can often be seen in molecules
with two non-metals. Methane (CH4) is an example of a non-polar covalent bond.
Solution
Polarity is measured on a scale of electronegativity (the electron disparity between two elements
that are combined in a compound). The more electrons you take from your partner element in the
bonding process, the greater your negative charge, and the greater your electronegativity.
There are three terms to describe the polarity of a given molecular bond:
Ionic
Polar covalent
Non-polar covalent
Ionic is the most polar - essentially, one atom physically takes electrons from another atom,
creating a huge electron disparity between the two atoms. This tends to happen in molecules
where one atom has very few valence electrons and the other has a lot of valence electrons.
Sodium chloride (NaCl) is a good example of an ionic bond.
Polar covalent is the mid-range - technically closer to ionic. This happens when one atom
attempts to take electrons from its partner, but cannot quite attract them all to itself. The result is
a covalent bond between the two atoms where the valence electrons are \"shared,\" but the
sharing is unequal. One atom pulls the \"shared\" electrons a little closer to itself. Polar covalent
bonds usually occur between very electronegative elements; hydrogen paired with elements like
oxygen and fluorine almost always creates polar covalent.
pH = - log(H+) = 1.86concentration of H+ = 0.0138molLSolution.pdf
pH = - log(H+) = 1.86
concentration of H+ = 0.0138mol/L
Solution
pH = - log(H+) = 1.86
concentration of H+ = 0.0138mol/L.
Pathway 1 Under aerobic conditions, pyruvate is first converted int.pdf
Pathway 1: Under aerobic conditions, pyruvate is first converted into acetyl-CoA. The resultant
acetyl-CoA enters citric acid cycle. Citric acid yields a net gain of around 14 ATP (2.5 ATP per
NADH, and 1.5 ATP per FADH2) per pyruvate molecule.
Pathways 2: Under anaerobic condition (example- lactate fermentation in skeletal muscles,
ethanol fermentation in S. cereviseae, etc.), pyruvate enters fermentative pathways depending on
the organism, and sometime, the cultural conditions. Fermentation of pyruvate does not produce
ATP. However, it regenerates NAD+ required for glycolysis to keep going.
Solution
Pathway 1: Under aerobic conditions, pyruvate is first converted into acetyl-CoA. The resultant
acetyl-CoA enters citric acid cycle. Citric acid yields a net gain of around 14 ATP (2.5 ATP per
NADH, and 1.5 ATP per FADH2) per pyruvate molecule.
Pathways 2: Under anaerobic condition (example- lactate fermentation in skeletal muscles,
ethanol fermentation in S. cereviseae, etc.), pyruvate enters fermentative pathways depending on
the organism, and sometime, the cultural conditions. Fermentation of pyruvate does not produce
ATP. However, it regenerates NAD+ required for glycolysis to keep going..
MELTINGWhen you heat something faster, chances are youre hea.pdf
MELTING
When you heat something \"faster,\" chances are you\'re heating the substance way above its
melting point. Therefore, when it actually melts, you will get results showing that the melting
point is lower. In fact, your data is just inaccurate. You have to heat something slowly in order to
determine an accurate melting point. For instance, if I heated water at 1,000 degrees, it will start
to boil quickly, but if you were trying to measure it with a thermometer, you would have no idea
when it actually started to boil. Same goes with melting points. If you\'re heating it faster, it is
probably because you\'re setting the temperature very high and thus you will get inaccurate
results.
Don\'t forget that adding two substances together may form impurities in the mixture which will
result in lower melting points.
BOiling
There are basically two types of bonding in substances that affect the boiling point. Some
compounds are composed of extensive networks of atoms held together by either ionic or
covalent bonds. These network substances have very high melting and boiling points. NaCl is an
example of an ionic network and SiO2 is an example of a covalent network.
The key factors that affect the boiling points of molecular compounds are the intermolecular
forces which attract one molecule to another.
For covalent compounds these intermolecular forces are called van der Waals forces and consist
of hydrogen bonding, dipole-dipole attraction, and London dispersion forces. Hydrogen bonding
is usually stronger than dipole-dipole interactions. London dispersion forces, often weaker
forces, are found between all molecules, even if other van der Waals forces are present.
The boiling point of a solution is also affected by the ambient pressure. Boiling occurs at a
temperature where the vapor pressure of the liquid is equal to the ambient pressure.
The third thing that affects the boiling point of a solution is any substance that is dissolved in the
liquid. The more particles (ions or molecules) there are dissolved in the solution, the higher the
boiling point.
Solution
MELTING
When you heat something \"faster,\" chances are you\'re heating the substance way above its
melting point. Therefore, when it actually melts, you will get results showing that the melting
point is lower. In fact, your data is just inaccurate. You have to heat something slowly in order to
determine an accurate melting point. For instance, if I heated water at 1,000 degrees, it will start
to boil quickly, but if you were trying to measure it with a thermometer, you would have no idea
when it actually started to boil. Same goes with melting points. If you\'re heating it faster, it is
probably because you\'re setting the temperature very high and thus you will get inaccurate
results.
Don\'t forget that adding two substances together may form impurities in the mixture which will
result in lower melting points.
BOiling
There are basically two types of bonding in substances that affect th.
Let Universe has size n.Then set of disjoint sets will be {) and U.pdf
Let Universe has size n.
Then set of disjoint sets will be {) and U.
Next would be if S consist of one element, then T can be all subsets formed from remaining n-1
elements.
Hence every subset from one such T will make with S two disjoint sets.
No of subsets when S contains one element = (n)2n-1
When S contains 2 elements, then T is set of all subsets formed from remaining n-2
Hence no of subsets = nC2(2n-2)
and so on.
This continues till S has all n elements and T is null set.
Hence total no of disjoint sets = 1+n(2)n-1+nC2(2)n-2+...+nCn
=(1+2)n
= 3n
==================================================
b) If both have n/2 mean
no of sets =nC(n/2) 2n/2
----------------------------------------------------------------------------------------------------
c) If Both S and T have n/3
then n/3 can be selected for S in nC(n/3) ways
and for T n/3 elements can be selected from remaining 2n/3 in 2n/3 C (n/3) ways
Hence No of disjoint subsets S and T with n/3 elements each = nC(n/3)2n/3 C (n/3)
Solution
Let Universe has size n.
Then set of disjoint sets will be {) and U.
Next would be if S consist of one element, then T can be all subsets formed from remaining n-1
elements.
Hence every subset from one such T will make with S two disjoint sets.
No of subsets when S contains one element = (n)2n-1
When S contains 2 elements, then T is set of all subsets formed from remaining n-2
Hence no of subsets = nC2(2n-2)
and so on.
This continues till S has all n elements and T is null set.
Hence total no of disjoint sets = 1+n(2)n-1+nC2(2)n-2+...+nCn
=(1+2)n
= 3n
==================================================
b) If both have n/2 mean
no of sets =nC(n/2) 2n/2
----------------------------------------------------------------------------------------------------
c) If Both S and T have n/3
then n/3 can be selected for S in nC(n/3) ways
and for T n/3 elements can be selected from remaining 2n/3 in 2n/3 C (n/3) ways
Hence No of disjoint subsets S and T with n/3 elements each = nC(n/3)2n/3 C (n/3).
Keywords Infrastructure, Civil Engineering, Sustainable development.pdf
Keywords: Infrastructure, Civil Engineering, Sustainable development (etc.)
Infrastructure states to the fundamental facilities and structures serving a nation, city, or region,
including the services and facilities necessary for its economy to function. It typically
characterizes technical structures such as roads, sewers, tunnels, bridges, electrical grids, water
supply, and so forth, and can be defined as \"the physical components of integrated systems
providing commodities and facilities essential to enable, withstand, or enhance societal living
index.”
The term infrastructure may be confused with the following overlapping or related concepts.
Land improvement and land development are general expressions that in some circumstances
may include infrastructure, but in the context of an infrastructure would refer only to smaller
scale coordination or works that are not included in infrastructure, because they are typically
limited to a single parcel and are owned and operated by the vendor. For example, an irrigation
canal that serves a region or district would be included with infrastructure, but the private
irrigation systems on individual land parcels would be considered land improvements, not
infrastructure.
Scopes:
Engineering and construction
Engineers generally limit the term \"infrastructure\" to describe fixed assets that are in the form
of a large network, in other words, hard infrastructure. Efforts to devise more generic definitions
of infrastructures have typically stated to the network aspects of most of the structures, and to the
accrued value of investments in the networks as assets. One such definition from 1998 defined
infrastructure as the set-up of assets \"where the system as a whole is intended to be maintained
indefinitely at a specified standard of service by the continuing replacement and refurbishment of
its components\".
Civil defense and economic development
Civil defense planners and developmental economists generally refer to both hard and soft
infrastructure, including public amenities such as schools and hospitals, emergency services such
as police and firefighting, and basic financial facilities. The notion of Infrastructure-based
development merging enduring infrastructure investments by government agencies at central and
regional levels with public-private partnerships has proven popular among Asian - notably
Singaporean, Mainland European and Chinese & Latin American economists.
Urban
Urban or municipal infrastructure refers to hard infrastructure systems generally owned and ran
by municipalities, such as streets, water distribution, and sewers. It may also include some of the
facilities associated with soft infrastructures, such as parks, public pools, schools, hospitals, and
libraries.
Green infrastructure
Green infrastructure is a conception that highlights the significance of the natural environment in
decisions about land use planning. In particular, there are a prominence on the \"life support\"
funct.
If we have to invest certain money in a business and operate it. Out.pdf
If we have to invest certain money in a business and operate it. Out of all the legal forms of
businesses, ie. Sole Proprietorship, Partnership or Company, which we choice is \"Sole
Proprietorship\" or \"Sole trader\" because it is always to start a business at a small level. As the
name sugggests, these firms are owned by one person, who performs its day-to-day jobs.
Sole proprietors owns all the assets of the business, assumes all the liabilities and investments.
The person also owns the profits generated by the business. The owner have to secure all the
necessary licenses, tax identification numbers, and certifications of name.
The related advantages and dis-advantages of the sole proprietorship over the other forms of
business organisations are :
Advantages :
(1) Easiest and least expensive form of ownership to organize.
(2) Sole proprietor is in complete control of business and make decisions under the parameters of
the law.
(3) Sole proprietors receive all income and profits generated by the business.
(4) Profits from the business are entered and taxed directly through the owner\'s personal tax
return.
(5) The business under the sole proprietorship is easy to dissolve whenever desired.
Disadvantages :
(i) Sole proprietors have unlimited liability and are legally responsibility for all debts.
(ii) Proprietor can raise funds from personal savings or consumer loans.
(iii) Have a hard time while handling employees being alone superviso of the enterprise.
(iv) Federal income tax is being charged at the lower level under the Sole-proprietorship.
(v) The sole proprietor can transfer the business just by the sale of business net assets and do not
have face much difficulty in exiting in comparison to other forms like corporation or partnership.
===================================
Solution
If we have to invest certain money in a business and operate it. Out of all the legal forms of
businesses, ie. Sole Proprietorship, Partnership or Company, which we choice is \"Sole
Proprietorship\" or \"Sole trader\" because it is always to start a business at a small level. As the
name sugggests, these firms are owned by one person, who performs its day-to-day jobs.
Sole proprietors owns all the assets of the business, assumes all the liabilities and investments.
The person also owns the profits generated by the business. The owner have to secure all the
necessary licenses, tax identification numbers, and certifications of name.
The related advantages and dis-advantages of the sole proprietorship over the other forms of
business organisations are :
Advantages :
(1) Easiest and least expensive form of ownership to organize.
(2) Sole proprietor is in complete control of business and make decisions under the parameters of
the law.
(3) Sole proprietors receive all income and profits generated by the business.
(4) Profits from the business are entered and taxed directly through the owner\'s personal tax
return.
(5) The business under the sole proprietorship is eas.
Here hypo act as reducing agent and reduces iodine to sodium i.pdf
Here hypo act as reducing agent and reduces iodine to sodium iodide and stops the reactivity
towards electrophilic substitution which can be easily removable in water wash.I2 + 2
Na2S2O3 ==> 2 NaI + NaS4O6
Here hypo act as reducing agent and reduces iodine to sodium iodide and stops the reactivity
towards electrophilic substitution which can be easily removable in water wash.
Solution
Here hypo act as reducing agent and reduces iodine to sodium iodide and stops the reactivity
towards electrophilic substitution which can be easily removable in water wash.I2 + 2
Na2S2O3 ==> 2 NaI + NaS4O6
Here hypo act as reducing agent and reduces iodine to sodium iodide and stops the reactivity
towards electrophilic substitution which can be easily removable in water wash..
Hashingclass LinearProbingHashTable{ private int currentS.pdf
//Hashing
class LinearProbingHashTable
{
private int currentSize, max;
private String[] keys;
private String[] values;
public LinearProbingHashTable(int capacity)
{
currentSize = 0;
max = capacity;
keys = new String[max];
values = new String[max];
}
//Inserting using linearprobing
public void insert(String key, String val)
{
int temp = hash(key);
int i = temp;
do
{
if (keys[i] == null)
{
keys[i] = key;
vals[i] = value;
currentSize++;
return;
}
if (keys[i].equals(key))
{
vals[i] = value;
return;
}
i = (i + 1) % maxSize;
} while (i != tmp);
}
Solution
//Hashing
class LinearProbingHashTable
{
private int currentSize, max;
private String[] keys;
private String[] values;
public LinearProbingHashTable(int capacity)
{
currentSize = 0;
max = capacity;
keys = new String[max];
values = new String[max];
}
//Inserting using linearprobing
public void insert(String key, String val)
{
int temp = hash(key);
int i = temp;
do
{
if (keys[i] == null)
{
keys[i] = key;
vals[i] = value;
currentSize++;
return;
}
if (keys[i].equals(key))
{
vals[i] = value;
return;
}
i = (i + 1) % maxSize;
} while (i != tmp);
}.
Effusion rate = volumetime is inversely proportional to square root.pdf
Effusion rate = volume/time is inversely proportional to square root of molar mass
Since volume is constant:
Effusion time t is directly proportional to square root of molar mass M
t1/t2 = (M1/M2)0.5
5.37/3.55 = (M1/28.01)0.5
Molas mass of unknown gas M1 = 64.1 g/mol
Solution
Effusion rate = volume/time is inversely proportional to square root of molar mass
Since volume is constant:
Effusion time t is directly proportional to square root of molar mass M
t1/t2 = (M1/M2)0.5
5.37/3.55 = (M1/28.01)0.5
Molas mass of unknown gas M1 = 64.1 g/mol.
AnswerAnswer (a)Gilmour CompanyComparative Balance sheetAs o.pdf
Answer
Answer (a)
Gilmour Company
Comparative Balance sheet
As of December 31, 2015 and 2014
Figures in $
Assets
2015
%
2014
%
Cash
180000
5.39
275000
9.87
Accounts Receivables
220000
6.59
155000
5.57
Short term investments
270000
8.08
150000
5.39
Inventories
1060000
31.74
980000
35.19
Prepaid Expenses
25000
0.75
25000
0.90
Plant and Equipment
2585000
77.40
1950000
70.02
Accumulated Depreciation
-1000000
-29.94
-750000
-26.93
Total
3340000
100.00
2785000
100
Liabilities
Accounts payable
50,000
1.50
75000
2.69
Accrued Expenses
170000
5.09
200000
7.18
Bonds Payables
450000
13.47
190000
6.82
Capital Stock
2100000
62.87
1770000
63.55
Retained Earnings
570000
17.07
550000
19.75
Total
3340000
100
2785000
100
Answer (b)
Gilmour Company
Comparative Balance sheet
As of December 31, 2015 and 2014
Figures in $
Assets
2015
2014
Dollar Change
% Change
a
b
c
(a-b)
(c/b)*100
Cash
180000
275000
-95000
-34.55
Accounts Receivables
220000
155000
65000
41.94
Short term investments
270000
150000
120000
80.00
Inventories
1060000
980000
80000
8.16
Prepaid Expenses
25000
25000
0
0.00
Plant and Equipment
2585000
1950000
635000
32.56
Accumulated Depreciation
-1000000
-750000
-250000
33.33
Total
3340000
2785000
555000
19.93
Liabilities
Accounts payable
50,000
75000
-25000
-33.33
Accrued Expenses
170000
200000
-30000
-15.00
Bonds Payables
450000
190000
260000
136.84
Capital Stock
2100000
1770000
330000
18.64
Retained Earnings
570000
550000
20000
3.64
Total
3340000
2785000
555000
19.93
Answer (c)
Part (a) provides % change in each asset or liability head as of ‘whole balance sheet total’ in
current (2015) year and its comparison to the last (2014) year.
Answer (d)
Part (b) provides change in each asset or liability head in current (2015) year compared to last
(2014) year in absolute figure ($) terms and in % terms.
Gilmour Company
Comparative Balance sheet
As of December 31, 2015 and 2014
Figures in $
Assets
2015
%
2014
%
Cash
180000
5.39
275000
9.87
Accounts Receivables
220000
6.59
155000
5.57
Short term investments
270000
8.08
150000
5.39
Inventories
1060000
31.74
980000
35.19
Prepaid Expenses
25000
0.75
25000
0.90
Plant and Equipment
2585000
77.40
1950000
70.02
Accumulated Depreciation
-1000000
-29.94
-750000
-26.93
Total
3340000
100.00
2785000
100
Liabilities
Accounts payable
50,000
1.50
75000
2.69
Accrued Expenses
170000
5.09
200000
7.18
Bonds Payables
450000
13.47
190000
6.82
Capital Stock
2100000
62.87
1770000
63.55
Retained Earnings
570000
17.07
550000
19.75
Total
3340000
100
2785000
100
Solution
Answer
Answer (a)
Gilmour Company
Comparative Balance sheet
As of December 31, 2015 and 2014
Figures in $
Assets
2015
%
2014
%
Cash
180000
5.39
275000
9.87
Accounts Receivables
220000
6.59
155000
5.57
Short term investments
270000
8.08
150000
5.39
Inventories
1060000
31.74
980000
35.19
Prepaid Expenses
25000
0.75
25000
0.90
Plant and Equipment
2585000
77.40
1950000
70.02
Accumulated Depreciation
-1000000
-29.94
-750000
-26.93
Total
3340000
100.00
2785000
100
Liabilities
.
Answer1. A. CalloseThe sieve plate pore contain callose, in mat.pdf
Answer:
1. A. Callose
The sieve plate pore contain callose, in mature sieve areas callose deposition may be throughout
the plate. The deposition of neighboring sieve areas may coalesce to a single mass and from the
callose pad.
3). D. Stomata allow 300-400 times more CO2 into the leaf than the H2O they lose out of the
leaf
Carbon dioxide is needed for photosynthesis to operate. Unfortunately, much more water leaves
the leaf than CO2 enters for three reasons:
a) H2O molecules are smaller than CO2 molecules and so they move to their destination faster.
b) CO2 is only about 0.036% of the atmosphere (and rising!) so the gradient for its entry into the
plant is much smaller than the gradient for H2O moving from a hydrated leaf into a dry
atmosphere.
c) CO2 has a much longer distance to travel to reach its destination in the chloroplast from the
atmosphere compared to H2O which only has to move from the leaf cell surface to the
atmosphere.
4). B. The supply of proteins to the phloem sieve tube from the companion cell
The plasmodesmata allow the direct flow of small molecules such as sugars, amino acids, and
ions between cells. This allows direct cytoplasm-to-cytoplasm flow of water and other nutrients
along concentration gradients.Q. As proteins are large molecules, they are not transported by
plasmodesmata.
5). A. Symplastic loading with polymer trapping
Apoplastic loading is an active process, in which higher concentration of sucrose is pumped from
the apoplast into the transfer cells by transporters.
6). A. Glycolysis, mitochondrial import, succinate oxidation, oxidative phosphorylation
Solution
Answer:
1. A. Callose
The sieve plate pore contain callose, in mature sieve areas callose deposition may be throughout
the plate. The deposition of neighboring sieve areas may coalesce to a single mass and from the
callose pad.
3). D. Stomata allow 300-400 times more CO2 into the leaf than the H2O they lose out of the
leaf
Carbon dioxide is needed for photosynthesis to operate. Unfortunately, much more water leaves
the leaf than CO2 enters for three reasons:
a) H2O molecules are smaller than CO2 molecules and so they move to their destination faster.
b) CO2 is only about 0.036% of the atmosphere (and rising!) so the gradient for its entry into the
plant is much smaller than the gradient for H2O moving from a hydrated leaf into a dry
atmosphere.
c) CO2 has a much longer distance to travel to reach its destination in the chloroplast from the
atmosphere compared to H2O which only has to move from the leaf cell surface to the
atmosphere.
4). B. The supply of proteins to the phloem sieve tube from the companion cell
The plasmodesmata allow the direct flow of small molecules such as sugars, amino acids, and
ions between cells. This allows direct cytoplasm-to-cytoplasm flow of water and other nutrients
along concentration gradients.Q. As proteins are large molecules, they are not transported by
plasmodesmata.
5). A. Symplastic loading with polymer trapping
Apop.
AnsCommon name of organism (Genus)Type of organismProducer or.pdf
Ans:
Common name of organism (Genus)
Type of organism
Producer or consumer
Filter feeder? (yes/no)
Stationary or mobile
Nori seaweed
Algae
producer
yes
Stationary
Black pine
Algae
producer
Yes
Stationary
Coral weed
Algae
producer
No
Stationary
Mussel
Mollusk
Consumer
Yes
Stationary
Acorn Barnacle
Crustacean
Consumer
Yes
Stationary
Goose Neck Barnacle
Crustacean
Consumer
Yes
Stationary
whelk
Mollusk
Consumer
Yes
Mobile
Chiton
Mollusk
Consumer
No
Mobile
starfish
Echinoderm
Consumer
Yes
Mobile
Common name of organism (Genus)
Type of organism
Producer or consumer
Filter feeder? (yes/no)
Stationary or mobile
Nori seaweed
Algae
producer
yes
Stationary
Black pine
Algae
producer
Yes
Stationary
Coral weed
Algae
producer
No
Stationary
Mussel
Mollusk
Consumer
Yes
Stationary
Acorn Barnacle
Crustacean
Consumer
Yes
Stationary
Goose Neck Barnacle
Crustacean
Consumer
Yes
Stationary
whelk
Mollusk
Consumer
Yes
Mobile
Chiton
Mollusk
Consumer
No
Mobile
starfish
Echinoderm
Consumer
Yes
Mobile
Solution
Ans:
Common name of organism (Genus)
Type of organism
Producer or consumer
Filter feeder? (yes/no)
Stationary or mobile
Nori seaweed
Algae
producer
yes
Stationary
Black pine
Algae
producer
Yes
Stationary
Coral weed
Algae
producer
No
Stationary
Mussel
Mollusk
Consumer
Yes
Stationary
Acorn Barnacle
Crustacean
Consumer
Yes
Stationary
Goose Neck Barnacle
Crustacean
Consumer
Yes
Stationary
whelk
Mollusk
Consumer
Yes
Mobile
Chiton
Mollusk
Consumer
No
Mobile
starfish
Echinoderm
Consumer
Yes
Mobile
Common name of organism (Genus)
Type of organism
Producer or consumer
Filter feeder? (yes/no)
Stationary or mobile
Nori seaweed
Algae
producer
yes
Stationary
Black pine
Algae
producer
Yes
Stationary
Coral weed
Algae
producer
No
Stationary
Mussel
Mollusk
Consumer
Yes
Stationary
Acorn Barnacle
Crustacean
Consumer
Yes
Stationary
Goose Neck Barnacle
Crustacean
Consumer
Yes
Stationary
whelk
Mollusk
Consumer
Yes
Mobile
Chiton
Mollusk
Consumer
No
Mobile
starfish
Echinoderm
Consumer
Yes
Mobile.
1) A router2) Converged3) SSH4) Use the console port to locall.pdf
1) A router
2) Converged
3) SSH
4) Use the console port to locally access the switch from a serial or USB interface of the PC
5) all layers of TCP/IP model
Solution
1) A router
2) Converged
3) SSH
4) Use the console port to locally access the switch from a serial or USB interface of the PC
5) all layers of TCP/IP model.
1) Fraud traingle comprise of percieved opportunity , pressure and r.pdf
1) Fraud traingle comprise of percieved opportunity , pressure and rationalisation
Pine had the opprotunity to embezzle as he was sole resposible for payroll accounting , was
trusted and had control over bank accounts.Also he had the pressure of supporting his three kids
and high credit cards balances, Rationalised the situation in which he could create fake accounts
2)According to Steve Alrecht\'s scale-High personal debt ( personal characterstic), Too much
trust(risk factor),Fraud opportunity when pressure is high , opportunity is more adn personal
intergrity is low.
3)According to Hollinger and Clark there are five interrelated sets - first being the economic
pressure, second the young ones are more likely to theft, third every employer can be tempted to
steal, fourth being jon dissatisfaction anfd fifth being theft occurs because of shared formal and
informal organisation structure. they believe theft are most likely to occur where employees are
have more access , there is less control.
4)They conducted internal audit when the accountant had trouble reconciling the accounts.
5)Segregation of duties- one person should not be made responsible for accounting and payment
of payrolls, there should be effective controls like internal audit.
Solution
1) Fraud traingle comprise of percieved opportunity , pressure and rationalisation
Pine had the opprotunity to embezzle as he was sole resposible for payroll accounting , was
trusted and had control over bank accounts.Also he had the pressure of supporting his three kids
and high credit cards balances, Rationalised the situation in which he could create fake accounts
2)According to Steve Alrecht\'s scale-High personal debt ( personal characterstic), Too much
trust(risk factor),Fraud opportunity when pressure is high , opportunity is more adn personal
intergrity is low.
3)According to Hollinger and Clark there are five interrelated sets - first being the economic
pressure, second the young ones are more likely to theft, third every employer can be tempted to
steal, fourth being jon dissatisfaction anfd fifth being theft occurs because of shared formal and
informal organisation structure. they believe theft are most likely to occur where employees are
have more access , there is less control.
4)They conducted internal audit when the accountant had trouble reconciling the accounts.
5)Segregation of duties- one person should not be made responsible for accounting and payment
of payrolls, there should be effective controls like internal audit..
The French Revolution Class 9 Study Material pdf free download
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
Supporting (UKRI) OA monographs at Salford.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
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The balanced equation isFe + CuSO4 = FeSO4 + CuReducing agent .pdf
The balanced equation is:
Fe + CuSO4 => FeSO4 + Cu
Reducing agent is Fe since it is oxidized (oxidation state of Fe increases from 0 to +2)
Oxidizing agent is CuSO4 since it is reduced (oxidation state of Cu decreases from +2 to 0)
Solution
The balanced equation is:
Fe + CuSO4 => FeSO4 + Cu
Reducing agent is Fe since it is oxidized (oxidation state of Fe increases from 0 to +2)
Oxidizing agent is CuSO4 since it is reduced (oxidation state of Cu decreases from +2 to 0).
The acid associated with gastric acidity is hydrochloric acid (HCl)..pdf
The acid associated with gastric acidity is hydrochloric acid (HCl).
The two ions formed are the hydrogen ion (H+) and the chloride ion (Cl-):
HCl(aq) => H+(aq) + Cl-(aq)
Solution
The acid associated with gastric acidity is hydrochloric acid (HCl).
The two ions formed are the hydrogen ion (H+) and the chloride ion (Cl-):
HCl(aq) => H+(aq) + Cl-(aq).
Teacher.javaimport java.util.Arrays; import java.util.Scanner;.pdf
Teacher.java
import java.util.Arrays;
import java.util.Scanner;
public class Teacher {
//Creating Arrays
String names[]=new String[5];
char grades[]=new char[5];
double tests[][]=new double[5][4];
double avgarr[]=new double[5];
Scanner sc=null;
//Default constructor
public Teacher() {
sc=new Scanner(System.in);
}
/*this method will get each student information
* and populates that information into an array
*/
public void getStudentsTestScore()
{
for(int i=0;i<5;i++)
{
//getting the name of each student
System.out.print(\"Enter Name of Student \"+(i+1)+\" :\");
names[i]=sc.next();
for(int j=0;j<4;j++)
{
//Getting the test score in each test of every student
System.out.print(\" Test \"+(j+1)+\" score :\");
tests[i][j]=sc.nextDouble();
}
System.out.println(\" \");
}
}
/* this method will display the grade of the student
* based on user entered name which is passed
* as parameter to this method
*/
public char getStudentGrade(String name)
{
char grade = 0;
double sum,avg=0.0;
for(int h=0;h<5;h++)
{
sum=0.0;
for(int m=0;m<4;m++)
{
//calculating the total score in all 4 tests of each student
sum+=tests[h][m];
}
//calculating average
avg=sum/4;
//Populating into an array
avgarr[h]=avg;
//based on the average test score corresponding grade will be given
if(avg>=90 && avg<=100)
{
grade=\'A\';
}
else if(avg>=80 && avg<=89)
{
grade=\'B\';
}
else if(avg>=70 && avg<=79)
{
grade=\'C\';
}
else if(avg>=60 && avg<=69)
{
grade=\'D\';
}
else if(avg<=59)
{
grade=\'F\';
}
grades[h]=grade;
}
//Getting the corresponding student grade
for(int i=0;i<5;i++)
if(names[i].equalsIgnoreCase(name))
{
grade=grades[i];
}
return grade;
}
/* This will return the average test score of a student
* whose name is passed as parameter to this method
*/
public double getStudentAvgTestScore(String name)
{
double sum=0.0,avg=0.0;
for(int i=0;i<5;i++)
if(names[i].equalsIgnoreCase(name))
{
for(int k=0;k<4;k++)
{
sum+=tests[i][k];
}
}
avg=sum/4;
return avg;
}
//toString(0 method displays each student name,average test score and grade
@Override
public String toString() {
for(int i=0;i<5;i++)
{
System.out.println(\"\ \ Student Name :\"+names[i]);
System.out.println(\"Average Test Score :\"+avgarr[i]);
System.out.println(\"Grade :\"+grades[i]);
}
return \"\";
}
}
___________________________________________
TestClass.java
import java.util.Scanner;
public class TestClass {
public static void main(String[] args) {
//Scanner class object is sued to read th inputs entered by the user.
Scanner sc=new Scanner(System.in);
//Creating Teacher class Object
Teacher t=new Teacher();
/*calling the method on the Teacher class
* Which will read the data of every student entered by the user
*/
t.getStudentsTestScore();
//Getting the name of the student for which he want to display the grade
System.out.print(\"Enter Student Name for Grade :\");
String name=sc.next();
//Displaying particular student\'s Average test score
System.out.println(name +\" Average test score is :\"+t.getStudentAvgTestScore(name));
//Dis.
H2SO4(aq)+HNO3(aq)--HNO3(aq)+SO2(g)+H2O(l) .pdf
H2SO4(aq)+HNO3(aq)-->HNO3(aq)+SO2(g)+H2O(l)
Solution
H2SO4(aq)+HNO3(aq)-->HNO3(aq)+SO2(g)+H2O(l).
Since evolution of mammals followed a linear pattern of evolution ra.pdf
Since evolution of mammals followed a linear pattern of evolution rather than rapid
advancements and spontaneous spurts of fast evolution, gradualism evolution has most likely
happened in mammalian evolution.Gradualism evolutionPunctuated evolutionSpecies with a
longer evolution are evolved mostly by gradualism.Species with a shorter evolution are evolved
mostly by punctuated evolution.In Gradualism, the changes in species are slow and gradual,
occurring in small periodic changes in the gene pool.In Punctuated evolution, the evolution
occurs in spurts of relatively rapid change.To sum up, Gradualism evolution is considered as a
slow steady process in which organisms change and develop slowly over time.To sum up,
Punctuated evolution is considered as prolonged periods of no evolutionary change followed by
swift periods of change.
Solution
Since evolution of mammals followed a linear pattern of evolution rather than rapid
advancements and spontaneous spurts of fast evolution, gradualism evolution has most likely
happened in mammalian evolution.Gradualism evolutionPunctuated evolutionSpecies with a
longer evolution are evolved mostly by gradualism.Species with a shorter evolution are evolved
mostly by punctuated evolution.In Gradualism, the changes in species are slow and gradual,
occurring in small periodic changes in the gene pool.In Punctuated evolution, the evolution
occurs in spurts of relatively rapid change.To sum up, Gradualism evolution is considered as a
slow steady process in which organisms change and develop slowly over time.To sum up,
Punctuated evolution is considered as prolonged periods of no evolutionary change followed by
swift periods of change..
Polarity is measured on a scale of electronegativity (the electron d.pdf
Polarity is measured on a scale of electronegativity (the electron disparity between two elements
that are combined in a compound). The more electrons you take from your partner element in the
bonding process, the greater your negative charge, and the greater your electronegativity.
There are three terms to describe the polarity of a given molecular bond:
Ionic
Polar covalent
Non-polar covalent
Ionic is the most polar - essentially, one atom physically takes electrons from another atom,
creating a huge electron disparity between the two atoms. This tends to happen in molecules
where one atom has very few valence electrons and the other has a lot of valence electrons.
Sodium chloride (NaCl) is a good example of an ionic bond.
Polar covalent is the mid-range - technically closer to ionic. This happens when one atom
attempts to take electrons from its partner, but cannot quite attract them all to itself. The result is
a covalent bond between the two atoms where the valence electrons are \"shared,\" but the
sharing is unequal. One atom pulls the \"shared\" electrons a little closer to itself. Polar covalent
bonds usually occur between very electronegative elements; hydrogen paired with elements like
oxygen and fluorine almost always creates polar covalent bonds. A good example of a polar
covalent bond is found in water (H2O).
Non-polar covalent is the least polar - in fact, it is not polar at all. This occurs when valence
electrons are shared equally between two atoms. There is little or no tendency for either atom to
pull any of the electrons toward itself. Non-polar covalent bonds can often be seen in molecules
with two non-metals. Methane (CH4) is an example of a non-polar covalent bond.
Solution
Polarity is measured on a scale of electronegativity (the electron disparity between two elements
that are combined in a compound). The more electrons you take from your partner element in the
bonding process, the greater your negative charge, and the greater your electronegativity.
There are three terms to describe the polarity of a given molecular bond:
Ionic
Polar covalent
Non-polar covalent
Ionic is the most polar - essentially, one atom physically takes electrons from another atom,
creating a huge electron disparity between the two atoms. This tends to happen in molecules
where one atom has very few valence electrons and the other has a lot of valence electrons.
Sodium chloride (NaCl) is a good example of an ionic bond.
Polar covalent is the mid-range - technically closer to ionic. This happens when one atom
attempts to take electrons from its partner, but cannot quite attract them all to itself. The result is
a covalent bond between the two atoms where the valence electrons are \"shared,\" but the
sharing is unequal. One atom pulls the \"shared\" electrons a little closer to itself. Polar covalent
bonds usually occur between very electronegative elements; hydrogen paired with elements like
oxygen and fluorine almost always creates polar covalent.
pH = - log(H+) = 1.86concentration of H+ = 0.0138molLSolution.pdf
pH = - log(H+) = 1.86
concentration of H+ = 0.0138mol/L
Solution
pH = - log(H+) = 1.86
concentration of H+ = 0.0138mol/L.
Pathway 1 Under aerobic conditions, pyruvate is first converted int.pdf
Pathway 1: Under aerobic conditions, pyruvate is first converted into acetyl-CoA. The resultant
acetyl-CoA enters citric acid cycle. Citric acid yields a net gain of around 14 ATP (2.5 ATP per
NADH, and 1.5 ATP per FADH2) per pyruvate molecule.
Pathways 2: Under anaerobic condition (example- lactate fermentation in skeletal muscles,
ethanol fermentation in S. cereviseae, etc.), pyruvate enters fermentative pathways depending on
the organism, and sometime, the cultural conditions. Fermentation of pyruvate does not produce
ATP. However, it regenerates NAD+ required for glycolysis to keep going.
Solution
Pathway 1: Under aerobic conditions, pyruvate is first converted into acetyl-CoA. The resultant
acetyl-CoA enters citric acid cycle. Citric acid yields a net gain of around 14 ATP (2.5 ATP per
NADH, and 1.5 ATP per FADH2) per pyruvate molecule.
Pathways 2: Under anaerobic condition (example- lactate fermentation in skeletal muscles,
ethanol fermentation in S. cereviseae, etc.), pyruvate enters fermentative pathways depending on
the organism, and sometime, the cultural conditions. Fermentation of pyruvate does not produce
ATP. However, it regenerates NAD+ required for glycolysis to keep going..
MELTINGWhen you heat something faster, chances are youre hea.pdf
MELTING
When you heat something \"faster,\" chances are you\'re heating the substance way above its
melting point. Therefore, when it actually melts, you will get results showing that the melting
point is lower. In fact, your data is just inaccurate. You have to heat something slowly in order to
determine an accurate melting point. For instance, if I heated water at 1,000 degrees, it will start
to boil quickly, but if you were trying to measure it with a thermometer, you would have no idea
when it actually started to boil. Same goes with melting points. If you\'re heating it faster, it is
probably because you\'re setting the temperature very high and thus you will get inaccurate
results.
Don\'t forget that adding two substances together may form impurities in the mixture which will
result in lower melting points.
BOiling
There are basically two types of bonding in substances that affect the boiling point. Some
compounds are composed of extensive networks of atoms held together by either ionic or
covalent bonds. These network substances have very high melting and boiling points. NaCl is an
example of an ionic network and SiO2 is an example of a covalent network.
The key factors that affect the boiling points of molecular compounds are the intermolecular
forces which attract one molecule to another.
For covalent compounds these intermolecular forces are called van der Waals forces and consist
of hydrogen bonding, dipole-dipole attraction, and London dispersion forces. Hydrogen bonding
is usually stronger than dipole-dipole interactions. London dispersion forces, often weaker
forces, are found between all molecules, even if other van der Waals forces are present.
The boiling point of a solution is also affected by the ambient pressure. Boiling occurs at a
temperature where the vapor pressure of the liquid is equal to the ambient pressure.
The third thing that affects the boiling point of a solution is any substance that is dissolved in the
liquid. The more particles (ions or molecules) there are dissolved in the solution, the higher the
boiling point.
Solution
MELTING
When you heat something \"faster,\" chances are you\'re heating the substance way above its
melting point. Therefore, when it actually melts, you will get results showing that the melting
point is lower. In fact, your data is just inaccurate. You have to heat something slowly in order to
determine an accurate melting point. For instance, if I heated water at 1,000 degrees, it will start
to boil quickly, but if you were trying to measure it with a thermometer, you would have no idea
when it actually started to boil. Same goes with melting points. If you\'re heating it faster, it is
probably because you\'re setting the temperature very high and thus you will get inaccurate
results.
Don\'t forget that adding two substances together may form impurities in the mixture which will
result in lower melting points.
BOiling
There are basically two types of bonding in substances that affect th.
Let Universe has size n.Then set of disjoint sets will be {) and U.pdf
Let Universe has size n.
Then set of disjoint sets will be {) and U.
Next would be if S consist of one element, then T can be all subsets formed from remaining n-1
elements.
Hence every subset from one such T will make with S two disjoint sets.
No of subsets when S contains one element = (n)2n-1
When S contains 2 elements, then T is set of all subsets formed from remaining n-2
Hence no of subsets = nC2(2n-2)
and so on.
This continues till S has all n elements and T is null set.
Hence total no of disjoint sets = 1+n(2)n-1+nC2(2)n-2+...+nCn
=(1+2)n
= 3n
==================================================
b) If both have n/2 mean
no of sets =nC(n/2) 2n/2
----------------------------------------------------------------------------------------------------
c) If Both S and T have n/3
then n/3 can be selected for S in nC(n/3) ways
and for T n/3 elements can be selected from remaining 2n/3 in 2n/3 C (n/3) ways
Hence No of disjoint subsets S and T with n/3 elements each = nC(n/3)2n/3 C (n/3)
Solution
Let Universe has size n.
Then set of disjoint sets will be {) and U.
Next would be if S consist of one element, then T can be all subsets formed from remaining n-1
elements.
Hence every subset from one such T will make with S two disjoint sets.
No of subsets when S contains one element = (n)2n-1
When S contains 2 elements, then T is set of all subsets formed from remaining n-2
Hence no of subsets = nC2(2n-2)
and so on.
This continues till S has all n elements and T is null set.
Hence total no of disjoint sets = 1+n(2)n-1+nC2(2)n-2+...+nCn
=(1+2)n
= 3n
==================================================
b) If both have n/2 mean
no of sets =nC(n/2) 2n/2
----------------------------------------------------------------------------------------------------
c) If Both S and T have n/3
then n/3 can be selected for S in nC(n/3) ways
and for T n/3 elements can be selected from remaining 2n/3 in 2n/3 C (n/3) ways
Hence No of disjoint subsets S and T with n/3 elements each = nC(n/3)2n/3 C (n/3).
Keywords Infrastructure, Civil Engineering, Sustainable development.pdf
Keywords: Infrastructure, Civil Engineering, Sustainable development (etc.)
Infrastructure states to the fundamental facilities and structures serving a nation, city, or region,
including the services and facilities necessary for its economy to function. It typically
characterizes technical structures such as roads, sewers, tunnels, bridges, electrical grids, water
supply, and so forth, and can be defined as \"the physical components of integrated systems
providing commodities and facilities essential to enable, withstand, or enhance societal living
index.”
The term infrastructure may be confused with the following overlapping or related concepts.
Land improvement and land development are general expressions that in some circumstances
may include infrastructure, but in the context of an infrastructure would refer only to smaller
scale coordination or works that are not included in infrastructure, because they are typically
limited to a single parcel and are owned and operated by the vendor. For example, an irrigation
canal that serves a region or district would be included with infrastructure, but the private
irrigation systems on individual land parcels would be considered land improvements, not
infrastructure.
Scopes:
Engineering and construction
Engineers generally limit the term \"infrastructure\" to describe fixed assets that are in the form
of a large network, in other words, hard infrastructure. Efforts to devise more generic definitions
of infrastructures have typically stated to the network aspects of most of the structures, and to the
accrued value of investments in the networks as assets. One such definition from 1998 defined
infrastructure as the set-up of assets \"where the system as a whole is intended to be maintained
indefinitely at a specified standard of service by the continuing replacement and refurbishment of
its components\".
Civil defense and economic development
Civil defense planners and developmental economists generally refer to both hard and soft
infrastructure, including public amenities such as schools and hospitals, emergency services such
as police and firefighting, and basic financial facilities. The notion of Infrastructure-based
development merging enduring infrastructure investments by government agencies at central and
regional levels with public-private partnerships has proven popular among Asian - notably
Singaporean, Mainland European and Chinese & Latin American economists.
Urban
Urban or municipal infrastructure refers to hard infrastructure systems generally owned and ran
by municipalities, such as streets, water distribution, and sewers. It may also include some of the
facilities associated with soft infrastructures, such as parks, public pools, schools, hospitals, and
libraries.
Green infrastructure
Green infrastructure is a conception that highlights the significance of the natural environment in
decisions about land use planning. In particular, there are a prominence on the \"life support\"
funct.
If we have to invest certain money in a business and operate it. Out.pdf
If we have to invest certain money in a business and operate it. Out of all the legal forms of
businesses, ie. Sole Proprietorship, Partnership or Company, which we choice is \"Sole
Proprietorship\" or \"Sole trader\" because it is always to start a business at a small level. As the
name sugggests, these firms are owned by one person, who performs its day-to-day jobs.
Sole proprietors owns all the assets of the business, assumes all the liabilities and investments.
The person also owns the profits generated by the business. The owner have to secure all the
necessary licenses, tax identification numbers, and certifications of name.
The related advantages and dis-advantages of the sole proprietorship over the other forms of
business organisations are :
Advantages :
(1) Easiest and least expensive form of ownership to organize.
(2) Sole proprietor is in complete control of business and make decisions under the parameters of
the law.
(3) Sole proprietors receive all income and profits generated by the business.
(4) Profits from the business are entered and taxed directly through the owner\'s personal tax
return.
(5) The business under the sole proprietorship is easy to dissolve whenever desired.
Disadvantages :
(i) Sole proprietors have unlimited liability and are legally responsibility for all debts.
(ii) Proprietor can raise funds from personal savings or consumer loans.
(iii) Have a hard time while handling employees being alone superviso of the enterprise.
(iv) Federal income tax is being charged at the lower level under the Sole-proprietorship.
(v) The sole proprietor can transfer the business just by the sale of business net assets and do not
have face much difficulty in exiting in comparison to other forms like corporation or partnership.
===================================
Solution
If we have to invest certain money in a business and operate it. Out of all the legal forms of
businesses, ie. Sole Proprietorship, Partnership or Company, which we choice is \"Sole
Proprietorship\" or \"Sole trader\" because it is always to start a business at a small level. As the
name sugggests, these firms are owned by one person, who performs its day-to-day jobs.
Sole proprietors owns all the assets of the business, assumes all the liabilities and investments.
The person also owns the profits generated by the business. The owner have to secure all the
necessary licenses, tax identification numbers, and certifications of name.
The related advantages and dis-advantages of the sole proprietorship over the other forms of
business organisations are :
Advantages :
(1) Easiest and least expensive form of ownership to organize.
(2) Sole proprietor is in complete control of business and make decisions under the parameters of
the law.
(3) Sole proprietors receive all income and profits generated by the business.
(4) Profits from the business are entered and taxed directly through the owner\'s personal tax
return.
(5) The business under the sole proprietorship is eas.
Here hypo act as reducing agent and reduces iodine to sodium i.pdf
Here hypo act as reducing agent and reduces iodine to sodium iodide and stops the reactivity
towards electrophilic substitution which can be easily removable in water wash.I2 + 2
Na2S2O3 ==> 2 NaI + NaS4O6
Here hypo act as reducing agent and reduces iodine to sodium iodide and stops the reactivity
towards electrophilic substitution which can be easily removable in water wash.
Solution
Here hypo act as reducing agent and reduces iodine to sodium iodide and stops the reactivity
towards electrophilic substitution which can be easily removable in water wash.I2 + 2
Na2S2O3 ==> 2 NaI + NaS4O6
Here hypo act as reducing agent and reduces iodine to sodium iodide and stops the reactivity
towards electrophilic substitution which can be easily removable in water wash..
Hashingclass LinearProbingHashTable{ private int currentS.pdf
//Hashing
class LinearProbingHashTable
{
private int currentSize, max;
private String[] keys;
private String[] values;
public LinearProbingHashTable(int capacity)
{
currentSize = 0;
max = capacity;
keys = new String[max];
values = new String[max];
}
//Inserting using linearprobing
public void insert(String key, String val)
{
int temp = hash(key);
int i = temp;
do
{
if (keys[i] == null)
{
keys[i] = key;
vals[i] = value;
currentSize++;
return;
}
if (keys[i].equals(key))
{
vals[i] = value;
return;
}
i = (i + 1) % maxSize;
} while (i != tmp);
}
Solution
//Hashing
class LinearProbingHashTable
{
private int currentSize, max;
private String[] keys;
private String[] values;
public LinearProbingHashTable(int capacity)
{
currentSize = 0;
max = capacity;
keys = new String[max];
values = new String[max];
}
//Inserting using linearprobing
public void insert(String key, String val)
{
int temp = hash(key);
int i = temp;
do
{
if (keys[i] == null)
{
keys[i] = key;
vals[i] = value;
currentSize++;
return;
}
if (keys[i].equals(key))
{
vals[i] = value;
return;
}
i = (i + 1) % maxSize;
} while (i != tmp);
}.
Effusion rate = volumetime is inversely proportional to square root.pdf
Effusion rate = volume/time is inversely proportional to square root of molar mass
Since volume is constant:
Effusion time t is directly proportional to square root of molar mass M
t1/t2 = (M1/M2)0.5
5.37/3.55 = (M1/28.01)0.5
Molas mass of unknown gas M1 = 64.1 g/mol
Solution
Effusion rate = volume/time is inversely proportional to square root of molar mass
Since volume is constant:
Effusion time t is directly proportional to square root of molar mass M
t1/t2 = (M1/M2)0.5
5.37/3.55 = (M1/28.01)0.5
Molas mass of unknown gas M1 = 64.1 g/mol.
AnswerAnswer (a)Gilmour CompanyComparative Balance sheetAs o.pdf
Answer
Answer (a)
Gilmour Company
Comparative Balance sheet
As of December 31, 2015 and 2014
Figures in $
Assets
2015
%
2014
%
Cash
180000
5.39
275000
9.87
Accounts Receivables
220000
6.59
155000
5.57
Short term investments
270000
8.08
150000
5.39
Inventories
1060000
31.74
980000
35.19
Prepaid Expenses
25000
0.75
25000
0.90
Plant and Equipment
2585000
77.40
1950000
70.02
Accumulated Depreciation
-1000000
-29.94
-750000
-26.93
Total
3340000
100.00
2785000
100
Liabilities
Accounts payable
50,000
1.50
75000
2.69
Accrued Expenses
170000
5.09
200000
7.18
Bonds Payables
450000
13.47
190000
6.82
Capital Stock
2100000
62.87
1770000
63.55
Retained Earnings
570000
17.07
550000
19.75
Total
3340000
100
2785000
100
Answer (b)
Gilmour Company
Comparative Balance sheet
As of December 31, 2015 and 2014
Figures in $
Assets
2015
2014
Dollar Change
% Change
a
b
c
(a-b)
(c/b)*100
Cash
180000
275000
-95000
-34.55
Accounts Receivables
220000
155000
65000
41.94
Short term investments
270000
150000
120000
80.00
Inventories
1060000
980000
80000
8.16
Prepaid Expenses
25000
25000
0
0.00
Plant and Equipment
2585000
1950000
635000
32.56
Accumulated Depreciation
-1000000
-750000
-250000
33.33
Total
3340000
2785000
555000
19.93
Liabilities
Accounts payable
50,000
75000
-25000
-33.33
Accrued Expenses
170000
200000
-30000
-15.00
Bonds Payables
450000
190000
260000
136.84
Capital Stock
2100000
1770000
330000
18.64
Retained Earnings
570000
550000
20000
3.64
Total
3340000
2785000
555000
19.93
Answer (c)
Part (a) provides % change in each asset or liability head as of ‘whole balance sheet total’ in
current (2015) year and its comparison to the last (2014) year.
Answer (d)
Part (b) provides change in each asset or liability head in current (2015) year compared to last
(2014) year in absolute figure ($) terms and in % terms.
Gilmour Company
Comparative Balance sheet
As of December 31, 2015 and 2014
Figures in $
Assets
2015
%
2014
%
Cash
180000
5.39
275000
9.87
Accounts Receivables
220000
6.59
155000
5.57
Short term investments
270000
8.08
150000
5.39
Inventories
1060000
31.74
980000
35.19
Prepaid Expenses
25000
0.75
25000
0.90
Plant and Equipment
2585000
77.40
1950000
70.02
Accumulated Depreciation
-1000000
-29.94
-750000
-26.93
Total
3340000
100.00
2785000
100
Liabilities
Accounts payable
50,000
1.50
75000
2.69
Accrued Expenses
170000
5.09
200000
7.18
Bonds Payables
450000
13.47
190000
6.82
Capital Stock
2100000
62.87
1770000
63.55
Retained Earnings
570000
17.07
550000
19.75
Total
3340000
100
2785000
100
Solution
Answer
Answer (a)
Gilmour Company
Comparative Balance sheet
As of December 31, 2015 and 2014
Figures in $
Assets
2015
%
2014
%
Cash
180000
5.39
275000
9.87
Accounts Receivables
220000
6.59
155000
5.57
Short term investments
270000
8.08
150000
5.39
Inventories
1060000
31.74
980000
35.19
Prepaid Expenses
25000
0.75
25000
0.90
Plant and Equipment
2585000
77.40
1950000
70.02
Accumulated Depreciation
-1000000
-29.94
-750000
-26.93
Total
3340000
100.00
2785000
100
Liabilities
.
Answer1. A. CalloseThe sieve plate pore contain callose, in mat.pdf
Answer:
1. A. Callose
The sieve plate pore contain callose, in mature sieve areas callose deposition may be throughout
the plate. The deposition of neighboring sieve areas may coalesce to a single mass and from the
callose pad.
3). D. Stomata allow 300-400 times more CO2 into the leaf than the H2O they lose out of the
leaf
Carbon dioxide is needed for photosynthesis to operate. Unfortunately, much more water leaves
the leaf than CO2 enters for three reasons:
a) H2O molecules are smaller than CO2 molecules and so they move to their destination faster.
b) CO2 is only about 0.036% of the atmosphere (and rising!) so the gradient for its entry into the
plant is much smaller than the gradient for H2O moving from a hydrated leaf into a dry
atmosphere.
c) CO2 has a much longer distance to travel to reach its destination in the chloroplast from the
atmosphere compared to H2O which only has to move from the leaf cell surface to the
atmosphere.
4). B. The supply of proteins to the phloem sieve tube from the companion cell
The plasmodesmata allow the direct flow of small molecules such as sugars, amino acids, and
ions between cells. This allows direct cytoplasm-to-cytoplasm flow of water and other nutrients
along concentration gradients.Q. As proteins are large molecules, they are not transported by
plasmodesmata.
5). A. Symplastic loading with polymer trapping
Apoplastic loading is an active process, in which higher concentration of sucrose is pumped from
the apoplast into the transfer cells by transporters.
6). A. Glycolysis, mitochondrial import, succinate oxidation, oxidative phosphorylation
Solution
Answer:
1. A. Callose
The sieve plate pore contain callose, in mature sieve areas callose deposition may be throughout
the plate. The deposition of neighboring sieve areas may coalesce to a single mass and from the
callose pad.
3). D. Stomata allow 300-400 times more CO2 into the leaf than the H2O they lose out of the
leaf
Carbon dioxide is needed for photosynthesis to operate. Unfortunately, much more water leaves
the leaf than CO2 enters for three reasons:
a) H2O molecules are smaller than CO2 molecules and so they move to their destination faster.
b) CO2 is only about 0.036% of the atmosphere (and rising!) so the gradient for its entry into the
plant is much smaller than the gradient for H2O moving from a hydrated leaf into a dry
atmosphere.
c) CO2 has a much longer distance to travel to reach its destination in the chloroplast from the
atmosphere compared to H2O which only has to move from the leaf cell surface to the
atmosphere.
4). B. The supply of proteins to the phloem sieve tube from the companion cell
The plasmodesmata allow the direct flow of small molecules such as sugars, amino acids, and
ions between cells. This allows direct cytoplasm-to-cytoplasm flow of water and other nutrients
along concentration gradients.Q. As proteins are large molecules, they are not transported by
plasmodesmata.
5). A. Symplastic loading with polymer trapping
Apop.
AnsCommon name of organism (Genus)Type of organismProducer or.pdf
Ans:
Common name of organism (Genus)
Type of organism
Producer or consumer
Filter feeder? (yes/no)
Stationary or mobile
Nori seaweed
Algae
producer
yes
Stationary
Black pine
Algae
producer
Yes
Stationary
Coral weed
Algae
producer
No
Stationary
Mussel
Mollusk
Consumer
Yes
Stationary
Acorn Barnacle
Crustacean
Consumer
Yes
Stationary
Goose Neck Barnacle
Crustacean
Consumer
Yes
Stationary
whelk
Mollusk
Consumer
Yes
Mobile
Chiton
Mollusk
Consumer
No
Mobile
starfish
Echinoderm
Consumer
Yes
Mobile
Common name of organism (Genus)
Type of organism
Producer or consumer
Filter feeder? (yes/no)
Stationary or mobile
Nori seaweed
Algae
producer
yes
Stationary
Black pine
Algae
producer
Yes
Stationary
Coral weed
Algae
producer
No
Stationary
Mussel
Mollusk
Consumer
Yes
Stationary
Acorn Barnacle
Crustacean
Consumer
Yes
Stationary
Goose Neck Barnacle
Crustacean
Consumer
Yes
Stationary
whelk
Mollusk
Consumer
Yes
Mobile
Chiton
Mollusk
Consumer
No
Mobile
starfish
Echinoderm
Consumer
Yes
Mobile
Solution
Ans:
Common name of organism (Genus)
Type of organism
Producer or consumer
Filter feeder? (yes/no)
Stationary or mobile
Nori seaweed
Algae
producer
yes
Stationary
Black pine
Algae
producer
Yes
Stationary
Coral weed
Algae
producer
No
Stationary
Mussel
Mollusk
Consumer
Yes
Stationary
Acorn Barnacle
Crustacean
Consumer
Yes
Stationary
Goose Neck Barnacle
Crustacean
Consumer
Yes
Stationary
whelk
Mollusk
Consumer
Yes
Mobile
Chiton
Mollusk
Consumer
No
Mobile
starfish
Echinoderm
Consumer
Yes
Mobile
Common name of organism (Genus)
Type of organism
Producer or consumer
Filter feeder? (yes/no)
Stationary or mobile
Nori seaweed
Algae
producer
yes
Stationary
Black pine
Algae
producer
Yes
Stationary
Coral weed
Algae
producer
No
Stationary
Mussel
Mollusk
Consumer
Yes
Stationary
Acorn Barnacle
Crustacean
Consumer
Yes
Stationary
Goose Neck Barnacle
Crustacean
Consumer
Yes
Stationary
whelk
Mollusk
Consumer
Yes
Mobile
Chiton
Mollusk
Consumer
No
Mobile
starfish
Echinoderm
Consumer
Yes
Mobile.
1) A router2) Converged3) SSH4) Use the console port to locall.pdf
1) A router
2) Converged
3) SSH
4) Use the console port to locally access the switch from a serial or USB interface of the PC
5) all layers of TCP/IP model
Solution
1) A router
2) Converged
3) SSH
4) Use the console port to locally access the switch from a serial or USB interface of the PC
5) all layers of TCP/IP model.
1) Fraud traingle comprise of percieved opportunity , pressure and r.pdf
1) Fraud traingle comprise of percieved opportunity , pressure and rationalisation
Pine had the opprotunity to embezzle as he was sole resposible for payroll accounting , was
trusted and had control over bank accounts.Also he had the pressure of supporting his three kids
and high credit cards balances, Rationalised the situation in which he could create fake accounts
2)According to Steve Alrecht\'s scale-High personal debt ( personal characterstic), Too much
trust(risk factor),Fraud opportunity when pressure is high , opportunity is more adn personal
intergrity is low.
3)According to Hollinger and Clark there are five interrelated sets - first being the economic
pressure, second the young ones are more likely to theft, third every employer can be tempted to
steal, fourth being jon dissatisfaction anfd fifth being theft occurs because of shared formal and
informal organisation structure. they believe theft are most likely to occur where employees are
have more access , there is less control.
4)They conducted internal audit when the accountant had trouble reconciling the accounts.
5)Segregation of duties- one person should not be made responsible for accounting and payment
of payrolls, there should be effective controls like internal audit.
Solution
1) Fraud traingle comprise of percieved opportunity , pressure and rationalisation
Pine had the opprotunity to embezzle as he was sole resposible for payroll accounting , was
trusted and had control over bank accounts.Also he had the pressure of supporting his three kids
and high credit cards balances, Rationalised the situation in which he could create fake accounts
2)According to Steve Alrecht\'s scale-High personal debt ( personal characterstic), Too much
trust(risk factor),Fraud opportunity when pressure is high , opportunity is more adn personal
intergrity is low.
3)According to Hollinger and Clark there are five interrelated sets - first being the economic
pressure, second the young ones are more likely to theft, third every employer can be tempted to
steal, fourth being jon dissatisfaction anfd fifth being theft occurs because of shared formal and
informal organisation structure. they believe theft are most likely to occur where employees are
have more access , there is less control.
4)They conducted internal audit when the accountant had trouble reconciling the accounts.
5)Segregation of duties- one person should not be made responsible for accounting and payment
of payrolls, there should be effective controls like internal audit..
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