This document presents a free body diagram showing forces acting on a structure and the calculations to determine the resultant force and angle. There are 5 forces shown on the diagram, ranging from 80 to 200 lbf. Equations sum the x and y components of each force. The calculations determine the resultant force is 242659.5847 lbf with an angle of 0.07196 radians (4.11607 degrees) from the x-axis.

1. Proyeksi Vektor-THP-FAPERIKA-
UR-2016-Paridah Hasibuan

2. F1 = 100 lbf
F4 = 100 lbf
F5 = 200 lbf
x
y
o
32
o
58
F1y
F5y
xFxFxFxFxFFx 54321 
  yFyFyFyFFy 5431
o
38
F2 = 80 lbf
F1xF2x
F3 = 110 lbf
F3x
F3y
F4y
F4x
F5x
o
28

3. 



32cos52cos62cos180cos58cos 54321
54321
FFFFFFx
xFxFxFxFxFFx
o




32sin52sin62sin58sin 5431
5431
FFFFFy
yFyFyFyFFy
ooo

4. 









2
54321
54321
lbf242659,5847Fx
lbf-206,542
32cos20052cos10062cos110180cos8058cos100
32cos52cos62cos180cos58cos
Fx
Fx
FFFFFFx
xFxFxFxFxFFx
o










22
5431
5431
lbf3220,919229
lbf14,86335
32sin20052sin10062sin11058sin100
32sin52sin62sin58sin
Fy
Fy
Fy
FFFFFy
yFyFyFyFFy
ooo

5. lbf207,0761
3220,919229242659,5847
22


 
R
R
FyFxR



 























-4,11607
0,07196-tan
206,542-
14,86335
tan
tan
1
1
1




Fx
Fy