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Probability Case Study RohiniGandhotra Susan ForgettRheam Thomas Smith
Probability is a numeric value of the likelihood, or chance, of something happening. Do we have a better chance of this event occurring or do we have a better chance of it not occurring? Generally, we discuss probability as a fraction, a decimal, or a percent (%). Introduction
0 < P < 1 ,[object Object]
Where 1 is an event that is sure to occur
In between, the possibility that an event will occur
The sum of the probabilities of all possible outcomes of an event is one (1).Probability Rules
Classical – probability of success is based on prior knowledge of the process involved. Empirical – the outcomes are based on observed data, not on prior knowledge of a process. Subjective – based on the decision maker’s opinion regarding the chances that an event will occur. 3 Approaches to Probability
Great Air Commuter Service is a small regional airline. Provides commuter service between Boston and New York – three round trips daily (total of six flights per day). Promotional contest awarding a large prize to be run one day per month on each flight.  Case Study Description
The day each month for contest to be run will be selected randomly on the first of each month. On each flight that day, all passengers will write down their birthday (month and day). If any two people on the plane have the same birthday, they will place their names in a hat and one name will be selected to receive the grand prize. Contest Description
Capacity of each flight is a maximum of 40 passengers (plus crew). The Marketing Director believes there is a very low chance of a birthday match, so only a small chance of giving away the large prize. Marketing Director states that the probability for a match will be 40/365 (10.95%) for a full plane and less than that when there are fewer than 40 passengers on board. Other Case Information
Probability Question The owner wants to know: What is the probability of one or more birthday matches on flights of 20, 30, or 40 passengers,?
Is the Marketing Director accurate in her assessment? Let’s test
Independent events are events in which the occurrence of the events will not affect the probability of the occurrence of any of the other events. Example:  The date of my birth has no bearing on your birth date. For independent events, the probability of all of the events occurring is equal to a product of the probabilities of each event occurring: P(A and B) = P(A) * P(B) * … Multiplication Rule for Independent Events
[object Object]
Looked at another way, what is the probability of 20 passengers not sharing a birthday?
20 independent events with each event as a corresponding person not sharing their birthday with any of the previously analyzed people.Calculating the Probability
DISREGARD: ,[object Object]
Twins
Seasonality of births***There are 365 birthdays equally likely Assumptions
Classical Probability: P(A) = the probability of at least two passengers having the same birthday: P(A) =    # of ways for event to occur                Total # of possible outcomes Calculating the Probability
The complement of event A: P(A’) = the probability of there not being any two passengers with the same birthday. Then, because P(A) and P(A’) are the only two possibilities and are also mutually exclusive: P(A’) = 1 – P(A) Calculating the Probability
P(1) = for one person, there are 365 distinct birthdays P(1) = 365            365 P(2) = for two people, there are 364 different ways that the second could have a birthday without matching the first: P(2) = 364            365 20 Passenger Probability Calculation
P(3) = if person 3 is born on any of the 363 days of the year other than the birthdays of people 1 and 2, person 3 will not share their birthday. P(3) = 363            365 20 Passenger Probability Calculation
Calculating for all 20 passengers: P(A’) = 365 * 364 * 363 * 362 * …*346  = .588528              365    365    365    365          365 Therefore, the probability of at least two passengers having the same birthday is: P(A) = 1 - .588528  or  41.15% 20 Passenger Probability Calculation
30 Passengers: P(A’) = 365 * 364 * 363 * 362 * …*336  = .293665              365    365    365    365          365 P(A) = 1 - .293665          = 70.63% 30 Passenger Calculation

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Probability Case Study Rheam, Smith, Gandhotra

  • 1. Probability Case Study RohiniGandhotra Susan ForgettRheam Thomas Smith
  • 2. Probability is a numeric value of the likelihood, or chance, of something happening. Do we have a better chance of this event occurring or do we have a better chance of it not occurring? Generally, we discuss probability as a fraction, a decimal, or a percent (%). Introduction
  • 3.
  • 4. Where 1 is an event that is sure to occur
  • 5. In between, the possibility that an event will occur
  • 6. The sum of the probabilities of all possible outcomes of an event is one (1).Probability Rules
  • 7. Classical – probability of success is based on prior knowledge of the process involved. Empirical – the outcomes are based on observed data, not on prior knowledge of a process. Subjective – based on the decision maker’s opinion regarding the chances that an event will occur. 3 Approaches to Probability
  • 8. Great Air Commuter Service is a small regional airline. Provides commuter service between Boston and New York – three round trips daily (total of six flights per day). Promotional contest awarding a large prize to be run one day per month on each flight. Case Study Description
  • 9. The day each month for contest to be run will be selected randomly on the first of each month. On each flight that day, all passengers will write down their birthday (month and day). If any two people on the plane have the same birthday, they will place their names in a hat and one name will be selected to receive the grand prize. Contest Description
  • 10. Capacity of each flight is a maximum of 40 passengers (plus crew). The Marketing Director believes there is a very low chance of a birthday match, so only a small chance of giving away the large prize. Marketing Director states that the probability for a match will be 40/365 (10.95%) for a full plane and less than that when there are fewer than 40 passengers on board. Other Case Information
  • 11. Probability Question The owner wants to know: What is the probability of one or more birthday matches on flights of 20, 30, or 40 passengers,?
  • 12. Is the Marketing Director accurate in her assessment? Let’s test
  • 13. Independent events are events in which the occurrence of the events will not affect the probability of the occurrence of any of the other events. Example: The date of my birth has no bearing on your birth date. For independent events, the probability of all of the events occurring is equal to a product of the probabilities of each event occurring: P(A and B) = P(A) * P(B) * … Multiplication Rule for Independent Events
  • 14.
  • 15. Looked at another way, what is the probability of 20 passengers not sharing a birthday?
  • 16. 20 independent events with each event as a corresponding person not sharing their birthday with any of the previously analyzed people.Calculating the Probability
  • 17.
  • 18. Twins
  • 19. Seasonality of births***There are 365 birthdays equally likely Assumptions
  • 20. Classical Probability: P(A) = the probability of at least two passengers having the same birthday: P(A) = # of ways for event to occur Total # of possible outcomes Calculating the Probability
  • 21. The complement of event A: P(A’) = the probability of there not being any two passengers with the same birthday. Then, because P(A) and P(A’) are the only two possibilities and are also mutually exclusive: P(A’) = 1 – P(A) Calculating the Probability
  • 22. P(1) = for one person, there are 365 distinct birthdays P(1) = 365 365 P(2) = for two people, there are 364 different ways that the second could have a birthday without matching the first: P(2) = 364 365 20 Passenger Probability Calculation
  • 23. P(3) = if person 3 is born on any of the 363 days of the year other than the birthdays of people 1 and 2, person 3 will not share their birthday. P(3) = 363 365 20 Passenger Probability Calculation
  • 24. Calculating for all 20 passengers: P(A’) = 365 * 364 * 363 * 362 * …*346 = .588528 365 365 365 365 365 Therefore, the probability of at least two passengers having the same birthday is: P(A) = 1 - .588528 or 41.15% 20 Passenger Probability Calculation
  • 25. 30 Passengers: P(A’) = 365 * 364 * 363 * 362 * …*336 = .293665 365 365 365 365 365 P(A) = 1 - .293665 = 70.63% 30 Passenger Calculation
  • 26. 40 Passengers: P(A’) = 365 * 364 * 363 * 362 * …*326 = .108760 365 365 365 365 365 P(A) = 1 - .108760 = 89.12% 40 Passenger Calculation
  • 27. 20 Passengers = 41.15% 30 Passengers = 70.63% 40 Passengers = 89.12 % Seems implausible, doesn’t it? Birthday Probability Summary
  • 28. Some of the terms people use for probability are: Chance Likelihood The chance that any one person in this room shares my birthday is much smaller: 1 – {(364/365) 25 times} or 6.7%. Our probability calculation reflects that it is likely that there are some birthday matches among the other people in the group, not matching just to me. Understanding Probability
  • 29.
  • 30. Joanne Woodward and Elizabeth Taylor (Feb 27)
  • 31. Barbra Streisand and Shirley MacLaine (April 24)http://en.wikipedia.org/wiki/Birthday_problem Tests of this probability:
  • 32. With six flights daily (carrying the same number of passengers: 20, 30, and 40), what are the chances that Great Air Commuter Service will end up awarding two or more major prizes during a given month? Awarding Prizes
  • 33. Consider the number of flights on the one day per month the contest is run (3 round trips, 6 flights total) Multiply by the probability of a birthday match assuming group size (20, 30, and 40 passenger possibilities). 6 x .4115 = 2.47 prizes/month for 20 passenger flights 6 x .7063 = 4.24 prizes/month for 30 passenger flights 6 x .8912 = 5.35 prizes/month for 40 passenger flights Awarding Prizes
  • 34.
  • 35. If I make everything unpredictable, human beings will have no motive to do anything as there is no rational basis for any decision.
  • 36. I must therefore create a mixture of two.[from E. F. Schumacher] LORD Final Thought on Probability