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Selected Topics in Physics
                                     for
                         Medical Sciences Students

                                     Unit 1
                         Units, Dimensions, and Vectors
                                   Lecture 1



Physics Academy                      Dr. Hazem Falah Sakeek
www.physicsacademy.org
                                      Al-Azhar University -
                                              Gaza
Units, Dimensions, and Vectors
         Introduction
         Unit systems
         Dimensional Analysis
         Vector and Scalar
         Coordinate system
         Properties of Vectors
         The unit vector
         Components of a vector
         Product of a vector


2
    Dr. Hazem F. Sakeek www.physicsacademy.org
About Physics
        Explains Nature

        Fundamental science

        Most technology of today (cell phones, DVD
           player, etc) are result of discoveries that
           happened in physics last century.
        Develop problem solving and logical
           reasoning skills – very important in any field of
           work!!!

3
    Dr. Hazem F. Sakeek www.physicsacademy.org
What is Physics?




4
    Dr. Hazem F. Sakeek www.physicsacademy.org
Idealized Models




5
    Dr. Hazem F. Sakeek www.physicsacademy.org
Physics and Measurements
     Physics is based on experimental
      observations and quantitative
      measurements. These observations have
      described by numbers and units.
     Numbers give us how large our
      measurement was, and
     the units tell us the nature of this
      measurement.Height = 2.29 m


                              Number             +   Unit

6
    Dr. Hazem F. Sakeek www.physicsacademy.org
Physical Quantity

                                          Basic
                                    Physical Quantity



               Time                              Length   Mass




7
    Dr. Hazem F. Sakeek www.physicsacademy.org
Unit systems
    Two systems of units are widely used in the world, the
     metric and the British systems.
    The metric system measures the length in meters whereas
      the British system makes use of the foot, inch, …..
    The metric system is the most widely used. Therefore the
      metric system will be used in this course.
    By international agreement the metric system was
     formalized in 1971 into the International System of Units
     (SI). There are seven basic units in the SI as shown in
     table Below.
    “For this Course only three units are used, the meter,
      kilogram, and second”.
8
    Dr. Hazem F. Sakeek www.physicsacademy.org
Basic units in the SI




9
    Dr. Hazem F. Sakeek www.physicsacademy.org
Definition of Basic Quantities
     Mass
     The SI unit of mass is the Kilogram, which is
       defined as the mass of a specific platinum-
       iridium alloy cylinder.

     Time
     The SI unit of time is the Second, which is the
       time required for a cesium-133 atom to
       undergo 9,192,631,770 vibrations.

     Length
     The SI unit of length is Meter, which is the
       distance traveled by light in vacuum during
       a time of 1/299,792,458 second.
10
      Dr. Hazem F. Sakeek www.physicsacademy.org
Power of ten prefixes
    3,000 m = 3 1,000 m
                                                  10x    Prefix Symbol
     = 3 103 m = 3 km
                                                  x=18    exa     E
                                                   15    peta    P
    1,000,000,000 = 109 = 1G
    1,000,000 = 106 = 1M                          12     tera   T
    1,000 = 103 = 1k                              9     giga    G
                                                   6     mega    M
    141 kg = ? g                                  3      kilo    k
    1 GB = ? Byte = ? MB                          2     hecto   h
                                                   1     deca    da


11
     Dr. Hazem F. Sakeek www.physicsacademy.org
Power of ten prefixes

    0.003 s = 3 0.001 s                          10x    Prefix Symbol
     = 3 10-3 s = 3 ms                            x=-1   deci     d
                                                   -2    centi    c
 0.01 = 10-2 = centi                              -3    milli    m
 0.001 = 10-3 = milli                             -6    micro    µ
 0.000 001 = 10-6 = micro                         -9    nano     n
 0.000 000 001 = 10-9 = nano                     -12     pico    p
 0.000 000 000 001 = 10-12                       -15    femto    f
  = pico = p                                      -18     atto    a
 3 cm = ? m = ? mm


12
     Dr. Hazem F. Sakeek www.physicsacademy.org
Role of “UNITS” in problem solving

         Need to know conversion.
         Do problems with all units in the same
          system.
         Only quantities with same units can be added
          or subtracted.




13
     Dr. Hazem F. Sakeek www.physicsacademy.org
40 m 11cm                         ?
     The above expression yields:
       a)    40.11 m
       b)    4011 cm
       c)    A or B
       d)    Impossible to evaluate (dimensionally invalid)


          1.5 m 3.0 kg                      ?
     The above expression yields:
     a)     4.5 m kg
     b)     4.5 g km
     c)     A or B
     d)     Impossible to evaluate (dimensionally invalid)

            Express a speed of 50 kilometers per hour as meters
            per second.
14
       Dr. Hazem F. Sakeek www.physicsacademy.org
Derived Quantities
 All physical quantities measured by physicists can be
 expressed in terms of the three basic unit of
 length, mass, and time. For example, speed is simply
 length divided by time, and the force is actually mass
 multiplied by length divided by time squared.

                                   [Speed] = L/T = LT -1
                                   [Force] = ML/T2 = MLT -2

     where [Speed] is meant to indicate the unit of
      speed, and M, L, and T represents mass, length, and
      time units.
15
      Dr. Hazem F. Sakeek www.physicsacademy.org
   Multiply and divide units just like numbers

        Derived quantities: area, speed, volume, density ……
           Area = Length   Length                unit for area
            = m2
           Volume = Length    Length Length unit for volume
            = m3
           Speed = Length / time                unit for speed
            = m/s
           Density = Mass / Volume             unit for density
            = kg/m3
                    100 m 100 m
             speed                    10.32 m/s
        In 2008 Olympic sGame, Usain Bolt sets world record at
                    9.69    9.69 s
16
         9.69 s in Men’s 100 m Final. What is his average speed?
     Dr. Hazem F. Sakeek www.physicsacademy.org
Dimensional Analysis
      The word dimension in physics indicates the
      physical nature of the quantity. For example the
      distance has a dimension of length, and the
      speed has a dimension of length/time.

      The dimensional analysis is used to check the
      formula, since the dimension of the left hand
      side and the right hand side of the formula must
      be the same.


17
     Dr. Hazem F. Sakeek www.physicsacademy.org
Example
 Using the dimensional analysis check that this
  equation
 x = ½ at2 is correct, where x is the distance, a is
   the acceleration and t is the time.

 Solution
                           x = ½ at2
  The right hand side      [x] = L
                        2     L
                     [at ]        T2   L
                             T2
  The left hand side


  This equation is correct because the dimension of the left
18
    and right side of the equation have the same
   Dr. Hazem F. Sakeek www.physicsacademy.org
Example
     Show that the expression v = vo+at is dimensionally
     correct, where v and vo are the velocities and a is the
     acceleration, and t is the time.

     Solutions:
       The right hand side
                                                   L
                                            [v]
                                                   T
         The left hand side
                                               L       L
                                    [at ]       2
                                                  T
                                              T        T

     Therefore, the expression is dimensionally correct
19
      Dr. Hazem F. Sakeek www.physicsacademy.org
Example
     Suppose that the acceleration of a particle moving in
     circle of radius r with uniform velocity v is proportional to
     the rn and vm. Use the dimensional analysis to determine
     the power n and m.

     Solution
     Let us assume a is represented in this expression
                                       a = k rn vm
     Where k is the proportionality constant of dimensionless
     unit.
     The Left hand side        L
                               T2
                         [a] =

20
      Dr. Hazem F. Sakeek www.physicsacademy.org
 The Right hand side
                                                           m
                                                     n L       Ln m
                               [k rn v m ]          L
                                                       T       Tm
     Therefore
                                        L          Ln m
                                         2           m
                                       T           T
     Hence, n+m=1                                  and m=2

     Therefore. n =-1 and the acceleration a is
                  a = k r -1 v2
     k=1                          2
                                                   v
                                            a
                                                    r
21
      Dr. Hazem F. Sakeek www.physicsacademy.org
Problem to be solved by
 yourself
  Which of the following equations are dimensionally
    correct?
 (a) vf = vi + ax
 (b) y = (2 m) cos(kx), where k = 2 m-1


  The position of a particle moving under uniform
   acceleration is some function of time and the
   acceleration. Suppose we write this position s = k am
   tn,
   where k is a dimensionless constant.
   Show by dimensional analysis that this expression is
   satisfied if m = 1 and n =2. Can this analysis give the
22 value of k?
   Dr. Hazem F. Sakeek www.physicsacademy.org

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Physmed11 u1 1

  • 1. Selected Topics in Physics for Medical Sciences Students Unit 1 Units, Dimensions, and Vectors Lecture 1 Physics Academy Dr. Hazem Falah Sakeek www.physicsacademy.org Al-Azhar University - Gaza
  • 2. Units, Dimensions, and Vectors  Introduction  Unit systems  Dimensional Analysis  Vector and Scalar  Coordinate system  Properties of Vectors  The unit vector  Components of a vector  Product of a vector 2 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 3. About Physics  Explains Nature  Fundamental science  Most technology of today (cell phones, DVD player, etc) are result of discoveries that happened in physics last century.  Develop problem solving and logical reasoning skills – very important in any field of work!!! 3 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 4. What is Physics? 4 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 5. Idealized Models 5 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 6. Physics and Measurements  Physics is based on experimental observations and quantitative measurements. These observations have described by numbers and units.  Numbers give us how large our measurement was, and  the units tell us the nature of this measurement.Height = 2.29 m Number + Unit 6 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 7. Physical Quantity Basic Physical Quantity Time Length Mass 7 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 8. Unit systems Two systems of units are widely used in the world, the metric and the British systems. The metric system measures the length in meters whereas the British system makes use of the foot, inch, ….. The metric system is the most widely used. Therefore the metric system will be used in this course. By international agreement the metric system was formalized in 1971 into the International System of Units (SI). There are seven basic units in the SI as shown in table Below. “For this Course only three units are used, the meter, kilogram, and second”. 8 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 9. Basic units in the SI 9 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 10. Definition of Basic Quantities Mass The SI unit of mass is the Kilogram, which is defined as the mass of a specific platinum- iridium alloy cylinder. Time The SI unit of time is the Second, which is the time required for a cesium-133 atom to undergo 9,192,631,770 vibrations. Length The SI unit of length is Meter, which is the distance traveled by light in vacuum during a time of 1/299,792,458 second. 10 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 11. Power of ten prefixes  3,000 m = 3 1,000 m 10x Prefix Symbol = 3 103 m = 3 km x=18 exa E 15 peta P  1,000,000,000 = 109 = 1G  1,000,000 = 106 = 1M 12 tera T  1,000 = 103 = 1k 9 giga G 6 mega M  141 kg = ? g 3 kilo k  1 GB = ? Byte = ? MB 2 hecto h 1 deca da 11 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 12. Power of ten prefixes  0.003 s = 3 0.001 s 10x Prefix Symbol = 3 10-3 s = 3 ms x=-1 deci d -2 centi c  0.01 = 10-2 = centi -3 milli m  0.001 = 10-3 = milli -6 micro µ  0.000 001 = 10-6 = micro -9 nano n  0.000 000 001 = 10-9 = nano -12 pico p  0.000 000 000 001 = 10-12 -15 femto f = pico = p -18 atto a  3 cm = ? m = ? mm 12 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 13. Role of “UNITS” in problem solving  Need to know conversion.  Do problems with all units in the same system.  Only quantities with same units can be added or subtracted. 13 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 14. 40 m 11cm ? The above expression yields: a) 40.11 m b) 4011 cm c) A or B d) Impossible to evaluate (dimensionally invalid) 1.5 m 3.0 kg ? The above expression yields: a) 4.5 m kg b) 4.5 g km c) A or B d) Impossible to evaluate (dimensionally invalid) Express a speed of 50 kilometers per hour as meters per second. 14 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 15. Derived Quantities All physical quantities measured by physicists can be expressed in terms of the three basic unit of length, mass, and time. For example, speed is simply length divided by time, and the force is actually mass multiplied by length divided by time squared. [Speed] = L/T = LT -1 [Force] = ML/T2 = MLT -2 where [Speed] is meant to indicate the unit of speed, and M, L, and T represents mass, length, and time units. 15 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 16. Multiply and divide units just like numbers  Derived quantities: area, speed, volume, density ……  Area = Length Length unit for area = m2  Volume = Length Length Length unit for volume = m3  Speed = Length / time unit for speed = m/s  Density = Mass / Volume unit for density = kg/m3 100 m 100 m speed 10.32 m/s  In 2008 Olympic sGame, Usain Bolt sets world record at 9.69 9.69 s 16 9.69 s in Men’s 100 m Final. What is his average speed? Dr. Hazem F. Sakeek www.physicsacademy.org
  • 17. Dimensional Analysis  The word dimension in physics indicates the physical nature of the quantity. For example the distance has a dimension of length, and the speed has a dimension of length/time.  The dimensional analysis is used to check the formula, since the dimension of the left hand side and the right hand side of the formula must be the same. 17 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 18. Example Using the dimensional analysis check that this equation x = ½ at2 is correct, where x is the distance, a is the acceleration and t is the time. Solution x = ½ at2 The right hand side [x] = L 2 L [at ] T2 L T2 The left hand side This equation is correct because the dimension of the left 18 and right side of the equation have the same Dr. Hazem F. Sakeek www.physicsacademy.org
  • 19. Example Show that the expression v = vo+at is dimensionally correct, where v and vo are the velocities and a is the acceleration, and t is the time. Solutions: The right hand side L [v] T The left hand side L L [at ] 2 T T T Therefore, the expression is dimensionally correct 19 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 20. Example Suppose that the acceleration of a particle moving in circle of radius r with uniform velocity v is proportional to the rn and vm. Use the dimensional analysis to determine the power n and m. Solution Let us assume a is represented in this expression a = k rn vm Where k is the proportionality constant of dimensionless unit. The Left hand side L T2 [a] = 20 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 21.  The Right hand side m n L Ln m [k rn v m ] L T Tm Therefore L Ln m 2 m T T Hence, n+m=1 and m=2 Therefore. n =-1 and the acceleration a is a = k r -1 v2 k=1 2 v a r 21 Dr. Hazem F. Sakeek www.physicsacademy.org
  • 22. Problem to be solved by yourself  Which of the following equations are dimensionally correct? (a) vf = vi + ax (b) y = (2 m) cos(kx), where k = 2 m-1  The position of a particle moving under uniform acceleration is some function of time and the acceleration. Suppose we write this position s = k am tn, where k is a dimensionless constant. Show by dimensional analysis that this expression is satisfied if m = 1 and n =2. Can this analysis give the 22 value of k? Dr. Hazem F. Sakeek www.physicsacademy.org