percent composition_demo.pptx
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Chemistry, percent composition is one of the topic under SHS that deals with the different compound found in our day to day food consumption. It is also said that most of the product that we consume everyday has different ingredients which is the combination of different substance, such elements, preservatives and others. For you to become well knowledgeable this slide presentation is presented for you to become easy for learners and for you. Elements and compounds that are present in our foods will be more convenient for us to know if we learn how much is the consumption do we need to intake.
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percent composition_demo.pptx
- 2. Calculate the molecular mass of water (H2O) H = 2 Hydrogen atoms O = 1 Oxygen atoms
- 3. Solution: Find the atomic mass of each element in the compound. H2O H = 1.008 amu O = 16 amu
- 4. Solution: molar mass of H2O = 2(1.008 amu) + (16 amu) = 18.02 g/mol = 3.008 + 16
- 6. PERCENT COMPOSITION PREPARED BY; MR. REYMARK R. CLEOPAS
- 7. OBJECTIVES At the end of the lesson the student are expected to; a. calculate the percent composition of a compound from its formula; b. calculate the empirical formula from the percent composition of a compound; and, c. cite the importance of percent composition of a compound in real life situation.
- 8. Is the percent by mass of the elements that make up a compound.
- 10. Calculate the percent composition of the compound H2O = weighs 18.02 g H = 2 Hydrogen atoms O = 1 Oxygen atoms H = 1.008 amu O = 16 amu PERCENT COMPOSITION…
- 11. Solution: % composition of H in H2O 2 (1.008 g) 18.02 g X 100% = 2.016 g 18.02 g X 100% = = 11.19 % PERCENT COMPOSITION…
- 12. Solution: % composition of O in H2O 1 (16 g) 18.02 g X 100% = 16 g 18.02 g X 100% = = 88.79 % PERCENT COMPOSITION…
- 13. Is the simplest formula for a compound which is defined as the ratio of subscripts of the smallest possible whole number of the elements present in the formula.
- 14. EMPIRICAL FORMULA… %composition of an element = no. of atoms atomic weight Formula:
- 15. Solution: EMPIRICAL FORMULA… STEP 1 11.19 g H 2 mol H 1.008 g H = 22.2 mol H Hydrogen 88.79 g O 1 mol H 16 g H = 5.54 mol O Oxygen
- 16. EMPIRICAL FORMULA… STEP 2 H = 22.2 5.54 = 4.0 O = 5.54 5.54 = 1 Multiply the results by the smallest integer that makes the values whole numbers.
- 17. EMPIRICAL FORMULA… H = 4.0 x 1 = 4 O = 1 x 1 = 1 Thus, the empirical formula of H2O is H4O
- 18. Marites a Grade 11 student of St. Joseph, conduct an experiment about the effectivity of ammonia (NH3) as one of the compound in her pesticides for her botanical garden. Help her to calculate the, a. molecular mass of the compound. b. % composition of the compound from its formula. c. empirical formula of the compound from its % composition.
- 20. Direction: Answer the following items in a 1 whole sheet of paper. (5 pts. each) 1. What is the empirical formula of a compound found to contain 13.5g Ca, 10.8g O, and 0.675g H? Show your solution.
- 21. 2. Calculate the empirical formula of NutraSweet, which is found to have 57.14% C, 6.16% H, 9.52% N, and 27.18% O. Show your solution. 3. Briefly explain the relationship of percent composition and empirical formula.
- 22. Thank You!