1. The document discusses calculating the volume and surface area of various geometric shapes like spheres, cylinders, and cones. It provides formulas and step-by-step workings for finding the volume and surface area of each shape. 2. Examples are given calculating the volume and surface area of specific spheres, cylinders, and cones by plugging measurements into the formulas. 3. The document demonstrates how to set up and solve multi-step word problems involving finding volumes and surface areas of objects with given measurements.

1. F 2
F ( 33101 ) 3
F F 1 16
4
1. F F
1.1 F F :
1. F F F FF F
2. F
1.2 F / :
1. F
2. F
3.
4. FF F
5. F F
1.3 F :
1. F
2.
3.
4.
5.
6.
7. F
8. F F F

2. 2. F
1. F F F F
= ×
2. F F F
= ×
3. F
1
1. F F F
F F F F
2. F F F
= ×
3. F 1 2 F F F 1
F 23 F 1.2 F 1 F F 24 F
F F 1 F F

3. 2
1. F 1.2 F 1 F F 24
F F F 1
2. F F F
FF F F × × F F
F F F FF F ×
2. F 1.2.1 F F F
F F F F F
3. F
4. F 1 F F F F
F
3
1. F F F F
F F F F F F F F F
F F F F F F F F F F F F
F F F F F F F F
F F F F F
F
3. F FF = × F
F F πr2 r
h FF
= πr2h
r
h
4. F 1 2 F F F 1
F 29 30 F F F F
F F F F
5. F

4. 6. F 1 F F F F
F
1. F F F F F8 F
10 F F
= π r2 h
22
= × 4 2× 10
7
= 502.86
F = 502.86 F
7. F 1.2 F 30 31 F 1 4 F
F F 1 F
4
1. F F F F
F F F F
3. F F F F 4 1.2.2 F F F
F F F F
F
4. F
4. F
1. F F F 1
2.
3. 1.2.1 1.2.2

5. 5.
1.
2.
3. F
1. F F 60 %
2. F F 60 %

6. 1.2.1
1. F 75,000 F F F F
F F 40 50 F
2. F F 80 120 80 F
F F 30 F

7. 1.2.1
1. F 75,000 F F F F
F F 40 50 F
F = ×
75,000 = (40 × 50) ×
∴ = 75,000
40×50
= 37.5
F F 37.5
2. F F 80 120 80 F
F F 30 F
F 80 . F F F 30 .
∴ 80 30 = 50 .
F = ×
= 80 × 120 × 50
= 480,000 F
1 F 1,000 F
480,000 F F 480,000 ÷1,000 = 480

8. 1.2.2
1. F F F 6 8
2. F 4 160π F

9. 1.2.2
1. F F F 6 8
= ×
= πr2 × 8
= π × 32 × 8
= 72π
F 72π F
2. F 4 160π F
= ×
160π = πr2 ×
160π = π × 42 ×
∴ F = 160π
π ×16
= 10
F F 10