F 4

                          F                   ( 33101 )                                                  3
     F                 F 1                                                                          16
                                                                                                2

1.                     F                      F
         1.1   F              F :
             1.                                                            F   F F         FF   F
             2.                                                                  F
         1.2 F                /                            :
             1.                           F
             2.                       F
             3.
             4.                                           FF                   F
             5.                                                F   F
         1.3 F                                    :
             1.                   F
             2.
             3.
             4.
             5.
             6.
             7.    F
             8.                                       F                F              F
2.                          F

                                                                    F F                                                  F
                                                    F                                                            F                      F F                 F


                                                                                          = 4 πr3
                                                                                            3
                                                                     r

               F            1                                                                         F .3 F 1                   F 43



3.                                      F

                                                                                          1
     1.                 F                                   F                                                                                   F       F

     2.                                                                           F               F
                                                F                                             F                              F                                  F
              F F                           F
     3.             F                                                         3
              3.1                                                                                        F
              3.2               F                       F                                                    F
              3.3                   F                                     F                                                                 F
          F                                                     2
                                                                3



                                                                                                                                                    2
                                                                                                                                                    3
                                            1                                         2                              3                  4
4.                                                                     F                               F                                             F
    F                                                             F                F                                   F           F               F

                                             F                            4 F
                                                     =       2
                                                              3
                                                     =       2 × πr2h
                                                              3
                     F                                   F    F F     F
                                 h                   =       2r

                                                              = 2 πr2 (2r) = 4 πr3
                                                                3            3
        5.                              F 1                                                        F                                           F       F 1 F 52
F                                    1.4.1                      F
        6.                               F                   1.4.1                     F
        7.       F                               1.4.2        F


                                                                      2
        1.                              F                    1.4.2                                                         F               F

        2.               F                       1.4.3                                     F           F                       F
             F                                                F       F                                    F                           F
        3.                              F
        4.                           F 1 F                                 F                   F                   F
                             F
4.             F/        F         F
     1.                                  F              F F 1
     2.
     3.
     4.             1.4.1, 1.4.2       1.4.3


5.

          1.
          2.
          3.         F

          1.                                   F   F   60 %
          2.                                            F F     60 %
1.4.1



1.   F F       F   14




2.         1
1.4.1



1.             F F               F
                                 14
     F F   F               14 . ∴ = 14 ÷ 2 = 7      .
                         =     4 πr3
                               3
                         =     4 π × 73
                               3
                         =    457 1 π
                                   3
                           F 457 31π    F



2.                   1
                         =           4 πr3
                                     3
                         =           4 π × 13
                                     3
                         =           11 π
                                      3
                             F        1π
                                     13         F
1.4.2



1.        15




2.             3           F F   F   F
     27
1.4.2



1.                           15
                                   =      1 × 4 πr3
                                          2 3
                                    =     2 π × 153
                                          3
                                    =    2,250π
                                   F 2,250π         F



2.                                     3                   F F         F       F
     27
          F F   F                 27 .∴               = 27 ÷ 2 =13.5       .
                    3   .∴           = 13.5 3 = 10.5 .
                                   =      4 πr3
                                          3
                                   =      4 π × 10.53
                                          3
                                   =         1,543.5π
                                           F 1,543.5π       F
1.4.3


1.   F   F F   F   F7            F F




2.                  F   22
1.4.2



1.   F             F F       F        F7                       F F
          F F            F   7 . ∴ = 7 ÷ 2 = 3.5 .
                               F F                               3.5   .
         ∴                         F     = 2πr
                                         = 2π × 3.5
                                         = 7π
                                     F F        F 7π



2.                                 F           22
          F                            =    2πr
              22                       =    2 × 22 × r
                                                   7
         ∴ r                           =     22×7
                                             22×2
                                       =    3.5
                                       =     4 × 22 × 3.53
                                             3       7
                                       =    179 32

                                           F 179 2  3      F

Pan3

  • 1.
    F 4 F ( 33101 ) 3 F F 1 16 2 1. F F 1.1 F F : 1. F F F FF F 2. F 1.2 F / : 1. F 2. F 3. 4. FF F 5. F F 1.3 F : 1. F 2. 3. 4. 5. 6. 7. F 8. F F F
  • 2.
    2. F F F F F F F F F = 4 πr3 3 r F 1 F .3 F 1 F 43 3. F 1 1. F F F F 2. F F F F F F F F F 3. F 3 3.1 F 3.2 F F F 3.3 F F F F 2 3 2 3 1 2 3 4
  • 3.
    4. F F F F F F F F F F 4 F = 2 3 = 2 × πr2h 3 F F F F F h = 2r = 2 πr2 (2r) = 4 πr3 3 3 5. F 1 F F F 1 F 52 F 1.4.1 F 6. F 1.4.1 F 7. F 1.4.2 F 2 1. F 1.4.2 F F 2. F 1.4.3 F F F F F F F F 3. F 4. F 1 F F F F F
  • 4.
    4. F/ F F 1. F F F 1 2. 3. 4. 1.4.1, 1.4.2 1.4.3 5. 1. 2. 3. F 1. F F 60 % 2. F F 60 %
  • 5.
    1.4.1 1. F F F 14 2. 1
  • 6.
    1.4.1 1. F F F 14 F F F 14 . ∴ = 14 ÷ 2 = 7 . = 4 πr3 3 = 4 π × 73 3 = 457 1 π 3 F 457 31π F 2. 1 = 4 πr3 3 = 4 π × 13 3 = 11 π 3 F 1π 13 F
  • 7.
    1.4.2 1. 15 2. 3 F F F F 27
  • 8.
    1.4.2 1. 15 = 1 × 4 πr3 2 3 = 2 π × 153 3 = 2,250π F 2,250π F 2. 3 F F F F 27 F F F 27 .∴ = 27 ÷ 2 =13.5 . 3 .∴ = 13.5 3 = 10.5 . = 4 πr3 3 = 4 π × 10.53 3 = 1,543.5π F 1,543.5π F
  • 9.
    1.4.3 1. F F F F F7 F F 2. F 22
  • 10.
    1.4.2 1. F F F F F7 F F F F F 7 . ∴ = 7 ÷ 2 = 3.5 . F F 3.5 . ∴ F = 2πr = 2π × 3.5 = 7π F F F 7π 2. F 22 F = 2πr 22 = 2 × 22 × r 7 ∴ r = 22×7 22×2 = 3.5 = 4 × 22 × 3.53 3 7 = 179 32 F 179 2 3 F