Number of Electrons Mass Charge Number of Neutrons Elernental Symbol N.docx
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Number of Electrons Mass Charge Number of Neutrons Elernental Symbol Number of protons Number Species 18 0 Ne 13 12 25 +3 Solution Element symbol number of protons number of neutrons number of electrons mass number charge Ne 10 8 10 18 0 Al 13 12 10 25 +3 .
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Ol4 0 Solutionname - 4-chlorophenyldiphenylmethanol Naming of organic.docx
Ol4 0
Solution
name = 4-chlorophenyldiphenylmethanol
Naming of organic compounds,according to IUPAC.
word root = indicates no of carbons in longest chain (1) = meth
primary suffix = indicates sturated/unsaturated = ane
secondary suffix = indicates functional group = ol
primary prefix = indicates cyclic compounds = no
secondary prefix = indicates substituent = 4-chlorophenyldiphenyl
so that ,
name of the molecule (S.Preffix)(P.preffix)(WordRoot)(P.suffix)(S.suffix)
name: 4-chlorophenyldiphenylmethanol.
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OLD DOMINION TRAIL BIKES Case Study In 1985 Ted Thomas took $6-000 of.docx
OLD DOMINION TRAIL BIKES
Case Study
In 1985 Ted Thomas took $6,000 of his savings, borrowed another $4,000 from his best friend, and opened a bike rental business in Vienna, VA, adjacent to the Washington & Old Dominion Trail (W&OD) that goes from Purcellville to Old Town Alexandria (45 Miles) and connects to the Mt Vernon Trail (18 Miles) and ends at George Washington
Solution
Ans 2.
Ted would need an office (1) information system that Tded could use to perform day to day office function such as creating distributing documents for the office or personnel, send messages through email instead of using the phone all the time to his other stores, for accounting purposes as well as storing employee information, and building databases for his business; (2) a transaction process system to maintain Teds
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nvert each of the following word equations into a balanced chemical eq.docx
nvert each of the following word equations into a balanced chemical equation (a) copper meal(s) + oxygen() ? copper(I) oxide(s) OXI (b) mercury() nitratee)potassium iodi dea)-mercury(D iodidey+ potassium nitrateo) (c) aluminum metals) + hydrochloric acidnp) aluminum chloridee) +hydrogenc) (d) sulfuric acid(a) +sodium hydroxide (ao)sodium sulfate(ao) + watera (o) iron(lII) carbonateooII) oxide) + carbon dioxide()
Solution
a. 4Cu(s) + O2(g) --------> 2Cu2O(s)
b. Hg(NO3)2(aq) + 2KI(aq) -------> HgI2(s) + 2KNO3(aq)
c. 2Al(s) + 6HCl(aq) ------> 2AlCl3(aq) + 3H2(g)
d. H2SO4(aq) + 2NaOH(aq) ------> Na2So4(aq) + 2H2O(l)
e. Fe2(CO3)3(s) ---------> Fe2O3(s) + 3CO2(g)
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Normalization Matching- Indicate which normal form- each of the follow.docx
Normalization Matching. Indicate which normal form, each of the following conditions represents. [1NF, 2NF, 3NF, 4NF] No partial Dependencies No multi-value attributes No dependency between non-key attributes All attributes are dependent on the key All attributes are dependent on the whole key All attributes are dependent on nothing but the key Similar to BCNF No transitive dependencies For a table to be considered a relation, it must at least satisfy
Solution
1)No Partial Dependencies 2NF 2)No multi-value attribute 1NF 3)No dependency between non-key attributes 3NF 4)All attributes are dependent on the key 1NF 5)All attributes are dependent on the whole key 2NF 6)All attributes are dependent on nothing but the key 3NF 7)Simillar to BCNF 4NF 8)No transitive dependencies 3NF 9)For a table to be considered a relation, it m 1NF
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Not sure if I have the right answer for question 1- any help would be.docx
Not sure if I have the right answer for question 1,
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QUESTION 1 A molecule which has absorbed a photon of energy in the visible range could move from the excited electronic state (S1) to a highly excited vibrational level of the ground state (So) with the same energy. What is this process called? a. fluorescence internal conversion C intersystem crossing dvibrational relaxation Save Click Save and Submit to save and submit. Click Save All Ansuwers to save all answers Deskt
Solution
Multiple choice
1.
Excitation from an excited electronic state S1 to higher electronic ground state of same energy So is called,
c. intersystem crossing
This is according to the Jablonski diagram.
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Norbit hikes up a mountain following a short and intense trail- Rasput.docx
Norbit hikes up a mountain following a short and intense trail. Rasputia also hikes up the mountain but takes a longer, easier trail. Which of the following statements is true? Select one: O A. Norbit gains more gravitational potential energy than Rasputia. 0 B. Norbit gains less gravitational potential energy than Rasputia. O C. Norbit gains the same gravitational potential energy as Rasputia. O D. To compare energies, we must know the height of the mountain. o E. To compare energies, we must know the lengths of the two trails.
Solution
1. since both reaches to the same height of mountain, irrespective of their path, both will gain the same P.E.
Answer (C)
2. Answer (C)
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Neon, Argon, and Oxygen. Start with a temperature at which these substances are solids and slowly increase the temperature but do not reach the melting point. What can be said about the relationship between the temperature of a solid and the motion that the solid has?
Solution
In a solid the molecules are not free to move. But as the temperature increases the molecules start vibrating from their mean position.As a result there is a linear,superfacial and volume expansion of the solid.At low temperature the molecules in solid are in low energy state.At absolute zero their oscillating motion ceases to exist.As the temperaure increases their vibratory motion and kinetic energy increases but not leaving their position until their boiling point comes.
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Netting Process Bill report the following capital gains and losses for.docx
Netting Process
Bill report the following capital gains and losses for the year:
Short term capital gain = $2000
Short term capital loss = $ - 5000
Long term capital gain (28%) = $6000
long term capital gain (25%) = $4000
long term capital loss (15%) = $-1000
compute bill\'s net capital net capital gain or loss
Solution
Net Capital Gain or Loss:
Net Capital:
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Ol4 0 Solutionname - 4-chlorophenyldiphenylmethanol Naming of organic.docx
Ol4 0
Solution
name = 4-chlorophenyldiphenylmethanol
Naming of organic compounds,according to IUPAC.
word root = indicates no of carbons in longest chain (1) = meth
primary suffix = indicates sturated/unsaturated = ane
secondary suffix = indicates functional group = ol
primary prefix = indicates cyclic compounds = no
secondary prefix = indicates substituent = 4-chlorophenyldiphenyl
so that ,
name of the molecule (S.Preffix)(P.preffix)(WordRoot)(P.suffix)(S.suffix)
name: 4-chlorophenyldiphenylmethanol.
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OLD DOMINION TRAIL BIKES Case Study In 1985 Ted Thomas took $6-000 of.docx
OLD DOMINION TRAIL BIKES
Case Study
In 1985 Ted Thomas took $6,000 of his savings, borrowed another $4,000 from his best friend, and opened a bike rental business in Vienna, VA, adjacent to the Washington & Old Dominion Trail (W&OD) that goes from Purcellville to Old Town Alexandria (45 Miles) and connects to the Mt Vernon Trail (18 Miles) and ends at George Washington
Solution
Ans 2.
Ted would need an office (1) information system that Tded could use to perform day to day office function such as creating distributing documents for the office or personnel, send messages through email instead of using the phone all the time to his other stores, for accounting purposes as well as storing employee information, and building databases for his business; (2) a transaction process system to maintain Teds
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nvert each of the following word equations into a balanced chemical eq.docx
nvert each of the following word equations into a balanced chemical equation (a) copper meal(s) + oxygen() ? copper(I) oxide(s) OXI (b) mercury() nitratee)potassium iodi dea)-mercury(D iodidey+ potassium nitrateo) (c) aluminum metals) + hydrochloric acidnp) aluminum chloridee) +hydrogenc) (d) sulfuric acid(a) +sodium hydroxide (ao)sodium sulfate(ao) + watera (o) iron(lII) carbonateooII) oxide) + carbon dioxide()
Solution
a. 4Cu(s) + O2(g) --------> 2Cu2O(s)
b. Hg(NO3)2(aq) + 2KI(aq) -------> HgI2(s) + 2KNO3(aq)
c. 2Al(s) + 6HCl(aq) ------> 2AlCl3(aq) + 3H2(g)
d. H2SO4(aq) + 2NaOH(aq) ------> Na2So4(aq) + 2H2O(l)
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Normalization Matching. Indicate which normal form, each of the following conditions represents. [1NF, 2NF, 3NF, 4NF] No partial Dependencies No multi-value attributes No dependency between non-key attributes All attributes are dependent on the key All attributes are dependent on the whole key All attributes are dependent on nothing but the key Similar to BCNF No transitive dependencies For a table to be considered a relation, it must at least satisfy
Solution
1)No Partial Dependencies 2NF 2)No multi-value attribute 1NF 3)No dependency between non-key attributes 3NF 4)All attributes are dependent on the key 1NF 5)All attributes are dependent on the whole key 2NF 6)All attributes are dependent on nothing but the key 3NF 7)Simillar to BCNF 4NF 8)No transitive dependencies 3NF 9)For a table to be considered a relation, it m 1NF
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Not sure if I have the right answer for question 1- any help would be.docx
Not sure if I have the right answer for question 1,
any help would be appreciated!
QUESTION 1 A molecule which has absorbed a photon of energy in the visible range could move from the excited electronic state (S1) to a highly excited vibrational level of the ground state (So) with the same energy. What is this process called? a. fluorescence internal conversion C intersystem crossing dvibrational relaxation Save Click Save and Submit to save and submit. Click Save All Ansuwers to save all answers Deskt
Solution
Multiple choice
1.
Excitation from an excited electronic state S1 to higher electronic ground state of same energy So is called,
c. intersystem crossing
This is according to the Jablonski diagram.
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Norbit hikes up a mountain following a short and intense trail- Rasput.docx
Norbit hikes up a mountain following a short and intense trail. Rasputia also hikes up the mountain but takes a longer, easier trail. Which of the following statements is true? Select one: O A. Norbit gains more gravitational potential energy than Rasputia. 0 B. Norbit gains less gravitational potential energy than Rasputia. O C. Norbit gains the same gravitational potential energy as Rasputia. O D. To compare energies, we must know the height of the mountain. o E. To compare energies, we must know the lengths of the two trails.
Solution
1. since both reaches to the same height of mountain, irrespective of their path, both will gain the same P.E.
Answer (C)
2. Answer (C)
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Solution
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Netting Process Bill report the following capital gains and losses for.docx
Netting Process
Bill report the following capital gains and losses for the year:
Short term capital gain = $2000
Short term capital loss = $ - 5000
Long term capital gain (28%) = $6000
long term capital gain (25%) = $4000
long term capital loss (15%) = $-1000
compute bill\'s net capital net capital gain or loss
Solution
Net Capital Gain or Loss:
Net Capital:
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Neilson Company has monthly salaries of $22-000- Assume Neilson pays a.docx
Neilson Company has monthly salaries of $22,000. Assume Neilson pays all the standard payroll taxes and no employees have reached the payroll tax limits. Journalize the accrual and payment of employer payroll taxes for Neilson Company (Assume all of the monthly salary is subject to FUTA and SUTA). (Click the icon to view payroll tax rate information.) Begin with the entry to accrue employer payr appear on the last line of the journal entry tab Now record the payment of employer payroll taxes for Nelson Company. (Record debits first, then credits. Explanations will appear on the last line of the journal entry table.)
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Info is hidden for the first journal Please unhide this
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Neuron cells generate electrical signals by concentration gradients ac.docx
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Solution
Let us consider Nernst equation:
E = (RT/zF)ln([X] out /[X] in )
where,
R = gas constant , 8.314J/Kmol
T = Temperature, 315K
z = Charge of the ion , for K+ it is +1
F = Faraday constant, 96485C/mol
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nest Rutherford was a prominent scientist who contributed significantl.docx
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Solution
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Solution
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On January 1- 2015- Alice Corporation had 20-000 shares of $6 par valu.docx
On January 1, 2015, Alice Corporation had 20,000 shares of $6 par value common stock and 10,000 shares of 8%, $100 par value convertible preferred stock outstanding. The preferred shares carried a 3 for 1 conversion privilege. As of December 31, 2015, none of the preferred shares had been converted. What number of shares must Alice use in computing diluted earnings per share at December 31, 2015?
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On January 1- 2014- Richards Inc- had cash and common stock of $62-150.docx
On January 1, 2014, Richards Inc. had cash and common stock of $62,150. At that date, the company had no other asset, liability, or equity balances. On January 2, 2014, it purchased for cash $20,810 of equity securities that it classified as available-for-sale. It received cash dividends of $4,700 during the year on these securities. In addition, it has an unrealized holding gain on these securities of $6,260 net of tax. Determine the following amounts for 2014: (a) net income; (b) comprehensive income; (c) other comprehensive income; and (d) accumulated other comprehensive income (end of 2014).
Solution
a. Net Income = $4,700
b. Comprehensive Income = $4,700 + $6,260 = $10,960
c. Other Comprehensive Income = $6,260
d. Accumulated Other Comprehensive Income = $6,260
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On January 1- 2014- Jay Company had 10-000 shares of $1 par common sto.docx
On January 1, 2014, Jay Company had 10,000 shares of $1 par common stock outstanding, and 4,000 shares of $100 par value, 7% cumulative, nonconvertible preferred stock. On April 1, 2014, Jay Company had a 2-for-1 stock split. On July 1, 2014, Jay Company issued 5,000 additional shares of common stock.
What is the weighted average shares outstanding to be used in basic earnings per share for 2014?
A) 20,000
B) 22,500
C) 25,000
D) 27,000
Solution
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Selected account balances from the two companies
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Neilson Company has monthly salaries of $22,000. Assume Neilson pays all the standard payroll taxes and no employees have reached the payroll tax limits. Journalize the accrual and payment of employer payroll taxes for Neilson Company (Assume all of the monthly salary is subject to FUTA and SUTA). (Click the icon to view payroll tax rate information.) Begin with the entry to accrue employer payr appear on the last line of the journal entry tab Now record the payment of employer payroll taxes for Nelson Company. (Record debits first, then credits. Explanations will appear on the last line of the journal entry table.)
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Solution
Let us consider Nernst equation:
E = (RT/zF)ln([X] out /[X] in )
where,
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T = Temperature, 315K
z = Charge of the ion , for K+ it is +1
F = Faraday constant, 96485C/mol
Therefore,
E =((2.303× 8.314(J/K mol) ×315K)/(+1×96485C/mol))log(0.135M/0.0035M)
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Solution
yes. all polynomials are continuous. reasons for discontinuity: 1. there is a denominator (which becomes 0 for some value of x) 2. there is a split in the definition of the function - this is for a piecewise function 3. there is a radical (even-indexed) for a polynomial, none of these cases occur.. . . thus there is no value of x where you expect a discontinuity.
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On January 1, 2015, Alice Corporation had 20,000 shares of $6 par value common stock and 10,000 shares of 8%, $100 par value convertible preferred stock outstanding. The preferred shares carried a 3 for 1 conversion privilege. As of December 31, 2015, none of the preferred shares had been converted. What number of shares must Alice use in computing diluted earnings per share at December 31, 2015?
Solution
b.20,000
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On January 1, 2014, Richards Inc. had cash and common stock of $62,150. At that date, the company had no other asset, liability, or equity balances. On January 2, 2014, it purchased for cash $20,810 of equity securities that it classified as available-for-sale. It received cash dividends of $4,700 during the year on these securities. In addition, it has an unrealized holding gain on these securities of $6,260 net of tax. Determine the following amounts for 2014: (a) net income; (b) comprehensive income; (c) other comprehensive income; and (d) accumulated other comprehensive income (end of 2014).
Solution
a. Net Income = $4,700
b. Comprehensive Income = $4,700 + $6,260 = $10,960
c. Other Comprehensive Income = $6,260
d. Accumulated Other Comprehensive Income = $6,260
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On January 1- 2014- Jay Company had 10-000 shares of $1 par common sto.docx
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C) 25,000
D) 27,000
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Selected account balances from the two companies
Solution
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Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
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Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
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Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
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