Now remove the two lenses at +20-0 cm and 20-0 cm and replace them wit.docx
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Now remove the two lenses at +20.0 cm and 20.0 cm and replace them with a single lens of focal length f3 at z = 0, We want to choose this new lens so that it produces an image at the same location as before A compound lens system consists of two converging lenses, one at z20.0 cm with focal length f1 +10.0 cm, and the other at +20.0 cm with focal length f2 +8.00 cm. (Figure 1)An object 1.00 centimeter tall is placed at z =-50.0 cm Part D What is the focal length of the new lens at the origin? Express your answer in centimeters, to three significant figures or as a fraction. View Available Hint(s) Figure 1 of 1> cm fi /2 Submit Part E This question will be shown after you complete previous question(s). Solution D) The object is 50 cm from the new lens and has an image distance of 31.76 cm. This gives an answer of 19.42 cm. 19.4 cm (3 sf) .
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Ol4 0 Solutionname - 4-chlorophenyldiphenylmethanol Naming of organic.docx
Ol4 0
Solution
name = 4-chlorophenyldiphenylmethanol
Naming of organic compounds,according to IUPAC.
word root = indicates no of carbons in longest chain (1) = meth
primary suffix = indicates sturated/unsaturated = ane
secondary suffix = indicates functional group = ol
primary prefix = indicates cyclic compounds = no
secondary prefix = indicates substituent = 4-chlorophenyldiphenyl
so that ,
name of the molecule (S.Preffix)(P.preffix)(WordRoot)(P.suffix)(S.suffix)
name: 4-chlorophenyldiphenylmethanol.
.
OLD DOMINION TRAIL BIKES Case Study In 1985 Ted Thomas took $6-000 of.docx
OLD DOMINION TRAIL BIKES
Case Study
In 1985 Ted Thomas took $6,000 of his savings, borrowed another $4,000 from his best friend, and opened a bike rental business in Vienna, VA, adjacent to the Washington & Old Dominion Trail (W&OD) that goes from Purcellville to Old Town Alexandria (45 Miles) and connects to the Mt Vernon Trail (18 Miles) and ends at George Washington
Solution
Ans 2.
Ted would need an office (1) information system that Tded could use to perform day to day office function such as creating distributing documents for the office or personnel, send messages through email instead of using the phone all the time to his other stores, for accounting purposes as well as storing employee information, and building databases for his business; (2) a transaction process system to maintain Teds
.
Number of Electrons Mass Charge Number of Neutrons Elernental Symbol N.docx
Number of Electrons Mass Charge Number of Neutrons Elernental Symbol Number of protons Number Species 18 0 Ne 13 12 25 +3
Solution
Element symbol number of protons number of neutrons number of electrons mass number charge
Ne 10 8 10 18 0
Al 13 12 10 25 +3
.
nvert each of the following word equations into a balanced chemical eq.docx
nvert each of the following word equations into a balanced chemical equation (a) copper meal(s) + oxygen() ? copper(I) oxide(s) OXI (b) mercury() nitratee)potassium iodi dea)-mercury(D iodidey+ potassium nitrateo) (c) aluminum metals) + hydrochloric acidnp) aluminum chloridee) +hydrogenc) (d) sulfuric acid(a) +sodium hydroxide (ao)sodium sulfate(ao) + watera (o) iron(lII) carbonateooII) oxide) + carbon dioxide()
Solution
a. 4Cu(s) + O2(g) --------> 2Cu2O(s)
b. Hg(NO3)2(aq) + 2KI(aq) -------> HgI2(s) + 2KNO3(aq)
c. 2Al(s) + 6HCl(aq) ------> 2AlCl3(aq) + 3H2(g)
d. H2SO4(aq) + 2NaOH(aq) ------> Na2So4(aq) + 2H2O(l)
e. Fe2(CO3)3(s) ---------> Fe2O3(s) + 3CO2(g)
.
Normalization Matching- Indicate which normal form- each of the follow.docx
Normalization Matching. Indicate which normal form, each of the following conditions represents. [1NF, 2NF, 3NF, 4NF] No partial Dependencies No multi-value attributes No dependency between non-key attributes All attributes are dependent on the key All attributes are dependent on the whole key All attributes are dependent on nothing but the key Similar to BCNF No transitive dependencies For a table to be considered a relation, it must at least satisfy
Solution
1)No Partial Dependencies 2NF 2)No multi-value attribute 1NF 3)No dependency between non-key attributes 3NF 4)All attributes are dependent on the key 1NF 5)All attributes are dependent on the whole key 2NF 6)All attributes are dependent on nothing but the key 3NF 7)Simillar to BCNF 4NF 8)No transitive dependencies 3NF 9)For a table to be considered a relation, it m 1NF
.
Not sure if I have the right answer for question 1- any help would be.docx
Not sure if I have the right answer for question 1,
any help would be appreciated!
QUESTION 1 A molecule which has absorbed a photon of energy in the visible range could move from the excited electronic state (S1) to a highly excited vibrational level of the ground state (So) with the same energy. What is this process called? a. fluorescence internal conversion C intersystem crossing dvibrational relaxation Save Click Save and Submit to save and submit. Click Save All Ansuwers to save all answers Deskt
Solution
Multiple choice
1.
Excitation from an excited electronic state S1 to higher electronic ground state of same energy So is called,
c. intersystem crossing
This is according to the Jablonski diagram.
.
Norbit hikes up a mountain following a short and intense trail- Rasput.docx
Norbit hikes up a mountain following a short and intense trail. Rasputia also hikes up the mountain but takes a longer, easier trail. Which of the following statements is true? Select one: O A. Norbit gains more gravitational potential energy than Rasputia. 0 B. Norbit gains less gravitational potential energy than Rasputia. O C. Norbit gains the same gravitational potential energy as Rasputia. O D. To compare energies, we must know the height of the mountain. o E. To compare energies, we must know the lengths of the two trails.
Solution
1. since both reaches to the same height of mountain, irrespective of their path, both will gain the same P.E.
Answer (C)
2. Answer (C)
.
Neon- Argon- and Oxygen- Start with a temperature at which these subst.docx
Neon, Argon, and Oxygen. Start with a temperature at which these substances are solids and slowly increase the temperature but do not reach the melting point. What can be said about the relationship between the temperature of a solid and the motion that the solid has?
Solution
In a solid the molecules are not free to move. But as the temperature increases the molecules start vibrating from their mean position.As a result there is a linear,superfacial and volume expansion of the solid.At low temperature the molecules in solid are in low energy state.At absolute zero their oscillating motion ceases to exist.As the temperaure increases their vibratory motion and kinetic energy increases but not leaving their position until their boiling point comes.
.
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Ol4 0 Solutionname - 4-chlorophenyldiphenylmethanol Naming of organic.docx
Ol4 0
Solution
name = 4-chlorophenyldiphenylmethanol
Naming of organic compounds,according to IUPAC.
word root = indicates no of carbons in longest chain (1) = meth
primary suffix = indicates sturated/unsaturated = ane
secondary suffix = indicates functional group = ol
primary prefix = indicates cyclic compounds = no
secondary prefix = indicates substituent = 4-chlorophenyldiphenyl
so that ,
name of the molecule (S.Preffix)(P.preffix)(WordRoot)(P.suffix)(S.suffix)
name: 4-chlorophenyldiphenylmethanol.
.
OLD DOMINION TRAIL BIKES Case Study In 1985 Ted Thomas took $6-000 of.docx
OLD DOMINION TRAIL BIKES
Case Study
In 1985 Ted Thomas took $6,000 of his savings, borrowed another $4,000 from his best friend, and opened a bike rental business in Vienna, VA, adjacent to the Washington & Old Dominion Trail (W&OD) that goes from Purcellville to Old Town Alexandria (45 Miles) and connects to the Mt Vernon Trail (18 Miles) and ends at George Washington
Solution
Ans 2.
Ted would need an office (1) information system that Tded could use to perform day to day office function such as creating distributing documents for the office or personnel, send messages through email instead of using the phone all the time to his other stores, for accounting purposes as well as storing employee information, and building databases for his business; (2) a transaction process system to maintain Teds
.
Number of Electrons Mass Charge Number of Neutrons Elernental Symbol N.docx
Number of Electrons Mass Charge Number of Neutrons Elernental Symbol Number of protons Number Species 18 0 Ne 13 12 25 +3
Solution
Element symbol number of protons number of neutrons number of electrons mass number charge
Ne 10 8 10 18 0
Al 13 12 10 25 +3
.
nvert each of the following word equations into a balanced chemical eq.docx
nvert each of the following word equations into a balanced chemical equation (a) copper meal(s) + oxygen() ? copper(I) oxide(s) OXI (b) mercury() nitratee)potassium iodi dea)-mercury(D iodidey+ potassium nitrateo) (c) aluminum metals) + hydrochloric acidnp) aluminum chloridee) +hydrogenc) (d) sulfuric acid(a) +sodium hydroxide (ao)sodium sulfate(ao) + watera (o) iron(lII) carbonateooII) oxide) + carbon dioxide()
Solution
a. 4Cu(s) + O2(g) --------> 2Cu2O(s)
b. Hg(NO3)2(aq) + 2KI(aq) -------> HgI2(s) + 2KNO3(aq)
c. 2Al(s) + 6HCl(aq) ------> 2AlCl3(aq) + 3H2(g)
d. H2SO4(aq) + 2NaOH(aq) ------> Na2So4(aq) + 2H2O(l)
e. Fe2(CO3)3(s) ---------> Fe2O3(s) + 3CO2(g)
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Normalization Matching- Indicate which normal form- each of the follow.docx
Normalization Matching. Indicate which normal form, each of the following conditions represents. [1NF, 2NF, 3NF, 4NF] No partial Dependencies No multi-value attributes No dependency between non-key attributes All attributes are dependent on the key All attributes are dependent on the whole key All attributes are dependent on nothing but the key Similar to BCNF No transitive dependencies For a table to be considered a relation, it must at least satisfy
Solution
1)No Partial Dependencies 2NF 2)No multi-value attribute 1NF 3)No dependency between non-key attributes 3NF 4)All attributes are dependent on the key 1NF 5)All attributes are dependent on the whole key 2NF 6)All attributes are dependent on nothing but the key 3NF 7)Simillar to BCNF 4NF 8)No transitive dependencies 3NF 9)For a table to be considered a relation, it m 1NF
.
Not sure if I have the right answer for question 1- any help would be.docx
Not sure if I have the right answer for question 1,
any help would be appreciated!
QUESTION 1 A molecule which has absorbed a photon of energy in the visible range could move from the excited electronic state (S1) to a highly excited vibrational level of the ground state (So) with the same energy. What is this process called? a. fluorescence internal conversion C intersystem crossing dvibrational relaxation Save Click Save and Submit to save and submit. Click Save All Ansuwers to save all answers Deskt
Solution
Multiple choice
1.
Excitation from an excited electronic state S1 to higher electronic ground state of same energy So is called,
c. intersystem crossing
This is according to the Jablonski diagram.
.
Norbit hikes up a mountain following a short and intense trail- Rasput.docx
Norbit hikes up a mountain following a short and intense trail. Rasputia also hikes up the mountain but takes a longer, easier trail. Which of the following statements is true? Select one: O A. Norbit gains more gravitational potential energy than Rasputia. 0 B. Norbit gains less gravitational potential energy than Rasputia. O C. Norbit gains the same gravitational potential energy as Rasputia. O D. To compare energies, we must know the height of the mountain. o E. To compare energies, we must know the lengths of the two trails.
Solution
1. since both reaches to the same height of mountain, irrespective of their path, both will gain the same P.E.
Answer (C)
2. Answer (C)
.
Neon- Argon- and Oxygen- Start with a temperature at which these subst.docx
Neon, Argon, and Oxygen. Start with a temperature at which these substances are solids and slowly increase the temperature but do not reach the melting point. What can be said about the relationship between the temperature of a solid and the motion that the solid has?
Solution
In a solid the molecules are not free to move. But as the temperature increases the molecules start vibrating from their mean position.As a result there is a linear,superfacial and volume expansion of the solid.At low temperature the molecules in solid are in low energy state.At absolute zero their oscillating motion ceases to exist.As the temperaure increases their vibratory motion and kinetic energy increases but not leaving their position until their boiling point comes.
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Netting Process Bill report the following capital gains and losses for.docx
Netting Process
Bill report the following capital gains and losses for the year:
Short term capital gain = $2000
Short term capital loss = $ - 5000
Long term capital gain (28%) = $6000
long term capital gain (25%) = $4000
long term capital loss (15%) = $-1000
compute bill\'s net capital net capital gain or loss
Solution
Net Capital Gain or Loss:
Net Capital:
.
Neilson Company has monthly salaries of $22-000- Assume Neilson pays a.docx
Neilson Company has monthly salaries of $22,000. Assume Neilson pays all the standard payroll taxes and no employees have reached the payroll tax limits. Journalize the accrual and payment of employer payroll taxes for Neilson Company (Assume all of the monthly salary is subject to FUTA and SUTA). (Click the icon to view payroll tax rate information.) Begin with the entry to accrue employer payr appear on the last line of the journal entry tab Now record the payment of employer payroll taxes for Nelson Company. (Record debits first, then credits. Explanations will appear on the last line of the journal entry table.)
Solution
Info is hidden for the first journal Please unhide this
.
Neuron cells generate electrical signals by concentration gradients ac.docx
Neuron cells generate electrical signals by concentration gradients across membranes. Assuming a potassium ion concentration of 0.00350 M inside the cell, and a concentration of 0.135 M outside the cell, what is the electrical potential across the cell membrane? Body temperature is 315 K. The sign identifies the change in the electrical potential across the membrane and which way the ions flow. (answer in mV)
Solution
Let us consider Nernst equation:
E = (RT/zF)ln([X] out /[X] in )
where,
R = gas constant , 8.314J/Kmol
T = Temperature, 315K
z = Charge of the ion , for K+ it is +1
F = Faraday constant, 96485C/mol
Therefore,
E =((2.303× 8.314(J/K mol) ×315K)/(+1×96485C/mol))log(0.135M/0.0035M)
= 0.0625V×log(0.135/0.0035)
E= 0.099V
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nest Rutherford was a prominent scientist who contributed significantl.docx
nest Rutherford was a prominent scientist who contributed significantly to the theory of atomic structure. Which of the following statements are true? Select all that apply. Rutherford devised the solar system model to describe the layout of the atom. Rutherford disproved the plum pudding model of the atom. Rutherford theorized that atoms contain a positively charged region called the nucleus. Rutherford devised the plum pudding model to describe the layout of an atom.
Solution
Correct one: c) Rutherford theorized that atoms contain a positively charged region called the nucleus.
After completing the alpha-particle scattering experiment, he theorized the presence of nucleus. Due to which plum pudding model given by J.J. thomson got disapproved.
.
Need some help!! Explain why all polynomial functions are continuou.docx
Need some help!! Explain why all polynomial functions are continuous. Explain how to find an irrational zero. Describe the concept of continuity. Provide one example of a continuous function and one example of a discontinuous function. Why is it important to know synthetic division? What is another way to accomplish the same thing?
Solution
yes. all polynomials are continuous. reasons for discontinuity: 1. there is a denominator (which becomes 0 for some value of x) 2. there is a split in the definition of the function - this is for a piecewise function 3. there is a radical (even-indexed) for a polynomial, none of these cases occur.. . . thus there is no value of x where you expect a discontinuity.
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On January 1- 2015- Alice Corporation had 20-000 shares of $6 par valu.docx
On January 1, 2015, Alice Corporation had 20,000 shares of $6 par value common stock and 10,000 shares of 8%, $100 par value convertible preferred stock outstanding. The preferred shares carried a 3 for 1 conversion privilege. As of December 31, 2015, none of the preferred shares had been converted. What number of shares must Alice use in computing diluted earnings per share at December 31, 2015?
Solution
b.20,000
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On January 1- 2014- Richards Inc- had cash and common stock of $62-150.docx
On January 1, 2014, Richards Inc. had cash and common stock of $62,150. At that date, the company had no other asset, liability, or equity balances. On January 2, 2014, it purchased for cash $20,810 of equity securities that it classified as available-for-sale. It received cash dividends of $4,700 during the year on these securities. In addition, it has an unrealized holding gain on these securities of $6,260 net of tax. Determine the following amounts for 2014: (a) net income; (b) comprehensive income; (c) other comprehensive income; and (d) accumulated other comprehensive income (end of 2014).
Solution
a. Net Income = $4,700
b. Comprehensive Income = $4,700 + $6,260 = $10,960
c. Other Comprehensive Income = $6,260
d. Accumulated Other Comprehensive Income = $6,260
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On January 1- 2014- Jay Company had 10-000 shares of $1 par common sto.docx
On January 1, 2014, Jay Company had 10,000 shares of $1 par common stock outstanding, and 4,000 shares of $100 par value, 7% cumulative, nonconvertible preferred stock. On April 1, 2014, Jay Company had a 2-for-1 stock split. On July 1, 2014, Jay Company issued 5,000 additional shares of common stock.
What is the weighted average shares outstanding to be used in basic earnings per share for 2014?
A) 20,000
B) 22,500
C) 25,000
D) 27,000
Solution
Weighted average shares outstanding to be used in basic earnings per share for 2014 = 10000*2*12/12 + 5000*6/12
Weighted average shares outstanding to be used in basic earnings per share for 2014 = 22500
Answer
B) 22,500
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On January 1- 2011- Phoenix Co- acquired 100 percent of the outstandin.docx
On January 1, 2011, Phoenix Co. acquired 100 percent of the outstanding voting shares of Sedona Inc. for $600,000 cash. At January 1, 2011, Sedona\'s net assets had a total carrying amount of $420,000. Equipment (eight-year remaining life) was undervalued on Sedonass financial records by $80,000. Any remaining excess fair over book value was attributed to a customer list developed by Sedona (four-year remaining life), but not recorded on its books. Phoenix applies the equity method to account for its investment in Sedona. Each year since the acquisition, Sedona has paid a $20,000 dividend. Sedona recorded income of $70,000 in 2011 and $80,000 in 2012.
Selected account balances from the two companies
Solution
Income from phoenix = Revevue - Expenditure = $148,000
Income from Sedona = $55,000
Net consolidated income = $148,000+$55,000 = $203,000
Answer B $203,000
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On a circular track with 24 -elds two players Blue and Yellow place th.docx
On a circular track with 24 ?elds two players Blue and Yellow place their eight tokens in pairs so that blue an yellow pairs are separated as in Figure 1. Then they take turns to move one of their own tokens an arbitrary number of ?elds, in an arbitrary direction, but not onto or over an occupied ?eld. The player who can
Solution
two players can overthrow a adjacent player by teaming up and moving on the positions acquired by the adjacent player so that after the 1st step its position can be defensed so then it will have no other option to move in any direction. 2)blue can acquired the adjacent positions of the yellow players.aso in the next move yellow cannot move out of the boundary created by the blue. so the only option it will have is to move in ward.repeat such that it gets no more steps to go to.
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Netting Process Bill report the following capital gains and losses for.docx
Netting Process
Bill report the following capital gains and losses for the year:
Short term capital gain = $2000
Short term capital loss = $ - 5000
Long term capital gain (28%) = $6000
long term capital gain (25%) = $4000
long term capital loss (15%) = $-1000
compute bill\'s net capital net capital gain or loss
Solution
Net Capital Gain or Loss:
Net Capital:
.
Neilson Company has monthly salaries of $22-000- Assume Neilson pays a.docx
Neilson Company has monthly salaries of $22,000. Assume Neilson pays all the standard payroll taxes and no employees have reached the payroll tax limits. Journalize the accrual and payment of employer payroll taxes for Neilson Company (Assume all of the monthly salary is subject to FUTA and SUTA). (Click the icon to view payroll tax rate information.) Begin with the entry to accrue employer payr appear on the last line of the journal entry tab Now record the payment of employer payroll taxes for Nelson Company. (Record debits first, then credits. Explanations will appear on the last line of the journal entry table.)
Solution
Info is hidden for the first journal Please unhide this
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Neuron cells generate electrical signals by concentration gradients ac.docx
Neuron cells generate electrical signals by concentration gradients across membranes. Assuming a potassium ion concentration of 0.00350 M inside the cell, and a concentration of 0.135 M outside the cell, what is the electrical potential across the cell membrane? Body temperature is 315 K. The sign identifies the change in the electrical potential across the membrane and which way the ions flow. (answer in mV)
Solution
Let us consider Nernst equation:
E = (RT/zF)ln([X] out /[X] in )
where,
R = gas constant , 8.314J/Kmol
T = Temperature, 315K
z = Charge of the ion , for K+ it is +1
F = Faraday constant, 96485C/mol
Therefore,
E =((2.303× 8.314(J/K mol) ×315K)/(+1×96485C/mol))log(0.135M/0.0035M)
= 0.0625V×log(0.135/0.0035)
E= 0.099V
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nest Rutherford was a prominent scientist who contributed significantl.docx
nest Rutherford was a prominent scientist who contributed significantly to the theory of atomic structure. Which of the following statements are true? Select all that apply. Rutherford devised the solar system model to describe the layout of the atom. Rutherford disproved the plum pudding model of the atom. Rutherford theorized that atoms contain a positively charged region called the nucleus. Rutherford devised the plum pudding model to describe the layout of an atom.
Solution
Correct one: c) Rutherford theorized that atoms contain a positively charged region called the nucleus.
After completing the alpha-particle scattering experiment, he theorized the presence of nucleus. Due to which plum pudding model given by J.J. thomson got disapproved.
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Need some help!! Explain why all polynomial functions are continuou.docx
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Solution
yes. all polynomials are continuous. reasons for discontinuity: 1. there is a denominator (which becomes 0 for some value of x) 2. there is a split in the definition of the function - this is for a piecewise function 3. there is a radical (even-indexed) for a polynomial, none of these cases occur.. . . thus there is no value of x where you expect a discontinuity.
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On January 1- 2015- Alice Corporation had 20-000 shares of $6 par valu.docx
On January 1, 2015, Alice Corporation had 20,000 shares of $6 par value common stock and 10,000 shares of 8%, $100 par value convertible preferred stock outstanding. The preferred shares carried a 3 for 1 conversion privilege. As of December 31, 2015, none of the preferred shares had been converted. What number of shares must Alice use in computing diluted earnings per share at December 31, 2015?
Solution
b.20,000
.
On January 1- 2014- Richards Inc- had cash and common stock of $62-150.docx
On January 1, 2014, Richards Inc. had cash and common stock of $62,150. At that date, the company had no other asset, liability, or equity balances. On January 2, 2014, it purchased for cash $20,810 of equity securities that it classified as available-for-sale. It received cash dividends of $4,700 during the year on these securities. In addition, it has an unrealized holding gain on these securities of $6,260 net of tax. Determine the following amounts for 2014: (a) net income; (b) comprehensive income; (c) other comprehensive income; and (d) accumulated other comprehensive income (end of 2014).
Solution
a. Net Income = $4,700
b. Comprehensive Income = $4,700 + $6,260 = $10,960
c. Other Comprehensive Income = $6,260
d. Accumulated Other Comprehensive Income = $6,260
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On January 1- 2014- Jay Company had 10-000 shares of $1 par common sto.docx
On January 1, 2014, Jay Company had 10,000 shares of $1 par common stock outstanding, and 4,000 shares of $100 par value, 7% cumulative, nonconvertible preferred stock. On April 1, 2014, Jay Company had a 2-for-1 stock split. On July 1, 2014, Jay Company issued 5,000 additional shares of common stock.
What is the weighted average shares outstanding to be used in basic earnings per share for 2014?
A) 20,000
B) 22,500
C) 25,000
D) 27,000
Solution
Weighted average shares outstanding to be used in basic earnings per share for 2014 = 10000*2*12/12 + 5000*6/12
Weighted average shares outstanding to be used in basic earnings per share for 2014 = 22500
Answer
B) 22,500
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On January 1- 2011- Phoenix Co- acquired 100 percent of the outstandin.docx
On January 1, 2011, Phoenix Co. acquired 100 percent of the outstanding voting shares of Sedona Inc. for $600,000 cash. At January 1, 2011, Sedona\'s net assets had a total carrying amount of $420,000. Equipment (eight-year remaining life) was undervalued on Sedonass financial records by $80,000. Any remaining excess fair over book value was attributed to a customer list developed by Sedona (four-year remaining life), but not recorded on its books. Phoenix applies the equity method to account for its investment in Sedona. Each year since the acquisition, Sedona has paid a $20,000 dividend. Sedona recorded income of $70,000 in 2011 and $80,000 in 2012.
Selected account balances from the two companies
Solution
Income from phoenix = Revevue - Expenditure = $148,000
Income from Sedona = $55,000
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Answer B $203,000
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On a circular track with 24 -elds two players Blue and Yellow place th.docx
On a circular track with 24 ?elds two players Blue and Yellow place their eight tokens in pairs so that blue an yellow pairs are separated as in Figure 1. Then they take turns to move one of their own tokens an arbitrary number of ?elds, in an arbitrary direction, but not onto or over an occupied ?eld. The player who can
Solution
two players can overthrow a adjacent player by teaming up and moving on the positions acquired by the adjacent player so that after the 1st step its position can be defensed so then it will have no other option to move in any direction. 2)blue can acquired the adjacent positions of the yellow players.aso in the next move yellow cannot move out of the boundary created by the blue. so the only option it will have is to move in ward.repeat such that it gets no more steps to go to.
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