The document describes MATLAB functions for numerical integration using various rules:
1) Trapezoidal, Simpsons 1/3, Simpsons 3/8, Booles, Weddles, and Rectangular rules are presented with code examples.
2) Each function takes the initial and final inputs, number of intervals, and function as inputs and returns the numerical integration as the output.
3) The functions break the interval into subintervals and calculate the area using the specific rule's formula to approximate the definite integral.
A state machine is any device storing the status of something at a given time. The status changes based on inputs, providing the resulting output for the implemented changes. A finite state machine has finite internal memory.
A formalization of complex event stream processingSylvain Hallé
Information systems in general, and business processes in particular, generate a wealth of information in the form of event traces or logs. The analysis of these logs, either offline or in real-time, can be put to numerous uses: computation of various statistics, detection of anomalous patterns or compliance violations of some form of contract. However, current solutions for Complex Event Processing (CEP) generally offer only a restricted set of predefined queries on traces, and otherwise require a user to write procedural code to compute custom queries. In this presentation, we present a formal and declarative language for the manipulation of event traces.
A state machine is any device storing the status of something at a given time. The status changes based on inputs, providing the resulting output for the implemented changes. A finite state machine has finite internal memory.
A formalization of complex event stream processingSylvain Hallé
Information systems in general, and business processes in particular, generate a wealth of information in the form of event traces or logs. The analysis of these logs, either offline or in real-time, can be put to numerous uses: computation of various statistics, detection of anomalous patterns or compliance violations of some form of contract. However, current solutions for Complex Event Processing (CEP) generally offer only a restricted set of predefined queries on traces, and otherwise require a user to write procedural code to compute custom queries. In this presentation, we present a formal and declarative language for the manipulation of event traces.
I wrote the following change it to having a header, main and cpp fi.pdfrishteygallery
I wrote the following: change it to having a header, main and cpp file.. THERE ARE ERRORS
PLEASE FIX.. Picture of output is given below
The internal representation of a Polynomial is an array of terms. Each term contains a coefficient
and an exponent, e.g., the term
2x4
has the coefficient 2 and the exponent 4.
Develop a complete class containing proper constructor and destructor functions as well as set,
get, and print functions. The class should also provide the following overloaded operator
capabilities:
a) Overload the addition operator (+) to add two Polynomials.
b) Overload the subtraction operator (-) to subtract two Polynomials.
c) Overload the assignment operator to assign one Polynomial to another.
d) Overload the multiplication operator (*) to multiply two Polynomials.
e) Overload the addition assignment operator (+=), subtraction assignment operator (-=), and
multiplication assignment operator (*=).
Write an application that tests all the functionality provided by class Polynomial:
• create three Polynomials
• add two Polynomials, using + and += operators
• subtract two Polynomials, using – and -= operators
• assign one Polynomial to another Polynomial
• multiply two Polynomials, using * and *= operators.
---------------------------------------------------------------------------------------------
#include
#include
using namespace std;
using std::setiosflags;
using std::resetiosflags;
class Polynomial
{
public:
Polynomial();
Polynomial operator+( const Polynomial& ) const;
Polynomial operator-( const Polynomial& ) const;
Polynomial operator*( const Polynomial& );
const Polynomial operator=( const Polynomial&);
Polynomial& operator+=( const Polynomial& );
Polynomial& operator-=( const Polynomial& );
void enterTerms( void );
void printPolynomial( void ) const;
private:
int exponents[ 100 ];
int coefficients[ 100 ];
};
Polynomial::Polynomial()
{
for ( int t = 0; t < 100; ++t ) {
coefficients[ t ] = 0;
exponents[ t ] = 0;
}
}
void Polynomial::printPolynomial( void ) const
{
int start;
bool zero = false;
if ( coefficients[ 0 ] ) { // output constants
cout << coefficients[ 0 ];
start = 1;
zero = true; // at least one term exists
}
else {
if ( coefficients[ 1 ] ) {
cout << coefficients[ 1 ] << \'x\'; // constant does not exist
// so output first term
// without a sign
if ( ( exponents[ 1 ] != 0 ) && ( exponents[ 1 ] != 1 ) )
cout << \'^\' << exponents[ 1 ];
zero = true; // at least one term exists
}
start = 2;
}
// output remaining polynomial terms
for ( int x = start; x < 100; ++x ) {
if ( coefficients[ x ] != 0 ) {
cout << setiosflags( ios::showpos ) << coefficients[ x ]
<< resetiosflags( ios::showpos ) << \'x\';
if ( ( exponents[ x ] != 0 ) && ( exponents[ x ] != 1 ) )
cout << \'^\' << exponents[ x ];
zero = true; // at least one term exists
}
}
if ( !zero ) // no terms exist in the polynomial
cout << \'0\';
cout << endl;
}
const Polynomial Polynomial::operator=( const Polynomial& r )
{
exponents[ 0 ] = r.exponents[ 0 ];
coefficients[.
I wrote the following change it to having a header, main and cpp fi.pdfrishteygallery
I wrote the following: change it to having a header, main and cpp file.. THERE ARE ERRORS
PLEASE FIX.. Picture of output is given below
The internal representation of a Polynomial is an array of terms. Each term contains a coefficient
and an exponent, e.g., the term
2x4
has the coefficient 2 and the exponent 4.
Develop a complete class containing proper constructor and destructor functions as well as set,
get, and print functions. The class should also provide the following overloaded operator
capabilities:
a) Overload the addition operator (+) to add two Polynomials.
b) Overload the subtraction operator (-) to subtract two Polynomials.
c) Overload the assignment operator to assign one Polynomial to another.
d) Overload the multiplication operator (*) to multiply two Polynomials.
e) Overload the addition assignment operator (+=), subtraction assignment operator (-=), and
multiplication assignment operator (*=).
Write an application that tests all the functionality provided by class Polynomial:
• create three Polynomials
• add two Polynomials, using + and += operators
• subtract two Polynomials, using – and -= operators
• assign one Polynomial to another Polynomial
• multiply two Polynomials, using * and *= operators.
---------------------------------------------------------------------------------------------
#include
#include
using namespace std;
using std::setiosflags;
using std::resetiosflags;
class Polynomial
{
public:
Polynomial();
Polynomial operator+( const Polynomial& ) const;
Polynomial operator-( const Polynomial& ) const;
Polynomial operator*( const Polynomial& );
const Polynomial operator=( const Polynomial&);
Polynomial& operator+=( const Polynomial& );
Polynomial& operator-=( const Polynomial& );
void enterTerms( void );
void printPolynomial( void ) const;
private:
int exponents[ 100 ];
int coefficients[ 100 ];
};
Polynomial::Polynomial()
{
for ( int t = 0; t < 100; ++t ) {
coefficients[ t ] = 0;
exponents[ t ] = 0;
}
}
void Polynomial::printPolynomial( void ) const
{
int start;
bool zero = false;
if ( coefficients[ 0 ] ) { // output constants
cout << coefficients[ 0 ];
start = 1;
zero = true; // at least one term exists
}
else {
if ( coefficients[ 1 ] ) {
cout << coefficients[ 1 ] << \'x\'; // constant does not exist
// so output first term
// without a sign
if ( ( exponents[ 1 ] != 0 ) && ( exponents[ 1 ] != 1 ) )
cout << \'^\' << exponents[ 1 ];
zero = true; // at least one term exists
}
start = 2;
}
// output remaining polynomial terms
for ( int x = start; x < 100; ++x ) {
if ( coefficients[ x ] != 0 ) {
cout << setiosflags( ios::showpos ) << coefficients[ x ]
<< resetiosflags( ios::showpos ) << \'x\';
if ( ( exponents[ x ] != 0 ) && ( exponents[ x ] != 1 ) )
cout << \'^\' << exponents[ x ];
zero = true; // at least one term exists
}
}
if ( !zero ) // no terms exist in the polynomial
cout << \'0\';
cout << endl;
}
const Polynomial Polynomial::operator=( const Polynomial& r )
{
exponents[ 0 ] = r.exponents[ 0 ];
coefficients[.
import java.util.Scanner;public class HornersPolynomial { .pdfaptex1
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days
Solution
For a first order reaction rate constant , k = ( 2.303 /t )x log ( a / (a-x))
Where
a = initial amount
a-x = amount left after time t = a / 10
t = time = ?
k = rate constant = 3.43x10 -2 d -2
Plug the values we get t = ( 2.303 /k )x log ( a / (a-x))
= ( 2.303 / 3.43x10 -2 )x log ( a / (a/10))
= 67.14 days.
Please need help on C++ language.Infix to Postfix) Write a program.pdfpristiegee
Please need help on C++ language.
Infix to Postfix) Write a program that converts an infix expression into an equivalent postfix
expression. The rules to convert an infix expression into an equivalent postfix expression are as
follows:
Initialize pfx to an empty expression and also initialize the stack.
Get the next symbol, sym, from infx.
If sym is an operand, append sym to pfx.
If sym is (, push sym into the stack.
If sym is ), pop and append all of the symbols from the stack until the most recent left
parentheses. Pop and discard the left parentheses.
If sym is an operator:
Pop and append all of the operators from the stack to pfx that are above the most recent left
parentheses and have precedence greater than or equal to sym.
Push sym onto the stack.
After processing infx, some operators might be left in the stack. Pop and append to pfx
everything from the stack.
In this program, you will consider the following (binary) arithmetic operators: +, -, *, and /.
You may assume that the expressions you will process are error free. Design a class that stores
the infix and postfix strings. The class must include the following operations:
getInfix: Stores the infix expression.
showInfix: Outputs the infix expression.
showPostfix: Outputs the postfix expression.
convertToPostfix: Converts the infix expression into a postfix expression. The resulting postfix
expression is stored in pfx.
precedence: Determines the precedence between two operators. If the first operator is of higher
or equal precedence than the second operator, it returns the value true; otherwise, it returns the
value false.
A + B - C;
(A + B ) * C;
(A + B) * (C - D);
A + ((B + C) * (E - F) - G) / (H - I);
A + B * (C + D ) - E / F * G + H;
Infix Expression: A+B-C;
Postfix Expression: AB+C-
Infix Expression: (A+B)*C;
Postfix Expression: AB+C*
Infix Expression: (A+B)*(C-D);
Postfix Expression: AB+CD-*
Infix Expression: A+((B+C)*(E-F)-G)/(H-I);
Postfix Expression: ABC+EF-*G-HI-/+
Infix Expression: A+B*(C+D)-E/F*G+H;
Postfix Expression: ABCD+*+EF/G*-H+
PLEASE PROVIDE FOLLOWING.
A UML diagram for your class.
The header file for your class.
The implementation file for your class.
The source code for your test program.
Solution
#include
using namespace std;
const int MAX = 50 ;
class InfixToPostfix
{
private :
char target[MAX], stack[MAX] ;
char *s, *t ;
int top ;
public :
InfixToPostfix( ) ;
void getInfix ( char *str ) ;
void showInfix () ;
void push ( char c ) ;
char pop( ) ;
void convertToPostfix( ) ;
int precedence ( char c ) ;
void showPostfix( ) ;
void Delete();
} ;
InfixToPostfix :: InfixToPostfix( )
{
top = -1 ;
strcpy ( target, \"\" ) ;
strcpy ( stack, \"\" ) ;
t = target ;
s = \"\" ;
}
void InfixToPostfix :: getInfix ( char *str )
{
s = str ;
}
void InfixToPostfix :: showInfix ( )
{
cout<<\"Infix Expression :\"<= precedence ( *s ) )
{
*t = opr ;
t++ ;
opr = pop( ) ;
}
push ( opr ) ;
push ( *s ) ;
}
else
push ( *s ) ;
s++ ;
}
if ( *s == \')\' )
{
opr = pop( ) ;
while ( ( opr ) != \.
The Roman Empire A Historical Colossus.pdfkaushalkr1407
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
How to Create Map Views in the Odoo 17 ERPCeline George
The map views are useful for providing a geographical representation of data. They allow users to visualize and analyze the data in a more intuitive manner.
Synthetic Fiber Construction in lab .pptxPavel ( NSTU)
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
For more information, visit-www.vavaclasses.com
The Indian economy is classified into different sectors to simplify the analysis and understanding of economic activities. For Class 10, it's essential to grasp the sectors of the Indian economy, understand their characteristics, and recognize their importance. This guide will provide detailed notes on the Sectors of the Indian Economy Class 10, using specific long-tail keywords to enhance comprehension.
For more information, visit-www.vavaclasses.com
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
This is a presentation by Dada Robert in a Your Skill Boost masterclass organised by the Excellence Foundation for South Sudan (EFSS) on Saturday, the 25th and Sunday, the 26th of May 2024.
He discussed the concept of quality improvement, emphasizing its applicability to various aspects of life, including personal, project, and program improvements. He defined quality as doing the right thing at the right time in the right way to achieve the best possible results and discussed the concept of the "gap" between what we know and what we do, and how this gap represents the areas we need to improve. He explained the scientific approach to quality improvement, which involves systematic performance analysis, testing and learning, and implementing change ideas. He also highlighted the importance of client focus and a team approach to quality improvement.
How to Make a Field invisible in Odoo 17Celine George
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
1. University of Engineering & Technology LHR
(FAISALABAD CAMPUS) by FAISAL SAEED
Trapezoidal Rule
function trapezoidalrule
x0=input('Enter the value of initial input: ');
xn=input ('Enter the value of final input: ');
n=input ('Enter the total no of intervals : ');
h=(xn-x0)/n
f=input('Enter the function to be evaluated:');
sum=0;
for i=x0:h:xn
if(i==x0 || i==xn)
continue;
end
sum=sum +f(i);
end
sum=sum*2;
trapezoidal=h/2*(f(x0)+f(xn)+sum)
end
2. Output:-
Simpsons 1/3 Rule
function simpsonsrule
x0=input('Enter the value of initial input: ');
xn=input ('Enter the value of final input: ');
n=input ('Enter the total no of intervals : ');
h=(xn-x0)/n
f=input('Enter the function to be evaluated:');
sum=f(x0)+f(xn)+4*f(xn-h);
for count=1:2:n-3;
sum=sum+4*f(x0+count*h)+2*f(x0+(count+1)*h);
A=h*sum/3;
end
fprintf('integration is %d n ',A);
end
4. Simpsons 3/8 Rule
function simpsonsrule
x0=input('Enter the value of initial input: ');
xn=input ('Enter the value of final input: ');
n=input ('Enter the total no of intervals : ');
h=(xn-x0)/n
f=input('Enter the function to be evaluated:');
sum=f(x0)+f(xn);
for count=1:n-1;
if (mod(count,3)==0)
sum=sum+2*f(x0+count*h);
else
sum=sum+3*f(x0+count*h);
end
end
A=sum*3*h/8;
fprintf('integration is %d n ',A);
end
Output:-
5. Booles Rule
function boolesrule
x0=input('Enter the value of initial input: ');
xn=input ('Enter the value of final input: ');
n=input ('Enter the total no of intervals : ');
h=(xn-x0)/n
f=input('Enter the function to be evaluated:');
sum=7*(f(x0)+f(xn))+32*f(xn-h);
for count=1:2:n-3;
sum=sum+32*f(x0+count*h)+12*f(x0+(count+1)*h);
A=2*h*sum/45;
end
fprintf('integration is %d n ',A);
end
Output:-
6. Weddles Rule
function weddlesrule
x0=input('Enter the value of initial input: ');
xn=input ('Enter the value of final input: ');
n=input ('Enter the total no of intervals : ');
h=(xn-x0)/n
f=input('Enter the function to be evaluated:');
sum=0;
sum1=0;
sum2=0;
for count=0:2:n;
sum=sum +f(count*h);
end
for count=1:4:n-1;
sum1=sum1+5*f(count*h);
end
for count=3:4:n-1;
sum2=sum2+6*f(count*h);
end
integrationis=3*h*(sum+sum1+sum2)/10
end
7. Output:-
Rectangular Rule
function rectangularrule
x0=input('Enter the value of initial input: ');
xn=input ('Enter the value of final input: ');
n=input ('Enter the total no of intervals : ');
h=(xn-x0)/n
f=input('Enter the function to be evaluated:');
sum=0;
for i=x0:h:xn
sum=f(i);
end
A=h*sum
end
Output:-
